Group Child Nodes based on Specific Condition - xslt-2.0

Question

I have been having trouble transforming below xml using XSLT 2.0. Could anyone help me resolve this please? Thanks
Input XML
<?xml version="1.0" encoding="UTF-8"?>
<Root>
<Row>
<EmployeeID>88888</EmployeeID>
<Remote/>
<StartDate>2014-10-19</StartDate>
<EndDate>2021-10-08</EndDate>
<Amount>100</Amount>
<BasePay>760</BasePay>
<Bonus>340</Bonus>
</Row>
<Row>
<EmployeeID>12345</EmployeeID>
<Remote/>
<StartDate>2017-10-10</StartDate>
<EndDate>2018-10-10</EndDate>
<Amount>250</Amount>
<BasePay>1500</BasePay>
<Bonus>150</Bonus>
</Row>
<Row>
<EmployeeID>23456</EmployeeID>
<Remote>N</Remote>
<StartDate/>
<EndDate></EndDate>
<Amount></Amount>
<BasePay>1500</BasePay>
<Bonus>150</Bonus>
</Row>
<Row>
<EmployeeID>23456</EmployeeID>
<Remote>N</Remote>
<StartDate/>
<EndDate>2020-10-10</EndDate>
<Amount>2400</Amount>
<BasePay>1500</BasePay>
<Bonus/>
</Row>
<Row>
<EmployeeID>23456</EmployeeID>
<Remote>N</Remote>
<StartDate>2018-10-24</StartDate>
<EndDate>2020-10-10</EndDate>
<Amount>2400</Amount>
<BasePay>1500</BasePay>
<Bonus/>
</Row>
<Row>
<EmployeeID>12345</EmployeeID>
<Remote/>
<StartDate>2017-10-10</StartDate>
<EndDate>2018-10-10</EndDate>
<Amount>350</Amount>
<BasePay>1600</BasePay>
<Bonus>170</Bonus>
</Row>
<Row>
<EmployeeID>65432</EmployeeID>
<Remote>Y</Remote>
<StartDate/>
<EndDate></EndDate>
<Amount></Amount>
<BasePay>1500</BasePay>
<Bonus>150</Bonus>
</Row>
<Row>
<EmployeeID>65432</EmployeeID>
<Remote>Y</Remote>
<StartDate>2021-10-25</StartDate>
<EndDate>2020-10-10</EndDate>
<Amount>8400</Amount>
<BasePay>1500</BasePay>
<Bonus/>
</Row>
</Root>
Desired Output
<?xml version="1.0" encoding="UTF-8"?>
<Root>
<Row>
<EmployeeID>88888</EmployeeID>
<Remote/>
<StartDate>2014-10-19</StartDate>
<EndDate>2021-10-08</EndDate>
<Amount>100</Amount>
<BasePay>760</BasePay>
<Bonus>340</Bonus>
</Row>
<Row>
<EmployeeID>12345</EmployeeID>
<Remote/>
<StartDate>2017-10-10</StartDate>
<EndDate>2018-10-10</EndDate>
<Amount>250</Amount>
<BasePay>1500</BasePay>
<Bonus>150</Bonus>
</Row>
<Row>
<EmployeeID>23456</EmployeeID>
<Remote>N</Remote>
<StartDate>2018-10-24</StartDate>
<EndDate>2020-10-10</EndDate>
<Amount>2400</Amount>
<BasePay>1500</BasePay>
<Bonus>150</Bonus>
</Row>
<Row>
<EmployeeID>12345</EmployeeID>
<Remote/>
<StartDate>2017-10-10</StartDate>
<EndDate>2018-10-10</EndDate>
<Amount>350</Amount>
<BasePay>1600</BasePay>
<Bonus>170</Bonus>
</Row>
<Row>
<EmployeeID>65432</EmployeeID>
<Remote>Y</Remote>
<StartDate>2021-10-25</StartDate>
<EndDate>2020-10-10</EndDate>
<Amount>8400</Amount>
<BasePay>1500</BasePay>
<Bonus>150</Bonus>
</Row>
</Root>
Grouping needs to be based on <Remote> element with value either Y or N.
For e.g. Employee 23456 appears thrice in the input xml with <Remote>set to N – Result xml is expected to have Employee 23456 only once but expected to pick up values for StartDate(i.e 2018-10-24) EndDate (i.e 2020-10-10) Amount(i.e. 2400)
For e.g. Employee 65432 appears twice in the input xml with value <Remote> set to Y – Result xml is expected to have Employee 65432 only once but expected to pick up values for StartDate (i.e 2021-10-25) EndDate (i.e 2020-10-10) Amount (8400)
Employee 12345 appears twice in the input xml with blank value for <Remote> - Result xml is expected to have Employee 12345 twice because <BasePay> and <Bonus> amounts are different.
Below is my attempt
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="xml" indent="yes"></xsl:output>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/Root">
<xsl:copy>
<xsl:for-each-group select="Row" group-by="EmployeeID/[Mobile='Y' or 'N']">
<Row>
<EmployeeID>
<xsl:value-of select="EmployeeID"/>
</EmployeeID>
<Remote>
<xsl:value-of select="Remote"/>
</Remote>
<StartDate>
<xsl:value-of select="StartDate"/>
</StartDate>
<EndDate>
<xsl:value-of select="EndDate"/>
</EndDate>
<Amount>
<xsl:value-of select="Amount"/>
</Amount>
<BasePay>
<xsl:value-of select="BasePay"/>
</BasePay>
<Bonus>
<xsl:value-of select="Bonus"/>
</Bonus>
</Row>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

Answer 1

Perhaps (using a composite grouping key as possible in XSLT 3)
<xsl:template match="/Root">
<xsl:copy>
<xsl:for-each-group select="Row" composite="yes" group-by="EmployeeID, Remote = ('Y', 'N')">
<xsl:choose>
<xsl:when test="current-grouping-key()[2]">
<xsl:apply-templates select="."/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
Or using a composite key and then a match pattern that removes/strips the duplicates is easier to preserve the original order:
<xsl:key name="group" match="Root/Row" composite="yes" use="EmployeeID, Remote = ('Y', 'N')"/>
<xsl:template match="Root/Row[. intersect key('group', (EmployeeID, true()))[position() > 1]]"/>
<xsl:output method="xml" indent="yes"/>
<xsl:mode on-no-match="shallow-copy"/>
As for your comment about empty children, perhaps
<xsl:template match="Root/Row[. intersect key('group', (EmployeeID, true()))[1]]">
<xsl:copy>
<xsl:for-each-group select="key('group', (EmployeeID, true()))/*[node()]" group-by="node-name()">
<xsl:apply-templates select="."/>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
ensures the non-empty child elements in a group of Rows are output instead of the child elements of the first item in a group.
An online sample is here.