I am trying to repeat the words for N times but different N value for each items.
For example in this picture is the desired output:
My current formula for this but I don't know how to make the N value into unique
=ARRAYFORMULA(FLATTEN(IF(SEQUENCE(1,C3),B3:B1000)))
Try below formula-
=QUERY(ArrayFormula(FLATTEN(SPLIT(REPT(A1:A3&"#",B1:B3),"#"))),"where Col1 is not null")
Related
In Google Sheets, I am trying to count the last 4 entries of specific text entries in one row that matches the text criteria based of another cell.
A
B
C
D
E
F
G
H
I
J (criteria)
K (results
X
Y
X
Y
Y
X
X
2
Criteria in cell J would be X, and results in cell K would be 2 (H+D).
Criteria for Y could also be set somewhere, and results would be 2(G+E).
The sample data must be only the last four entries in the row. As additional data is entered, the formula must account for only using the last four entries.
Anyone have a solution?
Thanks!!
Try
=ArrayFormula(countif(query(transpose({(A2:I2);column(A2:I2)}),"select Col1 where Col1 is not null order by Col2 desc limit 4"),J2))
I have 2 columns of numbers, the idea is to find the first & last value in column L that respects a criterion and return the value from the same row in column K.
As the criterion is "higher than 99% of the max value in column L", I tried the MINIFS formula, but I cannot use this as a criterion.
I guess the solution will include the MATCH, INDEX formula but I cannot find the right combination
In this specific example, we want to return the value of the first column that has in column L a number higher than 0,99*max(L3:L62)(=3.0879...) so it should return 19
This will be verified for a couple rows until the value goes below the 99% again. This last row is 58.
Link to sheet :
https://docs.google.com/spreadsheets/d/1MUkYDPoR1NxB8qWcYr_2Fp91FgUbnUOpfGd7EUuWCOg/edit?usp=sharing
You can also try the following:
For first value
=Index(K3:K62;Min(IFERROR(1/(1/((Row(K3:K62)*(L3:L62>0,99*max(L3:L62)))))))-2)
For last value
=Index(K3:K62;Max(IFERROR(1/(1/((Row(K3:K62)*(L3:L62>0,99*max(L3:L62)))))))-2)
Try
=query({K3:L62};"select Col1 where Col2 > "&substitute(to_text(0,99*MAX(L3:L62));",";".")&" limit 1";0)
query as app script needs US notation in values (dot instead of comma)
to get the last row
=query({K3:L62};"select Col1 where Col2 > "&SUBSTITUTE(to_text(0,99*MAX(L3:L62));",";".")&" order by Col1 desc limit 1";0)
I have 2 tables resulting from the query formulas
formula1
=query(BuchungSystem!A2:AZ,"Select C, F, H, I, J, K, L where Q = "& $B$10)
formula2
=arrayformula({{"MWST ",""}} & QUERY(query(BuchungSystem!A2:AZ,"Select M, N, L where Q = "& $B$10),"SELECT Col1*100, SUM(Col2) GROUP BY Col1, Col3 LABEL SUM(Col2) '' , Col1*100 ''"))
and the result is shown as below
I need to combine 2 ranges since the number of rows in table1 keeps changing and so in table2. Since both are query formulas, they would not expand if the underlying cells have data. To avoid such issues, I am thinking both tables can be joined together with 2 empty lines between tables.
I have tried to join the query result ranges using {formula1;formula2} but it gives me an error since both tables have differing columns. How can I merge the tables one below other?
Mind sharing an example sheet? Here is a quick example of how to include empty columns to make the ranges equal in column size.
={{QUERY(G1:K4,"SELECT G,H,I,J,K")};{"","","","",SUM(QUERY(G1:K4,"SELECT G,H,I,J,K"))}}
If you use 6 columns in one range and only 2 in the next, then you need 4 empty columns in the second {} so their sizes remain the same.
I have simple table that looks like this:
All i need is to SUM points for specific player (John) in his last 3 matches.
I was able to come with this formula:
SUMPRODUCT(LARGE((A2:B="John")*(C2:D);{1;2;3}))
The problem is that instead of what I was looking for, it sums the highest 3 values, that can be anywhere in that range.
Is there some similar formula, that can do only the last 3 matches?
I think a SUMPRODUCT can get you there with some constructed arrays using a COUNTIFS() and ROW() to get the most recent 3.
This formula:
=SUMPRODUCT((COUNTIFS(A:B,G2,ROW(A:B)*{1,1},">="&ROW(A:B)*{1,1})<=3)*(A:B=G2),C:D)
on this sheet I made seems to work.
I thnk I have a formula that gives what you want. It's not pretty, and I'm sure it can be made simpler, but this works:
=query( query(
{ arrayformula( {ROW(A1:A) } ),
query(A1:D,"select A, B, C, D",1)
} , "select * order by Col1 desc",1),
"select Col2, Col3, Col4, Col5
where (Col2 ='John' or Col3 = 'John')
order by Col1 desc limit 3",1)
Basically, it adds the row number as an extra column to the data, so that we can sort the data in reverse order by row number. Then we query the result to find the first three occurences of 'John', in either Col A or Col B.
Here is a sample sheet:
https://docs.google.com/spreadsheets/d/1-mhTb5Cpp3D-1OltlmCfwlmM-vc2OknHxfJAyHD7BjI/edit?usp=sharing
Credit to Erik Tyler for a previous answer on a different question, on how to add the row number to a query.
Edit: Updated the sheet to provide the SUM of John's (or any player's) scores from the last three matches. This can be combined with the previous formula, if you want a single formula to place somewhere. Or will you have a list of all the players, and you'll want their last three scores beside each of their names?
If I can simplify the formula, I'll update it here.
Let me know if you need something more than this, or if this has answered your question.
Approach
I would use the query formula to get the cells that you need so that you can leverage the limit statement.
You should put a column with the indexes so that you can order the cells in descending order and take the first 3.
Given that your table headers are:
+-----------------------------------------------+
| INDEX | NAME 1 | NAME 2 | POINTS 1 | POINTS 2 |
+-----------------------------------------------+
I would use this query to get your desired result:
=SUMPRODUCT(QUERY(A2:E, "Select D * E where B = 'John' or C = 'John'" order by A desc limit 3"))
I'm looking for solution for my problem. I have a sheet to summarize lap times for some competition. We make 3 laps in each qualification. We are qualifying to finals by 2 best laps one after another. So we sum first and second lap or second and third lap and then choose the smallest one sum. I've managed to get array of pairs and filter out empty cells (run not finished). Number of pairs may vary form 1 to 20.
Now is my question. How to find the smallest sum of pairs from my array in one elegant formula?
Here is my sample sheet: example sheet
=QUERY(QUERY({A17:B17;B17:C17;D17:E17;E17:F17;G17:H17;H17:I17};
"select Col1+Col2
where Col1 is not NULL
and Col2 is not NULL");
"select min(Col1)
label min(Col1)''")
I know this isn't exactly your question and fair play if it gets marked down, but in your quest for an 'elegant formula', I was wondering if there was a more general way to get the pairs in the first place.
You can do it with by using two ranges offset by one cell together with the mod of the column number:
=ArrayFormula(query(
query({transpose({A17:H17;B17:I17;mod(column(A17:H17),3)})},"select Col1+Col2 where Col1 is not null and Col2 is not null and Col3>0")
,"select min(Col1) label min(Col1) ''"))