I have a table for which I have the following data, as example:
=QUERY(Database!A:L;"SELECT A, C, L WHERE L=TRUE";1)
The thing is I want to return the data ONLY if the column B value (Tag column) is similar to the next one.
So, in the example above it should return only the following lines:
Can anybody help me?
you can try:
=QUERY({A:L,{"ZZ";MAKEARRAY(ROWS(C2:C),1,LAMBDA(r,c,IF(INDEX(C2:C,r)=OFFSET(INDEX(C2:C,r),-1,0),1,0)))}},"SELECT Col1,Col3,Col12 WHERE Col3!='' AND Col13=1",0)
-
You may try the following formula-
=LAMBDA(rng,FILTER(rng,INDEX(BYROW(rng,LAMBDA(x,COUNTIFS(A2:A&B2:B&C2:C,JOIN("",x)))))>1))(A2:INDEX(C2:C,COUNTA(A2:A)))
Related
I have this formula that checks for the 2nd(onwards) instance of duplicate using 2 columns. I want it to be automatically applied to new rows but can't seem to figure out how to use ARRAYFORMULA for COUNTIFS. Can anybody please help me convert this formula =COUNTIFS($K$2:$K2, $K2, $T$2:$T2, $T2)>1 to an arrayformula or something similar? Thanks!
MAP() function may be a good solution. Try-
=MAP($K$2:INDEX($K$2:$K,COUNTA($K$2:$K)),$T$2:INDEX($T$2:$T,COUNTA($K$2:$K)),LAMBDA(x,y,COUNTIFS($K$2:$K,x,$T$2:$T,y)>1))
K2:INDEX(K2:K,COUNTA(K2:K)) will return a array of range from K2 to next non empty cell of K column.
Same T2:INDEX(T2:T,COUNTA(K2:K)) will return a array of range from T column still base on K column last non empty cell.
Edit: As per comment, try below formula-
=INDEX(MAP(A2:INDEX(A2:A,COUNTA(A2:A)),C2:INDEX(C2:C,COUNTA(A2:A)),LAMBDA(x,y,COUNTIFS(A2:A,x,C2:C,y,ROW(A2:A),"<="&ROW(x))>1)))
Change ranges for your sheet.
Hi everyone,
I want to get all the rows where A=1, A=2. The query is very simple but I'm not sure why there is no output. I guess is the problem of the format for column A but I'm not sure what should I change in my formula so that the formula can work. Appreciate any help or advice!
A can't be both: 2 and 1. Instead try
=query(A3:C, "Where A = 2 or A = 1", 0)
It should have been OR not AND - it's impossible for any row in a particular column to have two values simultaneously:
=query(A3:C,"select * where A=1 or A=2",0)
QUERY() is good choice. You can also use FILTER() function like-
=FILTER(A3:C,A3:A>=1,A3:A<=2)
I need something that auto-fills for however many rows are in the spreadsheet, but I'm not sure if an array is the best way.
In my example below, I want Column C to show a 1 if the corresponding entry in Column A is unique, and a 0 if it isn't.
I had hoped it would be as easy as using ARRAYFORMULA(IF(UNIQUE(A1:A),1,0)), but forgot that IF wouldn't work with the text.
Here's my example with the most recent formula I tried.
Thank you!
Please use the following formula:
=ArrayFormula(IF(LEN(A1:A)<>0,
IF(COUNTIF(A1:A,A1:A)>1,0,1)
,""))
Functions used:
COUNTIF
ArrayFormula
LEN
You can combine ARRAYFORMULA and IF with IFERROR and COUNTIF
Sample:
=ARRAYFORMULA(IF(IFERROR(COUNTIF(A1:A,A1:A)=1,0)=TRUE,1,0))
I have a google sheet with a column (A) of urls.
Xttps://tXco/008wnbebbw
Xttps://tXco/00lR1FNKBo
Xttps://tXco/00lR1Fw9cO
Xttps://tXco/00UwZwgh2h
Xttps://tXco/00UwZwxSqR
Xttps://tXco/00UwZwxSqR
Xttps://tXco/044TcIFl72
In column B I need to find all unique urls up to the 18th character. For instance column B should show:
Xttps://tXco/008wnbebbw
Xttps://tXco/00lR1FNKBo
Xttps://tXco/00UwZwgh2h
Xttps://tXco/044TcIFl72
I have this formula which I was trying to adapt for it (not sure if it helps at all). I was trying to adapt this to use with =UNIQUE( ?
=SUMPRODUCT(--(LEFT($A$1:$A$15,18)=LEFT(A1,18)))>1
If it helps to take a look at the sheet, here it is: https://docs.google.com/spreadsheets/d/1tG7TpHNvNY86PRiePsKyKfxnuEZah6T7ZDL7dXOIcEA/edit?usp=sharing
Thanks in advance!
You may try this formula:
=ArrayFormula(vlookup(
UNIQUE(FILTER(LEFT(A2:A,17),A2:A<>"")),
FILTER({LEFT(A2:A,17),A2:A},A2:A<>""),
2,0))
How it works
it will first find unique left N chars:
UNIQUE(FILTER(LEFT(A2:A,17),A2:A<>"")
then get left N chars and original strings:
FILTER({LEFT(A2:A,17),A2:A},A2:A<>"")
and then use vlookup to get top first entry for uniques.
Try this instead without the extra column. Put it in B1:
=unique(arrayformula(if(left(A1:A,18)=left(A1:A,18),A1:A,"")))
Try this: =unique(arrayformula(left(A1:A,18)))
I want my google sheets query to just filter out the rows with a blank value and possibly the ones containing specific words as well
Here's an example spreadsheet, I've tried using "where B is not null" in the query but it's not working! I'm tearing my hair out over this as i'm sure it's a simple solution.
https://docs.google.com/spreadsheets/d/1xZH1MKeqLa8r1gRGL9wYHEWe02wQoNNpqqL_ca1fGf0/edit?usp=sharing
Thanks in advance for your help!
you may need to test for empty string instead of null, you can add AND to remove other values:
=QUERY(A2:B6,"select A, B where B<>'Pizza' and B<>''")
This just worked for me
=QUERY(A2:B6,"select A, B where B!='' ",0)