Two XSL files need single final output file - xslt-2.0

Question

I have a input file and two XSL files test1.xsl, test2.xsl
test1.xsl file transforming on input file and generating test1-output.xml
test2.xsl file transforming on test1-output.xml and generating the final output
Requirement:
I am using XSLT 2.0
I want run at a time both xslt files transform on input file and generate the final output.
How to do this requirement, Please suggest!
Input file:
<?xml version="1.0" encoding="UTF-8"?>
<k>
<page>content here</page>
<page1>content here</page1>
</k>
test1.xsl file:
<?xml version="1.0"qqq encoding="UTF-8"?>
<xsl:stylesheet xmqlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output indent="yes" method="xml"/>
<xsl:template match="#*| node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="page">
<page>
<kita>
<xsl:apply-templates/>
</kita>
</page>
</xsl:template>
</xsl:stylesheet>
output of test1.xsl
<?xml version="1.0" encoding="UTF-8"?>
<k>
<page>
<kita>content here</kita>
</page>
<page1>content here</page1>
</k>
test2.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output indent="yes" method="xml"/>
<xsl:template match="#*| node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="kita">
<kita>
<kita1>
<xsl:apply-templates/>
</kita1>
</kita>
</xsl:template>
</xsl:stylesheet>
This is my final xml output from the 2nd XSLT file:
<?xml version="1.0" encoding="UTF-8"?>
<k>
<page>
<kita>
<kita1>content here</kita1>
</kita>
</page>
<page1>content here</page1>
</k>
Thanks in advance

Answer 1

In XSLT 3 you could write a stylesheet with two parameters calling fn:transform twice e.g.
<xsl:param name="xslt1" as="document-node()"/>
<xsl:param name="xslt2" as="document-node()"/>
<xsl:template match="/">
<xsl:sequence
select="
transform(map {
'stylesheet-node' : $xslt1,
'source-node' : .
})?output ! transform(map {
'stylesheet-node' : $xslt2,
'source-node' : .
})?output"/>
</xsl:template>
or if you want to pass in the file URIs
<xsl:param name="xslt1" as="xs:string">test1.xsl</xsl:param>
<xsl:param name="xslt2" as="xs:string">test2.xsl</xsl:param>
<xsl:template match="/">
<xsl:sequence
select="
transform(map {
'stylesheet-node' : doc($xslt1),
'source-node' : .
})?output ! transform(map {
'stylesheet-node' : doc($xslt2),
'source-node' : .
})?output"/>
</xsl:template>