I have created a sheet that generate random math questions. I'm having issue create automated answers.
google sheet concat not working
issue example 2
How do I get the result in F6? In another word, how do I get 111 in F6 instead of the math 30+81"?
If you want to get the sum of the two numbers you must use the SUM() formula in the cell you want it to get the result.
The SUM() formula is used as follows:
=SUM(number_1,number_2,number_3...)
In your case the formula would be:
=SUM(B6,D6)
After your comment:
You can use the IFS formula, its a bit tricky but it would work.
The syntaxis is this:
IFS(condition1, value1, condition2, value2, …)
To do what you want you should implement something like this:
=IFS(C6="-"; B6-D6; C6="+"; B6+D6;C6="/"; B6/D6; C6="*"; B6*D6)
This formula will check the cell operator and depending on it will perform one action or another.
You may try QUERY() function with a helper column, like this-
=query(,"Select "&D1&" label "&D1&" ''",0)
Alternatively, without a helper column, the formula would be-
=query(,"Select "&A1&B1&C1&" label "&A1&B1&C1&" ''",0)
Related
I'm trying to use vloookup or index/match in Google sheets to pull and plug in a query formula, rather than just its resulting value.
For example, I'm trying to use this vlookup formula:
=ArrayFormula(IFERROR(VLOOKUP(A2:A100,'SMS VLOOKUP'!A2:$B$500,2,0),""))
to plug in the formula:
=QUERY(courtdates,"SELECT D, C, BO, H WHERE BO = date '"&TEXT(TODAY()-1,"yyyy-mm-dd")&"'",0)
As I understand, you want to take formula from one place using vlookup and then use it in other place? Something like eval or evaluate() ?
The first part is possible using FORMULATEXT(cell) but you can't convert text of the formula into actual formula. Nothing like this using formulas.
The only way is using a script.
I'd like to run a =SUM(A1:G1), but always skip one column, regardless if it has value or not.
In this case, it should calculate A1+C1+E1+G1.
Is there another function I could append to SUM() or other similar functions as SUM in order to skip one column?
Thank you!
Using the following method you can calculate any number of alternate columns, without the need of manual +
Suppose your data is in second row onwards, use this formula
=SUMPRODUCT(A2:G2, MOD(COLUMN(A2:G2),2))
Simply a sumproduct of cell values and a array of {1,0,1,0,1...}
Another slight variation
=SUMPRODUCT(A2:G2*ISODD(COLUMN(A2:G2)))
But if the even columns contain letters instead of numbers this will give an error, so you can use instead
=SUMPRODUCT(N(+A1:G1)*ISODD(COLUMN(A1:G1)))
Comparing #AnilGoyal's answer, this works as well
=SUMPRODUCT(A1:G1,--ISODD(COLUMN(A1:G1)))
You can use:
=SUM(INDEX(A1:G1,N(IF(1,{1,3,5,7}))))
Or with Excel O365:
=SUM(INDEX(A1:G1,{1,3,5,7}))
A bit more of a general solution:
=SUMPRODUCT(MOD(COLUMN(A1:G1),2)*A1:G1)
Or with Excel O365:
=SUM(MOD(COLUMN(A1:G1),2)*A1:G1)
Or even:
=SUM(INDEX(1:1,SEQUENCE(4,,1,2)))
Since you included Google-Sheets, I'll throw in an option using QUERY():
=SUM(QUERY(TRANSPOSE(1:1),"Select * skipping 2"))
Maybe a bit more verbose, but very understandable IMO.
Consider something of the format:
=SUM(A1:G1)-INDEX(A1:G1,2)
The 2 in the formula means remove the 2nd item in the part of the row. (so the 999 is dropped)
So the formula =SUM(BZ10:ZZ10)-INDEX(BZ10:ZZ10,2) drops CA10 from the sum, etc.(a similar formula can be constructed for columns)
google sheets:
=INDEX(MMULT(N(A1:H3), 1*ISODD(SEQUENCE(COLUMNS(A:H)))))
=INDEX(IF(ISODD(COLUMN(A:H)), TRANSPOSE(MMULT(TRANSPOSE(
IFERROR(A1:H3*ISODD(COLUMN(A:H)), 0)), 1^ROW(A1:A3))), ))
I am trying to use substitute function inside a query function but not able to find the correct syntax to do that. My use case is as follows.
I have two columns Name and Salary. Values in these columns have comas ',' in them. I want to import these two columns to a new spreadsheet but replace comas in "Salary" column with empty string and retain comas in "Name" column. I also want to apply value function to "Salary" column after removing comas to do number formatting.
I tried with the following code but it is replacing comas in both the columns. I want a code which can apply the substitute function only to a subset of columns.
Code:
=arrayformula(SUBSTITUTE(QUERY(IMPORTRANGE(Address,"Sheet1!A2:B5"),"Select *"),",",""))
Result:
Converted v/s Expected Result
Note :
I have almost 10 columns to import and comas should be removed from 3 of them.
Based on your suggestions, I was able to achieve the objective by treating columns separately. Below is the code.
=QUERY({IMPORTRANGE(Address,"Sheet1!A3:A5"),arrayformula(VALUE(SUBSTITUTE(IMPORTRANGE(Address,"Sheet1!B3:B5"),",","")))},"Select * where Col2 is not null")
Basically, two IMPORTRANGE functions side by side for each column.
The same query on the actual data with 10 columns will look like this.
=QUERY({IMPORTRANGE(Address,"Sheet1!A3:C"),arrayformula(VALUE(SUBSTITUTE(IMPORTRANGE(Address,"Sheet1!D3:H"),",",""))),IMPORTRANGE(Address,"Sheet1!I3:J")},"Select * where Col2 is not null")
I used 3 IMPORTRANGE functions so that I can format the columns D to H by removing comas and changing them to number.
My suggestion is to use 2 formulas and more space in your sheets.
Formula #1: get the data and replace commas:
=arrayformula(SUBSTITUTE(IMPORTRANGE(Address,"Sheet1!A2:B5"),",",""))
Formula #2: to convert text into numbers:
=arrayformula (range_of_text_to_convert * 1)
Notes:
using 2 formulas will need extra space, but will speed up formulas (importrange is slow)
the second formula uses math operation (*1) which is the same as value formula.
Try this. I treats the columns separately.
=arrayformula(QUERY({Sheet1!A2:A5,SUBSTITUTE(Sheet1!B2:B5,",","")},"Select *"))
Thanks to Ed Nelson, I was able to figure out this:
=arrayformula(QUERY({'Accepted Connections'!A:R,SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE('Accepted Connections'!A:R,"AIF®",""),"APA",""),"APMA®",""),"ASA",""),"C(k)P®",""),"C(k)PS",""),"CAIA",""),"CBA",""),"CBI",""),"CCIM",""),"","")},"Select *"))
That removed all the text I didn't need in specific columns.
Does anybody know how to arrayformula this join function?
My formula is not as complex as the example here. ArrayFormula a Filter in a Join (Google Spreadsheets)
It does not contain a filter function, so I'm not sure what from that answer applies and doesn't apply.
I want to array formula this: =if(isblank(B2),,join("," ,B2:I2))
Using the normal way to array something doesn't work:
=ArrayFormula(if(isblank(B2:b),,join(",",B2:b:I2:i)))
Also for splits, I have split(B2, ",")
=ArrayFormula(split(B2:B,",")) does nothing but the first row
Maybe try:
=ArrayFormula(if(len(B2:B), B2:B&C2:C&D2:D&E2:E&F2:F&G2:G&H2:H&I2:I,))
or
=ArrayFormula(substitute(transpose(query(transpose(B2:I),,rows(B2:B)))," ",""))
or, in case you want a space between the concatenated values:
=ArrayFormula(trim(transpose(query(transpose(B2:I),,rows(B2:B)))))
For using split() in arrayformula a workaround can be found here
I have a data set that looks like this: starting on A1 with "1"
1 a
2 b
3 c
4 d
Column A is an arrayformula =arrayformula(row(b1:b))
Column B is manual input
i want to query the database and finding the row of the item by match column B so i have code as such
=query("A1:B","select A where B like '%c%')
this should give me "3"
My question:
is there a way to pull the 1-4 numbers into the query line? with something like array formula row(b1:b). I don't want to waste an extra column on column A
so basically I want just the manual input and when i query it gives me the row number.
No script code please.
I've tried a few things and it didn't work.
Looking for a solutions that starts with
=query()
You can also use a formula to pull in more than one row in the dataset which matches the condition, if this is important to you:
=arrayformula(filter(row(B:B); B:B="c"))
And you can have wildcard type operators, under certain circumstances (you are going to match text or items that can look like text (so numbers can be treated as text - but boolean will need more steps); that the dataset is not huge), using regular expressions. e.g.
=arrayformula(filter(row(B:B); regexmatch(B:B, "(c|d)")))
You could also use standard spreadsheet wildcard operators, e.g.
=arrayformula(filter(row(B:B); countif(B:B, "*c*")))
Explanation: In this case, the filter will be true when countif is greater than zero, i.e. when it sees something with a letter c in it, since spreadsheets see a value greater than zero as a boolean true and so, for that row where there is a countif match, there will be a a filter match, and so it will display that row (indeed, it is a similar situation with the regexmatch creating a true when there is a match of either c or d, in the case above).
Personally, I wanted to learn regex a bit, so I would go towards the regexmatch option. But that is your choice.
You can also, of course, create the match outside of the cell. This makes it easy to create a list of matches that you want to satisfy elsewhere on the sheet. So you could have a column of words or parts of words, from Z2 downwards, and then join them together in cell Z1 for example like this
="("&join("|",filter(Z2:Z50,len(Z2:Z50)))&")"
Then your filter function would look like this:
=arrayformula(filter(row(B:B), regexmatch(B:B, Z1)))
If you want to use like operator in the query function, you can try something like this:
=arrayformula(query(if({1,0}, B:B,row(B:B)),"select Col2 where Col1 like '%c%' "))
You can also use the regular expressions in the query function, for example:
=arrayformula(query(if({1,0}, B:B,row(B:B)),"select Col2 where Col1 matches '(.*c.*|.*d.*)' "))
I'm not entirely clear on the question, but as I understand it, you want to be able to enter a formula, and have it return the row number of the matched item in a range? I'm not sure where array formulas come in.
If I've understood your question correctly, this should do the trick:
=MATCH("C",B1:B,0)
In your example, this returns 3.
Please forgive me if I've misunderstood your question.
Note: If there are multiple matches, this will return the row number for the first instance of your search.
=QUERY({A1:A,ARRAYFORMULA(ROW(A1:A))},"SELECT Col2 WHERE Col1 LIKE '%c%'")