I am looking for a software solution that will search for a specific string in a file name. ex: Search for: "1234" || Files Found: "A_1234" "B_1234"
When the program finds that file with the matching string, it will then open it and search for another string. ex: Search for: "foo" ||Files that are "1234" that contain "foo": "A_1234"
I can write my own code for it, I have a good idea on how to do it. Just looking for an existing solution so I do not have to make my own custom application.
Thanks!
Related
I have a script which saves some files at a given location. It works fine but when I send this code to someone else, he has to change the paths in the code. It's not comfortable for someone who does not know what is in that code and for me to explain every time where and how the code should be changed.
I want to get this path in a variable which will be taken from the configuration file. So it will be easier for everyone to change just this config file and nothing in my code. But I have never done this before and could not find any information on how I can do this in the internet.
PS: I do not have any code and I ask about an ultimate solution but it is really difficult to find something good in the internet about dxl, especially since I'm new with that. Maybe someone of you already does that or has an idea how it could be done?
DXL has a perm to read the complete context of a file into a variable: string readFile (string) (or Buffer readFile (string))
you can split the output by \n and then use regular expressions to find all lines that match the pattern
^\s*([^;#].*)\s*=\s*(.*)\s*$
(i.e. key = value - where comment lines start with ; or #)
But in DOORS I prefer using DOORS modules as configuration modules. Object Heading can be the key, Object Text can be the value.
Hardcode the full name of the configuration module into your DXL file and the user can modify the behaviour of the application.
The advantage over a file is that you need not make assumptions on where the config file is to be stored on the file system.
It really depends on your situation. You are going to need to be a little more specific about what you mean by "they need to change the paths in the code". What are these paths to? Are they DOORS module paths, are they paths to local/network files, or are the something else entirely?
Like user3329561 said, you COULD use a DOORS module as a configuration file. I wouldn't recommend it though, simply because that is not what DOORS modules were designed for. DOORS is fully capable of reading system files in one line at a time as well as all at once, but I can't recommend that option either until I know what types of paths you want to load and why.
I suspect that there is a better solution for your problem that will present itself once more information is provided.
I had the same problem, I needed to specify the path of my configuration file used in my dxl script.
I solved this issue passing the directory path as a parameter to DOORS.exe as follow:
"...\DOORS\9.3\bin\doors.exe" -dxl "string myVar = \"Hello Word\"
then in my dxl script, the variable myVar is a global variable.
I'm planning to do a program with Lua that will first of all read specific files
and get information from those files. So my first question is whats the "my documents" path name? I have searched a lot of places, but I'm unable to find anything. My second question is how can I use the first four letters of a file name to see which one is the newest made?
Finding the files in "my documents" then find the newest created file and read it.
The reading part shouldn't be a problem, but navigating to "my documents" and finding the newest created file in a folder.
For your first question, depends how robust you want your script to be. You could use Lua's builtin os.getenv() to get a variety of environment vars related to user, such as USERNAME, USERPROFILE, HOMEDRIVE, HOMEPATH. Example:
username = os.getenv('USERNAME')
dir = 'C:\\users\\' .. username .. '\\Documents'
For the second question, there is no builtin mechanism in Windows to have the file creation or modification timestamp as part of the filename. You could read the creation or modification timestamp, via a C extension you create or using an existing Lua library like lfs. Or you could read the contents of a folder and parse the filenames if they were named according to the pattern you mention. Again there is nothing built into Lua to do this, you would either use os.execute() or lfs or, again, your own C extension module, or combinations of these.
I'm using:
Rails 3.2x
Spree 1.2
Ruby 1.9.3x
I'm trying to edit the title of one of my pages, and I cannot find where it is getting defined. It is showing up in my base ERB file as 'title', but that name is sufficiently generic to make it next to impossible to find where it is defined.
I have prodded everywhere I can think, I've tried searching for "title =", but nothing is working. I tried calling source_location on it, but that appears to only work on methods.
Any tricks for finding where a variable is defined?
I can't think of an elegant way. A dumb-but-probably-effective way would be to dump stack trace in your erb, then see what those locations are doing and if title is defined there. It has to enter somewhere between the start of program and invoking your erb.
When I can't find something, I use grep -ri some_string . at the command-line to recursively search all the content of the directory.
It's also a good tactic to let your editor search all the source code, since the ones worth using have the ability to search through all files in a directory.
it is created from a mixture of product names, a site config, and something else
An alternate trick is to add a HTML-comment section in your ERB file, and put the pertinent information for the components used to create the title into that section. Then, let the pages be generated and look inside the page's content to determine what table and row ID it is, the site_config filename, etc.
You really should be able to figure it out based on the parts that are concatenated to build the title and then search your database or files. That information isn't magically created out of thin air by Rails; Someone had to tell Rails how to define the title. But, people move on, or they don't document correctly, so try the embedded information trick.
I'm trying to use Kivy as a GUI for my python app, which needs to read a file from the filesystem.
However, in some cases the kivy filechooser read wrong path or nothing causing an IndexError while I'm trying to set the read path for a text of a textfield.
I use the default example for reading files learned from http://kivy.org/docs/api-kivy.uix.filechooser.html
The relevant part of my app is in this function, where an exception handling is added as a not a good approach to handle this :)
def load(self, path, filename):
'''
this will load the file and dismiss the dialog
'''
print "Loading file..."
print "filename:",filename
print "path:",path
try:
self.selected_file = filename[0]
self.file_text_input.text = self.selected_file
self.dismiss_popup()
except IndexError as ie:
print "Something made a boo-boo...try again"+str(ie)
self.dismiss_popup()
self.show_popup("ERROR","Somehow I couldn't load the file:\nCheck the permissions or move it to other place")
self.show_popup() is just a helper function, which shows a popup with the set function params.
The basic error is that filename[0] will throw an IndexError since it does not read the correct path.
I'm using Linux with python2.7, and somethimes when I select a file in my home folder, the filename variable stores nothing, while path variable stores misteriously a random folder, for instance, /media, /opt, etc.
Did anyone meet this issue?
I found out why it was handled uncorrectly.
All the failures are caused by Kivy's
FileChooserListView
, which enables to click on folders and files via a list, but it also makes it possible to have a littel '>' sign at the beginning of every list element, which are directories.
I realized that when I used these '>' signs, then I get wrong path, but if I always clicks on the directories' list elements then everything works fine.
However, that little '>' cannot be disabled (for now), so the best and fastest alternate solution is using
FileChooserIconView
instead!
Now everything is good :)
I am trying to test the contents of a file that is generated from code. The problem is that the full name of the file is based on a timestamp abc123_#{d.strftime('%Y%m%d%I%M%S')}.log
How could I use File to find this file and read it? I tried doing File.exists?() with a regular expression as the parameter but that didn't work.
I found this in another question on stackoverflow:
File.basename(file_path).match(/_.*(css|scss|sass)/)
How would I be able to use that in my case where the file is located in mypublic folder?
ANSWER
So the two answers below both work and I used a combination of them.
Dir['public/*.log'].select { |f| f =~ /purge_cc_website/}
The * acts as a wildcard that is sort of a regular expression in itself. After that you filter the array using an actual regex.
Dir[] takes a file glob so, if your pattern isn't too complicated, you can just do:
Dir['public/abc123_*.log']
More glob info here.
File is for reading one file. You need to use Dir to find files by name.
files = Dir['*'].select {|x| x =~ /_.*(css|scss|sass)/ }
If you just want the last file in the case of dups:
files = Dir['*'].select {|x| x =~ /_.*(css|scss|sass)/ }.sort.last