my problem is that he uses all 3 spawn points instead of only 1 of the 3 that I put there to choose from
YY_Pos = {}
YY_Pos[1] = {m=3017299663, x=1700, y=13154, z=2450}
YY_Pos[2] = {m=3017299663, x=1775, y=12413, z=2436}
YY_Pos[3] = {m=3017299663, x=1775, y=12413, z=2500}
function YY_tmhz_1_OnCreatureDisappear(MapID, InstanceID, Creatur ID, x, y, z)
for i = 1,3 do
local Index_pos = math.random(1,3)
local CreatureID = map.MapCreateCreature(YY_Pos[i].m, InstanceID, 1534207, YY_Pos[i].x, YY_Pos[i].y, YY_Pos[i].z)
end
end
You create a random value Index_pos but you never use it.
Instead you use the loop counter variable i to index your coordinate table.
Also note that the code as is will not use 1 of three coordinates but 3 random coordinates.
You would have to move the math.random call out of the loop if you want to do something 3 times for the same random index.
Related
I need to make a trolleybus number, which won't repeat for game. For example, there is a number "101" and there musn't be more "101". How to do that? I have a code, but I know, he won't work and I won't test it lol
function giveNumber()
local number = math.random(100, 199)
local takedNumbers = {}
local i = 0
local massiv = i+1
script.Parent.pered.SurfaceGui.TextLabel.Text = number
script.Parent.zad.SurfaceGui.TextLabel.Text = number
script.Parent.levo.SurfaceGui.TextLabel.Text = number
script.Parent.pravo.SurfaceGui.TextLabel.Text = number
takedNumbers[massiv] = {number}
end
script.Parent.Script:giveNumber() // what I wrote here? idk...
if number == takedNumbers[massiv] then
giveNumber()
end
i didn't test it, because I think it won't work because this code is something bad
I think this will serve your needs.
In the function generateUniqueNumber, the script loops until it found a number that is not yet in the array. (in other words, that it hasn't given out yet)
Once it found that number, it will insert it into the table to remember that it has given it out, and then it will return the number.
Then on the bottom of the script we just give the numbers to the buses :-)
--[[
Goal: Give all buses a unique number
]]
-- Variables
local takenNumbers = {};
-- This function returns a random number in the range [100, 199] that has not been taken yet
function generateUniqueNumber()
local foundNumber = false;
while not foundNumber do
randomNumber = math.random(100, 199);
if not table.find(takenNumbers, randomNumber) then
table.insert(takenNumbers, randomNumber);
return randomNumber;
end
end
end
-- This function sets the number of the bus
script.Parent.pered.SurfaceGui.TextLabel.Text = tostring(generateUniqueNumber());
script.Parent.zad.SurfaceGui.TextLabel.Text = tostring(generateUniqueNumber());
script.Parent.levo.SurfaceGui.TextLabel.Text = tostring(generateUniqueNumber());
script.Parent.pravo.SurfaceGui.TextLabel.Text = tostring(generateUniqueNumber());
2 things:
I didn't test this code as Roblox is not installed on the pc I'm currently on.
Please try formatting your code nicely next time. It greatly improves the readability! For example, you can use this website:
https://codebeautify.org/lua-beautifier
Simpler
Fill a table with free numbers...
local freenumbers = {}
for i = 1, 99 do freenumbers[i] = i + 100 end
...for every new takennumbers use table.remove() on freenumbers
local takennumbers = {}
if #freenumbers > 0 then
takennumbers[#takennumbers + 1] = table.remove(freenumbers, math.random(1, #freenumbers))
end
Why isn't this working? I'm trying to put all my object tables in a single table and use a forloop to iterate through each of them and draw. It shows an error message saying: "}" expected near "=" at line 5
function love.load()
solidstatic = {
ground = {x = 0,y = 160,width = 1000,height = 1000},
box = {x = 80,y = 100,width = 15,height = 15}
}
end
function love.draw()
for i,obj in ipairs(solidstatic) do
love.graphics.rectangle("fill",obj[x],obj[y],obj[width],obj[height])
end
end
(edit) solved the error problem, I was running the wrong .lua file. But still, it doesn't draw anything on the screen
Two things.
Firstly, you must use pairs instead of ipairs to list keys that are not numbers.
for i, v in pairs(table) do
...
end
You must also index the variables as a string.
t = {
x = 1
}
t['x'] = 1
-- or
t.x = 1
This is because doing it without quotes would be indexing with the global variable x, which doesn't exist.
You need to use pairs instead of ipairs to iterate over elements in solidstatic as there are no array keys in that table.
I have six variables, that these variables have different position on the screen, I wanna put different images in these variables, hence i have an Array with the images.
misImagenes = {[1] = "rec/ro.png",[2] ="rec/az.png",[3] ="rec/ros.png",[4] ="rec/ne.png",[5] ="rec/ve.png",[6] ="rec/am.png"}
I put the elements of this Array into another Array into that have 2 different randoms, like this:
randoms = {[1] = misImagenes[math.random(1,6)],[2] = misImagenes[math.random(1,6)] }
So, I wanna put this randoms of random form, hence, i create an random of the randoms.
randomRan = randoms[math.random(1,2)]
I put the randomRan into the 6 variables, but the images of the variables are always equals.
uno = display.newImageRect(randomRan,340,280)
dos = display.newImageRect(randomRan,340,280)
tres = display.newImageRect(randomRan,340,280)
cuatro = display.newImageRect(randomRan,340,280)
cinco = display.newImageRect(randomRan,340,280)
seis = display.newImageRect(randomRan,340,280)
This variables have the randomRan, but the images are alway equals, i need that the images are differents, 2 differents images in random variables.
Thanks
It looks like what you want to do is commonly called shuffling and filtering an array.
Once you assign randoms[math.random(1,2)] to the randomRan variable, it is going to stay the same no matter what. It isn't like randomRan is going to be random each time it's used. However, if it were a function call, like randomRan(), then that would be a different case, depending on what the function did. A variable, once assigned to, generally stays the same unless changed.
math.randomseed(os.time()) -- Make sure to seed the random number generator.
local function shuffle(t)
local n = #t
while n >= 2 do
-- n is now the last pertinent index
local k = math.random(n) -- 1 <= k <= n
-- Quick swap
t[n], t[k] = t[k], t[n]
n = n - 1
end
return t
end
local misImagenes = {"rec/ro.png", "rec/az.png", "rec/ros.png", "rec/ne.png", "rec/ve.png", "rec/am.png"}
local randomImages = {}
-- Make a copy of misImagenes for randomImages.
for i, v in ipairs(misImagenes) do randomImages[i] = v end
-- Shuffle the new array. This will randomize the order of its contents.
shuffle(randomImages)
-- Since you want only two unique images for a total of six rectangles,
-- we'll have to duplicate and overwrite the other four, randomly.
for i = 1+2, 6 do
randomImages[i] = randomImages[math.random(1, 2)]
end
-- Now to filter the array with newImageRect.
for i=1, #randomImages do
randomImages[i] = display.newImageRect(randomImages[i], 340, 280)
end
-- randomImages now contains all of your randomized image rectangles.
The shuffle algorithm was borrowed from here to show an example of how this could work.
If you are doing
var1 = randomRan
var2 = randomRan
then var1 and var2 will have the same value - randomRan does not get recomputed each time its evaluated. YIf that is what you want, you can repeat the expression you used to initialize randomRan:
var1 = randoms[math.random(1,2)]
var2 = randoms[math.random(1,2)]
and if you want to avoid retyping that ocmplex expression, you can encapsulate it in a function:
--Return a random image
local function randomRan()
return randoms[math.random(1,2)]
end
var1 = randomRan()
var2 = randomRan()
I was working on a script to randomize the data inside of my array but I get and error
that says
unexpected symbol near "#"
When I go to that line, and I remove the "#" I get
attempt to perform arithmetic on local `n' (a table value)
Here is my shuffle function
function shuffle(array)
local array = array
local n = #array
local j
local random = math.random
for i=n-1, 1, -1 do
j = random(i)
array[j],array[i] = array[i],array[j]
end
return array
end
and here is what I am trying to randomize
shuffle(new_players)
for name,character in pairs(new_players) do
if (character.inside == true and character.death == 0) then
local player = getPlayerByName(name, map_copy)
if (player ~= nil) then
addState(player)
break
end
end
end
Here is my array
new_players= { }
new_players[charName] = { death = 0, inside= true }
Any help? If i am doing something completely wrong?
1) Try change charName from string to a number.
2) For shuffle you can use this code:
function swap(array, index1, index2)
array[index1], array[index2] = array[index2], array[index1]
end
function shuffle(array)
local counter = #array
while counter > 1 do
local index = math.random(counter)
swap(array, index, counter)
counter = counter - 1
end
end
If your Lua version is < 5.1 then there is no # operator. Use table.getn instead:
local n = table.getn(array);
(Update) Note that your function, while it does shuffle the items around, it does not really shuffle all elements. Also since you reduce the range with each iteration, you will almost certainly swap the first 10% of your array around multiple times. Now swapping them multiple times is not bad by itself, but that you are, by comparison, almost never swapping the other elements is.
So one option to solve this would be to always use the same range for your random variable. And I would go even further and select two random indexes to swap:
function shuffle(array)
local n, random, j = table.getn(array), math.random
for i=1, n do
j,k = random(n), random(n)
array[j],array[k] = array[k],array[j]
end
return array
end
The other option would be to select random elements from the source array and put them into a new output array:
local rnd,trem,getn,ins = math.random,table.remove,table.getn,table.insert;
function shuffle(a)
local r = {};
while getn(a) > 0 do
ins(r, trem(a, rnd(getn(a))));
end
return r;
end
I have done lots of research on invetory system for point and click game in Lua and corona.
I have come across this example,I am doing something similar to this,but I need a dynamic inventory system.
I mean if I have 4 slots,and all them are full the fifth object go to next slot,so there will be an arrow to the right so I can click on ;and go to the next page.
And imagine there are 5 items,and I have 4 slots,the fifth slot would be on the next page.
I use the third item,and third slot would then be empty,so I want the fourth and fifth item automatically move back to third and fourth slot.
I have hard time figuring this out.
Thanks for advance.
local myInventoryBag={}
local maxItems = 10 -- change this to how many you want
myInventoryBag[5]=3 -- Hammer for instance
myInventoryBag[4]=7 -- A metal Pipe for instance
local function getImageForItem(thisItem)
local itemNumber = tonumber(thisItem)
local theImage=""
if itemNumber==3 then
theImage="hammer.png"
elseif itemNumber == 7 then
theImage="metalpipe.png"
elseif ... -- for other options
...
else
return nil
end
local image = display.newImage(theImage)
return image
end
local function displayItems()
local i
for i=1,#myInventoryBag do
local x = 0 -- calculate based on the i
local y = 0 -- calculate based on the i
local image = getImageForItem(myInventoryBag[i])
if image==nil then return end
image.setReferencePoint(display.TopLeftReferencePoint)
image.x = x
image.y = y
end
end
local itemImages =
{
[0] = display.newImage('MISSING_ITEM_IMAGE.PNG'),
[3] = display.newImage('hammer.png'),
[7] = display.newImage('metalpipe.png'),
}
function getImageForItem(itemId)
return itemImages[itemId] or itemImages[0]
end
local myInventoryBag={}
local maxItems = 10 -- change this to how many you want
local visibleItems = 4 -- show this many items at a time (with arrows to scroll to others)
-- show inventory items at index [first,last]
local function displayInventoryItems(first,last)
local x = 0 -- first item goes here
local y = 0 -- top of inventory row
for i=first,last do
image = getImageForItem(myInventoryBag[i])
image.x = x
image.y = y
x = x + image.width
end
end
-- show inventory items on a given "page"
local function displayInventoryPage(page)
page = page or 1 -- default to showing the first page
if page > maxItems then
-- error! handle me!
end
local first = (page - 1) * visibleItems + 1
local last = first + visibleItems - 1
displayInventoryItems(first, last)
end
myInventoryBag[5] = 3 -- Hammer for instance
myInventoryBag[4] = 7 -- A metal Pipe for instance
displayInventoryPage(1)
displayInventoryPage(2)
Basically what you would do is loop through all the inventory slots and check if the slot is empty. If it's empty, place the item in that slot and stop the loop. If it's not, go to the next one.
If you want to remove an item from the inventory, you can simply call table.delete(myInventoryBag, slotToEmpty).
For pages, you'd simply have a page variable. When drawing the inventory slots, just loop from slots (page-1) * 4 + 1 to page * 4.
(Edit: I'd highly recommend using proper indentation, as it will make the code much much more readable.)