How can i outputs result between 2 specific characters in dart String
example
String myVlue = 'helloWorld';
wanted result is : anything between 'hel' and 'ld'
so the result is 'loWor'
Note : in my case the two specific characters are fixed and Unique
How can i tell dart to do that in best way .
thanks
You could define a regular expression to catch a group from your input:
void main() {
String myValue = 'helloWorld';
RegExp regExp = RegExp(r'hel(.*)ld');
String extract = regExp.firstMatch(myValue)![1]!;
print(extract); // loWor
}
Related
i have string who is
String hello = "test test {Brian} have you {Adam} always and {Corner} always";
want to make list string who is taking who have {string}
output :
List<String> data = ["{Brian}","{Adam}","{Corner}"];
its that possible in dart ?
i dont know what to use
You can achieve this by using RegExp(r"\{[^{}]*\}")
String hello = "test test {Brian} have you {Adam} always and {Corner} always";
RegExp regExp = RegExp(r"\{[^{}]*\}");
print(regExp.allMatches(hello).map((e) => e[0]).toList());
I'm a beginner in dart.
void main() {
var abf = '+37.4054-122.0999/';
var abf2;
abf2 = abf.replaceAll("+"," ");
var abf1 = abf2.split(RegExp('(?=[+-])'));
print (abf1[0]);
print (abf1[1]);
}
The above code splits abf into two values for me
I want to remove the ending '/'. I tried many split methods using other variables but it's not removing the '/' even though its removing the '+'.
It's not really clear what you're trying to do with the split.
But if you're looking the remove the / this should work:
String number = '+37.4054-122.0999/';
number = number.replaceAll("/"," ");
You can create substring from this while you like to remove last element.
String abf = '+37.4054-122.0999/';
final result = abf.substring(0, abf.length - 1);
print(result);
Dart's List class has a built-in removeLast method. Maybe you can try to split the string and then removing the last element:
String str = "str";
String newStr = str.split(''). removeLast().join('');
How can I pull out a string from two different patterns either side of the string I want: eg
String s= bg_img_pulloutthisstring#s_200
How can I pull out pulloutthisstring from s?
The easiest is to use a Regular Expression and use a match group:
void main() {
const s = 'bg_img_pulloutthisstring#s_200';
print(RegExp(r'bg_img_(.*)#s_200').firstMatch(s).group(1)); // pulloutthisstring
}
I'm writing a function to replace substrings (what laguange doesn't have this, grr), and I am getting some strange characters in my ouput. I cannot figure out why.
string replaceSubstring(string input, string targetSubstring, string substitute, bool matchCase)
{
string result = input
Buffer b = create
b = input
int targetStartPos
int targetLength
while (findPlainText(result, targetSubstring, targetStartPos, targetLength, matchCase))
{
string prefixStr = b[0:targetStartPos - 1]
string suffixStr = b[targetStartPos + targetLength:]
b = prefixStr substitute suffixStr
result = tempStringOf(b)
}
delete b
return result
}
When running print replaceSubstring("Jake Lewis", "ake", "ack", false), I get an output of �*��*�is. This would appear to be some sort of encoding issue, but I am unclear on how this is happening, or how to fix it.
Try using stringOf() instead of tempStringOf(). Your processing is fine, but the result becomes invalid after deleting b.
In some languages, like C# for example, you can create a string in the following way:
"String {0} formatted {1} "
And then format it with String.format by passing in the values to format.
The above declaration is good, because you don't have to know of what type its parameters are when you create the string.
I tried to find similar approach in Swift, but what I found out was something like the following format:
"String %d formatted %d"
which requires you to format the string with String(format: , parameters). This is not good because you would also have to know parameter types when declaring the string.
Is there a similar approach in Swift where I wouldn't have to know the parameter types?
Use this one:
let printfOutput = String(format:"%# %2.2d", "string", 2)
It's the same as printf or the Obj-C formatting.
You can also mix it in this way:
let parm = "string"
let printfOutput = String(format:"\(parm) %2.2d", 2)
Edit: Thanks to MartinR (he knows it all ;-)
Be careful when mixing string interpolation and formatting. String(format:"\(parm) %2.2d", 2) will crash if parm contains a percent character. In (Objective-)C, the clang compiler will warn you if a format string is not a string literal.
This gives some room for hacking:
let format = "%#"
let data = "String"
let s = String(format: "\(format)", data) // prints "String"
In contrast to Obj-C which parses the format string at compile time, Swift does not do that and just interprets it at runtime.
In Swift, types need to conform to the CustomStringConvertible protocol in order to be used inside strings. This is also a requirement for the types used in string interpolation like this:
"Integer value \(intVal) and double value \(doubleVal)"
When you understand the CustomStringConvertible, you can create your own function to fulfill your needs. The following function formats the string based on the given arguments and prints it. It uses {} as a placeholder for the argument, but you can change it to anything you want.
func printWithArgs(string: String, argumentPlaceHolder: String = "{}", args: CustomStringConvertible...) {
var formattedString = string
// Get the index of the first argument placeholder
var nextPlaceholderIndex = string.range(of: argumentPlaceHolder)
// Index of the next argument to use
var nextArgIndex = 0
// Keep replacing the next placeholder as long as there's more placeholders and more unused arguments
while nextPlaceholderIndex != nil && nextArgIndex < args.count {
// Replace the argument placeholder with the argument
formattedString = formattedString.replacingOccurrences(of: argumentPlaceHolder, with: args[nextArgIndex].description, options: .caseInsensitive, range: nextPlaceholderIndex)
// Get the next argument placeholder index
nextPlaceholderIndex = formattedString.range(of: argumentPlaceHolder)
nextArgIndex += 1
}
print(formattedString)
}
printWithArgs(string: "First arg: {}, second arg: {}, third arg: {}", args: "foo", 4.12, 100)
// Prints: First arg: foo, second arg: 4.12, third arg: 100
Using a custom implementation allows you to have more control over it and tweak its behavior. For example, if you wanted to, you could modify this code to display the same argument multiple times using placeholders like {1} and {2}, you could fill the arguments in a reversed order, etc.
For more information about string interpolation in Swift: https://docs.swift.org/swift-book/LanguageGuide/StringsAndCharacters.html#//apple_ref/doc/uid/TP40014097-CH7-ID292