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I have 3 sheets:
Sheet1 - list of transactions (Account, Credit, Debit, Date)
Sheet2 - list of transactions (Account, Credit, Debit, Date)
Sheet3 (I plan to lock it) - combined list of transactions, sorted by Date
Sheet3 looks like:
I need to add 1 more column to Sheet3 to count current balance for certain row to be like:
I'm able to do this with formula:
=SUM(FILTER($B$2:$B$8, ROW($A$2:$A$8) <= ROW($A2), A$2:A$8=$A2)) - SUM(FILTER($C$2:$C$8, ROW($A$2:$A$8) <= ROW($A2), A$2:A$8=$A2))
But this one I need continuously drag down.
Question: Is there way convert this formula to ArrayFormula, to avoid dragging
In G2 on sheet 3 I entered
=ArrayFormula(if(A2:A="",,mmult((A2:A=transpose(A2:A))*(row(A2:A)>= TRANSPOSE(row(A2:A)))*(transpose(B2:B)-transpose(C2:C)),row(A2:A)^0)))
See if that works for you?
In Sheet3 row 1, put your headers.
In Sheet3!A2, put
=sort({filter(Sheet1!A2:D,not(isblank(Sheet1!A2:A)));filter(Sheet2!A2:D,not(isblank(Sheet2!A2:A))),4,true)
In Sheet3!E2, put
=mmult(transpose(arrayformula(arrayformula(array_constrain(A2:A,counta(A2:A),1)=transpose(array_constrain(A2:A,counta(A2:A),1)))
*arrayformula(array_constrain(row(A2:A),counta(A2:A),1)<=transpose(array_constrain(row(A2:A),counta(A2:A),1))))),
arrayformula(array_constrain(B2:B,counta(A2:A),1)-array_constrain(C2:C,counta(A2:A),1))
To see why, let's temporarily remove the array_constrain(...,counta(...),1) wrappings, which is meant to auto detect the last data row:
=mmult(transpose(arrayformula(arrayformula(A2:A9=transpose(A2:A9))
*arrayformula(row(A2:A9)<=transpose(row(A2:A9))))),
arrayformula(B2:B9-C2:C9))
arrayformula(B2:B9-C2:C9) are the running sums of column B - column C (ie. credit - debit). It is a column vector with the length of your data size.
We want to, for each row, 1) filter this vector by comparison to column A (ie. account name) & 2) filter this vector by whether the running sums are below or above the row in question.
arrayformula(A2:A9=transpose(A2:A9)) does 1). arrayformula(row(A2:A9)<=transpose(row(A2:A9))) does 2).
We want elementwise product between the 2 matrices in order to compose the filter. Hence, arrayformula(...*...).
The columns of our filters are meant to be applied to the running sums. To use matrix multiplication, we can keep the column vector of running sums as the post-multiplier; and transpose the filter matrix as pre-multiplier so that the rows of the transposed matrix are multiplied (ie. applied) to the running sums. Hence, mmult(transpose(...),...).
Add back the array_constrain trick. And we are done.
Feel free to experiment with alternate placings of arrayformula. But remember to keep the () brackets wherever you omit arrayformula. Example:
=arrayformula(mmult(transpose(((array_constrain(A2:A,counta(A2:A),1)=transpose(array_constrain(A2:A,counta(A2:A),1)))
*(array_constrain(row(A2:A),counta(A2:A),1)<=transpose(array_constrain(row(A2:A),counta(A2:A),1))))),
(array_constrain(B2:B,counta(A2:A),1)-array_constrain(C2:C,counta(A2:A),1))))
Nonetheless, the 1 formula solution is computationally inefficient compared to individually spread formula per cell. That is because, without mutating the formula per row, we are forced to compute the filters as full n-by-n matrices where n is your data size.
Whereas, if in E2 we put =sum(filter(B$2:B2-C$2:C2,A$2:A2=A2)) and spread to the end by double right-clicking the square on bottom right when you select E2, the formula mutates per row, saving the row index comparison entirely, and also cutting the comparison to column A logarithmically.
Granted, we probably shouldn't rely on Google Sheet for a large database (e.g. >100k entries). But even for thousands of entries, if you square the amount of computations required, getting the results in browser becomes impractically slow well before one may expect.
In Google Spreadsheets, I want to read a cell containing the string 'e' into a formula which uses the 'e' as the horizontal component of a cell reference, eg 'e12'.
Hopefully clearer example:
a1 contains 'e'
a2 needs to contain 'e2'
then a2:a10 can contain 'eX' where X is 2 to 10.
I'm aware of the INDIRECT method, but I can't see how to use that to populate a2:a10 without a corresponding column of cells all containing 'e', one for each aX.
Perhaps I'm barking up the wrong tree.
I've got a table with list of names on the x axis and dates of meetings on the y axis. In each table element we have some string value to represent if they attended the meeting - eg "y" for attended the meeting "n" for did not, "a" for apologised for abscence in advance.
I also have a list, corresponding to the names on the x axis, of attendance, eg person1 has been to 60% of meetings. The trouble is that for every new meeting I insert a new column closest to the names list, and move all the other meetings one cell to the right. This means that for every new meeting, I have to update the formula with a new cell reference.
Before inserting a new meeting date, the formula looks roughly like DOSOMETHING(b2:y2). I then insert a column to the left of the b column. Google sheets cleverly updates the formula so to be DOSOMETHING(c2:z2), even though I really want the range to be b2:z2. I have tried DOSOMETHING($b2:y2), but inserting the column still causes this problem.
Thank you
instead of:
=DOSOMETHING(B2:Y2)
use this:
=DOSOMETHING(OFFSET($A2,0,1,1,99999))
the offset reference won't get messed up by the insertion of a column since it referrences column B by OFFSETing from column A. 99999 is just an arbitrarily large number that means "all the way to the right of the sheet.
you can read about offset here.
try like this in row 2:
=INDIRECT(A1&ROW()&":"&A1&10)
I'm trying to sum cell values based on an two adjacent cell values to help me organize/visualize my investment portfolio activity. I want to sum only the values in the cells under column B if the accompanying cell in column C and D meet a certain requirement.
Basically, for the values in B2:B1000, take the values for B(n) where C(n) equals "Deposit" and D(n) is equal to "Robinhood" and sum them. Below is a screenshot indicating the cells within column B that I want summed (in red) based on the criteria that meets both conditions. The below logic should give you the sum $1100.
I tried to at least check if C(n) equals Deposit with this line but then it just sums all of the values in column B.
=SUM(IF(C2:C1000=G2, B2:B1000, 0))
My guess is some of the cells in column C meet the condition it sums all of column B. That's the first problem. The second problem is I can't introduce the second condition without creating some sort of error.
My specific case is happening on google sheets.
Answer
Use SUMIFS(): =SUMIFS(B:B,C:C,"Deposit",D:D,"Robinhood")
I'm writing a spreadsheet to keep track of a small business' financials. They operate a few Rooms for rent, and the structure of the document is made so that each sheet holds a year's worth of booking for all the rooms.
Essentially, each row is defines a specific date, while each rooms spans a few columns (reason is that they don't just want to track whether or not a room is booked, but also record names of clients & other remarks), among which the daily calculated income (some factors alter the daily rate each room will generate).
So this is all fine and dandy, and I've created named ranges for each month of the year, and for each room.
For example, rows 6:36 will represent the month of January, while columns C:I will represent Room 1. Room 2 will span J:P and so forth.
Now, in another sheet, I wanted to make a dashboard which lists the earning for each room, per month. It's a very simple table with 12 rows (one for each month) and 10 columns (1 for each room) where I planned to sum up all the earnings.
So my issue is that I can't find a way to retrieve a specific column of a named range for a room ('vertical named range'), which is also limited in a named range for a month ('horizontal named range'). I had read about using ARRAYFORMULA(INDEX(named_range, ,wished_column)) but that only works for a single named range. My knowledge of these two functions being non-existent, I didn't manage to extend it to a 2-named-range version...
(I mean I did try something along the lines of ARRAYFORMULA(INDEX(January, , INDEX(Room1, , 3))) but that didn't work)
So because there isn't a one-to-one relation from the Dashboard cells to the Rooms cells, my current only solution is to manually reference everything, which you'll understand is inefficient and time-consuming...
My question, in fine, is: How can I retrieve a range that results of the intersection of 2 (or more) named ranges ? Once I have that resulting range, I know it will be very easy to use INDEX().
Define a named range Base as
A:Z
Define a range named Horizontal as
6:36
Define a range named Vertical as
C:I
Then the intersection of the vertical and horizontal ranges is given by:
index(Base,row(Horizontal),COLUMN(Vertical)):index(Base,row(Horizontal)+rows(Horizontal)-1,COLUMN(Vertical)+columns(Vertical)-1)
This can be verified by using it in a function e.g.
=countblank(index(Base,row(Horizontal),COLUMN(Vertical)):index(Base,row(Horizontal)+rows(Horizontal)-1,COLUMN(Vertical)+columns(Vertical)-1))
gives the result 7 * 31 = 217 in my sheet because I haven't filled in any of the cells.
The Offset version of this would be:
=countblank(offset(A1,row(Horizontal)-1,COLUMN(Vertical)-1):offset(A1,row(Horizontal)+rows(Horizontal)-2,COLUMN(Vertical)+columns(Vertical)-2))
or more simply:
=countblank(offset(A1,row(Horizontal)-1,COLUMN(Vertical)-1,rows(Horizontal),COLUMNS(Vertical)))
So this works well in OP's case where you have two fully overlapping ranges like this:
Partial Overlap
Suppose you have two partially overlapping ranges like this:
You can use a variation on the standard overlap formula (This is one of the early references to it as used with a date range)
max(start1,start2) to min(end1,end2)
So the previous formula becomes
=countblank(index(Base,max(row(index(Partial1,1,1)),row(index(Partial2,1,1))),max(COLUMN(index(Partial1,1,1)),column(index(Partial2,1,1)))):
index(Base,min(row(index(Partial1,1,1))+rows(Partial1)-1,row(index(Partial2,1,1))+rows(Partial2)-1),min(COLUMN(index(Partial1,1,1))+columns(Partial1)-1,column(index(Partial2,1,1))+columns(Partial2)-1)))
and the offset version is
=countblank(offset(A1,max(row(offset(Partial1,0,0)),row(offset(Partial2,0,0)))-1,max(COLUMN(offset(Partial1,0,0)),column(offset(Partial2,0,0)))-1):
offset(A1,min(row(offset(Partial1,0,0))+rows(Partial1)-2,row(offset(Partial2,0,0))+rows(Partial2)-2),min(COLUMN(offset(Partial1,0,0))+columns(Partial1)-2,column(offset(Partial2,0,0))+columns(Partial2)-2)))
I have tested this on ranges C2:F10 and D3:G11 which gives the result 24 as expected.
However, if there is no overlap, this can still give a non-zero result, so a suitable test needs adding to the formula:
=if(and(max(row(index(Partial1,1,1)),row(index(Partial2,1,1)))<=min(row(index(Partial1,1,1))+rows(Partial1)-1,row(index(Partial2,1,1))+rows(Partial2)-1),
max(column(index(Partial1,1,1)),column(index(Partial2,1,1)))<=min(column(index(Partial1,1,1))+columns(Partial1)-1,column(index(Partial2,1,1))+columns(Partial2)-1)),"Overlap","No overlap")
Perhaps the best approach in Google Sheets is to go back to the full version of the Offset call OFFSET(cell_reference, offset_rows, offset_columns, [height], [width]) . Although this is rather long, it will return a #Value! error if there is no overlap:
=Countblank(offset(A1,
max(row(offset(Partial1,0,0)),row(offset(Partial2,0,0)))-1,
max(COLUMN(offset(Partial1,0,0)),column(offset(Partial2,0,0)))-1,
min(row(offset(Partial1,0,0))+rows(Partial1),row(offset(Partial2,0,0))+rows(Partial2))-max(row(offset(Partial1,0,0)),row(offset(Partial2,0,0))),
min(COLUMN(offset(Partial1,0,0))+columns(Partial1),column(offset(Partial2,0,0))+columns(Partial2))-max(COLUMN(offset(Partial1,0,0)),column(offset(Partial2,0,0)))
))
Notes
Why did I have to introduce some more indexes (indices?) in the second formula to make it work? Because if you use the row function with a range in an array context, you get an array of row numbers which isn't what I want. As it happens, in the first formula you are not using it in an array context, so you just get the first row and column of the given range which is fine. In the second formula, Max and Min try to evaluate all the rows in the array, which gives the wrong answer, so I have used Index(range,1,1) to force it to look only at the top left hand corner of each range. The other thing is that both index and offset return a reference, so it is valid to use the construct Index(...):Index(...) or Offset(...):Offset(...) to define a new range.
I have also tested the above in Excel (where as mentioned the Index version would be preferable). In this case Base would be set to $1:$1048576.
Although in Excel you have the Intersect Operator (single space) so it's not necessary to use an Index or Offset formula at all e.g. the first example above would simply be:
=COUNTBLANK(Vertical Horizontal)
and if there is no overlap the formula returns a #NULL! error.
"I've created named ranges for each month of the year, and for each
room. For example, rows 6:36 will represent the month of January,
while columns C:I will represent Room 1. Room 2 will span J:P and so
forth."
What I suggest is that if "January" is defined for columns C to whatever (the last column of the last room), then that's all you need.
You haven't shown us the layout of the dashboard. But let's assume that at the very least you're interested in the income generated by each room.
=query({January},"select sum(Col3) label sum(Col3)'' ")
In this image, the range called "January" is highlighted. Note that it does NOT include the header. Note also that it can be many columns wide; in this example, I've just made up a few columns, but your range should cover all the columns for rooms 1 to n.
Syntax: QUERY(data, query, [headers])
Data: This formula queries the range called "January". That range can be on the same sheet, on on another sheet (such as your Dashboard). Reminder: in this screenshot, "my version of "January" is highlighted.
Query to count Number of People: "select sum(Col3) label sum(Col3)'' "
Query to sum the income earned: "select count(Col2) label count(Col2)'' "
Col2 & Col4 = Number of People for Room#1 and Room#2 respectively.
Col3 & Col5 = Income for Room#1 and Room#2 respectively.
[headers]: You can ignore them.
This formula delivers just the value of the query; even though it includes a "label", the label will not print.
Modify and adapt these formulae to create the other information required for your Dashboard.
How to create a Google Spreadsheet sum() which always ends on the cell above, even when new cells are added? I have several such calculations to make on each single column so solutions like this won't help.
Example:
On column B, I have several dynamic ranges which has to be summed. B1..B9 should be summed on B10, and B11..B19 should be summed on B20. I have tens such calculations to make. Every now and then, I add rows below the last summed row , and I want them to be added to the sum. I add a new row (call it 9.1) before row 10, and a new raw (let's call it 19.1) before row 20. I want B10 to contain the sum of B1 through B9.1 and B20 to contain the sum of B11:B19.1.
On excel, I have the offset function which does it like charm. But how to do it with google spreadsheet? I tried to use formulas like this:
=SUM(B1:INDIRECT(address(row()-1,column(),false))) # Formula on B10
=SUM(B11:INDIRECT(address(row()-1,column(),false))) # Formula on B20
But on Google Spreadsheet, all it gives is a #name error.
I wasted hours trying to find a solution, maybe someone can calp?
Please advise
Amnon
You are probably looking for formula like:
=SUM(INDIRECT("B1:"&ADDRESS(ROW()-1,COLUMN(),4)))
Google Spreadsheet INDIRECT returns reference to a cell or area, while - from what I recall - Excel INDIRECT returns always reference to a cell.
Given Google's INDIRECT indeed has some hard time when you try to use it inside SUM as cell reference, what you want is to feed SUM with whole range to be summed up in e.g. a1 notation: "B1:BX".
You get the address you want in the same way as in EXCEL (note "4" here for row/column relative, by default Google INDIRECT returns absolute):
ADDRESS(ROW()-1,COLUMN(),4)
and than use it to prepare range string for SUM function by concatenating with starting cell.
"B1:"&
and wrap it up with INDIRECT, which will return area to be sum up.
REFERRING TO BELOW ANSWER from Druvision (I cant comment yet, I didn't want to multiply answers)
Instead of time consuming formulas corrections each time row is inserted/deleted to make all look like:
=SUM(INDIRECT(ADDRESS(ROW()-9,COLUMN(),4)&":"&ADDRESS(ROW()-1,COLUMN(),4)))
You can spare one column in separate sheet for holding variables (let's name it "def"), let's say Z, to define starting points e.g.
in Z1 write "B1"
in Z2 write "B11"
etc.
and than use it as variable in your sum by using INDEX:
SUM(INDIRECT(INDEX(def!Z:Z,1,1)&":"&ADDRESS(ROW()-1,COLUMN(),4))) - sums from B1 to calculated row, since in Z1 we have "B1" ( the 1,1 in INDEX(...,1,1) )
SUM(INDIRECT(INDEX(def!Z:Z,2,1)&":"&ADDRESS(ROW()-1,COLUMN(),4))) - sums from B11 to calculated row, since in Z2 we have "B11" ( the 2,1 in INDEX(...,2,1) )
please note:
Separate sheet named 'def' - you don't want row insert/delete influence that data, thus keep it on side. Useful for adding some validation lists, other stuff you need in your formulas.
"Z:Z" notation - whole column. You said you had a lot of such formulas ;)
Thus you preserve flexibility of defining starting cell for each of your formulas, which is not influenced by calculation sheet changes.
By the way, wouldn't it be easier to write custom function/script summing up all rows above cell? If you feel like javascripting, from what I recall, google spreadsheet has now nice script editor. You can make a function called e.g. sumRowsAboveMe() and than just use it in your sheet like =sumRowsAboveMe() in sheet cell.
Note: you might have to replace commas by semicolons
NOTE
After testing this answer, it will only work if the sum is in a different column due to a circular dependency error. Otherwise, the solution is valid.
It's a bit of algebra, but we can take advantage of Spreadsheets' lower right corner drag.
=SUM(X:X) - SUM(X2:X)
Where X is the column you are working with and X2 is your ending point. Drag the formula down and Sheets will increment the X2, thus changing the ending point.
*You mentioned that you had tens of such calculations to make. So in order to fit your exact need, we would subtract your last summation to get that "middle" range that we wanted.
e.g.
B1..B9 should be summed on B10, and B11..B19 should be summed on B20
Because of the circular dependency error mentioned earlier, I can't solve it exactly and put the sum on the same line, but this could work in other cases where the sum needs to be stored in a different column.
=SUM(B:B) - SUM(B9:B) //Formula on C10 (Sum of B1..B9)
=SUM(B:B) - SUM(B19:B) - B10 // Formula on C20 (Sum of B11..B19)
This is based on #PsychoFish, here is the solution:
=SUM(INDIRECT(SUBSTITUTE(ADDRESS(1,COLUMN(),4),"1","")&"3:"&ADDRESS(ROW()-1,COLUMN(),4)))
Simply replace the "3:" for the row to start sum.
#PsychoFish is correct but cannot be dragged and copied since the column is literal and hard coded, and #Druvision was in the right direction but was wrong... basically ended up with the same issue of having to re-enter the ranges and then sliding the formulas over and over.
You guys are making this harder than you have to. I just leave a couple of empty rows above by "sum" row (you can format them to be filled with color or something to keep them from being inadvertently used), then just add your new rows just above those special rows.
Agree with what user7255446 said that everyone is overcomplicating. Keep one row blank before your sum row. And then whenever you want to insert a new row, click on your blank row and use "Insert row ABOVE" instead of "insert row below". Your sum formula will automatically adjust.
Example: I want to sum from B1 to B19. I leave row 20 blank. In cell B21, put =SUM(B1:B20). Then if you ever need to insert a new row, click on row 20 and choose "Insert row above". The sum formula automatically changes to =SUM(B1:B21) for you. And of course your sum cell is now B22.
General syntax:
=SUM(INDIRECT(cell_reference_as_string1 &":"& cell_reference_as_string2)
with for example:
cell_reference_as_string1 = ADDRESS(ROW(),COLUMN(),4)
cell_reference_as_string2 = ADDRESS(ROW()-1,COLUMN(),4)
I like how #abernier describes the general solution. So far only alphabet-based A1 notation (A being first column, 1 being first row) are being used. It keeps confusing me, especially when thinking of number of columns left of another column. I like the number-based R1C1 notation much better. To use R1C1 notation for INDIRECT, you need to pass FALSE like so:
=SUM(INDIRECT("R1C"&COLUMN()&":R"&(ROW()-1)&"C"&COLUMN(), FALSE))
I hope you find that helpful, too.
OFFSET() can be used/abused for this purpose. Give it the absolute address of the top left of the range, 0 and 0 for the row/column offsets, and the height/width of the range. Let OFFSET() be the argument to SUM(), SUMIF(), etc.
ROW() and COLUMN() are handy when computing the desired height/width. Be sure to remember to subtract one to exclude the current row/column, or else you're liable to end up with a circular reference. If you have header rows/columns, subtract for them too.
For example, to sum everything from A2 down, excluding the current row, try:
=SUM(OFFSET($A$2,0,0,ROW()-2,1))
To sum everything to the left of the current cell, wherever it may be, try:
=SUM(OFFSET(INDIRECT("RC1",FALSE),0,0,1,COLUMN()-1))
Now let's flip things upside down, to show that this works in the other direction. Suppose you want to sum the B column, starting below the current row, until (and including) row #10. Try this:
=SUM(OFFSET($B$10,ROW()-9,0,10-ROW(),1))
You can avoid negative offsets, while still summing column B:
=SUM(OFFSET(INDIRECT("RC2",FALSE),1,0,10-ROW(),1))
Remove the "2" to instead sum the current column:
=SUM(OFFSET(INDIRECT("RC",FALSE),1,0,10-ROW(),1))
(Credit to Tom Sharpe, who commented above.) INDEX() can be used in a range expression. You might prefer this over OFFSET(), so I'm putting it here. The following sums everything from G1 down to the row above the current:
=SUM(G1:INDEX(G:G,ROW()-1))
Here's how I do it.
This formula does not require you to edit or enter anything about the particular column you would like to sum
=SUM(INDIRECT(CONCATENATE(address(1,column(),4),":",LEFT(address(1,column(),4),1))&ROW()-1))
The answer by #PsychoFish led me in the correct way.
The only issue that I had to rewrite the formula again from each column and each sum. So here is the improved formula, which sums the previous 9 cells on the same column, without hardcoding the column or row numbers:
=SUM(INDIRECT(ADDRESS(ROW()-9,COLUMN(),4)&":"&ADDRESS(ROW()-1,COLUMN(),4)))
The only issue is that I had to rewrite the formulas if someone adds or deletes a row. In this case I should change 9 to 10 or 8 corrspondingly.