Swift regular expression for arabic decimals in arabic text - ios

Question

I have some Arabic text which has some decimals as well.
for example this text
"بِسۡمِ اللّٰہِ الرَّحۡمٰنِ الرَّحِیۡمِ ﴿۱﴾"
"وَاِذَا قِیۡلَ لَہُمۡ اٰمِنُوۡا کَمَاۤ اٰمَنَ النَّاسُ قَالُوۡۤا اَنُؤۡمِنُ کَمَاۤ اٰمَنَ السُّفَہَآءُ ؕ اَلَاۤ اِنَّہُمۡ ہُمُ السُّفَہَآءُ وَلٰکِنۡ لَّا یَعۡلَمُوۡنَ ﴿۱۴﴾"
This text has verse numbers as Arabic digits in the end.
I wanted to find out all the matches for the verse numbers in these verses.
In swift I am tring to use the regular expression but somehow i am not coming up with the correct regex.
Here is my code:
func getRegex() {
// unicode for the arabic digits
let regexStr = "[\u{0660}-\u{0669}]+"
//let regexStr = "[\\p{N}]+"
//let regexStr = "[۹۸۷۶۵۴۳۲۱۰]+"
do {
let regex = try NSRegularExpression(pattern: regexStr, options: .caseInsensitive)
let matches = regex.matches(in: self.arabicText, options: .anchored, range: NSRange(location: 0, length: self.arabicText.count))
print("Matches count : \(matches.count)")
} catch {
print(error)
}
}
Can somebody guide me on how I can get the matches for the Arabic digits in the example Arabic text?

Answer 1

The .anchored argument makes the pattern only match at the start of string, so you need to remove it.
Also, as your string is not ASCII, you need to use self.arabicText.utf16.count string property rather than accessing the self.arabicText.count directly.
So, you can use
let regexStr = "[۹۸۷۶۵۴۳۲۱۰]+"
and then
let matches = regex.matches(in: self.arabicText, options: [], range: NSRange(location: 0, length: self.arabicText.utf16.count))