I can't display String from API to View - ios

Question

I tried to store the text in a variable of API
in the class
I do not want to transfer the entire model, I want to transfer the text as it is here
class Api : ObservableObject{
#Published var title : String = ""
#Published var details : String = ""
func getDataModelApi () {
guard let url = URL(string: APIgetURL.demo) else { return }
var request = URLRequest(url: url)
let token = "38|xxxxx"
request.setValue("Bearer \(token)", forHTTPHeaderField: "Authorization")
URLSession.shared.dataTask(with: request) { data, responce, err in
guard let data = data else { return }
do {
let dataModel = try JSONDecoder().decode([model].self, from: data)
for i in dataModel {
DispatchQueue.main.async {
self.title = i.title
self.details = i.details
}
}
} catch {
print("error: ", error)
}
}
.resume()
}
}
In the title variable, the value was stored successfully, but the display in the view does not get anything
struct ContentView: View {
#StateObject var model3 = Api()
var body: some View {
VStack {
Text(model3.title)
}
.onAppear() {
Api().getDataModelApi()
}
}
}
Here in getData, it shows the complete model and needs a link, which I want to access from getDataModelApi
#Published var models : [model] = []
func getData (url : String) {
guard let url = URL(string: url) else { return }
var request = URLRequest(url: url)
let token = "38|xxx"
request.setValue("Bearer \(token)", forHTTPHeaderField: "Authorization")
URLSession.shared.dataTask(with: request) { data, responce, err in
guard let data = data else { return }
do {
let dataModel = try JSONDecoder().decode([model].self, from: data)
DispatchQueue.main.async {
self.models = dataModel
}
} catch {
print("error: ", error)
}
}
.resume()
}

Answer 1

You are using two different instances of Api and you throw away the second one in onAppear.
Replace
.onAppear() {
Api().getDataModelApi()
}
With
.onAppear() {
model3.getDataModelApi()
}