Save curl response in a variable in Jenkins declarative pipeline - jenkins

Question

I have a Jenkins decalarative pipeline where I am calling some URL via cURL which is returning JSON response. How to catch that JSON in a variable?
Have tried the below code but it's returning entire thing with path and command along with the response
environment {
token = bat(returnStdout: true, script: 'curl https://anypoint.mulesoft.com/accounts/login -H "Content-Type: application/json" -d "{\\"username\\" : \\"user\\",\\"password\\" : \\"pwd\\"}"').trim()
}
JSON response
C:\ProgramData\Jenkins\.jenkins\workspace\publish-api>curl https://anypoint.mulesoft.com/accounts/login -H "Content-Type: application/json" -d "{\"username\" : \"ap-1\",\"password\" : \"Ap5\"}"
{
"access_token": "axxxx-5ca2-48eb-9eb3-173c44a811",
"token_type": "bearer",
"redirectUrl": "/home/"
}

Answer 1

You can use the readJson method to get to your wished result. You don't necesseraly have to call it in your environment-block.
stage('Curl') {
steps {
script {
def cUrlResponse = bat(returnStdout: true, script: '#curl https://anypoint.mulesoft.com/accounts/login -H "Content-Type: application/json" -d "{\\"${env.username}\\" : \\"user\\",\\"${env.password}\\" : \\"pwd\\"}"').trim()
def responseJson = readJSON text: cUrlResponse
def accessToken = responseJson.access_token
def tokenType = responseJson.token_type
// do other stuff with the variables
}
}
}
To exclude the curl command from the output, add # in front of the script as stated in the documentation.