first_response = [
{"xId" => "123", "yId" => "321"},
{"xId" => "x", "yId" => "y" }
]
first_response.each do |resp|
x_id = resp['xId']
y_id = resp['yId']
puts x_id.to_s
puts y_id.to_s
end
This gives me outputs
123
321
x
y
output hash I want to create is
{123=>{321}, x=>{y}}
first service: I have an array of hash that has two different ids example:(x_id and y_id) (there would be multiple pairs like that in the response)
I want to create a hash that should contain the matching pair of x_id and y_ids that we get from the first service with x_id's as the key for all the pairs.
If you know every hash in first_response is going to contain exactly two key/value pairs, you can extract their values and then convert that result into a hash (see Enumerable#to_h):
first_response.to_h(&:values)
# {"123"=>"321", "x"=>"y"}
Looks like this approach works, but I am not completely sure if that is right
first_response = [{"xId"=>"123","yId"=> "321"}, {"xId"=>"x","yId"=> "y"}]
h = {}.tap do |element|
first_response.each do |resp|
x_id = resp['xId']
y_id = resp['yId']
element[x_id] = y_id
end
end
puts h.to_s
# {"123"=>"321", "x"=>"y"}
Related
I've created the following hash keys with values parsed from PDF into array:
columns = ["Sen", "P-Hire#", "Emp#", "DOH", "Last", "First"]
h = Hash[columns.map.with_index.to_h]
=> {"Sen"=>0, "P-Hire#"=>1, "Emp#"=>2, "DOH"=>3, "Last"=>4, "First"=>5}
Now I want to update the value of each key with 6 equivalent values from another parsed data array:
rows = list.text.scan(/^.+/)
row = rows[0].tr(',', '')
#data = row.split
=> ["2", "6", "239", "05/05/67", "Harp", "Erin"]
I can iterate over #data in the view and it will list each of the 6 values. When I try to do the same in the controller it sets the same value to each key:
data.each do |e|
h.update(h){|key,v1| (e) }
end
=>
{"Sen"=>"Harper", "P-Hire#"=>"Harper", "Emp#"=>"Harper", "DOH"=>"Harper", "Last"=>"Harper", "First"=>"Harper"
So it's setting the value of each key to the last value of the looped array...
I would just do:
h.keys.zip(#data).to_h
If the only purpose of h is as an interim step getting to the result, you can dispense with it and do:
columns.zip(#data).to_h
There are several ways to solve this problem but a more direct and straight forward way would be:
columns = ["Sen", "P-Hire#", "Emp#", "DOH", "Last", "First"]
...
#data = row.split
h = Hash.new
columns.each_with_index do |column, index|
h[column] = #data[index]
end
Another way:
h.each do |key, index|
h[key] = #data[index]
end
Like I said, there are several ways of solving the issue and the best is always going to depend on what you're trying to achieve.
I am trying to remove the elements in an array from a hash and the array forms part of the 'keys' in a hash. Here is an illustration.
hash = {'a' = 1, 'b' = 2, 'c' =3, 'd' = 4}
arr = ["a","d"] #Now I need to remove the elements from this array from the above hash
Resultant hash should be as below
new_hash = {'b' = 2,'c' =3}
This is what I tried unfortunately it doesn't seem to work
for i in 0..hash.length-1
arr.each do |key_to_del|
hash.delete key_to_del unless h.nil?
end
end
Your hash isn't correct format. It should be like this.
hash={"a"=>1, "b"=>2, "c"=>3, "d"=>4}
arr=["a","d"]
Solution 1
hash.reject! {|k, v| arr.include? k }
Solution 2
arr.each{|v| hash.delete(v)}
I have a Hash in the following format:
{"PPS_Id"=>["fe4d7c06-215a-48a7-966d-19ab58976548", "6e90208e-4ab2-4d44-bbaa-9a874bff095b"], "Amount"=>"[\"10000.000\", \"2374.000\"]"}
When I write this data into an excel get the following output.
I want to write the data into the Excel this way:
PPS_Id Amount
fe4d7c06-215a-48a7-966d-19ab58976548 10000.000
6e90208e-4ab2-4d44-bbaa-9a874bff095b 2374.000
How do I convert my current Hash to the below?
{PPS_Id"=>["fe4d7c06-215a-48a7-966d-19ab58976548","Amount"=>"10000.000"},{PPS_Id"=>["6e90208e-4ab2-4d44-bbaa-9a874bff095b","Amount"=>"2374.000"}
Can you please assist.
If you can modify your original hash from
hash = {"PPS_Id"=>["fe4d7c06-215a-48a7-966d-19ab58976548", "6e90208e-4ab2-4d44-bbaa-9a874bff095b"], "Amount"=>"[\"10000.000\", \"2374.000\"]"}
to
hash = {"PPS_Id"=>["fe4d7c06-215a-48a7-966d-19ab58976548", "6e90208e-4ab2-4d44-bbaa-9a874bff095b"], "Amount"=>["10000.000", "2374.000"]}
Note: the last value in the hash is an Array instead of a String.
Then, you can generate an Array of hashes on which you can iterate to fill your excel:
ary = hash.inject([]) do |r, (key, value)|
value.each_with_index do |e, i|
r[i] ||= {}
r[i][key] = e
end
r
end
ary # [{"PPS_Id"=>"fe4d7c06-215a-48a7-966d-19ab58976548", "Amount"=>"10000.000"}, {"PPS_Id"=>"6e90208e-4ab2-4d44-bbaa-9a874bff095b", "Amount"=>"2374.000"}]
If your hash really looks like this :
hash = {"PPS_Id"=>["fe4d7c06-215a-48a7-966d-19ab58976548", "6e90208e-4ab2-4d44-bbaa-9a874bff095b"],
"Amount"=>"[\"10000.000\", \"2374.000\"]"}
you can use scan to parse the floats first :
hash["Amount"] = hash["Amount"].scan(/[\d\-\.]+/)
Your hash will now look like :
{"PPS_Id"=>["fe4d7c06-215a-48a7-966d-19ab58976548", "6e90208e-4ab2-4d44-bbaa-9a874bff095b"],
"Amount"=>["10000.000", "2374.000"]}
To get the table you want, you could just transpose the hash values :
hash.values_at("PPS_Id", "Amount").transpose.each{|id, amount|
puts format("%s\t%.3f", id, amount)
}
It will output :
fe4d7c06-215a-48a7-966d-19ab58976548 10000.000
6e90208e-4ab2-4d44-bbaa-9a874bff095b 2374.000
What is the best way to achieve the following, I have following array of actions under ABC
ABC:-
ABC:Actions,
ABC:Actions:ADD-DATA,
ABC:Actions:TRANSFER-DATA,
ABC:Actions:EXPORT,
ABC:Actions:PRINT,
ABC:Detail,
ABC:Detail:OVERVIEW,
ABC:Detail:PRODUCT-DETAIL,
ABC:Detail:EVENT-LOG,
ABC:Detail:ORDERS
I want to format this as:
ABC =>{Actions=> [ADD-DATA,TRANSFER-DATA,EXPORT,PRINT], Detail => [Overview, Product-detail, event-log,orders]}
There's probably a ton of ways to do it but here's one:
a = ["ABC:Actions",
"ABC:Actions:ADD-DATA",
"ABC:Actions:TRANSFER-DATA",
"ABC:Actions:EXPORT",
"ABC:Actions:PRINT",
"ABC:Detail",
"ABC:Detail:OVERVIEW",
"ABC:Detail:PRODUCT-DETAIL",
"ABC:Detail:EVENT-LOG",
"ABC:Detail:ORDERS"]
a.map { |action| action.split(":") }.inject({}) do |m, s|
m[s.at(0)] ||= {}
m[s.at(0)][s.at(1)] ||= [] if s.at(1)
m[s.at(0)][s.at(1)] << s.at(2) if s.at(2)
m
end
The map call returns an array where each of the strings in the original array have been split into an array of elements that were separated by :. For example [["ABC","Actions","ADD-DATA"] ... ]
The inject call then builds up a hash by going through each of these "split" arrays. It creates a mapping for the first element, if one doesn't already exist, to an empty hash, e.g. "ABC" => {}. Then it creates a mapping in that hash for the second element, if one doesn't already exist, to an empty array, e.g. "ABC" => { "Detail" => [] }. Then it adds the third element to that array to give something like "ABC" => { "Detail" => ["OVERVIEW"] }. Then it goes onto the next "split" array and adds that to the hash too in the same way.
I will do this as below :
a = ["ABC:Actions",
"ABC:Actions:ADD-DATA",
"ABC:Actions:TRANSFER-DATA",
"ABC:Actions:EXPORT",
"ABC:Actions:PRINT",
"ABC:Detail",
"ABC:Detail:OVERVIEW",
"ABC:Detail:PRODUCT-DETAIL",
"ABC:Detail:EVENT-LOG",
"ABC:Detail:ORDERS"]
m = a.map{|i| i.split(":")[1..-1]}
# => [["Actions"],
# ["Actions", "ADD-DATA"],
# ["Actions", "TRANSFER-DATA"],
# ["Actions", "EXPORT"],
# ["Actions", "PRINT"],
# ["Detail"],
# ["Detail", "OVERVIEW"],
# ["Detail", "PRODUCT-DETAIL"],
# ["Detail", "EVENT-LOG"],
# ["Detail", "ORDERS"]]
m.each_with_object(Hash.new([])){|(i,j),ob| ob[i] = ob[i] + [j] unless j.nil? }
# => {"Actions"=>["ADD-DATA", "TRANSFER-DATA", "EXPORT", "PRINT"],
# "Detail"=>["OVERVIEW", "PRODUCT-DETAIL", "EVENT-LOG", "ORDERS"]}
It was just interesting to do it with group_by :)
a = ['ABC:Actions',
'ABC:Actions:ADD-DATA',
'ABC:Actions:TRANSFER-DATA',
'ABC:Actions:EXPORT',
'ABC:Actions:PRINT',
'ABC:Detail',
'ABC:Detail:OVERVIEW',
'ABC:Detail:PRODUCT-DETAIL',
'ABC:Detail:EVENT-LOG',
'ABC:Detail:ORDERS']
result = a.map { |action| action.split(":") }.group_by(&:shift)
result.each do |k1,v1|
result[k1] = v1.group_by(&:shift)
result[k1].each { |k2,v2| result[k1][k2] = v2.flatten }
end
p result
{"ABC"=>{"Actions"=>["ADD-DATA", "TRANSFER-DATA", "EXPORT", "PRINT"], "Detail"=>["OVERVIEW", "PRODUCT-DETAIL", "EVENT-LOG", "ORDERS"]}}
I have this code here and it works but there has to be a better way.....i need two arrays that look like this
[
{
"Vector Arena - Auckland Central, New Zealand" => {
"2010-10-10" => [
"Enter Sandman",
"Unforgiven",
"And justice for all"
]
}
},
{
"Brisbane Entertainment Centre - Brisbane Qld, Austr..." => {
"2010-10-11" => [
"Enter Sandman"
]
}
}
]
one for the past and one for the upcoming...the problem i have is i am repeating myself and though it works i want to clean it up ...here is my data
..
Try this:
h = Hash.new {|h1, k1| h1[k1] = Hash.new{|h2, k2| h2[k2] = []}}
result, today = [ h, h.dup], Date.today
Request.find_all_by_artist("Metallica",
:select => "DISTINCT venue, showdate, LOWER(song) AS song"
).each do |req|
idx = req.showdate < today ? 0 : 1
result[idx][req.venue][req.showdate] << req.song.titlecase
end
Note 1
In the first line I am initializing an hash of hashes. The outer hash creates the inner hash when a non existent key is accessed. An excerpt from Ruby Hash documentation:
If this hash is subsequently accessed by a key that doesn‘t correspond to a hash
entry, the block will be called with the hash object and the key, and should
return the default value. It is the block‘s responsibility to store the value in
the hash if required.
The inner hash creates and empty array when the non existent date is accessed.
E.g: Construct an hash containing of content as values and date as keys:
Without a default block:
h = {}
list.each do |data|
h[data.date] = [] unless h[data.date]
h[data.date] << data.content
end
With a default block
h = Hash.new{|h, k| h[k] = []}
list.each do |data|
h[data.date] << data.content
end
Second line simply creates an array with two items to hold the past and future data. Since both past and the present stores the data as Hash of Hash of Array, I simply duplicate the value.
Second line can also be written as
result = [ h, h.dup]
today = Date.today