Line graphs in Tableau - tableau-desktop

I have a line graph in Tableau over the past 6 months and it is filtered by person. Some people have no data for certain months. When they do not have data, the graph appears blank for that month. I would like for the graph to show 0 instead of a blank. For example, if person A had no sales in February, I would like for the graph to show 0 for February rather than a blank for February. I cannot use the Zn function because there are no null values.
Any ideas?
Thanks!
Edit: Here is an example using false data
The second graph is the same as the first graph except it is filtered by person. Even though Sally has no data in Feb, March, or June, this actually means that the value should be 0. I would like for the line graph to drop to 0 for these months. Further, then the average should be around 58 rather than 116.

Assuming you have a data like the following:
Date Person Sales
15/01/2021 Peter 10
15/02/2021 Peter 20
15/03/2021 Peter 10
15/04/2021 Peter 30
15/05/2021 Peter 40
15/06/2021 Peter 20
15/01/2021 Sally 20
15/03/2021 Sally 10
15/05/2021 Sally 50
Drag date into your colum shelf and make it Month-discrete
Drag Sales into the worksheet
Switch to line chart
Right click Sales --> Format --> Pane --> Marks --> Show at default value
Right click Month (Date) --> Show missing values
Add Person as a Filter --> show Filter
Then you should be able to get something like this having Sally (just 3 out of 5 total months) showing her non existing 2 values as zero.

Related

List unique dates and add line at the beginning of a new month

I have long (multiple thousand lines and growing) list of data in Sheets which have a date and additional columns with data. Here's a simplified example of this list (=TAB1):
Date Number Product-ID
02.09.2021 123 1
02.09.2021 2 1
01.09.2021 15 1
01.09.2021 675 2
01.09.2021 45 2
01.09.2021 52 1
31.08.2021 2 1
31.08.2021 78 1
31.08.2021 44 1
31.08.2021 964 2
30.08.2021 1 2
29.08.2021 ...
...
Three remarks:
The date is formatted to European standard DD.MM.YYYY
There definitely is more than one line per day per product (could be a big number depending on the day)
(for the formulas below) In the European standard Sheets uses ; instead of , as in =IF(A;B;C)
In a different tab (=TAB2), I want to add up all the numbers for a unique date for Product-ID 1. So far I've done it like this:
Date Sum (if Product-ID=1)
=UNIQUE('TAB1'!A2:A) =ARRAYFORMULA(SUMIF('TAB1'!A:A&'TAB1'!C:C;A2:A&"1";'TAB1'!B:B))
02.09.2021 125
01.09.2021 67
31.08.2021 124
30.08.2021 1
29.08.2021 ...
...
This works fine so far. Here's what I want to do now:
For every month (here: August and September 2021) I need an additional line above the current date (in this case: above 02.09.2021) AND above a completed month to sum over the whole month for column B. Here's how it should look like:
Date Sum (if Product-ID=1)
September 2021 192
02.09.2021 125
01.09.2021 67
August 2021 125
31.08.2021 124
30.08.2021 1
29.08.2021 ...
Of course, the line for the next day (03.09.2021) should be added above 02.09.2021 and below the sum for the month when it's automatically added to TAB1 on the next day.
I tried to play around with s.th. like =IF(DAY(UNIQUE('TAB1'!A2:A))=1;...;...) but didn't get far.
Is there anyone with an idea how to realize s.th. like this?
You want to learn about QUERY().
in cell A1 of an empty tab.
=QUERY('TAB1'!A2:C,"select A,SUM(B) where C = 1 group by A")
it makes a very big difference whether your product ids are text or numbers. the above was written as if they are numbers, but you might have just been simplifying. If they are text you would write it like this:
=QUERY('TAB1'!A2:C,"select A,SUM(B) where C = '1XYZ' group by A")
note the single quotes.
if the IDs are a MIX of text and letters then you need to force them all to text values in the original data by highlighting the IDs column and choosing Format>Number>Plain Text from the menu bar.
UPDATE:
I understand the requirements better now for intermixing a cumulative month total into the output. This may work.
=ARRAYFORMULA({QUERY({EOMONTH('TAB1'!A2:A,0),'TAB1'!B2:C},"select 'Total',Col1,SUM(Col2) where Col3 = 1 group by 'Total',Col1 label 'Total''',SUM(Col2)''",0);QUERY('TAB1'!A2:C,"select '',A,SUM(B) where C = 1 group by '',A label '''',SUM(B)''",0)},"order by Col2,Col1",0))

How to display two months data in a single line graph in google sheet?

I want to display data from 2 months in a line graph in google sheet. I tried and only one months data is displayed. Please help. Following is just a demo
date
birth
death
30/6/2021
22
6
1/7/2021
5
43
2/7/2021
9
22
3/7/2021
12
21
4/7/2021
23
11
You should display your data as bar chart if you want the result in grouping by month (add new column for month value only), to display the trend for dead and birth over the year, then you should choose line chart, here is how the two charts look like:

Split revenue by year with Google Sheets' QUERY function

I get monthly revenue data from the finance department that I have clean to input into a reporting format. Its monthly data that lists all revenue in a single column. I need to split out the revenue by years (2018, 2019, etc.).
I believe that I need to use a query function for this but if you have some other solution, then I'm open to that too.
The data looks like this:
Client Source Month Year Revenue
abc Google 1 2019 100
abc Google 1 2018 100
abc Facebook 1 2018 50
abc Facebook 2 2018 50
And I need it to look like this:
Client Source Month 2018 Revenue 2019 Revenue
abc Google 1 100 100
abc Facebook 1 50 0
abc Facebook 2 50 0
I'm familiar with query functions but I can't wrap my head around how to do this.
The pseudo code for this would be something like:
select Client,
Source,
Month,
Case when Year in 2019 then sum(Revenue) as 2019 Revenue else 0 end,
Case when Year in 2018 then sum(Revenue) as 2018 Revenue else 0 end
from Data
Group by Client, Source, Month
Please let me know if I need to provide any additional information. And I appreciate your help with this problem.
=QUERY(A1:E, "select A,B,C,sum(E) where A is not null group by A,B,C pivot D", 1)

'weeknum' function

Here is what I'm trying to do:
I have three Spreadsheets.
(1) Days (holds increase in user-nr per day)
(2) Weeks (is supposed to sum up user increases so they are shown each week)
(3) Months (is supposed to sum up user increases so they are shown each month)
To give an example: if we have 10 users on Monday, 20 more on Tuesday, 15 more on Wednesday (that's when the next calendar week starts), then I want in the sheet "weeks" to see e.g. 45 users in calendar week 27 or so.
So what I try is this: =SUMIF(WEEKNUM(Days!A2:A977); A2; Days!B2:B977)
A holds the date of the day
B holds the number of users.
What happens is it does not sum up the number of the users shown in B, but only gives the number in the first cell of the weeknumber shown in A2.
What is my mistake?
The formula seems to be correct, but two things are needed.
You should embrace it in ArrayFormula()
You should use one more weeknum()
=ArrayFormula(sumif(weeknum(Days!A2:A977);weeknum(Days!A2);Days!B2:B977))

Conditional array formulas

I have a massive dataset and am preparing a dashboard based on this dataset.
On my dashboard, I have a drop-down menu that allows me to select a month of my choice, from Jan to Apr.
Visitor Jan Feb Mar Apr
Jenny 2 3 0 1
Peter 2 0 1 3
Charley 0 2 4
Charley 1 2 2 3
Sam 1 4 2 3
Peter 2 2 5 0
John 3 3 6 9
Robin 4 0 7 0
I am looking for a formula that will give me the number of unique visitors who have been active at least once in the month that I choose from the drop-down menu.
Hoping this is really clear, but if not, please feel free to shoot back your questions.
This may be easier with Excel 2013, but if the results you want from your example are 6, 5, 5, and 5 for Jan>April respectively then perhaps:
Create a PivotTable from multiple consolidation ranges (example how here and for VALUES choose Sum of Value.
Count the non-zero values in the PT by column with a formula such as:
=COUNTIF(H5:H10,">"&0)
The above however would not be convenient for repetition each month, though a whole year might be prepared at one time.

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