Connection to tcp://localhost:8554?timeout=0 failed: Cannot assign requested address - docker

Question

I have two docker containers. The first one I run using this command:
docker run -d --network onprem_network --name rtsp_simple_server --rm -t -e RTSP_PROTOCOLS=tcp -p 8554:8554 aler9/rtsp-simple-server
The second docker is created from these files:
Dockerfile:
FROM python:slim-buster
ENV PYTHONUNBUFFERED 1
ENV PYTHONDONTWRITEBYTECODE 1
WORKDIR /code
COPY rtsp_streaming.py /code/
COPY ConsoleCapture_clipped.mp4 /code
RUN apt update && apt-get update && apt install ffmpeg -y # && apt-get install ffmpeg libsm6 libxext6 -y
CMD ["python", "/code/rtsp_streaming.py"]
rtsp_streaming.py:
import os
os.system("ffmpeg -re -stream_loop 0 -i ConsoleCapture_clipped.mp4 -c copy -f rtsp rtsp://localhost:8554/mystream")
I run the second docker container like so:
docker run --network onprem_network -v ${data_folder}:/code/Philips_MR --name rtsp_streaming -d rtsp_streaming
docker ps -a yields:
CONTAINER ID IMAGE COMMAND CREATED STATUS PORTS NAMES
48ea091b870d rtsp_streaming "python /code/rtsp_s…" 18 minutes ago Exited (0) 18 minutes ago rtsp_streaming
5376e070f89f aler9/rtsp-simple-server "/rtsp-simple-server" 19 minutes ago Up 19 minutes 0.0.0.0:8554->8554/tcp rtsp_simple_server
The second container exits quickly with this error:
Connection to tcp://localhost:8554?timeout=0 failed: Cannot assign
requested address
Any suggestions how to fix this?

Answer 1

You should use rtsp_simple_server:8554 instead of localhost.
Since in the container called rtsp_streaming, localhost means rtsp_streaming and in rtsp_simple_server, localhost means rtsp_simple_server`. So you should use the container's name.