Docker Copy files with wildcard keep folder structure - docker

Question

I have the following project separated into packages as follows:
libs/one/package.json
libs/one/index.js
libs/two/package.json
libs/two/index.js
package.json
I am looking for a way to copy all libs/*/package.json files in one line. in addition I want to avoid reinstalling all packages again and reading them from the cache.
this is my docker file
FROM node:16.14-alpine as base
RUN npm install -g lerna#4.0.0
WORKDIR /usr/app
FROM base as builder
ARG SERVICE_DIR
ARG TSCONFIG_BUILD_FILE
COPY .npmrc .
COPY lerna.json .
COPY ${TSCONFIG_BUILD_FILE} ./tsconfig.build.json
COPY package*.json ./
# copy package dependencies
COPY libs/service-http-handler/package.json ./libs/service-http-handler/
COPY libs/utils/package.json ./libs/utils/
COPY libs/commons/package.json ./libs/commons/
COPY libs/cache/package.json ./libs/cache/
COPY libs/internal-dto/package.json ./libs/internal-dto/
COPY libs/clients/package.json ./libs/clients/
COPY ${SERVICE_DIR}/package.json ./${SERVICE_DIR}/
# install service and package dependencies
RUN lerna bootstrap -- --production --no-optional --ignore-scripts --include-dependencies --scope ${SERVICE_DIR}
# Copy all libs and build by dependency order
COPY libs/ ./libs
COPY ${SERVICE_DIR}/ ./${SERVICE_DIR}
RUN lerna run build --include-dependencies --scope $(echo ${SERVICE_DIR} | cut -d'/' -f 2)
# copy recursive and follow symbolic link
RUN cp -RL ./node_modules/ /tmp/node_modules/
# Runner
FROM base
ARG SERVICE_DIR
# copy runtime dependencies
COPY --from=builder /tmp/node_modules/ ./node_modules/
# Copy runtime service
COPY --from=builder /usr/app/${SERVICE_DIR}/dist/ ./dist/
COPY ./${SERVICE_DIR}/package.json ./
EXPOSE 5001
#TODO - modify start script in production mode
CMD ["npm", "run", "start"]
any idea how I can do it without the need to run the step below on any changes in libs sources files.
RUN lerna bootstrap -- --production --no-optional --ignore-scripts --include-dependencies --scope ${SERVICE_DIR}