I have the habit for years to use this very easy and convenient .BAT file to create a simple TXT file of all my files in a directory:
dir *.* > LIST.TXT
but the result includes many pieces of information that I don't need
Now I have many files in a directory in this way:
file 01 [shYddYJQIGfffY].xyz
second file 00008 [shYddYJQIfGf11dfzrffY].exe
filex [shGffY].sys
file that i don't need.txt
many other files that i don't need.bat
1/ which command line can I use with DIR (or anything else) to have in the final LIST.txt files only those information? only the value between [ and ]
Expected result:
shYddYJQIGfffY
shYddYJQIfGf11dfzrffY
shGffY
2/ how to edit the .BAT file to add the string MYRESULT before each of those results, like:
MYRESULT shYddYJQIGfffY
MYRESULT shYddYJQIfGf11dfzrffY
MYRESULT shGffY
Use a for loop (see for /?):
for /f "tokens=2 delims=[]" %%a in ('dir /b *[*].*') do echo MYRESULT %%a
This for /f loop takes the output of dir /b *[*].* (filtering for relevant files, bare format) line per line and splits it into three parts, first token the part before the first [, token2 the part between [ and ]. and a third part after that. You need the second token only. Then just echo the string together with the extracted substring, done.
Related
So as an early task at a new junior developer position I was asked to go through and update thousands of old parameter data types in various stored procs. I did all the updates and loaded them to the team server and now have to push them into our SQL server so they will compile.
Last night my boss eluded to how I could pull the modified procs into a directory, then use command line to copy all text and create a new txt file that could be opened in SQL to run a mass update basically in batch mode per database.
I have almost no command line experience, can someone give me a quick overview.
My Pseudocode:
Open command line window in my UpdatedProcs folder, copy text from all files in same directory, create new text file containing all of the text (name of new file doesn't matter). Then open in SQL, look for errors one last time, and finally run.
This seems simple but I know nothing about command line.
Thanks for your help.
Use a for /f loop. You don't even need to copy the files from the subdirectory first. This appends all of the text files in the Temp subfolder (C:\Test\Temp) into a file named summary.log in the current folder (C:\Test):
c:\Test>for /f "tokens=*" %a in ("dir temp\*.txt") do type %a >> .\summary.log
summary.log now contains all of the content of the text files in a single file. You can open it with Notepad or any other text editor.
To run from a batch file, simply change the %a to %%a in both places.
c:\Test>copy con mergefiles.bat
for /f "tokens=*" %%a in ("dir temp\*.txt") do type %%a >> .\summary.log
F6 or Ctrl+Z
c:\Temp>mergefiles
Enter
c:\Temp>notepad summary.log
Enter
I currently have an exported text file (output.txt) from a Clear-Case command that I need to parse. It looks like this:
Comparing the following:
R1.PROD.V1#\VOB_pvob
R2.PROD.V1#\VOB_pvob
Differences:
>> M:\ACME_PROD\src\ACME##
>> M:\ACME_PROD\src\ACME\file 2.txt##
>> M:\ACME_PROD\src\ACME\file 1.txt##
>> M:\ACME_PROD\src\ACME\file 3.txt##
What I would like to do is use the findstr command to filter the strings that are contained between the ">> " and "##" strings to get an output file that looks like this (with quotes if possible:
"M:\ACME_PROD\src\ACME"
"M:\ACME_PROD\src\ACME\file 2.txt"
"M:\ACME_PROD\src\ACME\file 1.txt"
"M:\ACME_PROD\src\ACME\file 3.txt"
I am new to writing batch files and so I don't exactly know where to start. I have managed to find code that can loop through the lines of a text file and separate code for the findstr command, but I get stuck trying to put it all together!
Best regards,
Andrew
Here you go
setlocal enabledelayedexpansion
for /f "skip=1 tokens=* delims=> " %%a in ('"findstr /r [\w^>*] output.txt"') do (
set line=%%a
set line=!line:#=!
echo "!line!" >>new.txt
)
The filtered strings will be outputted into new.txt.
I want to read a file a extract information from it based on certain tag. For example :
SCRIPT_NAME:mySimpleShell.sh
This is a simple shell. I would like to have this as
Description. I also want to create a txt file our of this.
SCRIPT_NAME:myComplexShell.sh
This is a complex shell. I would like to have this as
Description. I also want to create a txt file our of this.
So when I pass in this file to my shell script, my shell will read it line by line and
when it gets to SCRIPT_NAME, It extract it and save it in $FILE_NAME, then starts writing
the description to a file on disk with $FILE_NAME.txt name. And It does it until It reaches the end of file. If there is 3 SCRIPT_NAME tag, then it creates 3 description file.
Thanks for helping me in advance :)
Read the lines using a while loop. Use a regex to check if a line has SCRIPT_NAME and if so, extract the filename. This is shown below:
#! /bin/bash
while IFS= read -r line
do
if [[ $line =~ SCRIPT_NAME:(.*$) ]]
then
FILENAME="${BASH_REMATCH[1]}"
echo "Writing to $FILENAME.txt"
else
echo "$line" >> "$FILENAME.txt"
fi
done < inputFile
#!/bin/sh
awk '/^SCRIPT_NAME:/ { split( $0, a, ":" ); name=a[2]; next }
name { print > name ".txt" }' ${1?No input file specified}
I have the following values in a DOS batch file (for example...):
..\Apple\Jones
..\Banana\Smith
..\Pear\Wilson
I need to extract the last name values ("Jones", "Smith", "Wilson") from each value. What one technique can I use that will always give me these substring values?
According to this topic : What is the best way to do a substring in a batch file?
I suggest you to use
%~n0
I already wrote a function for that. You give it any path and it returns you only it's filename or pathname. Works for any path: Url, Windows path, Unix path, etc...
Copy this function at the end of your batch script: (Instructions below)
rem ===========================================================================
:Name_From_Path
SetLocal
set _TMP_FOLDERNAME=%1
for %%g in ("%_TMP_FOLDERNAME%") do set _TMP_FOLDERNAME=%%~nxg
EndLocal & set _Name_From_Path=%_TMP_FOLDERNAME%
goto :EOF
rem ===========================================================================
Usage:
CALL :Name_Of_Path ..\Apple\Jones
ECHO %_Name_From_Path%
Result: Jones
I need path to the folder that contains cmd file.
With %0 I can get the file name. But how to get the folder name?
c:\temp\test.cmd >> test.cmd
P.S. My current directory != folder of the script.
For the folder name and drive, you can use:
echo %~dp0
You can get a lot more information using different modifiers:
%~I - expands %I removing any surrounding quotes (")
%~fI - expands %I to a fully qualified path name
%~dI - expands %I to a drive letter only
%~pI - expands %I to a path only
%~nI - expands %I to a file name only
%~xI - expands %I to a file extension only
%~sI - expanded path contains short names only
%~aI - expands %I to file attributes of file
%~tI - expands %I to date/time of file
%~zI - expands %I to size of file
The modifiers can be combined to get compound results:
%~dpI - expands %I to a drive letter and path only
%~nxI - expands %I to a file name and extension only
%~fsI - expands %I to a full path name with short names only
This is a copy paste from the "for /?" command on the prompt.
Related
Top 10 DOS Batch tips (Yes, DOS Batch...) shows batchparams.bat (link to source as a gist):
C:\Temp>batchparams.bat c:\windows\notepad.exe
%~1 = c:\windows\notepad.exe
%~f1 = c:\WINDOWS\NOTEPAD.EXE
%~d1 = c:
%~p1 = \WINDOWS\
%~n1 = NOTEPAD
%~x1 = .EXE
%~s1 = c:\WINDOWS\NOTEPAD.EXE
%~a1 = --a------
%~t1 = 08/25/2005 01:50 AM
%~z1 = 17920
%~$PATHATH:1 =
%~dp1 = c:\WINDOWS\
%~nx1 = NOTEPAD.EXE
%~dp$PATH:1 = c:\WINDOWS\
%~ftza1 = --a------ 08/25/2005 01:50 AM 17920 c:\WINDOWS\NOTEPAD.EXE
The accepted answer is helpful, but it isn't immediately obvious how to retrieve a filename from a path if you are NOT using passed in values. I was able to work this out from this thread, but in case others aren't so lucky, here is how it is done:
#echo off
setlocal enabledelayedexpansion enableextensions
set myPath=C:\Somewhere\Somewhere\SomeFile.txt
call :file_name_from_path result !myPath!
echo %result%
goto :eof
:file_name_from_path <resultVar> <pathVar>
(
set "%~1=%~nx2"
exit /b
)
:eof
endlocal
Now the :file_name_from_path function can be used anywhere to retrieve the value, not just for passed in arguments. This can be extremely helpful if the arguments can be passed into the file in an indeterminate order or the path isn't passed into the file at all.
In order to assign these to variables, be sure not to add spaces in front or after the equals sign:
set filepath=%~dp1
set filename=%~nx1
Then you should have no issues.
In case anyone wants an alternative method...
If it is the last subdirectory in the path, you can use this one-liner:
cd "c:\directory\subdirectory\filename.exe\..\.." && dir /ad /b /s
This would return the following:
c:\directory\subdirectory
The .... drops back to the previous directory.
/ad shows only directories
/b is a bare format listing
/s includes all subdirectories. This is used to get the full path of the directory to print.
I had same problem in my loop where i wanted to extract zip files in the same directory and then delete the zip file. The problem was that 7z requires the output folder, so i had to obtain the folder path of each file. Here is my solution:
FOR /F "usebackq tokens=1" %%i IN (`DIR /S/B *.zip` ) DO (
7z.exe x %%i -aoa -o%%i\..
)
%%i was a full filename path and %ii\.. simply returns the parent folder.
hope it helps.
In case the accepted answer by Wadih didn't work for you, try echo %CD%
This was put together with some edited example cmd
#Echo off
Echo ********************************************************
Echo * ZIP Folder Backup using 7Zip *
Echo * Usage: Source Folder, Destination Drive Letter *
Echo * Source Folder will be Zipped to Destination\Backups *
Echo ********************************************************
Echo off
set year=%date:~-4,4%
set month=%date:~-10,2%
set day=%date:~-7,2%
set hour=%time:~-11,2%
set hour=%hour: =0%
set min=%time:~-8,2%
SET /P src=Source Folder to Backup:
SET source=%src%\*
call :file_name_from_path nam %src%
SET /P destination=Backup Drive Letter:
set zipfilename=%nam%.%year%.%month%.%day%.%hour%%min%.zip
set dest="%destination%:\Backups\%zipfilename%"
set AppExePath="%ProgramFiles(x86)%\7-Zip\7z.exe"
if not exist %AppExePath% set AppExePath="%ProgramFiles%\7-Zip\7z.exe"
if not exist %AppExePath% goto notInstalled
echo Backing up %source% to %dest%
%AppExePath% a -r -tzip %dest% %source%
echo %source% backed up to %dest% is complete!
TIMEOUT 5
exit;
:file_name_from_path <resultVar> <pathVar>
(
set "%~1=%~nx2"
exit /b
)
:notInstalled
echo Can not find 7-Zip, please install it from:
echo http://7-zip.org/
:end
PAUSE
IMHO the simplest yet most powerful method to get the full path of a file is:
Start Notepad
Copy and Paste the following text:
#echo %1 | clip 3
Save the file as "CopyAsPath.bat"
Now you can either
drag a file over that batch
or
copy it into your SendTo menu folder (%USERPROFILE%\AppData\Roaming\Microsoft\Windows\SendTo)
Whether you follow the option 1 or the option 2, one millisecond later you can either
"press Ctrl-V"
or
use "Right Mouse Click -> Paste"
to paste the full path+filename wherever you want.
Simple, powerful, and without using any external Windows tool.