I decided to spring-clean and update my nvim config files/plugins, and thought I’d make proper use of the after/plug folder.
While setting up LSP (with mason, mason-lspconfig, and lspconfig), I wanted to move all the lsp language server settings out from after/plugin/lsp/init.lua to their own files (now in after/plugin/lsp/settings).
The problem is I don’t seem to be able to require them into the init.lua file.
Things I’ve tried to no avail:
require(‘after/plugin/lsp/settings/sumneko_lua.lua’)
require(vim.fn.stdpath("config") .. "/after/plugin/lsp/settings/sumneko_lua”)
require(vim.fn.expand('%:h').. ‘/settings/sumneko_lua’)
The attempt using expand works when I resource the file in nvim; but causes an error when starting nvim.
I understand that all the files in after/plugin are automagically sourced at startup. So if I had a file shared.lua:
local M = {}
function M.greet()
vim.notify("Hello!”)
end
return M
in the same folder as after/plugin/lsp/init.lua, how can I get access to the greet() function from init.lua?
Any pointers would be greatly appreciated.
It turned out to be quite a simple solution in the end: I simply updated the paths to be searched in init.lua
-- nvim/init.lua
-- Allow require to look in after/plugin folder
local home_dir = os.getenv("HOME”)
package.path = home_dir .. "/.config/nvim/after/plugin/?.lua;" .. package.path
And then I can require any file inside the after/plugin folder
e.g - require(‘lsp/settings/sumneko’) or require(‘lsp/shared’).greet()
Related
I'm trying to require files in Lua, in one case it is working, but when I want to simplify the requirements in updating the LUA PATH the file is not found, but it is in the trace!
To reproduce my require problem I did the test with the package.searchpath function, which takes the required key and the Lua path in arguments.
So the code :
print('MY LUA PATH')
local myLuaPath = "?;?.lua;D:\\Projets\\wow-addon\\HeyThere\\?;D:\\Projets\\wow-addon\\HeyThere\\src\\HeyThere\\?;D:\\Projets\\wow-addon\\HeyThere\\test\\HeyThere\\?"
print(myLuaPath)
print('package search core.add-test')
print(package.searchpath('core.add-test', myLuaPath))
print('package search test.HeyThere.core.add-test')
print(package.searchpath('test.HeyThere.core.add-test', myLuaPath))
The result :
MY LUA PATH
?;?.lua;D:\Projets\wow-addon\HeyThere\?;D:\Projets\wow-addon\HeyThere\src\HeyThere\?;D:\Projets\wow-addon\HeyThere\test\HeyThere\?
package search core.add-test
nil no file 'core\add-test'
no file 'core\add-test.lua'
no file 'D:\Projets\wow-addon\HeyThere\core\add-test'
no file 'D:\Projets\wow-addon\HeyThere\src\HeyThere\core\add-test'
no file 'D:\Projets\wow-addon\HeyThere\test\HeyThere\core\add-test'
package search test.HeyThere.core.add-test
test\HeyThere\core\add-test.lua
So the first try with 'core.add-test' should work with the 'D:\Projets\wow-addon\HeyThere\test\HeyThere\?' value in the path but fails...
In the trace, there is the file I want!
no file 'D:\Projets\wow-addon\HeyThere\test\HeyThere\core\add-test'
But with the same LUA PATH but starting in a parent folder the file is found... Second test with 'test.HeyThere.core.add-test' found from the 'D:\Projets\wow-addon\HeyThere\?'
-> test\HeyThere\core\add-test.lua
Can someone explains to me why it doesn't work the first time?
EDIT :
My current directory is D:\Projets\wow-addon\HeyThere
My lua.exe is in D:\Projets\wow-addon\HeyThere\bin\lua but is added to my PATH variable (I'm on Windows)
I set the LUA_PATH environment variable and execute
lua "test\test-suite.lua" -v
The code inside test-suite.lua is the test code described above
As #EgorSkriptunoff suggested, adding file extansion in the path resolve the problem...
Ex:
Wrong path D:\Projets\wow-addon\HeyThere\?
Good path D:\Projets\wow-addon\HeyThere\?.lua
The extension should be in the path variable because in the require the dot is replace and used as a folder separator.
I'm writing a tool to parse lua plugins created by other users. The only guarentee about the plugin is that it has a data.lua file in a known directory. Inside there users are free to do anything they wish. This particular plugin using require to load a file and that file loads another file. Both are relative paths but the second is relative to the location of the first file.
data.lua
foo/bar.lua
foo/baz.lua
data.lua:
require("foo.bar")
foo/bar.lua:
require("baz")
When I try to execute data.lua I get an error when foo/bar.lua tries to require "baz". None of the paths it tries are ./foo/.
Any idea how I can fix this? I could find any documentation specifically about this case, it seemed like I need to hard code /foo/ into the path but I don't know it ahead of time. This seems like something that should be automatic is there a setting I'm missing or am I running the wrong version of lua? I'm using NLua 4.0
Thanks
I tested this script using node-lua and it fixes the issue for me!
https://gist.github.com/hoelzro/1299679
Relavent code:
local oldrequire = require
function require(modname)
local regular_loader = package.loaders[2]
local loader = function(inner)
if string.match(modname, '(.*)%.') then
return regular_loader(string.match(modname, '(.*)%.') .. '.' .. inner)
end
end
table.insert(package.loaders, 1, loader)
local retval = oldrequire(modname)
table.remove(package.loaders, 1)
return retval
end
To get this to work with Lua 5.2 change all uses of package.loaders to package.searchers.
Also if you want to override the global require function you need this snippet as well:
_G.require = require
You can alter the search behavior of require by changing the package.path variable.
Resources on package.path:
https://www.lua.org/manual/5.3/manual.html#pdf-package.path
http://lua-users.org/wiki/PackagePath
Example adding foo folder to search locations:
package.path = package.path .. ';./foo/?.lua'
the ? character will be where the string passed to require is placed.
Alternatively you can add a default file to load, to the package.path:
package.path = package.path .. ';./nested_require.lua'
Then define the behavior you would like within this file. You can use the global variable _REQUIREDNAME to reference the value passed to the require function.
The documentation for this method can be found here at the bottom of the page: https://www.lua.org/pil/8.1.html
In a lua-script (for Domoticz # Raspberry) I apply the following script-segment to generate an htm-file and to put it in the designated folder.
Line02text till Line30text are variables which are dynamically filled elsewhere in the lua-script.
file = io.open("/home/pi/domoticz/scripts/lua/XXXXX.htm", "w+")
-- Opens a file named XXXXX.htm (stored under the designated sub-folder of Domoticz)
-- in append mode
-- write lines to opened file
file:write("SOF<br>")
file:write(Line02text .. "<br>")
file:write(Line03text .. "<br>")
....
file:write(Line29text .. "<br>")
file:write(Line30text .. "<br>")
file:write("EOF<br>")
file:close() -- closes the open file
All seems OK, because the htm-file appears as planned.
Next steps would be to copy the file to different folder, open in browser, etc..
But Owner of the htm-file is 'root' and Permission is 0640.
For further application Owner should be different, and Permission e.g. 777.
Trying manual change or use of chmod results in report 'Permission denied' by server.
Question:
How to set (as result of the lua-script) different Owner and other Permission for the htm-file?
Lua's target is to be as portable as possible, and ownership/permissions management is very os-specific. There's no embedded functions to handle that.
You'll need to expose some native function that will do what you need with files' permissions. Or use some already existing library for that, like maybe lua-fs: (https://github.com/clementfarabet/lua-fs-0.3)
We want to integrate a third-party Lua module (say) foo into our CoronaSDK application.
Main code of this module module is in foo/init.lua, to be required as require 'foo'.
We placed this module into corona/foo:
corona/foo$ ls
init.lua
In corona/main.lua we have:
package.path = package.path .. ";"
.. package.path:gsub("?.lua", "?/init.lua")
require 'foo' works in the simulator. However, it does not work on the device:
Lua Runtime Error: lua_pcall failed with status: 2, error message is:
module 'foo' not found:resource (foo.lua) does not exist in
archive
no field package.preload['foo']
no file '/var/mobile/Applications/0B609A43-54E8-40E5-9D44-F3C93CC4031E/Appname.app/foo.lua'
no file '/var/mobile/Applications/0B609A43-54E8-40E5-9D44-F3C93CC4031E/Appname.app/foo.lua'
no file '/var/mobile/Applications/0B609A43-54E8-40E5-9D44-F3C93CC4031E/Appname.app/foo/init.lua'
no file '/var/mobile/Applications/0B609A43-54E8-40E5-9D44-F3C93CC4031E/Appname.app/foo/init.lua'
no file './foo.so'
Strangely enough, require 'foo.init' does work.
Any clues?
Is your filename
foo.lua or Foo.lua?
it works on simulator for both cases, but in devices, the capital matters.
I had this nightmare (I wonder why my SVN client changed the capital for one of my files... I spent over an hour to find out what went wrong because my module couldn't be found in the device suddenly)
Try this
package.path = package.path .. ";"
.. package.path:gsub("?.lua", "?.init.lua")
path names for lua files called in packages should be done like this:
dir.luafile.lua
rather than dir/luafile.lua
hope that helps
If I have a file structure like this:
./main.lua
./mylib/mylib.lua
./mylib/mylib-utils.lua
./mylib/mylib-helpers.lua
./mylib/mylib-other-stuff.lua
From main.lua the file mylib.lua can be loaded with full path require('mylib.mylib'). But inside mylib.lua I would also like to load other necessary modules and I don't feel like always specifying the full path (e.g. mylib.mylib-utils). If I ever decide to move the folder I'm going to have a lot of search and replace. Is there a way to use just the relative part of the path?
UPD. I'm using Lua with Corona SDK, if that matters.
There is a way of deducing the "local path" of a file (more concretely, the string that was used to load the file).
If you are requiring a file inside lib.foo.bar, you might be doing something like this:
require 'lib.foo.bar'
Then you can get the path to the file as the first element (and only) ... variable, when you are outside all functions. In other words:
-- lib/foo/bar.lua
local pathOfThisFile = ... -- pathOfThisFile is now 'lib.foo.bar'
Now, to get the "folder" you need to remove the filename. Simplest way is using match:
local folderOfThisFile = (...):match("(.-)[^%.]+$") -- returns 'lib.foo.'
And there you have it. Now you can prepend that string to other file names and use that to require:
require(folderOfThisFile .. 'baz') -- require('lib.foo.baz')
require(folderOfThisFile .. 'bazinga') -- require('lib.foo.bazinga')
If you move bar.lua around, folderOfThisFile will get automatically updated.
You can do
package.path = './mylib/?.lua;' .. package.path
Or
local oldreq = require
local require = function(s) return oldreq('mylib.' .. s) end
Then
-- do all the requires
require('mylib-utils')
require('mylib-helpers')
require('mylib-other-stuff')
-- and optionally restore the old require, if you did it the second way
require = oldreq
I'm using the following snippet. It should work both for files loaded with require, and for files called via the command line. Then use requireRel instead of require for those you wish to be loaded with a relative path.
local requireRel
if arg and arg[0] then
package.path = arg[0]:match("(.-)[^\\/]+$") .. "?.lua;" .. package.path
requireRel = require
elseif ... then
local d = (...):match("(.-)[^%.]+$")
function requireRel(module) return require(d .. module) end
end
Under the Conky's Lua environment I've managed to include my common.lua (in the same directory) as require(".common"). Note the leading dot . character.
Try this:Here is my findings:
module1= require(".\\moduleName")
module2= dofile("..\\moduleName2.lua")
module3 =loadfile("..\\module3.lua")
To load from current directory. Append a double backslash with a prefix of a fullstop.
To specify a directory above use a prefix of two fullstops and repeat this pattern for any such directory.e.g
module4=require("..\\..\\module4")