How do you conditionally color a column where the column contains Alphanumeric text, such that all like strings are colored the same? Aware how to do this if you know the value of possible strings, but in this case combinations are not known ahead.
Thought about converting string=>hex=>binary=>decimal, then do a color scale format rule. Then realized these functions are readily available without custom functions.
Color scale formatting can only format numbers. Assuming that the text strings are in column A2:A, you can convert duplicates among them into fairly unique numbers with this formula in row 2 of a free column:
=arrayformula(
lambda(
data, modulo,
map(
to_text(data),
lambda(
text,
if(
countif(data, text) < 2,
iferror(1/0),
iferror(
mod(
sum(
mod(
1.1 ^ sequence(len(text))
*
code( mid(text, sequence(len(text)), 1) ),
modulo
)
),
modulo
)
)
)
)
)
)( A2:A, 8 )
)
Then format the new column as a color scale and use the values there as a guide to locate duplicate text strings in column A2:A.
You can try using the following formula:
=IF(REGEXMATCH(A1, "[^A-Za-z0-9]+"), FALSE, TRUE)
This is an example of how it works:
Once you have the formula you can use conditional formatting in Google Sheets to change the cell color to the one you prefer.
References:
Regular expressions
REGEXMATCH
Conditional formatting
Related
I'm using the filter formula to get data from another tab (products).
I type some keywords in C2 and I want the filter formula to return me the data when it matches with the 'product description'.
Now I'm using this condition: SEARCH(C2; products!D2:D) [my sheets is in Portuguese format ';']
It is working but not as desired. I want a filter formula to get the rows that contain all of the words entered in C2, regardless of the order in which they appear in the text.
Here is a sheet sample. I can't share the one I'm using:
https://docs.google.com/spreadsheets/d/1F8Gg1rG9smjW25bmjwXP7wADFvnuyrse9aPM1iQfxsA/edit?usp=sharing
I tried to use SEARCH() and SPLIT() and I also tried SEARCH() and MATCH(). I just can't figure it out.
Thanks!
Can you try this out:
=LAMBDA(x;FILTER(x;BYROW(LAMBDA(z;MAKEARRAY(ROWS(x);COUNTA(z);LAMBDA(r;c;IF(REGEXMATCH(INDEX(x;r);"(?i)"&INDEX(z;;c)&"");1;))))(SPLIT(C2;" "));LAMBDA(y;SUM(y)))=COUNTA(SPLIT(C2;" "))))(Products!D2:D)
To find rows where the product name contains all of the keywords, try this formula, based on rockinfreakshow's answer:
=lambda(
productNames, data, keyWords,
filter(
data,
counta(keyWords)
=
byrow(
makearray(
rows(productNames), counta(keyWords),
lambda(
rowIndex, columnIndex,
iferror(
sign(
search(
index(keyWords, 0, columnIndex),
index(productNames, rowIndex)
)
)
)
)
),
lambda(numMatches, sum(numMatches))
)
)
)(
A3:A, A3:B, split(E2, ", ", true, true)
)
To find rows where the product name contains any of the keywords, try filter() with regexmatch(), like this:
=filter(
A3:B,
regexmatch(
to_text(A3:A),
"(?i)" & regexreplace(to_text(E2), "[, ]+", "|")
)
)
To learn the exact regular expression syntax used by Google Sheets, see RE2.
Try this, I'm guessing your values are separated by commas. If not change it in Split
=FILTER(products!D2:D;BYROW(Products!D2:D;LAMBDA(each;INDEX(PRODUCT(IFERROR(SEARCH(TRIM(SPLIT(C2;",";1;1);each);0))))))
I got this "table" (page raids) and want to do function formating for highlight duplicates (yellow).
Google Sheet
In this case there is match in 2 strings (dark blue):
Name1
Gunslinger
I already try functions VLOOKUP, Match, Filter, countifs and Quary (dont know how it works...) with Index function, but nothing seems work as I want ...
VLOOKUP and Match only gives first value.
Filter doesnt work on this strucker or I dont know how to use it in this case (I know how it works in normal table)
Can someone tell me what function conbination to use that can be put in Function formating ?
Formating for each row:
Example: =IF(B3>0;IF(B4<1490;TRUE;FALSE);FALSE)
ECT.
After some searching and testing, I came up with this:
=ArrayFormula(SUM(IFERROR(FIND(B2&B3;MID(CONCATENATE((TRANSPOSE($B$2:$I$33)));SEQUENCE(LEN(CONCATENATE((TRANSPOSE($B$2:$I$33))));1;1;1);len(B2&B3)))=1)*1))>1
Still need to make the functions more tidy (picture 2 and 3).
See if this is what you are looking for?
Conditional formatting with Custom formula in Range: A2:H:
=LAMBDA(NAME,OR(A1=NAME,A2=NAME,A3=NAME))("Gunslinger")
or do you means you want to highlight only duplicates?
If that is the case, you may try this formula:
=LAMBDA(DATARANGE,
LAMBDA(FLAT,
{{"Team","Duplicate"};{UNIQUE(FLAT),BYROW(UNIQUE(FLAT),LAMBDA(NAME,COUNTIF(FLAT,NAME)>1))}}
)(
QUERY(FLATTEN(
BYCOL(DATARANGE,LAMBDA(C,
BYROW(C,LAMBDA(R,
IF((ROW(R)+1)/4=INT((ROW(R)+1)/4),R,"")
))
))
),"SELECT Col1 WHERE Col1 IS NOT NULL",0)
)
)(A2:H)
This formula returns an array of unique Names with checking if there are Duplicates in the given datarange.
Combine this with the 1st formula should be able to highlight repeated data sets from your table.
Solution for 2 criteria matching:
The formula inside the image form the table of unique match results,
use that result with OR(), XLOOKUP(), OFFSET(), INDEX() as below for the final formula to put into the custom formula in conditional formatting.
=LAMBDA(RESULT,
LAMBDA(NAME,DUP,KEY,
LAMBDA(KEY_M2,KEY_M1,KEY_P1,
OR(
XLOOKUP(KEY_M2&"&&"&KEY_M1,NAME,DUP,FALSE),
XLOOKUP(KEY_M1&"&&"&KEY,NAME,DUP,FALSE),
XLOOKUP(KEY&"&&"&KEY_P1,NAME,DUP,FALSE)
)
)(IFERROR(OFFSET(KEY,-2,0),""),IFERROR(OFFSET(KEY,-1,0),""),IFERROR(OFFSET(KEY,1,0),""))
)(INDEX(RESULT,,1),INDEX(RESULT,,2),A2)
)(
LAMBDA(DATARANGE,
LAMBDA(FLATCLASS,
{{"Name","Duplicate"};{UNIQUE(FLATCLASS),BYROW(UNIQUE(FLATCLASS),LAMBDA(NAME,COUNTIF(FLATCLASS,NAME)>1))}}
)(
QUERY(FLATTEN(
BYCOL(DATARANGE,LAMBDA(C,
BYROW(C,LAMBDA(R,
IF((ROW(R)+1)/4=INT((ROW(R)+1)/4),IF(R="","",INDEX(C,ROW(R)-2)&"&&"&R),"")
))
))
),"SELECT Col1 WHERE Col1 IS NOT NULL",0)
)
)($A$2:$H)
)
This question already has an answer here:
Concatenate non empty cells in each row with arrayformula in google sheets
(1 answer)
Closed 6 months ago.
The shared sheet shows multiple column rows which can be individually concatenated horizontally with a comma & space between using TEXTJOIN(", ", TRUE, A2:D2) and blank spaces are ignored. But textjoin cannot be used in Arrayformula as far as I know and I would like ot find a suitable replacement that can also be combined as a string along with other strings of information.
I want to be able to use this as an independent formula string that might be added to other strings of information. For example, "Favorite colors: "& textjoin(", ",1,A2:D2)&"Favorite foods:"&textjoin(", ",1,E2:G2)&"...
Possible solutions
May be a variant of one of the following:
Modifying this so it could be used w/ an array formula JOIN("~", SPLIT(JOIN(CHAR(60000), B3:E3), CHAR(60000)))
Modifying this formula works with join also JOIN(", ",FILTER(H2:H,H2:H<>""))
Using a combination of IF(a2:A<>"" along with a regex replacement at the end (see my answer below) but this could be very long formula compared to textjoin if there are many columns)
An ideal solution would be concise and look closest to something this:
arrayformula(TEXTJOIN(", ", TRUE, A2:A,B2:B,C2:C)
Shared sheet is here
use:
=INDEX(REGEXREPLACE(TRIM(FLATTEN(QUERY(TRANSPOSE(IF(A2:D="",,A2:D&",")),,9^9))), ",$", ))
Using a series of IF statements, adding a delimiter and then removing any trailing delimiters can be accomplished using: Arrayformula(regexreplace(if(A2:A100<>"",A2:A100&", ","")&if(B2:B100<>"",B2:B100&", ","")&if(C2:C100<>"",C2:C100&", ","")&if(D2:D100<>"",D2:D100&", ",""),", $",""))
Use a query smush, like this:
=transpose(query(transpose(A2:D), "", 9^9))
The formula will separate values with spaces. To separate with commas and remove unwanted white space, use trim() and substitute() or regexreplace(), like this:
=arrayformula( substitute( trim( transpose( query( transpose(A2:D), "", 9^9 ) ) ), " ", ", " ) )
I want to regexreplace the number 2 in some rows with "double", but I want to ignore if the numbers are 12, 22, 32 etc.
EDIT:
What if I add letters to the numbers? Like this:
There are a few ways to tackle this, but using ^2$ will only match 2
=ARRAYFORMULA(
IF(ISBLANK(A1:A),,
IF(
REGEXMATCH(
TO_TEXT(A1:A),
"^2$"),
"double",
A1:A)))
Using REGEXMATCH instead of REGEXREPLACE allows us to return the values in A1:A as actual numerical values instead of the text value the formula requires.
Working with a2 etc, this will allow for optional letters before the 2
=ARRAYFORMULA(
IF(ISBLANK(A1:A),,
IF(
REGEXMATCH(
TO_TEXT(A1:A),
"^(?i)[A-Z]+?2$"),
"double",
A1:A)))
I have a table using Google Sheets. It has three columns that will always have a null value or a specific value for that column. Each line will have one, two, or three values; it will never have three null values on one line. In the fourth column, I want an ArrayFormula that will combine those values and separate the values with a comma if there is more than one.
Here is a photo of what I am trying to accomplish.
I've tried several ideas so far and this formula is the closest I've gotten so far but it's still not quite working correctly; I think it is treating each column as an array before joining rather than doing the function line by line. I'm using the LEN function rather than A2="" or ISBLANK(A2) because columns A-C are ArrayFormulas as well. I realize this probably isn't the most efficient formula to use but I think it covers every possibility. I'm definitely open to other ideas as well.
={"Focus";
ArayFormula(
IFS(
$A$2:$A="", "",
(LEN(A2:A)>0 & LEN(B2:B)>0 & LEN(C2:C)>0), TEXTJOIN(", ", TRUE, A2:A, B2:B, C2:C),
(LEN(A2:A)>0 & LEN(B2:B)>0 & LEN(C2:C)=0), TEXTJOIN(", ", TRUE, A2:A, B2:B),
(LEN(A2:A)>0 & LEN(B2:B)=0 & LEN(C2:C)>0), TEXTJOIN(", ", TRUE, A2:A, C2:C),
(LEN(A2:A)=0 & LEN(B2:B)>0 & LEN(C2:C)>0), TEXTJOIN(", ", TRUE, B2:B, C2:C),
(LEN(A2:A)>0 & LEN(B2:B)=0 & LEN(C2:C)=0), A2:A,
(LEN(A2:A)=0 & LEN(B2:B)>0 & LEN(C2:C)=0), B2:B,
(LEN(A2:A)=0 & LEN(B2:B)=0 & LEN(C2:C)>0), C2:C
)
)
}
Is it possible to achieve this with Google Sheets?
Sample File
Please try:
=ARRAYFORMULA(SUBSTITUTE(TRIM(TRANSPOSE(QUERY(TRANSPOSE(FILTER(A2:C,ROW(A2:C)<=MAX(IF(LEN(A2:C),ROW(A2:C)*COLUMN(A2:C)^0,0)))),,2^99)))," ",", "))
Notes:
The formula will work incorrectly if some names have space inside: like "Aston Martin"
So if you have spaces, please try this:
=ARRAYFORMULA(SUBSTITUTE(
SUBSTITUTE(TRIM(TRANSPOSE(QUERY(TRANSPOSE(FILTER(SUBSTITUTE(A2:C," ",char(9)),ROW(A2:C)<=MAX(IF(LEN(A2:C),ROW(A2:C)*COLUMN(A2:C)^0,0)))),,2^99)))," ",", "),
CHAR(9)," "))
EDIT
Noticed the shorter variant (without *COLUMN(A2:C)^0) will work:
=ARRAYFORMULA(SUBSTITUTE(
SUBSTITUTE(TRIM(TRANSPOSE(QUERY(TRANSPOSE(FILTER(SUBSTITUTE(A2:C," ",char(9)),ROW(A2:C)<=MAX(IF(LEN(A2:C),ROW(A2:C),0)))),,2^99)))," ",", "),
CHAR(9)," "))
Notes:
I used an old trick to join strings with an array-formula. See sample file
Explanations
If you like to understand any tiered formula, the best way is to split it by parts:
Part 1. Filter the data
FILTER(any_columns,ROW(A2:C)<=MAX(IF(LEN(A2:C),ROW(A2:C)*COLUMN(A2:C)^0,0))). this is my way to limit the data range.
The range is open, means it starts from the second row (A2) and
ends in any row.
I want to get the limited array in this step to reduce work that the formula should do. This is done with a condition, if.
ROW(A2:C) must be less or equal to the max row of data.
MAX(IF(LEN(A2:C), some_rows) gives the max row.
If(len.. part checks if a cell has some text inside it.
Note some_rows part:
MAX(IF(LEN(A2:C),ROW(A2:C)*COLUMN(A2:C)^0,0)))),,2^99))).
ROW(A2:C) must be multiplied by columns, because filter formula
takes only one row into its condition. That is why I multiply by
COLUMN(A2:C)^0 which is columns with 1s. Edit. Now noticed,
that the formula works fine without *COLUMN(A2:C)^0, so it's an
overkill.
Part 2. Join the text
query formula has 3 arguments: data, query_text, and a number_of_header_rows.
data is made with a filter.
query_text is empty, which gives us equivalent to select all
("select *").
And the number of rows of a header is some big number (2^99).
This is a trick: when a query has more headers then one row,
it will join them with space.
After a union is made, transpose function will convert the result back to the column.
Part 3. Substitute and trim
The function trim deletes extra spaces.
Then we replace spaces with the delimiter: ", ". That is why the
formula needs to be modified if spaces are in strings. Correct
result: "Ford, Aston Martin". Incorrect: "Ford, Aston, Martin". But
if we previously replace spaces with some char (char(9) is Tab),
then we do not replace it in this step.