I want to understand z3 master source code.I followed the calls from main file for input kind of smt2. for this type of input main file calls smtlib_frontend file via the below code(line 341):
case IN_SMTLIB_2:
memory::exit_when_out_of_memory(true, "(error \"out of memory\")");
return_value = read_smtlib2_commands(g_input_file);
break;
and then this method calls smt2parser via(line 128) :
result = parse_smt2_commands(ctx, in);
in smt2parser.cpp and in the called method :
bool parse_smt2_commands(cmd_context & ctx, std::istream & is, bool
interactive, params_ref const & ps) {
smt2::parser p(ctx, is, interactive, ps);
return p();
}
I have 2 problem :
first : what does p() mean? parser class just has one constructor (parser (ctx, is, interactive, ps)) and don't have any method with the name of p.
second : after calling this method, the caller graph will be disconnected while this file is the main class for parsing smt2lib in z3 and has a method with the name "parse_cmd()" that seems it is main method for starting the parsing operation. but there is no refrence to this method.
These lines of code:
smt2::parser p(ctx, is, interactive, ps);
return p();
mean "construct an object of type smt2::parser with name p" (via the constructor that takes 4 arguments) and then call the function p.operator() (with no arguments) and return its result; see here. (Redefining what the parentheses mean is called "operator overloading" and is a concept that exists in many languages.)
SMT2 is a command language, i.e., a benchmark file contains a series of commands, each of which will trigger a call to parse_cmd.
Related
The Error Handling chapter of the Rust Book contains an example on how to use the combinators of Option and Result. A file is read and through application of a series of combinators the contents are parsed as an i32 and returned in a Result<i32, String>.
Now, I got confused when I looked at the code. There, in one closure to an and_then a local String value is created an subsequently passed as a return value to another combinator.
Here is the code example:
use std::fs::File;
use std::io::Read;
use std::path::Path;
fn file_double<P: AsRef<Path>>(file_path: P) -> Result<i32, String> {
File::open(file_path)
.map_err(|err| err.to_string())
.and_then(|mut file| {
let mut contents = String::new(); // local value
file.read_to_string(&mut contents)
.map_err(|err| err.to_string())
.map(|_| contents) // moved without 'move'
})
.and_then(|contents| {
contents.trim().parse::<i32>()
.map_err(|err| err.to_string())
})
.map(|n| 2 * n)
}
fn main() {
match file_double("foobar") {
Ok(n) => println!("{}", n),
Err(err) => println!("Error: {}", err),
}
}
The value I am referring to is contents. It is created and later referenced in the map combinator applied to the std::io::Result<usize> return value of Read::read_to_string.
The question: I thought that not marking the closure with move would borrow any referenced value by default, which would result in the borrow checker complaining, that contents does not live long enough. However, this code compiles just fine. That means, the String contents is moved into, and subequently out of, the closure. Why is this done without the explicit move?
I thought that not marking the closure with move would borrow any referenced value by default,
Not quite. The compiler does a bit of inspection on the code within the closure body and tracks how the closed-over variables are used.
When the compiler sees that a method is called on a variable, then it looks to see what type the receiver is (self, &self, &mut self). When a variable is used as a parameter, the compiler also tracks if it is by value, reference, or mutable reference. Whatever the most restrictive requirement is will be what is used by default.
Occasionally, this analysis is not complete enough — even though the variable is only used as a reference, we intend for the closure to own the variable. This usually occurs when returning a closure or handing it off to another thread.
In this case, the variable is returned from the closure, which must mean that it is used by value. Thus the variable will be moved into the closure automatically.
Occasionally the move keyword is too big of a hammer as it moves all of the referenced variables in. Sometimes you may want to just force one variable to be moved in but not others. In that case, the best solution I know of is to make an explicit reference and move the reference in:
fn main() {
let a = 1;
let b = 2;
{
let b = &b;
needs_to_own_a(move || a_function(a, b));
}
}
Please unwrap these type signatures to help me understand why this doesn't work.
Then, if you have a solution, that would be great too.
I have this code and the agent.Post command has the signature Observer.Create<'T>(onNext: Action<'T>) : IObserver<'T>
let reservatinoRequestObserver = Observer.Create agent.Post
interface IHttpControllerActivator with
To my knowledge, this means that Observer.Create should take an Action with a single generic parameter and then return an IObserver.
Now the definition of Post is member MailboxProcessor.Post : message:'Msg ->unit
So... Post is a method, no? It is a method that takes a single parameter no? And it returns void no? So shouldn't it be a candidate for Observer.Create? Isn't that the exact specification of Action<'T>?
Well, somethings up, I get This function takes too many arguments, or is used in a context where a function is not expected:
Help me out... I freely admit I suck at F#
First, agent.Post returns unit, which is a different thing from void. F# will usually convert back and forth between void and unit for you, but they are not the same thing.
Second, F# functions do not implicitly convert to .NET delegates.
But there are some ways to do it:
You can explicitly create the delegate using its constructor:
let o = Observer.Create (new Action<_>( agent.Post ))
Lambdas are nicely wrapped too
let o = Observer.Create (fun msg -> agent.Post msg)
Use F# Rx-wrappers
Also there are a couple of F# wrappers/interop for Rx on nuget - just have a look, I think any will do
These 4 lines compile but do not make sense to me :
open System
type mclas (y) =
member x.m = x.m
let z = mclas (1:>obj)
Question : In what case would we need to code in such way ? Am I activating subtle class features I am not aware of ?
Edit : If there is no use case, what is the status of this piece of code regarding compiler warning/error and is it eligible for some Issue raising on github ?
Note : At runtime, the debugger cannot evaluate variable z saying "Function evaluation timed out".
The member m actually compiles to something like this in IL:
.property instance object m {
.get instance object Program/mclas::get_m()
}
So m is a property of type object which has a getter that recurses endless. The C# equivalent of this would be:
public class mclas
{
public mclas(object y) { }
public object x {
get {
return x;
}
}
}
Because the recursion never ends, taking too long and/or there is a StackOverflowException happening when the Debugger tries to evaluate m, it cancels and spits out that the evaluation timed out.
And for your actual question: I don't think that you ever need this kind of self-reference in F#, at least I can't think of any possible use.
I think that this behaviour of the compiler makes sense, because a member without paramters will always compile to a get-only property, and then this would be the most obvious way of defining an infinite recursing property (just because this has no use doesn't mean that you can't do it).
I have a file with a module with some routines that take parameters and return unit, these routines have side-effects. I noticed that when accessing these f# routines from c# they're actually properties of type unit and when I try to access 1 property, it runs all properties in the module.
From the F# documentation all top level do bindings are run on type initialization.
What is the preferred way to write functions that should not be run on type initialization but are also not associated with other state i.e. a class with functions and member variables?
Should I put these functions inside a type and just have no records in the type?
Code example:
namespace test_space
open System.Diagnostics;
module test =
let test_1 =
Debug.WriteLine ("One")
let test_2 =
Debug.WriteLine ("Two")
I'm running this code with C#:
static void Main (string [] args)
{
Object o;
o = test.test_2;
}
And the output is:
One
Two
The problem is you didn't create functions but value bindings. test_1 is a value. test_1() is a function of type unit -> unit. Make sure you put () after the function name.
I don't fully understand the scenario you're describing - F# functions declared in a module will generally appear as methods and values will appear as properties. The code that is executed when you first access module (type initialization) is the initialization of values.
If you write just:
module Foo =
let Operation () =
printfn "hello"
...then calling Operation will be a method and calling Foo.Operation() will run the side-effect. If you can post some code that behaves unexpectedly, then someone can explain it.
Anyway, if you want to be sure about the behavior, you can write operations as static members of a class:
type Foo =
static member Operation() =
printfn "hello"
Then you can be sure that F# will compile them as static members of a class in a predictable way.
I want users of my C++ application to be able to provide anonymous functions to perform small chunks of work.
Small fragments like this would be ideal.
function(arg) return arg*5 end
Now I'd like to be able to write something as simple as this for my C code,
// Push the function onto the lua stack
lua_xxx(L, "function(arg) return arg*5 end" )
// Store it away for later
int reg_index = luaL_ref(L, LUA_REGISTRY_INDEX);
However I dont think lua_loadstring will do "the right thing".
Am I left with what feels to me like a horrible hack?
void push_lua_function_from_string( lua_State * L, std::string code )
{
// Wrap our string so that we can get something useful for luaL_loadstring
std::string wrapped_code = "return "+code;
luaL_loadstring(L, wrapped_code.c_str());
lua_pcall( L, 0, 1, 0 );
}
push_lua_function_from_string(L, "function(arg) return arg*5 end" );
int reg_index = luaL_ref(L, LUA_REGISTRY_INDEX);
Is there a better solution?
If you need access to parameters, the way you have written is correct. lua_loadstring returns a function that represents the chunk/code you are compiling. If you want to actually get a function back from the code, you have to return it. I also do this (in Lua) for little "expression evaluators", and I don't consider it a "horrible hack" :)
If you only need some callbacks, without any parameters, you can directly write the code and use the function returned by lua_tostring. You can even pass parameters to this chunk, it will be accessible as the ... expression. Then you can get the parameters as:
local arg1, arg2 = ...
-- rest of code
You decide what is better for you - "ugly code" inside your library codebase, or "ugly code" in your Lua functions.
Have a look at my ae. It caches functions from expressions so you can simply say ae_eval("a*x^2+b*x+c") and it'll only compile it once.