Hi Everyone hope all are good in this COVID time
So In a standard, all levels view i am able to view the links but when i change the view to level1 the links are not displayed.How can i display it any idea,why i need is i dont need to much data as in all level just enough as in level 1 view.
Thanks in advance
It is clear that the links are not shown: after all, Object 644 "ABCD" is not linked to any other object and changing the view to level 1 does exactly this: it shows only objects of Level 1 and nothing else, there is no cumulation.
The solution for your problem depends on what you want to do concretely.
If your goal is to count the links in the chapter, you could probably write a Layout DXL column like this
void recursiveCountOutLinks(Object o, int &iCount) {
// first count the links going out of Object o
Link l
for l in o->"*" do iCount++
// next, add all Links on lower levels
Object oChild
for oChild in o do {
if isDeleted(oChild) then continue
recursiveCountOutLinks (oChild, iCount)
}
}
int iTotal = 0
if (level obj == 1) {
recursiveCountOutLinks(obj, iTotal)
display iTotal ""
}
If your goal is to export these links you will have to adopt your exporter by doing this recursively as shown above.
Related
I have the following formula: =ArrayFormula(INDEX(Items!F2:F,MATCH(C2,Items!E2:E,0)))
I would like to extend it such that the entire C column runs the same formula for values. Please help. If a script is necessary to achieve this, I'd like to explore that option too.
Use Apps Script!
Sheet functions (formulae) work great (especially if you are a master like player0), but I find it much easier to work within Apps Script for anything much more complicated than a simple INDEX MATCH. If you are willing to learn some JavaScript, I highly recommend learning some.
Custom Functions
You can write custom sheet functions in Apps Script that you can call with the traditional =FUNCTION() from a cell.
The way it works is that you write a function in Apps Script that returns a two dimensional array corresponding to the area that it needs to fill.
For example, if wanted a function to fill a 2 x 2 block with 1, you would need to make your function return:
[[1,1],[1,1]]
Or you can write it like this:
[
[1, 1],
[1, 1]
]
Implementing Index Match
There are many ways you can implement it, here is an example.
The example spreadsheet has 2 tabs, "Ledger" and "Items".
The goal of the function that follows is to get the costs of the items from the "Items" tab.
function ledgerIndexMatch(){
// Initializing the location of data
let ss = SpreadsheetApp.getActive();
let ledger = ss.getSheetByName("Ledger");
let source = ss.getSheetByName("Items");
let ledgerRange = ledger.getDataRange();
let sourceRange = source.getDataRange();
// Getting the values into a 2D array
let ledgerValues = ledgerRange.getValues();
let sourceValues = sourceRange.getValues();
// Discarding the first row (headers)
ledgerValues.shift();
sourceValues.shift();
// Initializing the output array
let output = [];
// This is where the INDEX MATCH happens
// For each row in ledger
ledgerValues.forEach(ledgerRow => {
// Get the second column (index 1)
let item = ledgerRow[1];
// Initialize the column
let value = [];
// For each row in the source
sourceValues.some(sourceRow => {
// Check if the item is there
if (item == sourceRow[0]) {
// if so, add to value
value.push(sourceRow[1]);
// stop looking for values
return true
// if not matched, keep looking
} else return false
})
// Add the found value (or blank if not found)
// to the output array.
output.push(value);
})
return output;
}
Which can be used like this:
Whats nice about Apps Script is that you can customize it to your heart's content. In this example, the function automatically detects the height of the respective tables, so you don't need to fiddle around with ranges.
You might want to extend this function with arguments so that its more flexible. Or you could just have a few versions of it for different operations, if you don't have too many. Or refactor it... its up to you.
References
Apps Script
Custom Functions
Tutorials
SpreadsheetApp
use:
=ARRAYFORMULA(IFNA(VLOOKUP(C2:C, Items!E2:F, 2, 0)))
Thanks for reading my first question. I'm just starting out with google sheets to please bear with me.
Here is the sheet I'm working with
So,this sheet if for a game I play and we assign guild attacks based on power levels. I'm looking to create a function or script and put it in Column O. I'd like this function to compare Column F to a specific cell in Column M and then return the user associated with Column F that is >= than the specific cell in Column M. Like this enter image description here
I highlighted the first three as an example.
I can obviously do this manually but I takes time, and was looking to automate this process so it becomes more efficient. I've tried Vlookups, MATCH, IF and I've been unsuccessful. Any help would be greatly appreciated. Again, I'm just a beginner with google sheets so please go easy on me. :)
Solution
As you metioned that you would also be happy with an scripted solution I have created this script that I believe solves your issue. It has comments explaining step by step how it works:
function myFunction() {
// Get our sheet
var ss = SpreadsheetApp.getActive().getSheetByName('Automate Test');
// Get the values of the ranges of F and M. Flat will convert the 2D array we get from getValues() into a 1D one which is easier to work with
var valuesF = ss.getRange('F2:F16').getValues().flat();
var valuesD = ss.getRange('D2:D16').getValues().flat();
var valuesM = ss.getRange('M2:M16').getValues().flat();
var valuesN = ss.getRange('N17:N31').getValues().flat();
// We will iterate through all the players in column M to find their opponents
for(i=0;i<valuesM.length;i++){
// We create an empty array to be filled with the list of possible opponents to then choose a random one of the list
var playersHigherEqual = [];
// Iterate through the opponent list
for(j=0;j<valuesF.length;j++){
// If the opponent meets the condition
if(valuesF[j]>= valuesM[i]){
// Add it to the array of possible opponents
playersHigherEqual.push(ss.getRange(j+2, 2).getValue());
}
}
//Finally we will set the opponent by choosing a random one out of the list. Note that i+2 is because the arrays start from 0
ss.getRange(i+2, 15).setValue(playersHigherEqual[Math.floor(Math.random()*playersHigherEqual.length)]);
}
// We will iterate through all the players in column M to find their opponents
for(i=0;i<valuesN.length;i++){
// We create an empty array to be filled with the list of possible opponents to then choose a random one of the list
var playersHigherEqual = [];
// Iterate through the opponent list
for(j=0;j<valuesD.length;j++){
// If the opponent meets the condition
if(valuesD[j]>= valuesN[i]){
// Add it to the array of possible opponents
playersHigherEqual.push(ss.getRange(j+2, 2).getValue());
}
}
//Finally we will set the opponent by choosing a random one out of the list. Note that i+2 is because the arrays start from 0
ss.getRange(i+17, 15).setValue(playersHigherEqual[Math.floor(Math.random()*playersHigherEqual.length)]);
}
}
Please let me know if you also need a sheet formula solution for this question. For more information about Apps Script check out the documentation.
I hope this has helped you. Let me know if you need anything else or if you did not understood something. :)
void deleteDups(LinkedListNode n)
HashSet<Integer> set = new HashSet<Integer>();
LinkedListNode previous = null;
while(n!=null){
if(set.contains(n.data)){
previous.next = n.next;
}else {
set.add(n.data);
previous = n;
}
n = n.next;
}
}
This code snippet is to remove duplicate elements in a linked List.
I have been going through the linked list concepts in cracking the coding interview. Since only the code snippet is available I am not able to understand the flow and where the LinkedListNode n in the first line is actually from. I can understand that they are passing the entire linked list as a parameter, it would be helpful if anybody can tell me what the code for that LinkedListNode will be. Thank you in advance.
LinkedList traversal: Given the head (starting node) of the list, you could traverse the whole list. Each currentnode will have the information of nextnode which can be accessed by current.next.
In your code LinkedListNode 'n' is the starting node (head) of the list where duplicates needs to be removed
I am writing an app to simulate the nba lottery. I have already written the codes to generate the random combinations, and assigned them to each team.
Here is my method to simulate the drawings and assign the draft positions to each team. standingsArray is an array of Team items of type ObjectWrapper, with values of name, seed, wins, losses, draft position exc... for each team. So basically what Im doing is I have 14 balls and randomly choose 4 balls, which constitute a combination (order doesn't matter). So essentially there are a total of 1001 total possible combinations, but one is thrown out. (you can ignore the first while loop because that is just there so that the thrown out combination isnt selected). A number of combinations is assigned to the 14 lottery teams based on record (250 for worst team, 199 for second worst exc...). The argument in my method standingsArray already has the number of possibilities assigned to each team. Next, I randomly pull 4 balls from the total possibilities, and the team with that combination gets the first pick. But because all the combinations for that team selected cant be chosen again for the second pick, I have to remove all of those combinations, but that is very complicated so instead, i make a new array called tempPossibilities which appends all the combinations for every team except the one just selected, which then allows me to generate a new combination to select from.
However, I am getting an error at this line for j in 0...(standingsArray[i].possibilities?.count)!-1{ It says bad instruction error, and I cannot figure out why I am getting this error. And what else doesnt make sense is that the for loop works and the tempPossibilities array is fully populated with the correct amount of combinations (without the lottery team), even though the error happens at the for loop?
Code is below: any help is appreciated, thank you, and sorry for the really long paragraph
func setDraftPositions(var standingsArray: [Team])->[Team]{
var lottery: [Team]=[]
var totalPossibilities: [[Int]]=combosOfLength(14, m: 4)
var tempPossibilities = []
var rand = Int(arc4random_uniform(UInt32(totalPossibilities.count)))
var draw = totalPossibilities[rand]
while (draw==(unused?.first)!) {
rand = Int(arc4random_uniform(UInt32(totalPossibilities.count)))
draw = totalPossibilities[rand]
}
s: for x in 0...13{
for a in 0...(standingsArray[x].possibilities?.count)!-1{
if(draw==standingsArray[x].possibilities![a]){
standingsArray[x].setDraftingPosition(1)
standingsArray[x].isLottery=true;
lottery.append(standingsArray[x])
for i in 0...(standingsArray.count-1) {
if(standingsArray[i].firstName != standingsArray[x].firstName!) {
for j in 0... (standingsArray[i].possibilities?.count)!-1{ //ERROR is happening here
tempPossibilities.append(standingsArray[i].possibilities![j])
}
}
}
standingsArray.removeAtIndex(x)
break s;
}
}
}
(repeat this for the next 2 picks)
Try this:
for j in 0...(standingsArray[i].possibilities?.count)!-1{
should be written like this:
for j in 0...(standingsArray[i].possibilities?.count)! - 1{
it needs proper spacing.
Working on a grails application, wherein I am using dc-crossfilter to plot 5 bar graphs which are interconnected to each other.
Now, I want to do a simple thing here : In my first bar graph, there are 14 bars ( x number of departments and 1 "All" graph)
So the problem here is that the presence of "All" in the graph really messes up every other department's number as they are way too low (All is summation of all x number of departments) So each department number is so low that it's not even visible clearly.
But, it is very important to load the data for "All", as all the remaining 4 bar charts are filtered for "All" only.
So, is there any way how I can hide "All" in my first bar graph even though data is loaded? Is this even feasible?
There has to be some simple workaround to do this.
All approaches/suggestions are most welcome.
UPDATE :
Code:
This is the part where I define the groups and dimensions
var devValue = facts.dimension(function (d) {return d.c;});
var devValueGroupSum = devValue.group().reduceSum(function(d) { return +d.g;});
var mvValue = facts.dimension(function(d,i) {return d.b;});
var mvValueGroupSum = mvValue.group().reduceSum(function(d) {return +d.g;});
Now, where and how exactly do I define a fake group and prefilter the data. But will "ALL" be included in the actual dataset ( and not visualization part) even after prefiltering the data.
Code for fake group as in documentation :
var group = {
all:function () {
var cumulate = 0;
var g = [];
_group.all().forEach(function(d,i) {
cumulate += d.value;
g.push({key:d.key,value:cumulate})
});
return g;
}
};
I am really not able to understand the documentation as in how to implement this, can you help me in implementing this?
You can use a "fake group" to prefilter the data. Whenever the chart fetches the data it will go through your fake group, which then fetches the data from the real group and changes it.
The technique is described in the FAQ.