Dart: lists of supertype takes subtype only at runtime - dart

I ran into an issue similar to this:
void main() {
_buildMixedList([1,2.3,4,5.6,7.6,8]);
_buildHomogeneousList([1,2,4,5,7,8]);
}
abstract class NumberWrapper {}
class DoubleWrapper extends NumberWrapper{
final double myDouble;
DoubleWrapper(this.myDouble);
}
class IntWrapper extends NumberWrapper{
final int myInt;
IntWrapper(this.myInt);
}
List<NumberWrapper?> _buildMixedList(List<dynamic> numbers) {
List<NumberWrapper?> wrappers = numbers.map((number) {
if(number is int){
return IntWrapper(number);
}
if(number is double){
return DoubleWrapper(number);
}
return null;
}).toList();
wrappers.add(DoubleWrapper(0.2));
return wrappers;
}
List<NumberWrapper?> _buildHomogeneousList(List<dynamic> numbers) {
List<NumberWrapper?> wrappers = numbers.map((number) {
if(number is int){
return IntWrapper(number);
}
return null;
}).toList();
wrappers.add(DoubleWrapper(0.2));
return wrappers;
}
As you can see, the two methods are doing something similar (adding object of different types to a list). The first one adds different objects inside a map() function and the other adds only one type in map() and then adds another after.
The second one throws this error:
: TypeError: Instance of 'DoubleWrapper': type 'DoubleWrapper' is not a subtype of type 'IntWrapper?'Error: TypeError: Instance of 'DoubleWrapper': type 'DoubleWrapper' is not a subtype of type 'IntWrapper?'
As if the list is being changed to List<IntWrapper?> just because we only added IntWrappers in the map().
I wrote this test code after encountering this in one of my projects, so it's not representative of a real case. I tried it on dartPad.
Coming from a java background I was expecting the second method to work. Is it a bug or is it intended? If intended, why is that so?

Your problem is that there are a difference between the type of the variable and the type of the object which you are pointing to.
So in this case:
List<NumberWrapper?> wrappers = numbers.map((number) {
if(number is int){
return IntWrapper(number);
}
return null;
}).toList();
What you are actually are doing is creating a List<IntWrapper?> which you are using a variable of the type List<NumberWrapper?> to point at. Why? Because the type of the variable in this case does not change the type of the returned List from toList() (which type is determined by what type map() returns).
The reason the type is List<IntWrapper?> is because Dart are trying to be smart about automatically assigning the type. In this case, the analyzer can see you List will only contain IntWrapper or null.
I think the best solution here is to rewrite this part to something like this:
List<NumberWrapper?> _buildHomogeneousList(List<num> numbers) {
final wrappers = <NumberWrapper?>[
for (final number in numbers)
if (number is int) IntWrapper(number) else null
];
wrappers.add(DoubleWrapper(0.2));
return wrappers;
}
By using the [] syntax to create the List, it is easier to specify the type you want the List to be.
Alternative, you can do this where we add the expected type to the map method:
List<NumberWrapper?> _buildHomogeneousList(List<num> numbers) {
List<NumberWrapper?> wrappers = numbers.map<NumberWrapper?>((number) {
if (number is int) {
return IntWrapper(number);
}
return null;
}).toList();
wrappers.add(DoubleWrapper(0.2));
return wrappers;
}

Related

How to override enum's "name" property?

Minimal reproducible code:
enum Foo {
a,
b;
String get name {
switch (this) {
case Foo.a: return 'A';
case Foo.b: return 'B';
}
}
}
void main() {
printEnum<Foo>(Foo.values);
}
void printEnum<T extends Enum>(List<T> list) {
for (var e in list) {
print(e.name);
}
}
The for loop prints
a
b
But I wanted it to print
A
B
So, how do I override the name property in the enum?
Note:
Using (e as Foo).name will solve the issue, but I have many enums in my project, so I can't cast them like this.
Also, please don't post answers like, use toUpperCase(), etc, because I just provided a simple example, but in real world, things are quite different.
You cannot override the name getter "on Enum" because it's an extension getter, not an instance getter.
Overriding, aka. late binding, of instance members only apply to actual (virtual) instance members.
Extension members are statically resolved, so a call of .name either hits the extension member, or it doesn't, and it depends entirely on the static type of the receiver. If you have an Enum e; ... e.name ... then it will call the extension member, and there is absolutely no way to change that, or change what it does.
If you want to have a custom and overridable name getter, I'd introduce an interface like
abstract class NamedEnum extends Enum {
String get name;
}
and then let all your enums implement NamedEnum.
Then you can do (enumValue as NamedEnum).name for any of your enums.
It won't interact with other enum types' extension name getter.
Casting e as dynamic works, as long as you ensure that the name property exists on the enum you are printing. Ex:
void printEnum<T extends Enum>(List<T> list) {
for (var e in list) {
print((e as dynamic).name);
}
}

Equivalent of tuples in Dart [duplicate]

Is there a way to return several values in a function return statement (other than returning an object) like we can do in Go (or some other languages)?
For example, in Go we can do:
func vals() (int, int) {
return 3, 7
}
Can this be done in Dart? Something like this:
int, String foo() {
return 42, "foobar";
}
Dart doesn't support multiple return values.
You can return an array,
List foo() {
return [42, "foobar"];
}
or if you want the values be typed use a Tuple class like the package https://pub.dartlang.org/packages/tuple provides.
See also either for a way to return a value or an error.
I'd like to add that one of the main use-cases for multiple return values in Go is error handling which Dart handle's in its own way with Exceptions and failed promises.
Of course this leaves a few other use-cases, so let's see how code looks when using explicit tuples:
import 'package:tuple/tuple.dart';
Tuple2<int, String> demo() {
return new Tuple2(42, "life is good");
}
void main() {
final result = demo();
if (result.item1 > 20) {
print(result.item2);
}
}
Not quite as concise, but it's clean and expressive code. What I like most about it is that it doesn't need to change much once your quick experimental project really takes off and you start adding features and need to add more structure to keep on top of things.
class FormatResult {
bool changed;
String result;
FormatResult(this.changed, this.result);
}
FormatResult powerFormatter(String text) {
bool changed = false;
String result = text;
// secret implementation magic
// ...
return new FormatResult(changed, result);
}
void main() {
String draftCode = "print('Hello World.');";
final reformatted = powerFormatter(draftCode);
if (reformatted.changed) {
// some expensive operation involving servers in the cloud.
}
}
So, yes, it's not much of an improvement over Java, but it works, it is clear, and reasonably efficient for building UIs. And I really like how I can quickly hack things together (sometimes starting on DartPad in a break at work) and then add structure later when I know that the project will live on and grow.
Create a class:
import 'dart:core';
class Tuple<T1, T2> {
final T1 item1;
final T2 item2;
Tuple({
this.item1,
this.item2,
});
factory Tuple.fromJson(Map<String, dynamic> json) {
return Tuple(
item1: json['item1'],
item2: json['item2'],
);
}
}
Call it however you want!
Tuple<double, double>(i1, i2);
or
Tuple<double, double>.fromJson(jsonData);
You can create a class to return multiple values
Ej:
class NewClass {
final int number;
final String text;
NewClass(this.number, this.text);
}
Function that generates the values:
NewClass buildValues() {
return NewClass(42, 'foobar');
}
Print:
void printValues() {
print('${this.buildValues().number} ${this.buildValues().text}');
// 42 foobar
}
The proper way to return multiple values would be to store those values in a class, whether your own custom class or a Tuple. However, defining a separate class for every function is very inconvenient, and using Tuples can be error-prone since the members won't have meaningful names.
Another (admittedly gross and not very Dart-istic) approach is try to mimic the output-parameter approach typically used by C and C++. For example:
class OutputParameter<T> {
T value;
OutputParameter(this.value);
}
void foo(
OutputParameter<int> intOut,
OutputParameter<String>? optionalStringOut,
) {
intOut.value = 42;
optionalStringOut?.value = 'foobar';
}
void main() {
var theInt = OutputParameter(0);
var theString = OutputParameter('');
foo(theInt, theString);
print(theInt.value); // Prints: 42
print(theString.value); // Prints: foobar
}
It certainly can be a bit inconvenient for callers to have to use variable.value everywhere, but in some cases it might be worth the trade-off.
you can use dartz package for Returning multiple data types
https://www.youtube.com/watch?v=8yMXUC4W1cc&t=110s
Dart is finalizing records, a fancier tuple essentially.
Should be in a stable release a month from the time of writing.
I'll try to update, it's already available with experiments flags.
you can use Set<Object> for returning multiple values,
Set<object> foo() {
return {'my string',0}
}
print(foo().first) //prints 'my string'
print(foo().last) //prints 0
In this type of situation in Dart, an easy solution could return a list then accessing the returned list as per your requirement. You can access the specific value by the index or the whole list by a simple for loop.
List func() {
return [false, 30, "Ashraful"];
}
void main() {
final list = func();
// to access specific list item
var item = list[2];
// to check runtime type
print(item.runtimeType);
// to access the whole list
for(int i=0; i<list.length; i++) {
print(list[i]);
}
}

Multiple types for a single variable (parameter/return type)

I am very new to Dart so excuse me if I didnt see this part.
I want to make a union type e.g. for a function input. In TS this would be:
let variableInput: string | number
typedef doesnt really define types but functions and enums dont really help too.
On the other side how should it look like when a function return either one or the other of two types? There must be something I dont see here.
There are no union types in Dart.
The way to do this in Dart is returning/accepting dynamic as a type:
dynamic stringOrNumber() { ... }
void main() {
final value = stringOrNumber();
if (value is String) {
// Handle a string value.
} else if (value is num) {
// Handle a number.
} else {
throw ArgumentError.value(value);
}
}
See also: https://dart.dev/guides/language/sound-dart

Syntax error when trying to determine if a variable is of a certain type

Pretty much as the title says: If you have a Type stored in a variable, there's no way to compare your actual object to this type variable, as far as I can tell. I can probably accomplish what I'm trying to do with mirrors, but I'd prefer not to if at all possible.
void example() {
Type myType = String;
String myExample = "Example";
//Syntax error here: The name 'myType' is not a type and cannot be used in an 'is' expression
if (myExample is myType) {
}
}
You can't generally test if a value is of a type using the Type object.
Type objects are reflected types, not real types. They represent the real type, but you can't use them in the code where you need a type: as type assertions, as generic type parameters or with the is/as operators. You must use the name of a type in those places, and not the name of a normal variable that happens to hold a Type object.
Clever stuff using mirrors might get there, but it's likely overkill for most cases (and I understand that you don't want it).
What you might be able to do instead, is to not pass around raw Type objects. You could instead make your own type abstraction, something like:
class MyType<T> {
const MyType();
Type get type => T;
bool isA(Object object) => object is T;
}
Then you can use that to represent types, not a Type object, and do something like:
void main(List<String> args) {
MyType myType = const MyType<String>();
String myExample = "Example";
if(myType.isA(myExample)) {
print('is');
} else {
print('is not');
}
}
That does require that your entire program uses your type objects to pass around types, but it also gives you a lot of control over those objects, so you can implement the functionality that you need.
I tried
library x;
void main(List<String> args) {
Type myType = String;
String myExample = "Example";
if(myExample.runtimeType == myType) {
print('is');
} else {
print('is not');
}
}
and it worked.
I have not much experience with such code in Dart though. Maybe that is not a fail-safe approach.
import 'package:reflection/reflection.dart';
void main() {
var childType = typeInfo(Child);
var baseType = typeInfo(Base);
if(childType.isA(baseType)) {
print("Child is Base");
}
if(baseType.isAssignableFrom(childType)) {
print("Base is assignable from Child");
}
}
class Base {
}
class Child extends Base {
}
Child is Base
Base is assignable for Child
P.S.
The "reflection" package incompatible with dart2js. It work only when used in Dart language.

Is there a way to pass a primitive parameter by reference in Dart?

I would like to pass a primitive (int, bool, ...) by reference. I found a discussion about it (paragraph "Passing value types by reference") here: value types in Dart, but I still wonder if there is a way to do it in Dart (except using an object wrapper) ? Any development ?
The Dart language does not support this and I doubt it ever will, but the future will tell.
Primitives will be passed by value, and as already mentioned here, the only way to 'pass primitives by reference' is by wrapping them like:
class PrimitiveWrapper {
var value;
PrimitiveWrapper(this.value);
}
void alter(PrimitiveWrapper data) {
data.value++;
}
main() {
var data = new PrimitiveWrapper(5);
print(data.value); // 5
alter(data);
print(data.value); // 6
}
If you don't want to do that, then you need to find another way around your problem.
One case where I see people needing to pass by reference is that they have some sort of value they want to pass to functions in a class:
class Foo {
void doFoo() {
var i = 0;
...
doBar(i); // We want to alter i in doBar().
...
i++;
}
void doBar(i) {
i++;
}
}
In this case you could just make i a class member instead.
No, wrappers are the only way.
They are passed by reference. It just doesn't matter because the "primitive" types don't have methods to change their internal value.
Correct me if I'm wrong, but maybe you are misunderstanding what "passing by reference" means? I'm assuming you want to do something like param1 = 10 and want this value to still be 10 when you return from your method. But references aren't pointers. When you assign the parameter a new value (with = operator), this change won't be reflected in the calling method. This is still true with non-primitive types (classes).
Example:
class Test {
int val;
Test(this.val);
}
void main() {
Test t = new Test(1);
fn1(t);
print(t.val); // 2
fn2(t);
print(t.val); // still 2, because "t" has been assigned a new instance in fn2()
}
void fn1(Test t) {
print(t.val); // 1
t.val = 2;
}
void fn2(Test t) {
t = new Test(10);
print(t.val); // 10
}
EDIT
I tried to make my answer more clear, based on the comments, but somehow I can't seem to phrase it right without causing more confusion. Basically, when someone coming from Java says "parameters are passed by reference", they mean what a C/C++ developer would mean by saying "parameters are passed as pointers".
As dart is compiled into JavaScript, I tried something that works for JS, and guess what!? It worked for dart!
Basically, what you can do is put your value inside an object, and then any changes made on that field value inside that function will change the value outside that function as well.
Code (You can run this on dartpad.dev)
main() {
var a = {"b": false};
print("Before passing: " + a["b"].toString());
trial(a);
print("After passing: " + a["b"].toString());
}
trial(param) {
param["b"] = true;
}
Output
Before passing: false
After passing: true
One of the way to pass the variables by reference by using the values in List. As arrays or lists are Pass by reference by default.
void main() {
List<String> name=['ali' ,'fana'];
updatename(name);
print(name);
}
updatename(List<String> name){
name[0]='gufran';
}
Try this one, This one of the simplest way to pass by reference.
You can use ValueNotifier
And, you can pass it as ValueListenable to classes or methods that needs to know up-to-date value, but should not edit it:
class Owner {
final theValue = ValueNotifier(true);
final user = User(theValue);
...
}
class User {
final ValueListeneble<bool> theValue;
User(this.theValue);
...
}
It provides more functionality than actually needed, but solves the problem.
If ValueNotifier + ValueListenable do not work for you (you want to make sure the client does not listen to every change of the value, or your package is pure Dart package and thus cannot reference Flutter libraries), use a function:
class Owner {
int _value = 0;
int getValue() => _value;
void increase() => _value++;
}
void main() {
final owner = Owner();
int Function() obtainer = owner.getValue;
print(obtainer());
owner.increase();
print(obtainer());
}
Output will be:
0
1
This approach has memory usage related downside: the obtainer will hold the reference to the owner, and this, even if owner is already not referenced, but obtainer is still reachable, owner will be also reachable
and thus will not be garbage collected.
If you do not want the downside, pass the smaller container than the entire owner:
import 'package:flutter/foundation.dart';
class ListenableAsObtainer<T> implements ValueObtainer<T> {
ListenableAsObtainer(this._listenable);
final ValueListenable<T> _listenable;
#override
T get value => _listenable.value;
}
class FunctionAsObtainer<T> implements ValueObtainer<T> {
FunctionAsObtainer(this._function);
final T Function() _function;
#override
T get value => _function();
}
class ValueAsObtainer<T> implements ValueObtainer<T> {
ValueAsObtainer(this.value);
#override
T value;
}
/// Use this interface when the client needs
/// access to the current value, but does not need the value to be listenable,
/// i.e. [ValueListenable] would be too strong requirement.
abstract class ValueObtainer<T> {
T get value;
}
The usage of FunctionAsObtainer will still result in holding the owner from garbage collection, but two other options will not.
Just to make it clear:
void main() {
var list1 = [0,1,2];
var modifiedList1 = addMutable(list1, 3);
var list2 = [0,1,2];
var modifiedList2 = addImmutable(list2, 3);
print(list1);
print(modifiedList1);
print(list2);
print(modifiedList2);
}
List<int> addMutable(List<int> list, int element){
return list..add(element);
}
List<int> addImmutable(List<int> list, int element){
return [...list, element];
}
Output:
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2]
[0, 1, 2, 3]
All variables are passed by value. If a variable contains a primitive (int, bool, etc.), that's it. You got its value. You can do with it whatever you want, it won't affect the source value. If a variable contains an object, what it really contains is a reference to that object.
The reference itself is also passed by value, but the object it references is not passed at all. It just stayed where it was. This means that you can actually make changes to this very object.
Therefore, if you pass a List and if you .add() something to it, you have internally changed it, like it is passed by reference. But if you use the spread operator [...list], you are creating a fresh new copy of it. In most cases that is what you really want to do.
Sounds complicated. Isn't really. Dart is cool.

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