changing the text field in parser of antlr tool - parsing

In Antlr4 grammar , I have a simple rule which is equivalent to
a : b
;
I want to concat a string('hello') to the end of the text of a
I tried something like
a : b
{
$b.text.concat('Hello');
};
But this didn't work .. How can I achieve this?
Note : a aint the outermost rule or start rule of grammar

No, that is not possible. b is a parser rule which is a ordered collection of 0 or more tokens. You can't just append a string to this, nor is it possible to insert a token on the fly.

Related

How to get a quote-enclosed string and discard the quote itself

I would like to parse text enclosed in single quotes as just the text itself. For example:
"hello" --> hello
I'm able to parse the string with the quotes in antlr using the following rule:
grammar Test;
root
: string EOF
;
string
: QUOTE WORD QUOTE
;
WORD
: [a-zA-Z0-9-]+
;
QUOTE
: '"'
;
And with the input text "mrrogers":
However I'm not sure how to 'discard' the S_QUOTE values, I've tried doing the following two items and it seems like I'm on the wrong course:
fragment QUOTE
: '\''
;
And:
QUOTE
: '\'' -> skip
;
What would be the proper way to do this?
IMO it's better to just keep the quotes in the token and eliminate them at the stage where you need the text. This also allows you to handle special case, like the conversion of double-quotes (two consecutive quote char) to single quotes or handle escape codes (if this is something you want to support).
If you separate your grammar into a Lexer grammar and a Parser grammar, you can use lexical modes to control which tokens are emitted for use by the parser.
As #MikeCargal has intimated, this is a simplistic solution but may help you see how your grammars may be structured.
TestLexer.g4
lexer grammar TestLexer;
tokens { WORD }
NEWLINE
: [\n\r]
->channel(HIDDEN)
;
QUOTE
: '"'
->pushMode(STRING_MODE),channel(HIDDEN)
;
mode STRING_MODE;
WORD
: [a-zA-Z0-9-]+
;
STRING_MODE_QUOTE
: '"'
->popMode,channel(HIDDEN)
;
The tokens { WORD } is an instruction to ANTLR to include the WORD token in the generated TestLexer.tokens file. This makes it visible to the parser.
The pushMode(STRING_MODE) is a way to have the lexer only emit tokens defined in the section mode STRING_MODE. ANTLR maintains a stack of modes, lexing starts out in DEFAULT_MODE and each pushMode() pushes a new mode onto the stack as the current mode governing which tokens will be emitted. Each popMode pops the current mode off the stack and the next one on the stack takes precedence.
TestParser.g4
parser grammar TestParser;
options { tokenVocab=TestLexer; }
root
: string EOF
;
string
: WORD
;
These are very simplistic rules for a String type. How would you handle a string that should contain a ', for example. (Maybe you're string content is as simple as your word rule, but it looks more like this is just a starting point.
It will probably serve you well to take a look at the String rules in a grammar for a language with strings similar to what you want to allow. (You can find many grammars here. (It's pretty common to need to use Lexer modes to properly parse a String token)
I think you'll find that you need to capture the initial and terminal ' (or ") characters in the Lexer rule, so they will, necessarily be a part of the token. It's really trivial to strip thee first and last character from your token to get the string content from the token in your ParseTree.

How to differentiate between a parser and lexer rule in the following?

Sometimes I get a bit confused between a lexing rule vs. a parsing rule, and there's been a nice thread on it here. For example in the following:
value
: string CAST_OPERATOR type
;
string
: S_QUOTE STRING_VALUE S_QUOTE
;
# <-- what is this?
type
: 'date' | 'string'
;
STRING_VALUE
: [a-zA-Z0-9-]+
;
CAST_OPERATOR
: '::'
;
For the type -- this is either the string (or character stream) date or string. Should that be a lexing rule or a parsing rule? I suppose I could break it down even more into:
type
: DATE_TYPE | STRING_TYPE
;
DATE_TYPE
: 'date'
;
STRING_TYPE
: 'string'
;
But still I'm not quite sure which of the above is preferable, and why it would be so. The first two rules -- value and string seem clear to me to be parsing rules -- and the last two rules -- STRING_VALUE and CAST_OPERATOR seem clear to me to be lexing rules (only by intuition though, I could not give a proper explanation). So why would the type be one way or the other?
Literally the only practical difference I've found is that a lexing rule can include a character class and a parsing rule cannot.
Update: I suppose another thing is a lexing rule is terminal, it won't provide any subdivision of parts. For example in the following we can break down $55 into $ and 55:
But if we set the cost as a lexing rule, it will not break it down any further:
So basically a lexing rule is atomic and terminal, whereas a parsing rule is more like a molecule that consists of various parts (atoms) that can be seen within it. Is that a good description/understanding of it?
Your "Update" is on the right track. That's a definite distinction.
You also need to understand the ANTLR pipeline. I.e. that the stream of characters is processed by the Lexer rules to produce a stream of tokens (atoms, in you analogy). It does not do that with recursive descent rule matching, but rather attempts to match you input against all of the Lexer rules. Where:
The rule that matches the longest sequence of input characters will "win"
In the event that multiple Lexer rules match the same length character sequence, then the rule that occurs first will "win"
Once you've got you stream of "atoms" (aka Tokens), then ANTLR uses the parser rules (recursively from the start rule) to try to match sequences of tokens.

ANTLR Tries to Match an Expression That Wasn't Specified as an Option

I'm trying to understand how ANTLR grammars work and I've come across a situation where it behaves unexpectedly and I can't explain why or figure out how to fix it.
Here's the example:
root : title '\n' fields EOF;
title : STR;
fields : field_1 field_2;
field_1 : 'a' | 'b' | 'c';
field_2 : 'd' | 'e' | 'f';
STR : [a-z]+;
There are two parts:
A title that is a lowercase string with no special characters
A two character string representing a set of possible configurations
When I go to test the grammar, here's what happens: first I write the title and, on a new line, give the character for the first field. So far so good. The parse tree looks as I would expect up to this point.
When I add the next field is when the problem comes up. ANTLR decides to reinterpret the line as an instance of STR instead of a concatenation of the fields that I was expecting.
I do not understand why ANTLR tries to force an unrelated terminal expression when it wasn't specified as an option by the grammar. Shouldn't it know to only look for characters matching the field rules since it is descended from the fields node in the parse tree? What's going on here and how do I write my ANTLR grammars so they don't have this problem?
I've read that ANTLR tries to match the format greedily from the top of the grammar to the bottom, but this doesn't explain why this is happening because the STR terminal is the very last line in the file. If ANTLR gives special precedence to matching terminals, how do I format the grammar so that it interprets it properly? As far as I understand, regexes do not work for non-terminals so it seems that have to define it how it is now.
A note of clarification: this is just an example of a possible grammar that I'm trying to make work with the text format as is, so I'm not looking for answers like adding a space between the fields or changing the title to be uppercase.
What I didn't understand before is that there are two steps in generating a parser:
Scanning the input for a list of tokens using the lexer rules (uppercase statements) and then...
Constructing a parse tree using the parser rules (lowercase statements) and generated tokens
My problem was that there was no way for ANTLR to know I wanted that specific string to be interpreted differently when it was generating the tokens. To fix this problem, I wrote a new lexer rule for the fields string so that it would be identifiable as a token. The key was making the FIELDS rule appear before the STR rule because ANTLR checks them in the order they appear.
root : title FIELDS EOF;
title : STR;
FIELDS : [a-c] [d-f];
STR : [a-z]+;
Note: I had to bite the bullet and read the ANTLR Mega Tutorial to figure this out.

Lexer rule optional suffix not matching, when it should match

Using ANTLR 3, my lexer has rule
SELECT_ASSIGN:
'SELECT' WS+ IDENTIFIER WS+ 'ASSIGN' WS+ (('TO'|'USING') WS+)?
using this these match correctly
SELECT VAR1 ASSIGN TO
SELECT VAR1 ASSIGN USING
and this also matches
SELECT VAR1 ASSIGN FOO
However this does not match
SELECT VAR1 ASSIGN TWO
Whereas I have marked TO|USING as optional in the rule.
From generated Java code I see...
When lexer notices T of TWO, it goes to match('TO')
but since does not find O after T
then generates failure.... and returns all the way from the rule -- hence not matching it.
How do I get my lexer rule to match, when input has word with chars starting with suffixed optional part of the rule
Basically I want my rule to match this also (beside what it already matches - as lised at the start):
SELECT VAR1 ASSIGN TWO
Kindly suggest how I approach/resolve this situation.
NOTE:
Such rules are recommended in the parser - But I have this in lexer - because I do not want to parse the entire input by the parser, and want to parse only content of interest. So using such rules in lexer, I locate sections which I really want to parse by the parser.
UPDATE 1
I could circumvent this problem by making 2 rules, like so:
SELECT_ASSIGN_USING_TO
: tok='SELECT' WS+ name=IDENTIFIER WS+ 'ASSIGN' WS+ ('USING'|'TO')
SELECT_ASSIGN
: tok='SELECT' WS+ name=IDENTIFIER WS+ 'ASSIGN'
But is it possible to do the desired in one lexer rule?
An approach to get this in one rule, suggested by my senior - use syntactic predicate
SELECT_ASSIGN
: tok='SELECT' WS+ name=IDENTIFIER WS+ 'ASSIGN'
(
(WS+ ('TO'|'USING') WS+)=> (WS+ ('TO'|'USING') WS+)
| (WS+)
)
Tokens match a complete char sequence or none. It cannot match partially and the grammar rule determines which exactly. You cannot expect a rule for TO to match TWO. If you want TWO to match too you have to add it to your lexer rule.
A few notes here:
The solution your "senior" gave you makes no sense at all. A
syntactic predicate is a kinda lookahead to guide the parser in case
of ambiquities. There are no ambiquities involved here.
Writing
the entire SELECT_ASSIGN rule as a lexer rule is very uncommon and
not flexible. A lexer rule should not be used for entire sentences,
but only for a small set of characters to find tokens to assign them
a type (usually elementary structures of a language like string,
number, comment etc.).
ANTLR3 is totally outdated and I wonder why this is still used in your class. ANTLR4 is out since 5 years and should be the choice for any new project.

How to match any symbol in ANTLR parser (not lexer)?

How to match any symbol in ANTLR parser (not lexer)? Where is the complete language description for ANTLR4 parsers?
UPDATE
Is the answer is "impossible"?
You first need to understand the roles of each part in parsing:
The lexer: this is the object that tokenizes your input string. Tokenizing means to convert a stream of input characters to an abstract token symbol (usually just a number).
The parser: this is the object that only works with tokens to determine the structure of a language. A language (written as one or more grammar files) defines the token combinations that are valid.
As you can see, the parser doesn't even know what a letter is. It only knows tokens. So your question is already wrong.
Having said that it would probably help to know why you want to skip individual input letters in your parser. Looks like your base concept needs adjustments.
It depends what you mean by "symbol". To match any token inside a parser rule, use the . (DOT) meta char. If you're trying to match any character inside a parser rule, then you're out of luck, there is a strict separation between parser- and lexer rules in ANTLR. It is not possible to match any character inside a parser rule.
It is possible, but only if you have such a basic grammar that the reason to use ANTlr is negated anyway.
If you had the grammar:
text : ANY_CHAR* ;
ANY_CHAR : . ;
it would do what you (seem to) want.
However, as many have pointed out, this would be a pretty strange thing to do. The purpose of the lexer is to identify different tokens that can be strung together in the parser to form a grammar, so your lexer can either identify the specific string "JSTL/EL" as a token, or [A-Z]'/EL', [A-Z]'/'[A-Z][A-Z], etc - depending on what you need.
The parser is then used to define the grammar, so:
phrase : CHAR* jstl CHAR* ;
jstl : JSTL SLASH QUALIFIER ;
JSTL : 'JSTL' ;
SLASH : '/'
QUALIFIER : [A-Z][A-Z] ;
CHAR : . ;
would accept "blah blah JSTL/EL..." as input, but not "blah blah EL/JSTL...".
I'd recommend looking at The Definitive ANTlr 4 Reference, in particular the section on "Islands in the stream" and the Grammar Reference (Ch 15) that specifically deals with Unicode.

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