How do I correctly perform a for-loop that returns as a f-string (like in Python.)
For example,
for i=10, 1, -1 do
test = string.gsub('checkbox[val = "a"]','a', i)
return test
end
Returns
checkbox[v10l = "10"]
However, I was expecting:
checkbox[val = "1"]
checkbox[val = "2"]
..
..
checkbox[val = "10"]
I'm honestly not sure what are you trying to do here. Lua has no supports for f-strings and you're trying to return multiple times from function?
This is probably the closest to what you want:
for i=1, 10 do
print(string.format('checkbox[val = "%d"]', i))
end
You're doing the following:
Running for loop from 10 to 1, in opposite direction of what you want.
Replacing all occurrences of string a in checkbox[val = "a"] with loop variable, giving you resulting string and assigning that to (global, which is not good) variable test.
Returning string you just got, thus exiting loop and function that contains loop.
If you're trying to pass multiple values from loop to the outside world, you can do one of the following:
Add them into table and return it:
local tab = {}
for i=1, 10 do
tab[i] = string.format('checkbox[val = "%d"]', i)
end
return tab
Accept callback, so caller passes in a function to call on each value:
function example(cb)
for i=1, 10 do
cb(string.format('checkbox[val = "%d"]', i))
end
end
example(print) -- Here, we pass `print` as a callback, but it's usually your own function
Choose whatever better suits your particular interface.
Related
Edited for more details:
I'm trying to have a turtle that is sitting in front of a sapling wait for it to grow before cutting it down. It compares the log to the item in front until it matches. The system I'm currently using works, but I was hoping there was a slightly more minimal way to write it.
checkTarget = {
forward = function(tgt)
check = {turtle.inspect()} --creates table with first as boolean, second as information table
local rtn = {false, check[2]}
if type(tgt) == "table" then
for k, v in pairs(tgt) do
if check[2].name == v then
rtn = {true, v}
break
end
end
elseif tgt == nil then
return check[1]
elseif check[2].name == tgt then
rtn[1] = true
end
return rtn
end,--continued
This takes an argument, either a string or an array of strings, to compare against. When it checks the block in front it saves the detailed information to the second element in rtn and the first to a default of false. If the string matches the checked block's name, then it changes rtn[1] to true and returns all of it, which is the table at the bottom when doing checkTarget.forward("minecraft:log").
My question was, I am currently making a disposable variable to store the array that is returned from checkTarget, and then calling the variable's first element to get if it's true or not. I was hoping there was a way to include it in the if statement without the disposable variable (tempV)
repeat
local tempV = fox.checkTarget.forward("minecraft:log")
if tempV[1] then
cut()
fox.goTo({x = 0, y = 0, z = 0})
fox.face(0)
end
tempV = fox.checkTarget.forward("minecraft:log")
until not run
{
false,
{
state = {
stage = 0,
type = "birch",
},
name = "minecraft:sapling",
metadata = 2
}
}
Instead of
local tempV = fox.checkTarget.forward("minecraft:log")
if tempV[1] then
end
You can do
if fox.checkTarget.forward("minecraft:log")[1] then
end
and then calling the variable's first element to get if it's true or
not.
With tempV[1] you're not calling the first element, you're indexing it.
To call something you have to use the call operator () which doesn't make sense as a boolean is not callable.
I am confused about the difference between function calls via . and via :
> x = {foo = function(a,b) return a end, bar = function(a,b) return b end, }
> return x.foo(3,4)
3
> return x.bar(3,4)
4
> return x:foo(3,4)
table: 0x10a120
> return x:bar(3,4)
3
What is the : doing ?
The colon is for implementing methods that pass self as the first parameter. So x:bar(3,4)should be the same as x.bar(x,3,4).
For definition it is exactly the same as specifying self manually - it will even produce same bytecode on compilation. I.e. function object:method(arg1, arg2) is same as function object.method(self, arg1, arg2).
On use : is almost the same as . - a special kind of call will be used internally to make sure object and any possible side-effects of calculations/access are calculated only once. Calling object:method(arg1, arg2) is otherwise same as object.method(object, arg1, arg2).
To be completely precise, obj:method(1, 2, 3) is the same as
do
local _obj = obj
_obj.method(_obj, 1, 2, 3)
end
Why the local variable? Because, as many have pointed out, obj:method() only indexes _ENV once to get obj. This normally just important when considering speed, but consider this situation:
local tab do
local obj_local = { method = function(self, n) print n end }
tab = setmetatable({}, {__index = function(idx)
print "Accessing "..idx
if idx=="obj" then return obj_local end
end})
end
tab.obj.method(tab.obj, 20)
--> Accessing obj
--> Accessing obj
--> 20
tab.obj:method(10)
--> Accessing obj
--> 10
Now imagine the __index metamethod did more than just printing something. Imagine it increased a counter, logged something to a file or deleted a random user from your database. There's a big difference between doing that twice or only once. In this case, there's a clear difference between obj.method(obj, etc) and obj:method(etc).
I have created a function that (pseudo)randomly creates a table containing numbers. I then loop this function until at least correct result is found. As soon as I've confirmed that at least one such result exists, I stop the function and return the table.
When I create tables containing small values, there are no issues. However, once the random numbers grow to the range of hundreds, the function begins to return nil, even though the table is true the line before I return it.
local sort = table.sort
local random = math.random
local aMin, aMax = 8, 12
local bMin, bMax = 200, 2000
local function compare( a, b )
return a < b
end
local function getNumbers()
local valid = false
local numbers = {}
-- Generate a random length table, containing random number values.
for i = 1, random( aMin, aMax ) do
numbers[i] = random( bMin, bMax )
end
sort( numbers, compare )
-- See if a specific sequence of numbers exist in the table.
for i = 2, #numbers do
if numbers[i-1]+1 == numbers[i] or numbers[i-1] == numbers[i] then
-- Sequence found, so stop.
valid = true
break
end
end
for i = 1, #numbers-1 do
for j = i+1, #numbers do
if numbers[j] % numbers[i] == 0 and numbers[i] ~= 1 then
valid = true
break
end
end
end
if valid then
print( "Within function:", numbers )
return numbers
else
getNumbers()
end
end
local numbers = getNumbers()
print( "Outside function:", numbers )
This function, to my understanding, is supposed to loop infinitely until I find a valid sequence. The only way that the function can even end, according to my code, is if valid is true.
Sometimes, more often than not, with large numbers the function simply outputs a nil value to the outside of the function. What is going on here?
You're just doing getNumbers() to recurse instead of return getNumbers(). This means that if the recursion gets entered, the final returned value will be nil no matter what else happens.
In the else case of the if valid then, you are not returning anything. You only return anything in the valid case. In the else case, a recursive call may return something, but then you ignore that returned value. The print you see is corresponding to the return from the recursive call; it isn't making it out the original call.
You mean to return getNumbers().
How can I get variables that not declared yet?
Here are simple example:
a = b
b = 123
What I want from these 2 lines is a << 123. But obv it doesn't work.
I know the easy way to get the answer a = 123 is cut 1st line and paste it to lower than 2nd line.
But I'm in some problem. I need some function like 'WillDeclaredVar()' that I can use in like this:
a = WillDeclaredVar(b)
sheepCount = 123
b = sheepCount
print(a)
so I can get the answer '123'.
Or there are any built-in functions that will allows me to do similar thing?
===
I think the link given by timrau is not telling my case. the key point is how to get Variables 'that not declared yet'.
===
Adding actual Code:
triggerCount = 0 -- Counting number of 'Trigger' function
local Trigger = function (t)
triggerCount = triggerCount + 1
return Trigger (t)
end
-- following Triggers are same as while statement.
-- following Triggers doing: Add 1 MarineCount until get 64000 MarineCount
Trigger { -- Here the Trigger function. Now triggerCount = 1.
players = {P1}
actions = {
SetDeaths(P1, Add, 1, "Terran Marine")
},
flag = {preserved},
}
Portal(LoopStart);
-- function Portal(VariableName) returns VariableName = triggerCount. So LoopStart = 1.
Trigger { -- Now triggerCount = 2.
players = {P1}
actions = {
LinkList(LoopEnd, LoopStart);
-- function LinkList(From, To) changes 'From' Trigger's next pointer to the 'To' Trigger.
-- But now the problem happens. Because 'LoopEnd' is not declared yet.
},
flag = {preserved},
}
Trigger { -- Now triggerCount = 3.
players = {P1}
conditions = {
Deaths(P1, Exactly, 64000, "Terran Marine");
}
actions = {
_LinkList(LoopEnd);
-- Reset LoopEnd's next pointer(= LoopEscape) if MarineCount hits 64000
},
flag = {preserved},
}
Portal(LoopEnd); -- LoopEnd = 3.
Changing Order of Triggers will break the Trigger logic(while statement).
All i want is get easy to coding. To put in bluntly, I don't need to solve this problem(get undeclared var). I can imagine a few ways to avoid it. But if i using these ways then the coding work will be very complicated and the difficulty of coding will increases greatly. The difficulty made me stop coding in recent months.
How can I get variables that not declared yet?
Short of time travel, you can't.
Your example code doesn't explain the motivation for the question, because this:
a = WillDeclaredVar(b)
sheepCount = 123
b = sheepCount
print(a)
Can trivially be rearranged into this:
sheepCount = 123
b = sheepCount
a = WillDeclaredVar(b)
print(a)
It would be easier to answer your question if you showed the actual problem you're trying to solve (to avoid an XY problem).
However, as stated there are few things we can note.
First, you need to distinguish between declaring a variable and giving it a value. In Lua you can say:
local b
To declare b as a local variable, which presumably will make a slot for it in the stack frame and let you bind closures to it, before you give it a value. However, the line:
a = WillDeclaredVar(b)
Will pass WillDeclaredVar the value that b currently has, and there's no way for a to change retroactively as a result of b being assigned a new value. That's simply not going to happen, ever. Neither a nor WillDeclaredVar are even aware that b exists, they are receive the value it contains at the point of call.
You could however bind the variable b to a closure which will fetch b's current value when needed.
-- declare b before giving it a value, aka "forward reference"
local b
a = function() return b end
sheepCount = 123
b = sheepCount
print(a()) -- call a to get b's current value
Another way to do that would be to make b a global variable, which is really just a key into your environment table, so you could say:
a = WillDeclaredVar('b')
And have a be some object that can fetch the current value of __ENV['b'] when required.
However, neither of these will support this syntax:
print(a)
a needs to be a function, something that looks up the value of b when needed rather than simply holding a previously computed value. You could do it in this particular instance (i.e. a needs to be convertable to a string), by creating a proxy object that implements __tostring.
function WillDeclaredVar(variableName)
local proxy = { environment = _ENV or _G, variableName = variableName }
return setmetatable(proxy, {
__tostring = function(proxy)
return proxy.environment[proxy.variableName]
end
})
end
-- a will compute a value based on the current value of b when needed
a = WillDeclaredVar('b')
sheepCount = 123
b = sheepCount
print(a)
Output:
123
To make var1 be a reference for var2 write var1 = ReferenceF or var2 (please note a space inside "ReferenceFor"!)
do
local values, references, reference_flag = {}, {}
setmetatable(_G, {
__index = function (_, name)
if name == 'ReferenceF' then
reference_flag = true
elseif reference_flag then
reference_flag = false
return {[references] = name}
elseif references[name] then
return _G[references[name]]
else
return values[name]
end
end,
__newindex = function (_, name, val)
if type(val) == 'table' and val[references] then
references[name] = val[references]
else
values[name] = val
end
end
})
end
a = ReferenceF or b -- a is Reference For b
b = ReferenceF or c -- b is Reference For c
sheepCount = 123
c = sheepCount
print(a, b, c) --> 123 123 123
My game engine pushes a value on to the lua stack as a parameter to a function and then invokes it using lua_pcall. The lua code will run and call additional lua functions. Eventually this lua code will invoke a C function. Is it possible for this function to retrieve the value that was originally pushed on to the stack?
Its like this:
<engine function A>
pushes parameter value X on to stack for lua
<lua func>
<lua func>
<lua func>
<engine function B>
can I extract the values X that was pushed by function A here?
Yes, with a combination of getinfo, getlocal and getupvalue you can get all that information (you can even change those values using set* functions).
Here is a fragment from MobDebug that returns stack information along with a table of locals and upvalues at each level. The variables at each level will be indexed in the same order they appear in the code (starting from parameters). For each get* function you can use their C equivalents (lua_getinfo, lua_getlocal, and lua_getupvalue), but the logic should be exactly the same.
local function stack(start)
local function vars(f)
local func = debug.getinfo(f, "f").func
local i = 1
local locals = {}
while true do
local name, value = debug.getlocal(f, i)
if not name then break end
if string.sub(name, 1, 1) ~= '(' then locals[name] = {value, tostring(value)} end
i = i + 1
end
i = 1
local ups = {}
while func and true do -- check for func as it may be nil for tail calls
local name, value = debug.getupvalue(func, i)
if not name then break end
ups[name] = {value, tostring(value)}
i = i + 1
end
return locals, ups
end
local stack = {}
for i = (start or 0), 100 do
local source = debug.getinfo(i, "Snl")
if not source then break end
table.insert(stack, {
{source.name, source.source, source.linedefined,
source.currentline, source.what, source.namewhat, source.short_src},
vars(i+1)})
if source.what == 'main' then break end
end
return stack
end