I know a bit of excel and google sheets but I am struggling to find out a few things.
My goal is to have a function that outputs a line of code with a number within that is taken from a different cell.
I have a drop down that allows me to choose a character type. I have a second cell that checks what character type is selected and finds the corresponding number for said character. I would then like to take that number and be able to swap it within a line of code for the game.
A1 is the drop down with list of classes
B1 Outputs corresponding number (numbers can range from 0-1000)
C1 uses B1 number to change the game code number
C1 ---> <s16 name="mRomPawnAiNo" value="964"/ >
the 964 is what I am trying to change and match from B1
It would also be amazing if the output of C1 showed the whole code.
Things that I have tried (they might still work I was just unable to figure them out) - Replace, Substitute, ToText, Double and Triple quotation marks, using Char(34). Both figuuring out how to change just the number and displaying the code with its included < >'s ='s and " "'s is causing me problems
Figured it out. I went to far down the rabbit hole and got lost in the weeds.
Answer:
="<s16 name=" & """" & "mRomPawnAiNo" & """" &"value=""" & B1 & """" &"/>"
Related
I'm trying to remove a piece of text (Perfomance) from a column in Google Spreadsheet that contains (XX Performance) XX is a number like 89. I'm using:
=REGEXREPLACE(D:D, " Performance "," - ")
But no love...
enter image description here
Try this Example Sheet
=ArrayFormula(IF(D2:D="",, REGEXEXTRACT(D2:D, "[0-9]+")))
You can use the expression \D+:
\D matches any character that's not a digit (equivalent to [^0-9])
+ matches the previous token between one and unlimited times, as many times as possible, giving back as needed
The formula will be like:
=REGEXREPLACE(D:D, "\D+","")
UPDATE
I did put it in another column otherwise it creates a circular dependency. The data is imported via API from another app.
Then you will need to create another sheet or use a hidden column to put that information and then use the regex on the column you want the final result.
In Google Sheets, I have 2 columns (A and B) of text and I'm trying to set up conditional formatting to identify partial duplicates for when these 2 criteria are both met:
Text in A exactly matches with any other cell in A
and
Any of the individual words in cell B match any of the words in any other cell in B
So, if A2 = "target.com" and B2 = "Big Bonus"
I want it to flag any other cells where A = "target.com" and B = "Bonus Donuts" or "Biggest Exciting Bonus Ever" (because "Bonus" is identified as the duplicate) or "Exciting Big Day" (because "Big" is identified as the duplicate). I need it to be case-agnostic.
Nothing I have tried has even come close to working, so I won't include any of it here.
Sample Data: https://docs.google.com/spreadsheets/d/1DO-0uJRf6MOJ7fJiza5MAmFNIqpCwJ4WMH28j6wp22w/edit#gid=0
I've added a new sheet ("Erik Help") to your sample spreadsheet, with the following custom CF rule applied to the range A3:B ...
=AND($A3=$A$1, REGEXEXTRACT(LOWER($B3),SUBSTITUTE(TRIM(LOWER($B$1))," ","|")))
$A3=$A$1 should be self-explanatory.
For the rest, you see I used LOWER to make the comparisons caps-agnostic. I applied TRIM, just in case you accidentally added any spaces into the B1 string and then just replaced remaining spaces with the pipe symbol, which is interpreted by REGEXEXTRACT as OR.
If you don't want partial word matching (Big in Biggest), try this in the conditional custom formula:
=and($A3=$A$1, regexextract(" "&lower($B3)&" "," "&substitute(lower($B$1)," "," | ")&" "))
Here is an example of a formula I have written:
=DatabaseVerName&"."&INDIRECT(ADDRESS(4,2,1,TRUE,""&B2&"ChangeLog"))
DatabaseVerName is a named range ...It just so happens that the first word in the string (in this case Database), is the value in cell B2. I would like to be able to update the formula so that when I change the value in B2 (say to the word Report) that the formula references the named range "ReportVerName" and not "DatabaseVerName". FWIW, B2 is a a data validated list with 4 options available.
Is this possible and if so how would I do it?
I haven't tested it, but something like this might work.
=INDIRECT(B3 & "VerName") & "." & INDIRECT(ADDRESS(5,2,1,TRUE,""&B3&"ChangeLog"))
So B3 would be equal to "Database" or some other text, and would get concatenated in front of "VerName" to make up the name of a matching named range and then the remaining part of the address, which appears to have been working for you, would be added.
I haven't tested this, but I think it should work. Let us know.
I am trying to do a calculation of two cells, where one of them contains a number like this: 1 250.
If the number is written like that, and not 1250, then I cannot get the spreadsheet to do any calculations with it. Google suddenly do not treat it as a legit number anymore.
Why not just type 1250 instead of 1 250?
Well, I am getting the cell values from a html import function.
Any good advice on how to get around this?
Try something like this:
=Substitute(A2," ","")
In this formula, A2 is a cell. You are finding any spaces in that cell and then replacing it with a "non-space".
Use the substitute function to transform your number before using it in a formula. For instance, let's say you wanted to multiple F8 by 2, but F8 may contain spaces. You would then do:
=substitute(F8, " ","") * 2
Substitute didn't work form me. But these steps did:
Select one or several columns of data
Press Ctrl + H to get the "Find and Replace" dialog
Make sure "Search using regular expressions" is checked ✅
Enter \s to the "Find" field, and leave "Replace with" empty
Click on the "Replace all" button
Explanation:
\s is a regular expression matching any kind of whitespace character. There may have been some other kind of whitespace in my spreadsheet, not a regular " " (space) character, and that's why regex worked for me, while SUBSTITUTE() didn't.
I've also tried the REGEXREPLACE(A2, "\s", "") function, but it didn't seem to to anything in my case.
I have a column in open office like this:
abc-23
abc-32
abc-1
Now, I need to get only the sum of the numbers 23, 32 and 1 using a formula and regular expressions in calc.
How do I do that?
I tried
=SUMIF(F7:F16,"([:digit:].)$")
But somehow this does not work.
Starting with LibreOffice 6.4, you can use the newly added REGEX function to generically extract all numbers from a cell / text using a regular expression:
=REGEX(A1;"[^[:digit:]]";"";"g")
Replace A1 with the cell-reference you want to extract numbers from.
Explanation of REGEX function arguments:
Arguments are separated by a semicolon ;
A1: Value to extract numbers from. Can be a cell-reference (like A1) or a quoted text value (like "123abc"). The following regular expression will be applied to this cell / text.
"[^[:digit:]]": Match every character which is not a decimal digit. See also list of regular expressions in LibreOffice
The outer square brackets [] encapsulate the list of characters to search for
^ adds a NOT, meaning that every character not included in the search list is matched
[:digit:] represents any decimal digit
"": replace matching characters (every non-digit) with nothing = remove them
"g": replace all matches (don't stop after the first non-digit character)
Unfortunately Libre-Office only supports regex in find/replace and in search.
If this is a once-only deal, I would copy column A to column to B, then use [data] [text to columns] in B and use the - as a separator, leaving you with all the text in column B and the numbers in column C.
Alternatively, you could use =Right(A1,find("-",A1,1)+1) in column B, then sum Column C.
I think that this is not exactly what do you want, but maybe it can help you or others.
It is all about substring (in Calc called [MID][1] function):
First: Choose your cell (for example with "abc-23" content).
Secondly: Enter the start length ("british" --> start length 4 = tish).
After that: To print all remaining text, you can use the [LEN][2] function (known as length) with your cell ("abc-23") in parameter.
Code now looks like this:
D15="abc-23"
=MID(D15; 5; LEN(D15))
And the output is: 23
When you edit numbers (in this example 23), no problem. However, if you change anything before (text "abc-"), the algorithm collapses because the start length is defined to "5".
Paste the string in a cell, open search and replace dialog (ctrl + f) extended search option mark regular expression search for ([\s,0-9])([^0-9\s])+ and replace it with $1
adjust regex to your needs
I didn't figure out how to do this in OpenOffice/LibreOffice directly. After frustrations in searching online and trying various formulas, I realised my sheet was a simple CSV format, so I opened it up in vim and used vim's built-in sed-like feature to find/replace the text in vim command mode:
:%s/abc-//g
This only worked for me because there were no other columns with this matching text. If there are other columns with the same text, then the solution would be a bit more complex.
If your sheet is not a CSV, you could copy the column out to a text file and use vim to find/replace, and then paste the data back into the spreadsheet. For me, this was a lot less frustrating than trying to figure this out in LibreOffice...
I won't bother with a solution without knowing if there really is interest, but, you could write a macro to do this. Extract all the numbers and then implement the sum by checking for contained numbers in the text.