Cypher select vertices whose any neighbours do not contain a property - neo4j

Question

{
"identity": 7,
"labels": [
"Parent"
],
"properties": {
"name": "foo1"
}
},
{
"identity": 8,
"labels": [
"Child"
],
"properties": {
"name": "bar2"
}
},
{
"identity": 9,
"labels": [
"Child"
],
"properties": {
"name": "bar1"
}
},
{
"identity": 10,
"labels": [
"Parent"
],
"properties": {
"name": "foo2"
}
}
I want to select the Parents which do not have any child with name='abc'
Expected Behaviour : I should get both Parents (foo1 and foo2) as result
Query1 :
Match (x1:Parent) with x1
optional Match (x1)-[:CHILD]-(x2:Child) with x1 , collect(x2) as x3
UNWIND x3 as x2
WITH x1 , x2 , x3
where none (x IN x3 where x.name IN ['abc'])
return DISTINCT x1
This query is returning me only 1 Parent(foo1) but it should return both parents and 2nd parent(foo2) is not connected to any child.
PS : Reason for using UNWIND is to use the variables for further WHERE clauses on variable x2.

Answer 1

This will get all Parents without a child name: 'abc' or without any child
MATCH (p:Parent)
WHERE NOT EXISTS((p)-[:CHILD]->(:Child {name: 'abc'}))
RETURN p
Check if the given parent, p has a child not named: 'abc'
==========
EDITED:
Personally I dislike this query because it is collecting x2 then unwinding it later. But for sake of answering the SO question,
Match (x1:Parent) with x1
optional Match (x1)-[:CHILD]->(x2:Child) with x1 , collect({x1:x1, x2:x2}) as x3
UNWIND x3 as x2
WITH x2.x1 as x1, x2.x2 as x2, x3
where NOT x2.name IN ['abc'] OR x2 is NULL
RETURN distinct x1
I collected BOTH x1 and x2 then UNWIND the collection by getting x1
and x2 during unwind. This will include other nodes that has no x2
(without a CHILD). I also simplified the where condition because x2 is also accessible rather than looping again on x3