Exclusive gestures in SwiftUI when gestures not in the same hierarchy - ios

Question

Basically I would like this to work:
struct TestView: View {
var body: some View {
VStack {
Text("Should work simultaneously").onTapGesture {
print("Work simultaneously")
}
Text("Should work simultaneously").onTapGesture {
print("Work simultaneously")
}
Text("Should be exclusive").onTapGesture {
print("Work exclusively")
}
}
.simultaneousGesture(
TapGesture().onEnded {
print("Should work everywhere except for 3th child view")
}
)
}
}
The VStack has a gesture that should always be recognized, except when one their childs wants to handle the touches exclusively.
The pasted code is a minimal example.
In my real project, the 3th child view is a custom DatePicker that appears on some condition. I would like to dismiss the picker when one clicks outside, but if one clicks inside the picker it shouldn't be dismissed yet. For this reason I need handle the touches in the picker exclusively.

Answer 1

You can't block up the view hierarchy, only down. In order to have the simultaneous gesture on only part of the VStack, you will need to separate those views into their own composed view with the .simultaneousGesture() on that view. Presuming you don't want to change the look of your view, I would simply wrap the subviews you want the .simultaneousGesture() on in a Group{}. Something like this:
struct TestView: View {
var body: some View {
VStack {
Group {
Text("Should work simultaneously").onTapGesture {
print("Work simultaneously")
}
Text("Should work simultaneously").onTapGesture {
print("Work simultaneously")
}
}
.simultaneousGesture(
TapGesture().onEnded {
print("Should work everywhere except for 3th child view")
}
)
Text("Should be exclusive")
.onTapGesture {
print("Work exclusively")
}
}
}
}