I am using location to access the current temperature in my app. I got the weather temperature but I need only double value from it.
let weatherTemp = "41.7°C"
The required thing is:
weatherTemp = 41.7
How can I do that? I used:
extension Double {
static func parse(from string: String) -> Double? {
return Double(string.components(separatedBy: CharacterSet.decimalDigits.inverted).joined())
}
}
This prints all the digits but not the decimal. I need the decimal too.
Split the string on the '°' and convert the first part to Double
if let tempString = weatherTemp.split(separator: "°").first, let temp = Double(tempString) {
print(temp)
}
Related
I am getting some coordinates from server in string array. And I am trying to save those coordinates in SQLite Database by splitting and converting them to double value. But some coordinates are getting saved in scientific notations. For example I am getting the following coordinate from server:
"-0.0000558,51.3368066"
I am splitting the string and converting it to double resulting in the following values:
[-5.58e-05,51.3368066]
I have tried following solutions but still returning same result:
1.
Double(latLongArr[0])
extension String{
var doubleValue: Double? {
return NumberFormatter().number(from: self)?.doubleValue
}
}
extension String{
var doubleValue: Double? {
let numberFormatter = NumberFormatter()
numberFormatter.allowsFloats = true
numberFormatter.maximumFractionDigits = 10
numberFormatter.numberStyle = .decimal
return numberFormatter.number(from: "\(self)")!.doubleValue
}
}
I have used the above code but it still returns in scientific format but I need it in normal decimal format. So what is the issue?
The last option is the option I would go for and I believe it works right.
I believe your issue is only when you print to console:
As you can see, the double variable is actually converted properly but just when it is formatted to print to the console it shows it as a scientific notation string.
Your other option besides using doubleValue is to use decimalValue
I suggest putting a breakpoint and checking the actual value of your double than reviewing it from the console output which is a formatted string.
Just for reference, code used in the image above:
let number = "-0.0000558"
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = .decimal
numberFormatter.maximumFractionDigits = 10
let finalNumber = numberFormatter.number(from: number)
let decimalNumber = finalNumber!.decimalValue
let doubleNumber = finalNumber!.doubleValue
print(decimalNumber)
print(doubleNumber)
If you want to print your Doubles without scientific notation use
String(format: "%.7f", value).
Example:
let value = Double(3.141592)
print(String(format: "%.7", value)
will print 3.1415920.
I have used the below extension to represent scientific values in the decimal format.
extension String {
func getDecimalValue() -> Decimal{
return NSNumber(value: Double(self)!).decimalValue
}
}
Usage:
let numberString = "+5.58e-05"
print(numberString.getDecimalValue()) //0.0000558
I managed to convert a NSDecimalNumber to a hex String using BInt library. Here is my code:
public func toDecimalHex(value: NSDecimalNumber) -> String{
let bint = BInt(value.stringValue)
return (bint?.asString(radix: 16))!
}
example:
let number = NSDecimalNumber(string: "1000000000000000000000000")
let hex = toDecimalHex(value: number)
//result : d3c21bcecceda1000000
Basically, how can I convert without using any library like BInt? This brings too much overhead. I just want to get rid of it.
I am trying to use an iOS app to dial a number. The problem is that the number is in the following format:
po placeAnnotation.mapItem.phoneNumber!
"+1 (832) 831-6486"
I want to get rid of some special characters and I want the following:
832-831-6486
I used the following code but it did not remove anything:
let charactersToRemove = CharacterSet(charactersIn: "()+-")
var telephone = placeAnnotation.mapItem.phoneNumber?.trimmingCharacters(in: charactersToRemove)
Any ideas?
placeAnnotation.mapItem.phoneNumber!.components(separatedBy: CharacterSet.decimalDigits.inverted)
.joined()
Here you go!
I tested and works well.
If you want something similar to CharacterSet with some flexibility, this should work:
let phoneNumber = "1 (832) 831-6486"
let charsToRemove: Set<Character> = Set("()+-".characters)
let newNumberCharacters = String(phoneNumber.characters.filter { !charsToRemove.contains($0) })
print(newNumberCharacters) //prints 1 832 8316486
I know the question is already answered, but to format phone numbers in any way one could use a custom formatter like below
class PhoneNumberFormatter:Formatter
{
var numberFormat:String = "(###) ### ####"
override func string(for obj: Any?) -> String? {
if let number = obj as? NSNumber
{
var input = number as Int64
var output = numberFormat
while output.characters.contains("#")
{
if let range = output.range(of: "#", options: .backwards)
{
output = output.replacingCharacters(in: range, with: "\(input % 10)")
input /= 10
}
else
{
output.replacingOccurrences(of: "#", with: "")
}
}
return output
}
return nil
}
func string(from number:NSNumber) -> String?
{
return string(for: number)
}
}
let phoneNumberFormatter = PhoneNumberFormatter()
//Digits will be filled backwards in place of hashes. It is easy change the custom formatter in anyway
phoneNumberFormatter.numberFormat = "###-##-##-##-##"
phoneNumberFormatter.string(from: 18063783889)
Swift 3
func removeSpecialCharsFromString(_ str: String) -> String {
struct Constants {
static let validChars = Set("1234567890-".characters)
}
return String(str.characters.filter { Constants.validChars.contains($0) })
}
To Use
let str : String = "+1 (832) 831-6486"
let newStr : String = self.removeSpecialCharsFromString(str)
print(newStr)
Note: you can add validChars which you want in string after operation perform.
If you have the number and special character in String format the use following code to remove special character
let numberWithSpecialChar = "1800-180-0000"
let actulNumber = numberWithSpecialChar.components(separatedBy: CharcterSet.decimalDigit.inverted).joined()
Otherwise, If you have the characters and special character in String format the use following code to remove special character
let charactersWithSpecialChar = "A man, a plan, a cat, a ham, a yak, a yam, a hat, a canal-Panama!"
let actulString = charactersWithSpecialChar.components(separatedBy: CharacterSet.letters.inverted).joined(separator: " ")
NSString *str = #"(123)-456-7890";
NSLog(#"String: %#", str);
// Create character set with specified characters
NSMutableCharacterSet *characterSet =
[NSMutableCharacterSet characterSetWithCharactersInString:#"()-"];
// Build array of components using specified characters as separtors
NSArray *arrayOfComponents = [str componentsSeparatedByCharactersInSet:characterSet];
// Create string from the array components
NSString *strOutput = [arrayOfComponents componentsJoinedByString:#""];
NSLog(#"New string: %#", strOutput);
Basically, I have a Float, for example: 3.511054256.
How can I extract n number of digits after the decimal point?
i.e. I'd like to retrieve 0.51, 0.511, 0.5110 or etc.
I know I can easily achieve something like this:
var temp: Float = 3.511054256
var aStr = String(format: "%f", temp)
var arr: [AnyObject] = aStr.componentsSeparatedByString(".")
var tempInt: Int = Int(arr.last as! String)!
However, this gives me 511054. I'd like the option of retrieving any number of digits past the decimal point easily.
For a task I'm doing, I only need to retrieve the first 2 digits after the decimal point, but less restriction would be ideal.
Thanks.
You can specify the number of decimal digits, say N, in your format specifier as %.Nf, e.g., for 5 decimal digits, %.5f.
let temp: Float = 3.511054256
let aStr = String(format: "%.5f", temp).componentsSeparatedByString(".").last ?? "Unexpected"
print(aStr) // 51105
Alternatively, for a more dynamic usage, make use of an NSNumberFormatter:
/* Use NSNumberFormatter to extract specific number
of decimal digits from your float */
func getFractionDigitsFrom(num: Float, inout withFormatter f: NSNumberFormatter,
forNumDigits numDigits: Int) -> String {
f.maximumFractionDigits = numDigits
f.minimumFractionDigits = numDigits
let localeDecSep = f.decimalSeparator
return f.stringFromNumber(num)?.componentsSeparatedByString(localeDecSep).last ?? "Unexpected"
}
/* Example usage */
var temp: Float = 3.511054256
var formatter = NSNumberFormatter()
let aStr = getFractionDigitsFrom(temp, withFormatter: &formatter, forNumDigits: 5)
print(aStr) // 51105
Note that both solutions above will perform rounding; e.g., if var temp: Float = 3.519, then asking for 2 decimal digits will produce "52". If you really intend to treat your float temp purely as a String (with no rounding whatsoever), you could solve this using just String methods, e.g.
/* Just treat input as a string with known format rather than a number */
func getFractionDigitsFrom(num: Float, forNumDigits numDigits: Int) -> String {
guard let foo = String(temp).componentsSeparatedByString(".").last
where foo.characters.count >= numDigits else {
return "Invalid input" // or return nil, for '-> String?' return
}
return foo.substringWithRange(foo.startIndex..<foo.startIndex.advancedBy(numDigits))
}
/* Example usage */
let temp: Float = 3.5199
let aStr = getFractionDigitsFrom(temp, forNumDigits: 2) // 51
Is there a way to create random unique IDs similar to the YouTube IDs in Swift?
I know there are similar answers on this link, but they are for Php. But I want something in Swift.
I have tried using timestamp and UUIDs, but I want an alphanumeric short keys which would be around 4-10 characters so users can easily share with others verbally.
Thanks.
Looking for just a unique string
You can use UUIDs they're pretty cool:
let uuid = NSUUID().UUIDString
print(uuid)
From the docs
UUIDs (Universally Unique Identifiers), also known as GUIDs (Globally
Unique Identifiers) or IIDs (Interface Identifiers), are 128-bit
values. UUIDs created by NSUUID conform to RFC 4122 version 4 and are
created with random bytes.
Some info about uuid: https://en.wikipedia.org/wiki/Universally_unique_identifier
Looking for a more specific length
Try something like this:
func randomStringWithLength(len: Int) -> NSString {
let letters : NSString = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
let randomString : NSMutableString = NSMutableString(capacity: len)
for _ in 1...len{
let length = UInt32 (letters.length)
let rand = arc4random_uniform(length)
randomString.appendFormat("%C", letters.character(at: Int(rand)))
}
return randomString
}
But i'll keep my answer incase someone else stumbles upon this looking for a UUID
This will allow you to create a random short code. It can create codes from Hexadecimal all the way to base 62 codes and of varying lengths.
aka.
let myCode = ShortCodeGenerator.getCode(length: 6)
3dH7t8,
fdE7j1,
Gl6jKd,
Hv8gU3,
let myBase32Code = ShortCodeGenerator.getCode(withBase: UInt32(32), length: 6)
3HF75J,
J67N9D,
B47SO3,
L9SD2N
You would have to check for redundancy and then create a new one if it has already been used.
struct ShortCodeGenerator {
private static let base62chars = [Character]("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz".characters)
private static let maxBase : UInt32 = 62
static func getCode(withBase base: UInt32 = maxBase, length: Int) -> String {
var code = ""
for _ in 0..<length {
let random = Int(arc4random_uniform(min(base, maxBase)))
code.append(base62chars[random])
}
return code
}
}
This answer was useful in creating the above code and also has good
information on the number of unique identifiers you can have with each base number and length.
The total number of unique identifiers you need can be calculated by the equation:
BaseNumber^length = # of unique IDs
EDIT:
I have added even more functionality for converting Int's and NSDate's to shortcodes for my own project as well and put those into a project on GitHub.
Updated for swift 3:
If you want to generate Short Random Unique alphanumeric keys, used below lines of codes;
//function defination:
func generateTransactionId(length: Int) -> String {
var result = ""
let base62chars = [Character]("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz".characters)
let maxBase : UInt32 = 62
let minBase : UInt16 = 32
for _ in 0..<length {
let random = Int(arc4random_uniform(UInt32(min(minBase, UInt16(maxBase)))))
result.append(base62chars[random])
}
return result
}
//function call:
let mTranactionId = self.generateTransactionId(length: 5) // you can change the value of length as you want
print("mTranactionId: \(mTranactionId)")
Ex: Result looks like: XHA7K, QTC92, MS1PT, YE2PV
//Enjoy coding...!
Does NSUUID().UUIDString do what you need?
I'm very pleased with NanoID.
https://github.com/ai/nanoid
...and here's the SWIFT version:
https://github.com/antiflasher/NanoID
You just need to drag 1 file (NanoID.swift) into your project, and you are good to go!
TAGS: Short GUID, Short UUID, Short Unique ID, Swift, iOS
Swift custom alternative(these version doesn't check for duplicate char):
func randomString(length: Int) -> String {
let letters = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789")
var randomString: String = ""
for _ in 0..<length {
let randomNumber = Int.random(in: 0..<letters.count)
randomString.append(letters[randomNumber])
}
return randomString
}
You can archive this just using UUID.
If you don't want the whole string, as any String in Swift, you select a small portion of the string by using range, like this:
let text = UUID().uuidString
let index = text.index(text.startIndex, offsetBy: 8)
let small = text[text.startIndex..<index]
Notice 8 is the length of string I suggested, you can improve this by clamping this value using min(size, text.count) for example.
And finally, small is a Substring, to cast it to String just cast as usual - String(small)
Swift 5 version using a String extension
extension String {
static func random(length: Int) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
return String((0..<length).compactMap { _ in
letters.randomElement()
})
}
}