The code below plays a link from you tube automatically and it's working fine. I just want to toggle (show/hide) the ListView so that I can select another link. The problem is that the listview quickly shows and then it hides.
private void playYoutube(String lnk) {
webView.getSettings().setJavaScriptEnabled(true);
webView.getSettings().setDomStorageEnabled(true);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.JELLY_BEAN_MR1) {
webView.getSettings().setMediaPlaybackRequiresUserGesture(false);
}
webView.loadUrl(lnk);
webView.setWebViewClient(new WebViewClient() {
public void onPageFinished(WebView view, String url) {
webView.loadUrl("javascript:(function() { document.getElementsByClassName('ytp-large-play-button ytp-button')[0].click(); })()");
}`your text`
});
webView.setOnTouchListener(new View.OnTouchListener() {
#Override
public boolean onTouch(View v, MotionEvent event) {
if (listview.isShown())
listView.setVisibility(View.GONE);
else
listView.setVisibility(View.VISIBLE);
return true;
}
});
}
I have tried the above code but it shows the list view and then it hides.
Related
I have a splitlayout in my vaadin application in which in the first column I should show different pages added through the addToPrimary method, while in the second column I should have a page which contains an IFrame with a videoconference. Now the problem is that when I change route in the first column, even the second is updated and this refreshes the IFrame. The implementation of the showRouterLayoyutContent is the following:
#Override
public void showRouterLayoutContent(HasElement content) {
if (this.accessControl.isAccessGranted(UI.getCurrent(), ((ContentView) content).getName()) && ((ContentView) content).getName().equals("contattaView") ) {
setLayoutCall((com.vaadin.flow.component.Component) content);
}
else if (this.accessControl.isAccessGranted(UI.getCurrent(), ((ContentView) content).getName())) {
setLayoutContent((com.vaadin.flow.component.Component) content);
}
}
And the two methods setLayoutCall and setLayoutContent are the following:
private void setLayoutContent(com.vaadin.flow.component.Component content) {
split.addToPrimary(content);
}
private void setLayoutCall(com.vaadin.flow.component.Component content) {
split.addToSecondary(content);
split.setThemeName("visible-split");
}
How can I avoid to refresh the entire content when I update the first column of the split layout through navigation?
UPDATE: I'm showing also a very simple code on which I'm testing. The following class is the main layout:
private SplitLayout split = new SplitLayout();
private HorizontalLayout hl = new HorizontalLayout();
private Div firstDiv = new Div();
private Div secondDiv = new Div();
public MainView() {
Button button = new Button("Click me",
event -> Notification.show("Clicked!"));
final VerticalLayout menuBar = new VerticalLayout();
menuBar.add(new RouterLink("first view", FirstView.class));
menuBar.add(new RouterLink("second view", SecondView.class));
menuBar.setAlignItems(Alignment.CENTER);
add(menuBar);
//split.addToPrimary(firstDiv);
//split.addToSecondary(secondDiv);
//firstDiv.setId("first");
//secondDiv.setId("second");
//hl.add(firstDiv,secondDiv);
add(split);
//add(hl);
}
#Override
public void showRouterLayoutContent(HasElement element) {
if(element!=null && element.getClass().getName().contains("FirstView")) {
split.addToPrimary((Component) element);
//firstDiv.removeAll();
//firstDiv.add((Component) element);
//firstDiv.removeAll();
//firstDiv.getElement().appendChild(new Element[]{element.getElement()});
}
else if(element!=null && element.getClass().getName().contains("SecondView") ) {
secondDiv.removeAll();
secondDiv.add((Component) element);
split.addToSecondary((Component) element);
//split.addToSecondary(element.getElement().getComponent().get());
}
}
While these are the two views added to the split:
#Route(value="v1",layout=MainView.class)
public class FirstView extends VerticalLayout implements RouterLayout {
public FirstView() {
add(new Label("First View"));
}
}
#Route(value = "v2",layout=MainView.class)
public class SecondView extends VerticalLayout implements RouterLayout {
public SecondView() {
IFrame frame = new IFrame();
frame.setSrc("https://www.youtube.com/watch?v=LoigVtPCYPk&list=RDLoigVtPCYPk&start_radio=1");
add(frame);
}
}
Your comment does indeed seem to be the issue.
I recommend creating a Div wrapper for the primary content, and instead changing the content of that.
private final Div wrapper;
public MyLayout() {
wrapper = new Div();
wrapper.setSizeFull();
split.addToPrimary(wrapper);
}
private void setLayoutContent(com.vaadin.flow.component.Component content) {
wrapper.removeAll();
wrapper.add(content);
}
You might also want to do the same for the secondary. In addition, to prevent any components from being automatically removed when navigating, you can override removeRouterLayoutContent as well (available in Vaadin 14)
#Override
public void removeRouterLayoutContent(HasElement oldContent) {
// Do nothing, we remove manually in showRouterLayoutContent
}
Edit
If you can't override removeRouterLayoutContent, you can try creating your own instance of the HasElement to add. This is a bit of a hack, but might be the simplest solution.
public void showRouterLayoutContent(HasElement content) {
if (content.getClass().getSimpleName().contains("TestView")) {
// Creating a new instance should stop it from being auto removed
content = new TestView();
firstDiv.add((Component) content);
}
...
}
I am creating a Twitter client using Fabric but I can not create a custom onClick.
I created this custom adapter and tried to create a OnClickListener but not working. Always open in browser tweet.
public class TweetAdapter extends TweetTimelineListAdapter {
public ArrayList<Long> tweetIds=new ArrayList<Long>();
public TweetAdapter(Context context, Timeline<Tweet> timeline) {
super(context, timeline);
}
#Override
public View getView(int position, View convertView, ViewGroup parent) {
Object rowView = convertView;
final Tweet tweet = (Tweet)this.getItem(position);
if(convertView == null) {
rowView = new CompactTweetView(this.context, tweet);
} else {
((BaseTweetView)convertView).setTweet(tweet);
((View)rowView).setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View view) {
tweetIds.add(tweet.getId());
}
});
}
return (View)rowView;
}
}
In BaseTweetView class it is the function type OnClickListener but in this case I can't think of any idea to overwrite.
private void setPermalinkLauncher() {
BaseTweetView.PermalinkClickListener listener = new BaseTweetView.PermalinkClickListener();
this.setOnClickListener(listener);
this.contentView.setOnClickListener(listener);
}
class PermalinkClickListener implements OnClickListener {
PermalinkClickListener() {
}
public void onClick(View v) {
if(BaseTweetView.this.getPermalinkUri() != null) {
BaseTweetView.this.scribePermalinkClick();
BaseTweetView.this.launchPermalink();
}
}
}
Any ideas? Thanks
Finally I made this works using a custom Adapter (very similar that the one you use in the question). This adapter obtains the resulting view from super implementation and adds an onClickListener to overrides the fabric defaults one:
class CustomTweetTimelineListAdapter extends TweetTimelineListAdapter {
public CustomTweetTimelineListAdapter(Context context, Timeline<Tweet> timeline) {
super(context, timeline);
}
#Override
public View getView(final int position, View convertView, ViewGroup parent) {
View view = super.getView(position, convertView, parent);
//disable subviews to avoid links are clickable
if(view instanceof ViewGroup){
disableViewAndSubViews((ViewGroup) view);
}
//enable root view and attach custom listener
view.setEnabled(true);
view.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
String tweetId = "click tweetId:"+getItemId(position);
Toast.makeText(context, tweetId, Toast.LENGTH_SHORT).show();
}
});
return view;
}
//helper method to disable subviews
private void disableViewAndSubViews(ViewGroup layout) {
layout.setEnabled(false);
for (int i = 0; i < layout.getChildCount(); i++) {
View child = layout.getChildAt(i);
if (child instanceof ViewGroup) {
disableViewAndSubViews((ViewGroup) child);
} else {
child.setEnabled(false);
child.setClickable(false);
child.setLongClickable(false);
}
}
}
}
Full code example here.
Hope it helps.
Here is My Code.
I just want to get the page content from the Webview after load the URL .
On Android, I have a WebView that is displaying a page.
How do I get the page source without requesting the page again?
It seems WebView should have some kind of WebResourceResponse () method in Android 3.0 but don't know how to use it.
public class WebActivity extends Activity {
WebView mWebView;
/** Called when the activity is first created. */
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
mWebView = (WebView) findViewById(R.id.webView);
mWebView.getSettings().setJavaScriptEnabled(true);
mWebView.loadUrl("https://xyz.com");
mWebView.setWebViewClient(new HelloWebViewClient());
}
private class HelloWebViewClient extends WebViewClient {
public WebResourceResponse shouldInterceptRequest (WebView view, String url)
{
return null;
}
#Override
public void onPageFinished(WebView view, String url)
{
/* This call inject JavaScript into the page which just finished loading. */
mWebView.loadUrl("javascript:window.HTMLOUT.processHTML('<head>'+document.getElementsByTagName('html')[0].innerHTML+'</head>');");
}
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
#Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if ((keyCode == KeyEvent.KEYCODE_BACK) && mWebView.canGoBack()) {
mWebView.goBack();
return true;
}
return super.onKeyDown(keyCode, event);
}}
I know this is old, but for future visitors, the following should work.
First, you need to define an interface such as:
final class LoadingInterface {
#JavascriptInterface
public void outputHTML(final String html){
//do what ever you want with html
}
}
Then on your WebView call
webView.addJavascriptInterface(new LoadingInterface(), "INTERFACE");
In onPageFinished put:
String js = "javascript:"
+"var html = document.getElementsByTagName('html')[0].innerHTML;"
+"window.INTERFACE.outputSchedule(html);";
webView.loadUrl(js);
If you only need part of a page, you can replace getElementsByTagName('html')[0] with something like getElementById('partOfPage')
I want to come to home screen when clicking on the back button from my application in blackberry. I have searched for this in google and stackoverflow, But I didn't get any solution. Anybody help for this.
In My Starting Screen i wrote like this for back button.
protected boolean keyDown(int keycode, int time)
{
if (Keypad.key(keycode) == Keypad.KEY_ESCAPE)
{
close();
return true;
}
else
{
return super.keyDown(keycode, time);
}
}
In my HomeScreen i wrote like this.
protected boolean keyDown(int keycode, int time)
{
if (Keypad.key(keycode) == Keypad.KEY_ESCAPE)
{
UiApplication.getUiApplication().pushScreen(new StartingScreen());
return true;
}
else
{
return super.keyDown(keycode, time);
}
}
From my application HomeScreen I am able to come to starting screen of the my application. after that when i click on back button from starting screen i need to go to blackberry home screen that means i need to exit the app and come out of that. I wrote close(); to come to blackberry home screen. but its not working. it is again coming to my application homescreen.
Override keyDown method in your subclass of MainScreen.
protected boolean keyDown(int keycode, int time) {
int key = Keypad.key(keycode);
if(key==Characters.ESCAPE){
// do something here
return true;
}
return super.keyDown(keycode, time);
}
To come to home screen
while(!(UiApplication.getUiApplication().getActiveScreen() instanceof HomeScreen)){
UiApplication.getUiApplication().popScreen(UiApplication.getUiApplication().getActiveScreen());
}
I got the Solution... i have written lik this.
public boolean onClose()
{
int choose=Dialog.ask(Dialog.D_YES_NO, "Are you sure Want to Exit?");
if(choose==Dialog.YES)
{
System.exit(0);
}
return true;
}
Try this -
public class yourclass extends MainScreen{
public yourclass(){
}
}
public boolean onClose() {
Application.getApplication().invokeLater(new Runnable() {
public void run() {
//close this screen and push your home screen
}
});
return true;
}
I create a custom menu in new class extends popupScreen. I went when the user clock on the menu button the menu display. I use this code
protected boolean keyDown(int keycode, int time) {
if(Keypad.KEY_MENU == Keypad.key(keycode))
{
UiApplication.getUiApplication().popScreen(getScreen());
Menu popup = new Menu();
UiApplication.getUiApplication().pushScreen(popup);
return true;
}
else
return super.keyDown(keycode, time);
}
but I obtain error on this line UiApplication.getUiApplication().pushScreen(popup); causes by pushScreen. How can I change this code or there is another method to display this menu.
try this
protected boolean keyDown(int keycode, int time) {
if(Keypad.KEY_MENU == Keypad.key(keycode))
{
synchronized (UiApplication.getEventLock())
{
UiApplication.getUiApplication().popScreen(getScreen());
Menu popup = new Menu();
UiApplication.getUiApplication().pushScreen(popup);
}
return true;
}
else
return super.keyDown(keycode, time);
}
In Blackberry, creating, displaying and hiding of Menu is handled by the system; you will be provided with callbacks at appropriate time. The callbacks you will need to code are:
public boolean onMenu( int instance )
{
return true; // Menu is created
}
public void makeMenu( Menu menu, int instance )
{
MenuItem _desired_menu_item = new MenuItem()
{
public void run()
{
}
}
menu.add( _desired_menu_item );
super.makeMenu( menu, instance)
}
That's it! It would work. Please check Blackberry "UI and Navigation guide" for more details