So, I have a spreadsheet with a column of barcodes that should be 6 digits long, like this A02938 (a letter with 5 numbers after it), but sometimes another digit is added by mistake, turning it into something like this A024938. So, my question is this...
How can I highlight the cell if it contains more than 6 digits?
Thanks for your help.
Go to Format > Conditional Formatting
In apply to range select the column where you have the barcodes.
For example (A:A)
In format rules, select the dropdown-menu option Custom formula is and add
=LEN(A:A) > 6
Choose the formatting style you prefer below
Related
I have 2 columns one with letters A,B,C and other one with number 1,2,3. If I want to only see those letters whose corresponding numbers are less than 3, I would =filter(O39:O41,P39:P41<3). It works.
If I change second column to dates, this breaks. =filter(O39:O41,P39:P41<1/3) tells me No matches are found in FILTER evaluation.
Please help :)
You can wrap it up in date or use something relative to date like =filter(range, date_range< TODAY(), date_range> TODAY()-50)
I have a sheet containing my weekly schedule. Only school cells have a room number in it, so how do I format the cells to color only the ones that contain a number.
note: Actually, the room number is a number in range(A:E) followed by a three digits number in range(000:499). Ex.:(A433, B166, D254)
I tried: Text contains"(A:F)(000:444)" but it didn't work.
EDIT:
For some reason, "=REGEXMATCH(B2, "[A-F][0-9]{3}")" worked. Could anyone tell me why? I tried replacing B2 by B1, but then it didn't work. Does it have anything to do with the fact that B1 is a weekday, and so does not contain REGEXP(B1,"[A-F][0-9]{3}) returned false.
What seemed more logical to me was "=REGEXMATCH(B2:F22, "[A-F][0-9]{3}")" To apply this function in range B2 to F22. What am I missing here?
In order to match patterns, you'll need to use regular expressions. Since the standard Conditional Formatting options don't include regular expressions, you'll need to choose "Custom formula is" and then use REGEXMATCH, which returns a Boolean value.
If you really want to look for the specific room number format you mentioned, then you would use the formula:
=REGEXMATCH(A1, "[A-E][0-9]{3}")
But if you just want to look for any numbers, you can use
=REGEXMATCH(A1, "[0-9]+")
In both cases, the text you're checking is in cell A1
You might try Conditional Formatting with a custom formula rule of the type:
=if(isnumber(A1),1,regexmatch(A1,"\d"))
The above was an attempt to respond to:
Google spreadsheets conditional formatting if text contains numbers
A more particular fit for the stated room number style would be:
=REGEXMATCH(A1,"[A-F]\d\d\d")
where the first character is any of the first six letters of the alphabet, if capitalised, followed by three instances of any number.
Greeting
I'm sorry for the intrusion, but I have a question that seems no one asked before.
I want to know if there is a formula for Conditional Formatting in spreadsheet to highlight certain cell, if a duplicate of certain text came in sequence in the same row.
A B C D E F
26 27 28 29 30
deni V X X V X
In the above example, I want to highlight the name "deni" when there are 2 "X"'s that came in sequence, which was the case at the 27 and 28 date.
Is there any formula for this? I have tried =OR(B2=C2,C2=D2) but it only works for 2 cells (B2&C2) with any text (not the "X" only).
Here is an example of the spreadsheet
PS: i'm sorry, i used excel tag before. but i need this formula to work in google spreadsheet. my bad, sorry
Conclusion: My Question have been answered, i used both formulas from I'-'I and Tom Sharpe and it worked like a charm. Many thanks to the people that responded My Question :)
=SUMPRODUCT((D2:AG2="x")*(E2:AH2="x"))
Apply to:
A2:A
Also
=countifs(D2:AG2,"x",E2:AH2,"x")
If you want to check if there is a duplicate text (not the "X"), you can use:
=IF(SUM(COUNTIF(D2:AH2,D2:AH2))>COUNTA(D2:AH2),1,0)
1 means true, 0 means false. This is because if there is at least one duplicate text, the sum of all the texts' appearance times will greater than the count of all the texts (if not they will be equal).
To be highlight a certain cell, here is deni, you can use Conditional Formatting -> Highlight Cell Rules -> More Rules -> use a formula to datemine which cells to format, and then paste the formula above in the cell.
Step1:Select the range of cells you want to apply conditional formatting to.
Step2:On the Home tab, click Conditional Formatting.
Step3:Point to Highlight Cells Rules, Go on More Rules...
Step4:Choose Use a formula... Paste the following one,
=SUMPRODUCT(COUNTIF(C3:G3,C3:G3)-1)>0
Step5:Format how you want to highlight
Step6:Click OK and Apply
Hope this helps you.
Note: Change the range in the formula as per your data.
I'm trying to sort a list of documents, but I'm having an issue with the documents that have a letter as a suffix.
Whenever we amend a document we add a letter to the end of the number, but when I sort by number in excel it sorts like this:
1
2
3
10
11
1606
1603D
1605B
1606A
1606C
1610A
1623A
20A
220B
390A
399A
402A
415A
450A
488A
557B
How can I make it sort in order of document number and amendment?
Like so:
1
2
3
10
11
1603D
1605B
1606
1606A
1606C
1610A
1623A
20A
220B
390A
399A
402A
415A
450A
488A
557B
As long as you have a mix of text and number, you won't be able to use Excel's built-in sort to achieve the result you describe.
If you append a letter to a number you effectively change the data type from number to text. Text will always be sorted after any number, hence the number 1606 comes before the text 1606A.
You could try to make all values real text, maybe indicate levels by appending digits with dots, like this:
1.
1.0.
1.1.
1.6.0.3.D
1.6.0.5.B
1.6.0.6.
1.6.0.6.A
1.6.0.6.C
1.6.1.0.A
1.6.2.3.A
2.
2.0.A.
2.2.0.B.
3.
3.9.0.A.
3.9.9.A.
4.0.2.A.
4.1.5.A.
4.5.0.A.
4.8.8.A.
5.5.7.B.
But even that does not give you the sort order you describe as the desired result.
Your desired sort order will be hard to achieve even if all values are text, or if you replace the A, B, C with a decimal .1, .2, .3. -- It's really hard to understand why 20 would come after 1623.
The solution I found was to add a column, and copy this formula into each cell:
=IF(ISNUMBER(--RIGHT(A2)),A2,LEFT(A2,LEN(A2)-1))
The formula removes the letters from the numbers, you can then sort your sheet using the new column of clean numbers.
I have 5 columns of numbers that I want to sort per row into another set of columns. I figured I need to use small() (e.g. small(a2:e2,1) for f2; small(a2:e2,2) for g2 and so on). Is there away to iterate this for the next rows; if possible using only native google spreadsheet formulas?
Thanks in advance
I was able to make a temporary work around, but I had to use 3 cheat columns. It looks ok for now but I imagine it will be troublesome for really huge numbers.
Here's a sample sheet for reference: https://docs.google.com/spreadsheets/d/1MQTP2XkRsPRAnPQ5wLhkR8JoNVY6YOExVlOkkX8UeRs/edit#gid=0
The original data are in A3:E
The first cheat column (G3:G) simply creates a column of numbers from 1 to the largest number found in the source data. 1-9 is changed to 01-09 for easier searching. "#" is then added at the end-this will come handy later:
Cheat Column 1 =filter(if(row(A:A)=max(A:E)+1,ʺ#ʺ,text(row(A:A),ʺ00ʺ)),row(A:A)<=max(A:E)+1)
The second cheat column (H3:H) combines each row into a string separated by "-" with a "#" marker:
Cheat Column 2=filter(text(A3:A,ʺ00ʺ)&ʺ-ʺ&text(B3:B,ʺ00ʺ)&ʺ-ʺ&text(C3:C,ʺ00ʺ)&ʺ-ʺ&text(D3:D,ʺ00ʺ)&ʺ-ʺ&text(E3:E,ʺ00ʺ)&ʺ#ʺ,A3:A<>ʺʺ)
The last cheat column (I3:I) sorts each line (from cheat column 2) by finding each number from cheat column from 01 up to the max number, then the "#" char (this ensures that each line will still have the # end marker). "Find" will return the "position" of each number or an error if it's not found. By using "if", we can make "find" return the actual number or "" instead.
=filter(arrayformula(if(iferror(find(transpose(filter(G3:G,G3:G<>ʺʺ)),H3:H),ʺʺ), transpose(filter(G3:G,G3:G<>ʺʺ)),ʺʺ)),A3:A<>ʺʺ)
The formula above creates as many columns as there are numbers from cheat column 1. To prevent this, a "-" is added to each number then "Concatenate" is used to combine everything into one massive string with each set separated by "#". The string is then split using the "#" marker.
Cheat Column 3 =transpose(split(concatenate(filter(arrayformula(if(iferror(find(transpose(filter(G3:G,G3:G<>ʺʺ)),H3:H),ʺʺ),ʺ-ʺ&transpose(filter(G3:G,G3:G<>ʺʺ)),ʺʺ)),A3:A<>ʺʺ)),ʺ#ʺ))
Each number is then separated into each corresponding column by using mid().
Small 1 =filter(mid(I3:I,2,2)*1,A3:A<>ʺʺ)
Small 2 =filter(mid(I3:I,5,2)*1,A3:A<>ʺʺ)
Small 3 =filter(mid(I3:I,8,2)*1,A3:A<>ʺʺ)
Small 4 =filter(mid(I3:I,11,2)*1,A3:A<>ʺʺ)
Small 5 =filter(mid(I3:I,14,2)*1,A3:A<>ʺʺ)
Note that the formula above is only for numbers 1-99. For larger numbers, the Text() formulas should have more zeroes to correspond to the number of digits of the biggest number. The Mid() formulas should also be adjusted accordingly.
I would like to stress that I am very far from being a spreadsheet expert and that this solution is very "unoptimized". It requires several cheat columns; with the first one even having more rows than the original data. If anyone can help me get rid of the cheat columns (or at least the first one) I will be very grateful.
How about using SMALL like you mentioned in your question?
=small($A3:$E3,column()-columns($A3:$G3))
You will need to change the ranges accordingly. The last $G$3 is the cell just before the cell where the formula is placed.
Sample