I have a numeric variable (year of birth) in SPSS and i would like to take the last for digits out of it. Most values are like 1988, 2001, 1948 etc. But about 250 respondents entered their year of birth like 30-2-1947, or 2-9-1984 etc. That means not all values have the same length. By taking the last 4 digits into a new variable I could create an age category for all the respondents.
How can I do that?
I tried by converting the variable to a string and using substr to get a part of the value, but I always had to choose a starting point. I want to start from the last digit and then move backwards.
Instead of using SUBSTR() you can try using RIGHT() to grab the last four digits.
* convert yob to string variable.
ALTER TYPE yob (A10).
EXE .
* use RIGHT to extract the last 4 digits and convert to numeric.
COMPUTE n_yob = NUMBER(RIGHT(yob, 4, F4)) .
EXE .
You can now use n_yob to calcuate age (ex: COMPUTE age = 2022-n_yob .). You can also use ALTER_TYPE again if you want to convert yob back to it's original type.
Related
In my shopping app, I want to show the item's price in two formats. In the currency of my country which is the HUF and we don't use decimals.
e.g. HUF 1250 or 1250 Ft
The other is the EUR and there we write two digits after the decimal point. These two digits are always there, even if they are 00.
e.g. EUR 12.00 or 12,00 €
I know how can I set the maximum count of digits with the double.toStringAsFixed() method but I didn't find a solution to the opposite setting. Is there in the Dart API any method to solve my problem or do I need to find an alternative way to do this?
You can define the currency with number format like so:
import 'package:intl/intl.dart';
final oCcy = new NumberFormat("#,##0.00", "en_US");
void main () {
print("Eg. 1: ${oCcy.format(123456789.75)}");
print("Eg. 2: ${oCcy.format(.7)}");
print("Eg. 3: ${oCcy.format(12345678975/100)}");
print("Eg. 4: ${oCcy.format(int.parse('12345678975')/100)}");
print("Eg. 5: ${oCcy.format(double.parse('123456789.75'))}");
}
How do I get a random number in Lua to the eighth decimal?
Example : 0.00000001
I have tried the following and several variations of this but can not get the format i need.
math.randomseed( os.time() )
x = math.random(10000000,20000000) * 0.00000001
print(x)
i would like to put in say 200 and get this 0.00000200
Just grab a random number from 0-9, and slide it down 6 places. You can use format specifiers to create the string representation of the number that you desire. For floats we use %f, and indicate how many decimal places we want to have with an intermediate .n, where n is a number.
math.randomseed(os.time())
-- random(9) to exclude 0
print(('%.8f'):format(math.random(0, 9) * 1e-6))
--> '0.00000400'
string.format("%.8f",math.random())
to help anyone else. my question should have been worded a bit better. i wanted to be able to get random numbers and get it to the 8th decimal place.
but i wanted to be able to have those numbers from 1-10,000 so he is updated how i wanted it and the help of Oka got me to this
math.randomseed(os.time())
lowest = 1
highest = 7000
rand=('%.8f'):format(math.random(lowest, highest) / 100000000)
print(rand)
Hope this helps someone else or if it can be cleaned up please let me know
I have an SPSS variable containing lines like:
|2|3|4|5|6|7|8|10|11|12|13|14|15|16|18|20|21|22|23|24|25|26|27|28|29|
Every line starts with pipe, and ends with one. I need to refactor it into boolean variables as the following:
var var1 var2 var3 var4 var5
|2|4|5| 0 1 0 1 1
I have tried to do it with a loop like:
loop # = 1 to 72.
compute var# = SUBSTR(var,2#,1).
end loop.
exe.
My code won't work with 2 or more digits long numbers and also it won't place the values into their respective variables, so I've tried nest the char.substr(var,char.rindex(var,'|') + 1) into another loop with no luck because it still won't allow me to recognize the variable number.
How can I do it?
This looks like a nice job for the DO REPEAT command. However the type conversion is somewhat tricky:
DO REPEAT var#i=var1 TO var72
/i=1 TO 72.
COMPUTE var#i = CHAR.INDEX(var,CONCAT("|",LTRIM(STRING(i,F2.0)),"|"))>0).
END REPEAT.
Explanation: Let's go from the inside to the outside:
STRING(value,F2.0) converts the numeric values into a string of two digits (with a leading white space where the number consist of just one digit), e.g. 2 -> " 2".
LTRIM() removes the leading whitespaces, e.g. " 2" -> "2".
CONCAT() concatenates strings. In the above code it adds the "|" before and after the number, e.g. "2" -> "|2|"
CHAR.INDEX(stringvar,searchstring) returns the position at which the searchstring was found. It returns 0 if the searchstring wasn't found.
CHAR.INDEX(stringvar,searchstring)>0 returns a boolean value indicating if the searchstring was found or not.
It's easier to do the manipulations in Python than native SPSS syntax.
You can use SPSSINC TRANS extension for this purpose.
/* Example data*/.
data list free / TextStr (a99).
begin data.
"|2|3|4|5|6|7|8|10|11|12|13|14|15|16|18|20|21|22|23|24|25|26|27|28|29|"
end data.
/* defining function to achieve task */.
begin program.
def runTask(x):
numbers=map(int,filter(None,[i.strip() for i in x.lstrip('|').split("|")]))
answer=[1 if i in numbers else 0 for i in xrange(1,max(numbers)+1)]
return answer
end program.
/* Run job*/.
spssinc trans result = V1 to V30 type=0 /formula "runTask(TextStr)".
exe.
Suppose I have a factor variable with labels "a" "b" and "c" and want to see which observations have a label of "b". Stata refuses to parse
gen isb = myfactor == "b"
Sure, there is literally a "type mismatch", since my factor is encoded as an integer and so cannot be compared to the string "b". However, it wouldn't kill Stata to (i) perform the obvious parse or (ii) provide a translator function so I can write the comparison as label(myfactor) == "b". Using decode to (re)create a string variable defeats the purpose of encoding, which is to save space and make computations more efficient, right?
I hadn't really expected the comparison above to work, but I at least figured there would be a one- or two-line approach. Here is what I have found so far. There is a nice macro ("extended") function that maps the other way (from an integer to a label, seen below as local labi: label ...). Here's the solution using it:
// sample data
clear
input str5 mystr int mynum
a 5
b 5
b 6
c 4
end
encode mystr, gen(myfactor)
// first, how many groups are there?
by myfactor, sort: gen ng = _n == 1
replace ng = sum(ng)
scalar ng = ng[_N]
drop ng
// now, which code corresponds to "b"?
forvalues i = 1/`=ng'{
local labi: label myfactor `i'
if "b" == "`labi'" {
scalar bcode = `i'
break
}
}
di bcode
The second step is what irks me, but I'm sure there's a also faster, more idiomatic way of performing the first step. Can I grab the length of the label vector, for example?
An example:
clear all
set more off
sysuse auto
gen isdom = 1 if foreign == "Domestic":`:value label foreign'
list foreign isdom in 1/60
This creates a variable called isdom and it will equal 1 if foreigns's value label is equal to "Domestic". It uses an extended macro function.
From [U] 18.3.8 Macro expressions:
Also, typing
command that makes reference to `:extended macro function'
is equivalent to
local macroname : extended macro function
command that makes reference to `macroname'
This explains one of the two : in the offered syntax. The other can be explained by
... to specify value labels directly in an expression, rather than through
the underlying numeric value ... You specify the label in double quotes
(""), followed by a colon (:), followed by the name of the value
label.
The quote is from Stata tip 14: Using value labels in expressions, by Kenneth Higbee, The Stata Journal (2004). Freely available at http://www.stata-journal.com/sjpdf.html?articlenum=dm0009
Edit
On computing the number of distinct observations, another way is:
by myfactor, sort: gen ng = _n == 1
count if ng
scalar sc_ng = r(N)
display sc_ng
But yours is fine. In fact, it is documented here: http://www.stata.com/support/faqs/data-management/number-of-distinct-observations/, along with more methods and comments.
I'm writing a Wireshark dissector in lua and trying to decode a time-based protocol field.
I've two components 1)
local ref_time = os.time{year=2000, month=1, day=1, hour=0, sec=0}
and 2)
local offset_time = tvbuffer(0:5):bytes()
A 5-Byte (larger than uint32 range) ByteArray() containing the number of milliseconds (in network byte order) since ref_time. Now I'm looking for a human readable date. I didn't know this would be so hard, but 1st it seems I cannot simple add an offset to an os.time value and 2nd the offset exceeds Int32 range ...and most function I tested seem to truncate the exceeding input value.
Any ideas on how I get the date from ref_time and offset_time?
Thank you very much!
Since ref_time is in seconds and offset_time is in milliseconds, just try:
os.date("%c",ref_time+offset_time/1000)
I assume that offset_time is a number. If not, just reconstruct it using arithmetic. Keep in mind that Lua uses doubles for numbers and so a 5-byte integer fits just fine.