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I'm working on a search bar within my iOS App and have a SQLite offlite db with about 300k records in it. The text name is how I'd like the search to person. I have the following code working which just does a basic search on String.
func searchList(searchQuery: String, filter: SearchFilter, limit: Int = 20, page: Int = 0) -> outputItems {
guard let db = self.db else { return [] }
var outputTable = Table(OfflineDBSchema.DBTables.outputTable.rawValue)
if !searchQuery.isEmpty {
outputTable = outputTable.filter(OfflineoutputTableColumnExpressions.name.lowercaseString.like("%\(searchQuery.lowercased())%"))
}
I'm looking for a search basic algorithm that is a little bit "smarter" which is better at finding those keywords and returning a results back with most relevant terms at the top.
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Hello I wrote this little piece of code, but I have the impression that it is not optimal, indeed as the field variable is in get only : I can not directly change it .... but I am junior : so I would be delighted if someone has a better idea :) thank you .
let keyword = ["potatoes","garlic"]
var field: String {
var element = ""
keyword.forEach {
element += "&field=" + $0
}
return element
}
a shorter code coming from professionalswift developper :)
this would be better
let keyword = ["potatoes","garlic"]
var field: String {
return keyword.map { "&field=\($0)"}.joined()
}
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I am new to swift programming.I am working in an app of emoji.When i click an emoji from Apple keyboard it show the unicode of that emoji.How can i get this.
Here is list of uicodes
https://apps.timwhitlock.info/emoji/tables/unicode
you can also use Edit->Emoji and drag the to the text
let str = "Ti😁 \u{1F601} tle"
use Swift Unicode escape sequence concept:
let emojiString = "\u{1F4C4}"
and if you want to get all emoji's Unicode then try this
let emojiRanges = [
0x1F601...0x1F64F,
0x2702...0x27B0,
0x1F680...0x1F6C0,
0x1F170...0x1F251
]
for range in emojiRanges {
for i in range {
var c = String(UnicodeScalar(i))
print(c)
}
}
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this method was writing with swift 3 in swift 4 I get error and I don't know where is the error
var CURRENT_USER: User? {
if let currentUser = Auth.auth().currentUser {
return currentUser
}
return nil
}
The error might have something to do with the optional type since it states that:
Cannot convert return expression of type 'User' to return type 'User?'
A good place to start would be to return an optional value by changing your code to
var CURRENT_USER: User? {
return Auth.auth().currentUser
}
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I'm trying to observe this value:
With this code:
But this give me error. I tried many times with other database methods like make value1 in a single child divided by value 2.
Try this
ref2.child("keywords").child("hello").child("hello").observe(.value, with: { snapshot in
guard
let dict = snapshot.value as? [String:Any],
let value1 = dict["value1"] as? Int
else { print("Error"); return }
print(value1)
})
Next time paste your code as text, not as an image
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I use below line of code to allocate an Object(Suppose my Object name is Car) dynamically.
[self initliazieObject:[Car class]]
- (id)initliazieObject:(Class)model{
id record = [[model alloc] init];
return record;
}
How I can do this in swift 3.
Exactly as in Objective-C. Try this in a playground:
class Car : NSObject {}
func factory(type:NSObject.Type) -> NSObject {
return type.init()
}
let c = factory(type:Car.self)
print(type(of:c)) // Car
(We can get fancy and do clever things with generics or Self to specify the type of the returned object more precisely, but my goal in this code is simply to do things the dumb way, just like Objective-C.)