I'm building a server and I need to serve binary files.
My code is this:
//lib/handler.dart
import 'dart:io';
import 'package:mime/mime.dart';
class FileResponse {
Object name;
ContentType type;
FileResponse(this.name, this.type);
}
Object tr(String f) {
Object res = File(f).readAsBytesSync();
try {
File(f).readAsStringSync();
res = File(f).readAsStringSync();
} catch(_) {}
return res;
}
FileResponse fileHandler(String uri) {
if(uri == "/") uri = "/index.html";
if(File("/Users/jett/Sites$uri").existsSync()) {
ContentType tpe = ContentType.parse(lookupMimeType(uri)!);
Object resp = tr("/Users/jett/Sites/$uri");
return FileResponse(resp, tpe);
} else if(File("/Users/jett/Sites$uri/index.html").existsSync()) {
ContentType tpe = ContentType.parse(lookupMimeType(uri)!);
Object resp = tr("/Users/jett/Sites/$uri/index.html");
return FileResponse(resp, tpe);
} else if(File("/Users/jett/Sites${uri}index.html").existsSync()) {
ContentType tpe = ContentType.parse(lookupMimeType(uri)!);
Object resp = tr("/Users/jett/Sites/${uri}index.html");
return FileResponse(resp, tpe);
} else {
return FileResponse(File("/Users/jett/Sites/404.html").readAsStringSync(), ContentType.html);
}
}
//bin/srv.dart
import 'package:srv/handler.dart';
import 'dart:io';
void main() async {
final HttpServer srvs = await HttpServer.bindSecure('127.0.0.1', 443, SecurityContext()..useCertificateChain("/Users/jett/srv/fc.pem"));
final HttpServer srv = await HttpServer.bind('127.0.0.1', 80);
await for(final HttpRequest request in srv) {
print(request.uri.path);
FileResponse res = fileHandler(request.uri.path);
request.response
..headers.contentType = res.type
..write(res.name);
request.response.close();
}
}
I created an empty server and added a handler to it. The file handler checks for an existing file or a 404 page. The text files work fine(html js css json)... but the image and video files crash.
And the docs tell me this:
// TODO(ajohnsen): Add documentation of how to pipe a file to the response.
So how do I pipe a binary file into the response.
Related
I am trying to upload image from client (flutter) to server (Aqueduct.io) using MultipartRequest.
It's working, but currently file names are assigned the current time, how can I pass the filename from a client and parse it on a server side?
Client code:
final String imageName = nameController.text.replaceAll(" ", "");
var postUri = Uri.parse("http://***:8888/media");
var request = new http.MultipartRequest("POST", postUri);
request.files.add(new http.MultipartFile.fromBytes('file', image,
filename: imageName, contentType: MediaType('image', 'jpeg')));
request.send().then((response) {
if (response.statusCode == 200) print("Uploaded!");
});
}
Server code:
import 'dart:async';
import 'dart:io';
import 'package:aqueduct/aqueduct.dart';
import 'package:mime/mime.dart';
import 'package:http_server/http_server.dart';
class MediaController extends ResourceController {
MediaController() {
acceptedContentTypes = [ContentType("multipart", "form-data")];
}
#Operation.post()
Future<Response> postMultipartForm() async {
final transformer = MimeMultipartTransformer(
request.raw.headers.contentType.parameters["boundary"]);
final bodyStream =
Stream.fromIterable([await request.body.decode<List<int>>()]);
final parts = await transformer.bind(bodyStream).toList();
for (var part in parts) {
final HttpMultipartFormData multipart = HttpMultipartFormData.parse(part);
final content = multipart.cast<List<int>>();
final filePath =
"public/" + DateTime.now().millisecondsSinceEpoch.toString() + ".jpg"; // <---current filename implementation
final IOSink sink = File(filePath).openWrite();
await for (List<int> item in content) {
sink.add(item);
}
await sink.flush();
await sink.close();
}
return Response.ok({});
}
}
Okay, I have the asnwer
import 'dart:async';
import 'dart:io';
import 'package:aqueduct/aqueduct.dart';
import 'package:mime/mime.dart';
import 'package:http_server/http_server.dart';
class MediaController extends ResourceController {
MediaController() {
acceptedContentTypes = [ContentType("multipart", "form-data")];
}
#Operation.post()
Future<Response> postMultipartForm() async {
final transformer = MimeMultipartTransformer(
request.raw.headers.contentType.parameters["boundary"]);
final bodyStream =
Stream.fromIterable([await request.body.decode<List<int>>()]);
final parts = await transformer.bind(bodyStream).toList();
for (var part in parts) {
final HttpMultipartFormData multipart = HttpMultipartFormData.parse(part);
List<String> tokens = part.headers['content-disposition'].split(";");
String filename;
for (var i = 0; i < tokens.length; i++) {
if (tokens[i].contains('filename')) {
filename = tokens[i]
.substring(tokens[i].indexOf("=") + 2, tokens[i].length - 1);
}
}
print('file $filename.jpg uploaded');
final content = multipart.cast<List<int>>();
final filePath =
// "public/" + DateTime.now().millisecondsSinceEpoch.toString() + ".jpg";
'public/$filename.jpg';
final IOSink sink = File(filePath).openWrite();
await for (List<int> item in content) {
sink.add(item);
}
await sink.flush();
await sink.close();
}
return Response.ok({});
}
}
I am using the Flutter Plugin Image_picker to choose images so that I want to upload image after selected the image
Future<File> _imageFile;
void _onImageButtonPressed(ImageSource source) async {
setState(() {
_imageFile = ImagePicker.pickImage(source: source);
});
}
I find this code in flutter documentation but its not work
var uri = Uri.parse("http://pub.dartlang.org/packages/create");
var request = new http.MultipartRequest("POST", url);
request.fields['user'] = 'nweiz#google.com';
request.files.add(new http.MultipartFile.fromFile(
'package',
new File('build/package.tar.gz'),
contentType: new MediaType('application', 'x-tar'));
request.send().then((response) {
if (response.statusCode == 200) print("Uploaded!");
});
Use MultipartRequest class
Upload(File imageFile) async {
var stream = new http.ByteStream(DelegatingStream.typed(imageFile.openRead()));
var length = await imageFile.length();
var uri = Uri.parse(uploadURL);
var request = new http.MultipartRequest("POST", uri);
var multipartFile = new http.MultipartFile('file', stream, length,
filename: basename(imageFile.path));
//contentType: new MediaType('image', 'png'));
request.files.add(multipartFile);
var response = await request.send();
print(response.statusCode);
response.stream.transform(utf8.decoder).listen((value) {
print(value);
});
}
Check this answer
This code works properly.
Used MultipartRequest class
void uploadImage() async {
File _image;
File pickedImage = await ImagePicker.pickImage(source: ImageSource.camera);
setState(() {
_image = pickedImage;
});
// open a byteStream
var stream = new http.ByteStream(DelegatingStream.typed(_image.openRead()));
// get file length
var length = await _image.length();
// string to uri
var uri = Uri.parse("enter here upload URL");
// create multipart request
var request = new http.MultipartRequest("POST", uri);
// if you need more parameters to parse, add those like this. i added "user_id". here this "user_id" is a key of the API request
request.fields["user_id"] = "text";
// multipart that takes file.. here this "image_file" is a key of the API request
var multipartFile = new http.MultipartFile('image_file', stream, length, filename: basename(_image.path));
// add file to multipart
request.files.add(multipartFile);
// send request to upload image
await request.send().then((response) async {
// listen for response
response.stream.transform(utf8.decoder).listen((value) {
print(value);
});
}).catchError((e) {
print(e);
});
}
name spaces:
import 'package:path/path.dart';
import 'package:async/async.dart';
import 'dart:io';
import 'package:http/http.dart' as http;
If you want the uploading function to return the server response, you can use toBytes() instead of transform(), in order to wait until data transmission is complete.
Future<String> upload() async {
String responseString = '';
// Pick image
final image = await ImagePicker().getImage(
source: ImageSource.gallery // or ImageSource.camera
imageQuality: 100,
maxWidth: 1000,
);
// Convert to File
final file = File(image.path);
// Set URI
final uri = Uri.parse('URL');
// Set the name of file parameter
final parameter = 'Name';
// Upload
final request = http.MultipartRequest('POST', uri)
..files.add(await http.MultipartFile.fromPath(parameter, file.path));
final response = await request.send();
if (response.statusCode == 200) {
responseString = String.fromCharCodes(await response.stream.toBytes());
}
return responseString;
}
Uploading a single image seems to be no problem with retrofit 2.
However,
i cant figure out how to upload 2 images at the same time.
if followed the documentation:
http://square.github.io/retrofit/2.x/retrofit/retrofit2/http/PartMap.html
File file = new File(path, "theimage");
File file2 = new File(path2, "theimage");
RequestBody requestBody = RequestBody.create(MediaType.parse("image/png"), file);
RequestBody requestBody2 = RequestBody.create(MediaType.parse("image/png"), file2);
Map<String, RequestBody> params = new HashMap<>();
params.put("image2", requestBody2 );
Call<ResponseBody> call = service.upload(requestBody, params);
call.enqueue(new Callback<ResponseBody>() {
#Override
public void onResponse(Response<ResponseBody> response, Retrofit retrofit) {
Log.v("Upload", "success");
}
interface:
public interface FileUploadService {
#Multipart
#POST("/upload")
Call<ResponseBody> upload(
//#Part("image_logo\"; filename=\"image.png\" ") RequestBody file,
#Part("file") RequestBody file,
#PartMap Map<String, RequestBody> params
// #Part("description") String description
);
this gives a 'Upload: success' but on the server side i get gibberish:
CONTENT_TYPE: multipart/form-data;
boundary=50fbfeb3-3abc-4f15-b130-cdcb7e3a0e4f
CONTENT POST:Array (
[file] => �PNG IHDR L alotofbinarygibberish.... ... snip
[file2] => �PNG
IHDR L more binary gibberish...
can anyone point me in the right direction?
single upload does work so thats not the problem, i'm trying to upload 2 or more images.
if i change it to this:
HashMap<String, RequestBody> partMap = new HashMap<String, RequestBody>();
partMap.put("file\"; filename=\"" + file.getName(), requestBody);
partMap.put("file\"; filename=\"" + file2.getName(), requestBody);
Call<ResponseBody> call = service.upload(partMap);
#Multipart
#POST("/upload")
Call<ResponseBody> upload(
#PartMap() Map<String, RequestBody> partMap,
i get no gibberish but only the second image is uploaded... !?
UPDATE
i tried this Retrofit(2.0 beta2) Multipart file upload doesn't work solution but get an error that #body can not me used with multipart:
Java.lang.IllegalArgumentException: #Body parameters cannot be used with form or multi-part encoding. (parameter #1)
for (String key : keys) {
Bitmap bm = selectedImages.get(key);
File f = new File(saveToInternalStorage(bm, key), key);
if (f.exists()) {
buildernew.addFormDataPart(key, key + ".png", RequestBody.create(MEDIA_TYPE, f));
}
}
RequestBody requestBody = buildernew.build();
-
Call<ResponseBody> upload(
#Body RequestBody requestBody
This works:
final MediaType MEDIA_TYPE=MediaType.parse("image/png");
HashMap<String,RequestBody> map=new HashMap<>(selectedImages.size());
RequestBody file=null;
File f=null;
Set<String> keys = selectedImages.keySet();
for (String key : keys) {
try {
Bitmap bitmap = selectedImages.get(key);
f = new File(saveToInternalStorage(bitmap, key), key);
FileOutputStream fos = new FileOutputStream(f);
if(bitmap!=null){
bitmap.compress(Bitmap.CompressFormat.PNG, 0 , fos);
fos.flush();
fos.close();
}
} catch (Exception e) {
e.printStackTrace();
return;
}
file=RequestBody.create(MEDIA_TYPE, f);
map.put(""+key+"\"; filename=\""+key+".jpg",file);
Log.i("##MYLOG###", "### MAP PUT:" + key + " filename:"+key+".jpg file:" + file.toString() +" type:"+ file.contentType() );
file=null;
f = null;
}
--
Call<ResponseBody> upload(
#PartMap() Map<String,RequestBody> mapFileAndName //for sending multiple images
--
beware: while debugging this with the httpClient.interceptors() i saw only a single upload but when checking the endpoint itself to see what it actually got, it DID get the multiple uploads!
I might be late but my answer might help future visitors
I am asking user to select multiple images like this:
int PICK_IMAGE_MULTIPLE = 1;
Intent intent = new Intent();
intent.setType("image/*");
intent.putExtra(Intent.EXTRA_ALLOW_MULTIPLE, true);
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Select Picture"), PICK_IMAGE_MULTIPLE);
Then in onActivityResult() I am doing this:
ArrayList<String> filePaths;
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == PICK_IMAGE_MULTIPLE) {
if (data != null) {
filePaths=new ArrayList<>();
// If data.getData() == null means multiple images selected, else single image selected.
if (data.getData() == null) {
ClipData clipData = data.getClipData();
if (clipData != null) {
for (int i = 0; i < clipData.getItemCount(); i++) {
ClipData.Item item = clipData.getItemAt(i);
Uri uri = item.getUri();
filePaths.add(FileUtils.getPath(Activity.this, uri));
}
}
} else {
filePaths.add(FileUtils.getPath(Activity.this,data.getData()));
}
sendToServer();
}
}
}
You can get FileUtils class from this Github link
My sendToServer() method looks like this:
private void sendToServer() {
if(filePaths!=null) {
ApiInterface apiService = ApiClient.getClient().create(ApiInterface.class);
MediaType MEDIA_TYPE_IMG = MediaType.parse("image/jpeg");
MultipartBody.Builder builder=new MultipartBody.Builder();
builder.setType(MultipartBody.FORM);
RequestBody requestBody;
try {
for (int i = 0; i < filePaths.size(); i++) {
File file = new File(filePaths.get(i));
requestBody=RequestBody.create(MEDIA_TYPE_IMG,file);
builder.addFormDataPart("photo"+i,file.getName(),requestBody);
}
RequestBody finalRequestBody=builder.build();
Call<YourResponse> call=apiService.addEvent(finalRequestBody);
call.enqueue(new Callback<YourResponse>() {
#Override
public void onResponse(Call<YourResponse> call, Response<YourResponse> response) {
// process response
}
#Override
public void onFailure(Call<YourResponse> call, Throwable t) {
t.printStackTrace();
t.getCause();
}
});
}catch (Exception e){
e.printStackTrace();
}
}
}
Finally my Retrofit endpoint looks like this:
#POST("event/add")
Call<YourResponse> addEvent(#Body RequestBody body);
Note that YourResponse can be your custom model class for handling response, or you can also use raw Response class in you don't want to make your model class.
Hope this helps new visitors.
Try This
For API:
//Multiple Images
#Multipart
#POST(HttpConstants.FILEMULTIPLEUPLOAD)
Call<Result>uploadMultipleImage(#Part MultipartBody.Part files1,#Part MultipartBody.Part files2, #Query("total_images") int total, #Query("stdID") int stdID);
Client
public class RaytaServiceClass {
public RaytaServiceClass() {
}
private static Retrofit getRetroClient(){
Gson gson = new GsonBuilder()
.setLenient()
.create();
return new Retrofit.Builder()
.baseUrl(HttpConstants.baseUrl)
.addConverterFactory(GsonConverterFactory.create(gson))
.build();
}
public static RaytaApi getApiService(){
return getRetroClient().create(RaytaApi.class);
}
}
The Call
RaytaApi service= RaytaServiceClass.getApiService();
File file1 = new File(selectedPath1);
File file2 = new File(selectedPath2);
RequestBody requestFile = RequestBody.create(MediaType.parse("multipart/form-data"), file1);
RequestBody requestFile2 = RequestBody.create(MediaType.parse("multipart/form-data"), file2);
MultipartBody.Part body =
MultipartBody.Part.createFormData("uploaded_file", file1.getName(), requestFile);
MultipartBody.Part body2 =
MultipartBody.Part.createFormData("uploaded_file", file2.getName(), requestFile2);
Call<Result> resultCall=service.uploadMultipleImage(body,body2,2,1);
Log.v("####WWE","REquest "+resultCall.toString());
Log.v("###WWE","Retrofit Request Method = "+resultCall.request().method());
Log.v("###WWE","Retrofit Request Body = "+resultCall.request().body());
Log.v("###WWE","Retrofit Request Url = "+resultCall.request().url());
final Result[] result = {new Result()};
resultCall.enqueue(new Callback<Result>() {
#Override
public void onResponse(Call<Result> call, Response<Result> response) {
progressDialog.dismiss();
Log.v("###WWE","Respnse");
result[0] =response.body();
Log.v("###WWE","Response Result "+result[0].getResult());
if(response.isSuccessful()){
Toast.makeText(UploadMultipleImageActivity.this,"Sucess",Toast.LENGTH_SHORT).show();
Toast.makeText(UploadMultipleImageActivity.this,"Press Refresh Button",Toast.LENGTH_LONG).show();
supportFinishAfterTransition();
}
}
#Override
public void onFailure(Call<Result> call, Throwable t) {
progressDialog.dismiss();
Log.v("###WWE","Failure ");
Log.v("###WWE","MEssage "+t.getMessage());
}
});
I have included a link on my website to download images. When I click on the link I would like the download to automatically start.
Currently when I click on the link I’m getting back the response message: Example:
StatusCode: 200, ReasonPhrase: 'OK', Version: 1.1, Content: System.Net.Http.PushStreamContent, Headers: { Content-Type: application/octet-stream Content-Disposition: attachment; filename=895621d7-57a4-47a5-8dc5-ae36a2623826Banneraaaaaaaa.jpg }
How do I modify the code below to start the download automatically. I think I might be returning the wrong type:
Here is my code:
public HttpResponseMessage DownloadImageFile(string filepath)
{
filepath = "https://mysite.com/" + filepath;
try
{
var response = new HttpResponseMessage();
response.Content = new PushStreamContent((Stream outputStream, HttpContent content, TransportContext context) =>
{
try
{
DownloadFile(filepath, outputStream);
}
finally
{
outputStream.Close();
}
});
response.Content.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue("application/octet-stream");
response.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment");
response.Content.Headers.ContentDisposition.FileName = Path.GetFileName(filepath);
return response;
}
catch (Exception ex)
{
}
return null;
}
public void DownloadFile(string file, Stream response)
{
var bufferSize = 1024 * 1024;
using (var stream = new FileStream(file, FileMode.Open, FileAccess.Read))
{
var buffer = new byte[bufferSize];
var bytesRead = 0;
while ((bytesRead = stream.Read(buffer, 0, bufferSize)) > 0)
{
response.Write(buffer, 0, bytesRead);
}
response.Flush();
}
}
}
You should use one of the Controller.File overload. The File() helper method provides support for returning the contents of a file. The MediaTypeNames class can be used to get the MIME type for a specific file name extension.
For example:
public FileResult Download(string fileNameWithPath)
{
// Option 1 - Native support for file read
return File(fileNameWithPath, System.Net.Mime.MediaTypeNames.Application.Octet, Path.GetFileName(fileNameWithPath));
// Option 2 - Read byte array and pass to file object
//byte[] fileBytes = System.IO.File.ReadAllBytes(fileName); return
//File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet,
//fileName);
}
I have already try to understand the API doc, the articles about them, and this post: How do you create a Stream in Dart
I'm making a simple web app using WebSocket. Actually, it's working well, but I want add a feature (enjoy learn).
This is my class (can be optimized I guess)
library Ask;
import 'dart:html';
import 'dart:async';
import 'dart:convert';
class Ask {
final String addr;
String _protocol;
String _port;
WebSocket _ws;
bool openned;
Map<int, Completer> _completer_list = {};
int _counter = 0;
static final Map<String, Ask> _cache = <String, Ask>{};
factory Ask(String addr) {
if (_cache.containsKey(addr)) {
return _cache[addr];
} else {
final ask_server = new Ask._internal(addr);
_cache[addr] = ask_server;
return ask_server;
}
}
Ask._internal(this.addr);
Future<bool> open() {
if (openned)
return true;
_completer_list[0] = new Completer();
if (window.location.protocol == 'http:') {
_port = ':8080/ws';
_protocol = 'ws://';
} else {
_port = ':8443/ws';
_protocol = 'wss://';
}
_ws = new WebSocket(_protocol + addr + _port);
_ws.onOpen.listen((e) {
_get_data();
_get_close();
openned = true;
_completer_list[0].complete(true);
});
return _completer_list[0].future;
}
Future<String> send(Map data) {
bool check = false;
int id;
_completer_list.forEach((k, v) {
if (v.isCompleted) {
id = data['ws_id'] = k;
_completer_list[k] = new Completer();
_ws.send(JSON.encode(data));
check = true;
}
});
if (!check) {
_counter++;
id = data['ws_id'] = _counter;
_completer_list[id] = new Completer();
_ws.send(JSON.encode(data));
}
return _completer_list[id].future;
}
void _get_data() {
_ws.onMessage.listen((MessageEvent data) {
var response = JSON.decode(data.data);
_completer_list[response['ws_id']].complete(response);
});
}
void _get_close() {
_ws.onClose.listen((_) {
print('Server have been lost. Try to reconnect in 3 seconds.');
new Timer(new Duration(seconds: 3), () {
_ws = new WebSocket(_protocol + addr + _port);
_get_data();
_get_close();
_ws.onOpen.listen((e) => print('Server is alive again.'));
});
});
}
}
Example of use:
void showIndex() {
Element main = querySelector('main');
Ask connect = new Ask('127.0.0.1');
Map request = {};
request['index'] = true;
connect.open().then((_) {
connect.send(request).then((data) {
main.setInnerHtml(data['response']);
});
});
}
I would replace the then by a listen who will be canceled when the message will completed. By this way, I can add a progress bar, I think...
So my question, my send function can be a stream and keep my concept of one websocket for all ? (yes, if my function is used when a request is in progress, it's sent and if she's finish before the first, I recovered her properly. Thank you ws_id).
Thank you.
I think what you need is a StreamController
https://api.dartlang.org/apidocs/channels/stable/dartdoc-viewer/dart-async.StreamController