A contractor I'm working with wants to give us a small bonus based on any "overtime" work we may or may not have done. Problem is, we didn't exactly keep a log of any activity we did outside of normal working day hours. I'm trying to use my Jira activity as a starting point. How can I track any and all activity (leaving a comment, changing a status, assigning the ticket to someone else, etc) conducted by me within certain hours, within certain dates.
For example, any and all activity conducted by me between the hours of 7PM - 8AM from February 3, 2021 to January 15, 2022.
You can get it from the Jira database.
For any activity, you can use following SQL query for retrieve any change in a project:
SELECT p.pname, p.pkey, i.issuenum, cg.ID, cg.issueid, au.lower_user_name, cg.AUTHOR, cg.CREATED, ci.FIELDTYPE, ci.FIELD, ci.OLDVALUE, ci.OLDSTRING, ci.NEWVALUE, ci.NEWSTRING
FROM changegroup cg
inner join jiraissue i on cg.issueid = i.id
inner join project p on i.project = p.id
inner join changeitem ci on ci.groupid = cg.id
inner join app_user au on cg.author = au.user_key
WHERE p.pkey = '<PROJECT_KEY>'
order by 1,3,4;
You can modify that query by filtering cg.CREATED in order to get activity between certain dates.
NOTE: Query can be changed depend on your database.
NOTE2: You can look that Atlassian link for further information.
Related
JIRA has an excellent ability to search issues with workLog items created in specific date and by a specific user. For example:
worklogDate > 2017-04-01 AND worklogDate < 2017-05-01 AND worklogAuthor = some-user
In this search result I can see a column Time Spent - it's a total time spent on a task. How can I aggregate time from workLogs only for selected days? For example, we worked on the task in Mar and April. How to write JQL to calculate only April's time.
It is possible?
To get the time spent by the user by tasks, if you have access to the database, you can run this query:
select wl.timeworked, wl.worklogbody, wl.updateauthor, wl.updated,
u.display_name, ji.summary,
concat(concat(p.pkey,'-'),ji.issuenum) as IssueKey
from worklog wl
inner join cwd_user u
on wl.updateauthor = u.user_name
inner join jiraissue ji
on ji.id = wl.issueid
inner join project p
on (ji.project = p.id)
where issueid in (
select j.ID
from jiraissue j
inner join project p
on (j.project = p.id)
where u.user_name = 'userid')
Replace the userid with the userid of the person that submitted the worklog. Take note that for each JIRA ticket (issue), there can be multiple worklog submission by different user. This will give you every worklog submitted by the userid and it will also show you which ticket (issue) they are for. You can add in the date constraint in the where clause if you want to just query for specific timeframe. The unit of measurement for the timeworked column is in second as recorded by JIRA.
According to Time Since Issues Report if JIRA's Documentation, Time Spend is the amount of time spent on the issue. This is the aggregate amount of time that has been logged against this issue. Are you looking to aggregate the time of one person in different issues?
I am trouble figuring out the proper syntax to structure this query correctly. I am trying to show ALL records from both the SalesHistoryDetail AND from the SalesVsBudget table. I believe my query allows for some of the records on SalesVsBudget to not be pulled, whereas I want them all for that period, regardless of whether there was a corresponding sale. Here is my code:
SELECT MAX(a.DispatchCenterOrderKey) AS DispatchCenter,
a.CustomerKey,
CASE WHEN a.CustomerKey IN
(SELECT AddressKey
FROM FinancialData.dbo.DimAddress
WHERE AddressKey >= 99000 AND AddressKey <= 99599) THEN 1 ELSE 0 END AS InterCompanyFlag,
MAX(a.Customer) AS Customer,
a.SalesmanID,
MAX(a.Salesman) AS Salesman,
a.SubCategoryKey,
MAX(a.SubCategoryDesc) AS Subcategory,
SUM(a.Value) AS SalesAmt,
b.FiscalYear AS Year,
b.FiscalWeekOfYear AS Week,
MAX(c.BudgetLbs) AS BudgetLbs,
MAX(c.BudgetDollars) AS BudgetDollars
FROM dbo.SalesHistoryDetail AS a
LEFT OUTER JOIN dbo.M_DateDim AS b ON a.InvoiceDate = b.Date
FULL OUTER JOIN dbo.SalesVsBudget AS c ON a.SalesmanID = c.SalesRepKey
AND a.CustomerKey = c.CustomerKey
AND a.SubCategoryKey = c.SubCategoryKey
AND b.FiscalYear = c.Year AND b.FiscalWeekOfYear = c.WeekNo
GROUP BY a.SalesmanID, a.CustomerKey, a.SubCategoryKey, b.FiscalYear, b.FiscalWeekOfYear
There are two different data sets that I am pulling from, obviously the SalesHistoryDetail table and the SalesVsBudget table. I'm hoping to get ALL budgetLbs, and BudgetDollars values from the SalesVsBudget table regardless of whether they match in the join. I want all of the matching joining records too, but I also want EVERY record from SalesVsBudget. Essentially I want to show ALL sales records and I want to reference the budget values from SalesVsBudget when the salesman,customer,subcategory, year and week match but I also want to see budget entries that fall in my date range that don't have corresponding sales records in that period. Hopefully that makes sense. I feel I am very close, but my budget numbers doesn't reflect the whole story and I think that is because some of my records are being excluded! Please help.
I was able to accomplish this through playing with the FULL OUTER JOIN. My problems was there were more records in SalesVsBudget than SalesHistory_V. Therefore I had to make SalesVsBudget the initial FROM table and SaleHistory_V with a FULL OUTER JOIN and all records lined up.
I am having problems joining three tables in report builder 3.0. I have experimented with various joins and can not achieve the desired result.
PLACES
place ref,
address,
place type (place type = 1)
JOBS
place ref,
description,
cost,
job number,
JOBS INFO
job number,
date comp (date comp = 25/12/2015)
I need all places with place type 1.
Then I need to link all jobs completed 25/12/2015 by job number and then link these to places on place ref.
The first problem I have is despite which join I chose to link places to jobs and jobs info all I get is the places which have had jobs. I need to also show the places that haven't.
Also the database sometimes contains duplicate jobs so I only need to display the same job number once.
Any help with this would be much appreciated!
You need a LEFT JOIN when PLACES is your master table :
SELECT * FROM PLACES p
LEFT OUTER JOIN (select distinct * from Jobs j
INNER JOIN Jobs_Info ji ON(j.job_number = ji.job_number)
WHERE ji.date_comp = '25/12/2015') t
ON(p.place_ref = t.place_ref)
WHERE p.place_type = 1
I have a problem to which I can't seem to find a simple solution.
I want to achieve the following:
* i have a list of tasks, each with an owner and a due date
* i want to display a list of all tasks grouped by owner
* i want to sort the owners based on the due dates: e.g. The owner with the lowest due date first, followed by the owner with the second lowest, etc
* I want to be able to paginate the results, preferable with will_paginate
To ilustrate, this would be a result i am looking for:
Harry
- task 1, due date 1
- task 3, due date 4
Ben
- task 2, due date 2
Carol
- task 4, due date 3
So far, I can query for all owners with tasks, sort them on a virtual attribute with their "earliest due date" and then display them and their tasks in a view.
There are multiple problems with this approach, imo:
* i run multiple queries from the view (owner.tasks.each etc). I always learned that running queries from the view is bad
* i'm doing the sorting by loading all records in memory (virtual attribute), which could get problematic with large records set.
* I have no idea how i can get pagination in on this, that will be sensitive to the amount of tasks displayed
I can't seem to crack this nut, so any help or hints would be greatly appreciated!
Erwin
Try this query, you have not provided sample data (ideally using SQL) so that we could play ourselves:
SELECT
u.id as owner_id, u.name as owner_name, t.id, t.due_date
FROM users u
INNER JOIN tasks m ON u.id = m.owner_id
INNER JOIN tasks t ON u.id = t.owner_id
GROUP BY u.id, u.name, t.id, t.due_date
ORDER BY MIN(m.due_date), t.due_date
You should get all the data you need in the proper order, and you can paginate simply by applying LIMIT to it (or converting it to AR and submitting it to will_paginate).
I have two tables - tool_downloads and tool_configurations. I am trying to retrieve the most recent build date for each tool in my database. The layout of the DB is simple. One table called tool_downloads keeps track of when a tool is downloaded. Another table is called tool_configurations and stores the actual data about the tool. They are linked together by the tool_conf_id.
If I run the following query which omits dates, I get back 200 records.
SELECT DISTINCT a.tool_conf_id, b.tool_conf_id
FROM tool_downloads a
JOIN tool_configurations b
ON a.tool_conf_id = b.tool_conf_id
ORDER BY a.tool_conf_id
When I try to add in date information I get back hundreds of thousands of records! Here is the query that fails horribly.
SELECT DISTINCT a.tool_conf_id, max(a.configured_date) as config_date, b.configuration_name
FROM tool_downloads a
JOIN tool_configurations b
ON a.tool_conf_id = b.tool_conf_id
ORDER BY a.tool_conf_id
I know the problem has something to do with group-bys/aggregate data and joins. I can't really search google since I don't know the name of the problem I'm encountering. Any help would be appreciated.
Solution is:
SELECT b.tool_conf_id, b.configuration_name, max(a.configured_date) as config_date
FROM tool_downloads a
JOIN tool_configurations b
ON a.tool_conf_id = b.tool_conf_id
GROUP BY b.tool_conf_id, b.configuration_name