turn other toggles off in Swiftui - ios

Question

I'm new to swift and swiftUI, so probably done something obvious wrong, but I display a list of toggles. When one of these is turned on, I want the others to be turned off, so only one of the items can be selected at once. I've got an array of toggles, and that works fine, but I can't get the 'turn off all the other toggles to work' without it giving compile errors. I'm getting errors on the follow lines.
errors
Here's all the code.
import SwiftUI
struct SheetView: View {
#FetchRequest(sortDescriptors:[SortDescriptor(\Book.timestamp)]) private var items: FetchedResults<Book>
#State var doesClose:[Bool] = []
init(numberOfBooks: Int) {
var values: [Bool] = []
for i in 0..<numberOfBooks {
values.append(false)
}
_doesClose = State(initialValue: values)
print(numberOfBooks)
print(self.doesClose)
}
var body: some View {
NavigationStack{
List {
ForEach(Array(items.enumerated()), id: \.element) { idx, item in
HStack (spacing: 20){
VStack (alignment: .leading, spacing: 5) {
Text(item.bookName!)
Toggle("", isOn: $doesClose[idx])
.onChange(of: doesClose[idx], perform: {for i in 0..<doesClose.count {
if(i != idx)
{
doesClose[i] = false
}
}})
}
}
}
}
.navigationTitle("List")
}
}
private func turnAllOtherButtonsOff(onIndex:Int)
{
for i in 0..<doesClose.count {
if(i != onIndex)
{
doesClose[i] = false
}
}
}
}
I also tried running the func at the perform stage with similar errors. Thanks for any help.

Answer 1

Posting this if this helps anyone. I dropped the idea of going through the array, and just concentrated on keeping track of the previous index, and then switching that when there's an onChange. Here's the code.
Toggle("", isOn: $doesClose[idx])
.onChange(of: doesClose[idx], perform: {value in
print(value)
if(value == true)
{
if(oldToggle != -1){
doesClose[oldToggle] = false
}
oldToggle = idx
}
print(oldToggle)
})