Test for xsi:nil="true" - xslt-2.0

I wish to test for xsi:nil="true".
I'm using the replies from kjhughes & Michael Kay in these posts, respectively.
How to implement if-else statement in XSLT?
How do I check if XML value is nil in XSLT
XML:
<OSM>
<EstablishmentDetail>
<RatingValue>5</RatingValue>
<RatingDate>2008-05-15</RatingDate>
</EstablishmentDetail>
<EstablishmentDetail>
<RatingValue>AwaitingInspection</RatingValue>
<RatingDate xsi:nil="true"/>
</EstablishmentDetail>
</OSM>
A snip of the XSL:
<xsl:template>
"Value": "<xsl:value-of select="if (nilled(RatingDate)) then RatingValue else 'XX' "/>",
</xsl:template>
It's producing output but both are 'XX'. Is it just a syntax error?

The function https://www.w3.org/TR/xpath-functions/#func-nilled is meant to work with schema-aware XSLT and validated input i.e. if you use Saxon EE you can expect it to do its job:
In practice, the function returns true only for an element node that
has the attribute xsi:nil="true" and that is successfully validated
against a schema that defines the element to be nillable;

Need to add the namespace in the input document:
<OSM xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<EstablishmentDetail>
<RatingValue>5</RatingValue>
<RatingDate>2008-05-15</RatingDate>
</EstablishmentDetail>
<EstablishmentDetail>
<RatingValue>AwaitingInspection</RatingValue>
<RatingDate xsi:nil="true"/>
</EstablishmentDetail>
</OSM>
I'm not getting the right value out of the standard fn:nilled() function hence substituted a user function:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet
version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:l="local:functions">
<xsl:output method="xml" indent="yes" />
<xsl:template match="/">
<RatingValues>
<xsl:for-each select="//EstablishmentDetail">
<EstablishmentDetail index="{position()}" >
<RatingValue>
<xsl:value-of select="('XX'[l:nilled(current()/RatingDate) ],
current()/RatingValue)[1]" />
</RatingValue>
<Nilled>
<xsl:value-of select="nilled(RatingDate)" />
</Nilled>
</EstablishmentDetail>
</xsl:for-each>
</RatingValues>
</xsl:template>
<xsl:function name="l:nilled" as="xs:boolean" >
<xsl:param name="e" as="element()" />
<xsl:sequence select="exists($e/#xsi:nil) and $e/#xsi:nil eq 'true'" />
</xsl:function>
</xsl:stylesheet>
which produces:
<?xml version="1.0" encoding="UTF-8"?>
<RatingValues xmlns:l="local:functions" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<EstablishmentDetail index="1">
<RatingValue>5</RatingValue>
<Nilled>false</Nilled>
</EstablishmentDetail>
<EstablishmentDetail index="2">
<RatingValue>XX</RatingValue>
<Nilled>false</Nilled>
</EstablishmentDetail>
</RatingValues>
The Nilled elements in the output just to show that I'm getting false for both cases.

Related

Sum two elements by grouping using XSLT 2.0

I'm trying to sum two elements "amount" and "retroAmount" group by "tmid" using xslt 2.0 and I tried two methods, in method-1 everything is stacking up and in the method-2 it displays NaN. Any ideas about how this can be fixed?
Here is my XML file:
<?xml version="1.0" encoding="UTF-8"?>
<Request xmlns:env="http://schemas.xmlsoap.org/soap/envelope/">
<row>
<tmid>abc</tmid>
<amount>651.03</amount>
<retroAmount>0</retroAmount>
</row>
<row>
<tmid>abc</tmid>
<amount>250.75</amount>
<retroAmount>-10</retroAmount>
</row>
<row>
<tmid>abc</tmid>
<amount>132</amount>
<retroAmount>-16.1</retroAmount>
</row>
<row>
<tmid>xyz</tmid>
<amount>129.19</amount>
<retroAmount>49.96</retroAmount>
</row>
<row>
<tmid>xyz</tmid>
<amount>148.76</amount>
<retroAmount>0</retroAmount>
</row>
<row>
<tmid>xyz</tmid>
<amount>92.29</amount>
<retroAmount>12</retroAmount>
</row>
</Request>
Output I am expecting:
<top xmlns:env="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Results>
<tmId>abc</tmId>
<total>1007.68</total>
</Results>
<Results>
<tmId>xyz</tmId>
<total>432.2</total>
</Results>
</top>
Any help is appreciated.
The XSLT code I was playing with:
Method-1 (everything is stacking up or being displayed without summing)
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:env="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:xsd="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<root>
<xsl:for-each-group select="Request/row"
group-by="tmid">
<row>
<tmid>
<xsl:value-of
select="current-grouping-key()"
/>
</tmid>
<xsl:for-each-group select="current-group()" group-by=".">
<amount>
<xsl:value-of select="sum(number(current-group()/amount))"/>
</amount>
<retroamount>
<xsl:value-of select="sum(number(current-group()/retroAmount))"/>
</retroamount>
</xsl:for-each-group>
</row>
</xsl:for-each-group>
</root>
</xsl:template>
</xsl:stylesheet>
Method-2 (I was only using "amount" and still it is displaying NaN, I would like to sum up both "amount" and "retroAmount"
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:env="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:xsd="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/*">
<top>
<xsl:for-each-group select="//tmid" group-by=".">
<Results>
<tmId>
<xsl:sequence
select="current-grouping-key()"
/>
</tmId>
<total>
<xsl:sequence select="sum(number(current-group()/amount))"/>
</total>
</Results>
</xsl:for-each-group>
</top>
</xsl:template>
</xsl:stylesheet>
You basically want
<xsl:template match="Request">
<xsl:copy>
<xsl:for-each-group select="row" group-by="tmid">
<Results>
<tmId>{current-grouping-key()}</tmId>
<total>{sum(current-group()!(amount, retroAmount))}</total>
</Results>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
(that is XSLT 3 with XPath 3.1 syntax, but in XSLT 2 with XPath 2 syntax you would use
<xsl:template match="Request">
<xsl:copy>
<xsl:for-each-group select="row" group-by="tmid">
<Results>
<tmId>
<xsl:value-of select="current-grouping-key()"/>
</tmId>
<total>
<xsl:value-of select="sum(current-group()/(amount, retroAmount))"/>
</total>
</Results>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
I only later noticed that the Request element is meant to be transformed to a top element so change the <xsl:template match="Request"><xsl:copy>...</xsl:copy></xsl:template> from above suggestions to <xsl:template match="Request"><step>...</step></xsl:template>.

Convert Date from DD-MMM-YYYY to YYYY-MMM-DD using xslt 2.0

I have a XML that has a date formatted as (2019-Aug-19) (YYYY-MMM-DD).
I want this to be transformed to (2019-08-19) (YYYY-MM-DD)
Hear is a sample what i have done. But no luck
<xsl:value-of select="format-dateTime(xs:dateTime(concat(date, T00:00:00Z')), '[D01]-[M01]-[Y0001]')"/>
Here you go may be another simple method:
XML:
<time>2019-Aug-19T00:00:00Z</time>
XSLT:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:output method="text" doctype-public="XSLT-compat" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />
<xsl:variable name="dt" select="time"/>
<xsl:template match="/">
<xsl:value-of select="format-dateTime(xs:dateTime(replace($dt, substring-before(substring-after($dt,'-'),'-') ,format-number(index-of(('jan','feb','mar','apr','may','jun','jul','aug','sep','oct','nov', 'dec'),lower-case(substring-before(substring-after(lower-case($dt),'-'), '-'))),'00'))),'[D01]-[M01]-[Y0001]')"/>
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:transform>
Result:
19-08-2019
For YYYY-MM-DD you can do:
<xsl:value-of select="format-dateTime(xs:dateTime(replace($dt, substring-before(substring-after($dt,'-'),'-') ,format-number(index-of(('jan','feb','mar','apr','may','jun','jul','aug','sep','oct','nov', 'dec'),lower-case(substring-before(substring-after(lower-case($dt),'-'), '-'))),'00'))),'[Y0001]-[M01]-[D01]')"/>
Result:
2019-08-19
See Link: http://xsltransform.net/nbiCsZm

Unable to group the element value using group by in XSLT

I have an XML lie below:
<Products>
<Product1>
<Reference>000510143244</Reference>
<Value1>543</Value1>
</Product1>
</Products>
<Products>
<Product1>
<Reference>000510143244</Reference>
<Value1>543</Value1>
</Product1>
</Products>
<Products>
<Product1>
<Reference>45768799322</Reference>
<Value1>543</Value1>
</Product1>
</Products>
<Products>
<Product2>
<Reference>35726318090</Reference>
<Value1>543</Value1>
</Product2>
</Products>
<Products>
<Product2>
<Reference>35726318090</Reference>
<Value1>543</Value1>
</Product2>
</Products>
I want to get only first value of the Product1 reference...but I am unable to get that.Also it is not mandatory that Product 1 will always be the first element in input xml.
Any suggestions how can I get that?
I have tried to get the value as :
<xsl:template match="//Products">
<xsl:variable name="Product1">
<xsl:for-each-group select="/Reference" group-by="/Reference">
<xsl:copy-of select="." />
</xsl:for-each-group>
</xsl:variable>
</xsl:template>
Update:1
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="Products[child::Product1][1]">
<xsl:value-of select="." />
</xsl:template>
<xsl:template match="text()" />
</xsl:stylesheet>
My expected output is :000510143244
To get the first occurrence of <Products> who has <Product1>, you might need to match the parent tag or root tag of your input XML.
Assuming your input as below:
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<root>
<Products>
<Product2>
<Reference>35726318090</Reference>
</Product2>
</Products>
<Products>
<Product1>
<Reference>02563899183</Reference>
</Product1>
</Products>
<Products>
<Product1>
<Reference>000510143244</Reference>
</Product1>
</Products>
<Products>
<Product1>
<Reference>000510143244</Reference>
</Product1>
</Products>
<Products>
<Product2>
<Reference>35726318090</Reference>
</Product2>
</Products>
</root>
The following code can give you the result:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="root">
<xsl:for-each-group select="Products/Product1" group-by="Reference">
<xsl:copy-of select="current-group()[1]" />
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
See the demo: https://xsltfiddle.liberty-development.net/3NJ38Zx
Update:
OR you can simply achieve it by following code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="Products[child::Product1][1]">
<xsl:copy-of select="." />
</xsl:template>
<xsl:template match="text()" />
</xsl:stylesheet>
Update 2:
<xsl:template match="root">
<xsl:variable name="ref">
<xsl:for-each-group select="Products/Product1" group-by="Reference">
<xsl:copy-of select="current-group()[1]/Reference" />
</xsl:for-each-group>
</xsl:variable>
<xsl:value-of select="$ref"/>
</xsl:template>
https://xsltfiddle.liberty-development.net/3NJ38Zx/1
Update 3:
You cannot assign a value to global variable from a template.
There are two ways to get what you required.
1) Create a global variable as below which will take first <Products> whose child element is <Product1> and will display it's Reference
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:variable name="ref" select="root/Products[child::Product1][1]/Product1/Reference" />
<xsl:template match="/">
<xsl:value-of select="$ref" />
</xsl:template>
</xsl:stylesheet>
2) You can modify the template as below to get the result.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="Products[child::Product1][1]/Product1/Reference">
<xsl:value-of select="." />
</xsl:template>
<xsl:template match="text()" />
</xsl:stylesheet>

Dynamically replacing substring in an given data(XML to fixed length)

Actually I have started with my XSLT work recently, I am facing difficulty in solving one of the requirement.
I am trying to fetch an substring from DATA element in the mentioned input i,e is ECHO and OKAY these codes need to be replaced with the values present under CODE/ECHO and CODE/OKAY in the same input. I had tried storing the substring in a variable and as the variable value and tag value would be same, I have tried to fetch that in . But its not working.
Is it that we cant use variables in the XPATHS or there is some other representation which needs to be used? Could anyone please help me with this.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output omit-xml-declaration="yes" />
<xsl:param name="break" select="'
'" />
<xsl:template match="/">
<xsl:variable name="String" select="substring(DATA, (string-length(substring(DATA,0,77)) + 1), 4)" />
<xsl:variable name="String1" >
<xsl:value-of select="Root/CODES/$String" />
</xsl:variable>
<xsl:value-of select="$break" />
<xsl:value-of select="$String1" />
</xsl:for-each>
</xsl:template>
Input:
<?xml version='1.0' encoding='utf-8'?>
<ROOT>
<INPUT>
<I_FILENAME>ERES</I_FILENAME>
</INPUT>
<CODES>
<ECHO>A1</ECHO>
<OKAY>A2</OKAY>
</CODES>
<TABLES>
<T_ER>
<item>
<DATA> HEADERERESRGCITIS220190301124112000000RGERSD46</DATA>
</item>
<item>
<DATA>000000 ABCD EF 0000000000 2018-11-060000000000EF 000000000000010000ECHO00400300000000000XXXXXX 000{ P 2018-11-05</DATA>
</item>
<item>
<DATA>000000 ABCD EF 0000000000 2018-11-060000000000EF 000000000000010000OKAY00400300000000000XXXXXX 000{ P 2018-11-05</DATA>
</item>
<item>
<DATA>TRAILERERESRGCITIS220190301124112000000001570000</DATA>
</item>
</T_ER>
</TABLES>
</ROOT>
EXPECTED OUT PUT:
HEADERERESRGCITIS220190301124112000000RGERSD46
000000 ABCD EF 0000000000 2018-11-060000000000EF 000000000000010000A100400300000000000XXXXXX 000{ P 2018-11-05
000000 ABCD EF 0000000000 2018-11-060000000000EF 000000000000010000A200400300000000000XXXXXX 000{ P 2018-11-05
<xsl:template match="INPUT|CODES">
</xsl:template>
<xsl:template match="TABLES">
<xsl:variable name="break" select="'
'" />
<xsl:for-each select="T_ER/item"><xsl:value-of select="$break"></xsl:value-of>
<xsl:value-of select="DATA"/>
</xsl:for-each>
</xsl:template>

XSLT - make xsl:analyze-string return string instead of sequence of strings?

Is it possible to make xsl:analyze-string return one string instead of a sequence of strings?
Background: I'd like to use xsl:analyze-string in a xsl:function that should encapsulate the pattern matching. Ideally, the function should return an xs:string to be used as sort criteria in an xsl:sort element.
At the moment, i have to apply string-join() on every result of the function call since xsl:analyze-string returns a sequence of strings, and xsl:sort doesn't accept such a sequence as sort criteria. See line 24 of the stylesheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:my="www.my-personal-namespa.ce"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output indent="yes" method="xml" />
<xsl:function name="my:sortierung" >
<xsl:param name="inputstring" as="xs:string"/>
<xsl:analyze-string select="$inputstring" regex="[0-9]+">
<xsl:matching-substring>
<xsl:value-of select="format-number(number(.), '00000')" />
</xsl:matching-substring>
<xsl:non-matching-substring>
<xsl:value-of select="." />
</xsl:non-matching-substring>
</xsl:analyze-string>
</xsl:function>
<xsl:template match="/input">
<result>
<xsl:apply-templates select="value" >
<xsl:sort select="string-join((my:sortierung(.)), ' ')" />
</xsl:apply-templates>
</result>
</xsl:template>
<xsl:template match="value">
<xsl:copy-of select="." />
</xsl:template>
</xsl:stylesheet>
with this input:
<?xml version="1.0" encoding="UTF-8"?>
<input>
<value>A 1 b 120</value>
<value>A 1 b 1</value>
<value>A 1 b 2</value>
<value>A 1 b 1a</value>
</input>
In my example, is there a way to modify the xsl:function to return a xs:string instead of a sequence?
There are several ways I think, you could put the result of the analyze-string into a variable inside of the function and then use xs:sequence select="string-join($var, ' ')" in the function.
However the following with xsl:value-of should also do:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:my="www.my-personal-namespa.ce"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="my xs">
<xsl:output indent="yes" method="xml" />
<xsl:function name="my:sortierung" as="xs:string">
<xsl:param name="inputstring" as="xs:string"/>
<xsl:value-of separator=" ">
<xsl:analyze-string select="$inputstring" regex="[0-9]+">
<xsl:matching-substring>
<xsl:value-of select="format-number(number(.), '00000')" />
</xsl:matching-substring>
<xsl:non-matching-substring>
<xsl:value-of select="." />
</xsl:non-matching-substring>
</xsl:analyze-string>
</xsl:value-of>
</xsl:function>
<xsl:template match="/input">
<result>
<xsl:apply-templates select="value" >
<xsl:sort select="my:sortierung(.)" />
</xsl:apply-templates>
</result>
</xsl:template>
<xsl:template match="value">
<xsl:copy-of select="." />
</xsl:template>
</xsl:stylesheet>

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