I need to return a two column table from query where the first column shows the position order and then full name. So essentially in MySQL form it would be an autoincrement but I cannot get it to work. I'm using =arrayformula(QUERY({G4:G18, arrayformula(row(G4:G18)) & ". " & H4:H18&" "&I4:I18, J4:J18}, "SELECT Col2, Col3 WHERE Col1 = 'Yes' ORDER BY Col3 ASC LABEL Col2 '', Col3 ''")) which I realize the row(G4:G18) is just going to return the row number but I've tried everything else I can think of and can't get it to work. Any help is greatly appreciated. Note: I want to keep this in query form versus filter for various reasons. thanks.
Sample sheet to see in action
I have come up with a solution but to do it, I need to have 2 queries. 1 that returns the Full name with incrementing numbers, and the other one which returns the Person ID. Please see screenshots below:
1st query(for Full names with incrementing numbers):
=INDEX(arrayformula(ifna(arrayformula(row(G4:G18)-3) & ". " & QUERY({G4:G18, H4:H18&" "&I4:I18, J4:J18}, "SELECT Col2, Col3 WHERE Col1 = 'Yes' ORDER BY Col3 ASC LABEL Col2 '', Col3 ''"), "")), 0, 1)
2nd query(for the Person ID)
=INDEX(arrayformula(QUERY({G4:G18, H4:H18&" "&I4:I18, J4:J18}, "SELECT Col2, Col3 WHERE Col1 = 'Yes' ORDER BY Col3 ASC LABEL Col2 '', Col3 ''")), 0, 2)
They are basically the same query, but I split them into two in order to concatenate an incrementing value to the Full names. I tried doing it using only 1 query but what happens is that the incrementing value will also be seen in the Person ID column(eg. 1. 2, 2. 3, 3. 5). Please let me know if this solution solves your problem.
Related
I'm not too savvy with programming, so bear with me. The data is of the players' names and fighters in a fighting game, with the table as below:
I'm making a leaderboard where it will show which fighter each player uses most. I found a formula that shows which fighter is used the most in general using the following formula:
=index(query({E2:E,G2:G},
"select Col1,count(Col1)
group by Col1
order by count(Col1) desc"), 2, 1)
The problem is, I don't understand how to make a formula that checks the player's name before returning the most used fighter from two columns. What I'm after is a result like so:
Thanks in advance!
Formula
=ArrayFormula(
{QUERY(QUERY({SPLIT("Wins"&"|"&UNIQUE({D2:D;F2:F}&"|"&"."),"|");SPLIT("Loss"&"|"&UNIQUE({D2:D;F2:F}&"|"&"."),"|");
SPLIT("Wins"&"|"&FILTER(D2:D&"|"&E2:E,D2:D<>""),"|");
SPLIT("Loss"&"|"&FILTER(F2:F&"|"&G2:G,F2:F<>""),"|")},
"select Col2,count(Col3)-1 where Col2!='.' group by Col2 pivot Col1"),"select Col1,Col3,Col2,Col3/Col2,Col3/(Col3+Col2) order by Col3 desc label Col1 'Name',Col2 'Loss',Col3 'Wins',Col3/Col2 'W/L',Col3/(Col3+Col2) 'Win Rate %' format Col3/Col2 '0.0',Col3/(Col3+Col2) '#.0%'"),
VLOOKUP(INDEX(QUERY({D2:D},"select Col1,count(Col1) where Col1!='' group by Col1 order by count(Col1) desc label Col1 'Name'"),0,1),QUERY({D2:E;F2:G},"select Col1,Col2,count(Col2) group by Col1,Col2 order by Count(Col2) desc label Col1 'Name',Col2 'Most Used Character'"),2,0)})
Note:
column Wins/Loss cannot be calculated when Loss=0 .
Hope you're okay with that
I know the code to find the most frequent value in a single column, but I'm trying to figure out the code that lets me find the most frequent value in multiple specific columns.
For example:
=ARRAYFORMULA(INDEX(A2:A17,MATCH(MAX(COUNTIF(A2:A17,A2:A17)),COUNTIF(A2:A17,A2:A17),0)))
^^this formula only allows me to have two arguments for COUNTIF
=INDEX(A2:A6,MODE(MATCH(A2:A6,A2:A6,0)))
^^this one only allows 4 arguments max in the index
I want an equation that'll allow me to find the most frequent text value for 16 specific columns.
Is that even possible?
BETTER FORMULA
You asked for formula when you have 2 top values with the same frequency
=SORTN(QUERY(FLATTEN(H2:K),
"select Col1, count(Col1)
where Col1 is not null group by Col1
order by count(Col1) desc label count(Col1) '' ",0),1,1,2,0)
First answer
Use only 1 QUERY formula
For top value
=QUERY(FLATTEN(A2:D),
"select Col1, count(Col1)
where Col1 is not null group by Col1
order by count(Col1) desc limit 1",0)
For all values
=QUERY(FLATTEN(A2:D),
"select Col1, count(Col1)
where Col1 is not null group by Col1
order by count(Col1) desc limit 1",0)
I show it in 2 steps then combine steps together in one formula:
First you flatten table and remove duplicates to get a column of values you check frequency for:
unique(flatten(B2:I25))
Then for each one you check number of occurences:
ArrayFormula(countif($B$2:$I$25,unique(flatten(B2:I25))))
Then you have to filter new table and get only rows with highest values:
=filter({first , second column};second column = max(second column)
Using earlier values:
=filter({unique(flatten(B2:I25)),ArrayFormula(countif($B$2:$I$25,unique(flatten(B2:I25))))},ArrayFormula(countif($B$2:$I$25,unique(flatten(B2:I25))))=max(ArrayFormula(countif($B$2:$I$25,unique(flatten(B2:I25))))))
My solution is available here:
https://docs.google.com/spreadsheets/d/1gMZDFWOY8qbA1Bhp8rZ_por3Skb0i_qQtlaSlCTKXgM/copy
If your columns are scattered around your sheet, you should use { } and make a table of them.
I'm looking for a formula, =query possibly, that will turn this:
Into this:
I used the following formula successfully to get the AFTER picture, but I can't get the counts. I tried using concatenate but there isn't a way to do that to each item in the array. Maybe there is a way to do this using a query?
=transpose(split(join(",",unique(C1:C98)),","))
And here's my flavour of it, which also needs to be dragged to the right, to fill the other columns:
=ARRAYFORMULA(QUERY(
{UNIQUE(A$2:A) & " - " & COUNTIF(A$2:A,UNIQUE(A$2:A))},
"where Col1<>' - 0'",0))
Yes, you can use query to get the unique values and counts then join the two columns
=ArrayFormula(index(query(A2:A,"select A,count(A) where A is not null group by A label count(A) ''"),0,1)&"-"&index(query(A2:A,"select A,count(A) where A is not null group by A label count(A) ''"),0,2))
Apologies, in order to drag it across you would have to put:
=ArrayFormula(index(query({A2:A},"select Col1,count(Col1) where Col1 is not null group by Col1 label count(Col1) ''"),0,1)
&"-"&index(query({A2:A},"select Col1,count(Col1) where Col1 is not null group by Col1 label count(Col1) ''"),0,2))
Try the following in cell A2 and drag to the right.
=ARRAY_CONSTRAIN(ArrayFormula(IFERROR(CONCAT(UNIQUE(A2:A99)&" - ",
ArrayFormula(COUNTIFS(A2:A99,UNIQUE(A2:A99)))))),COUNTUNIQUE(A2:A99),1)
Also using a query
=ArrayFormula(index(query({A2:A},"select Col1,count(Col1) where Col1 is not null group by Col1 label count(Col1) ''"),0,1)&"-"&
index(query({A2:A},"select Col1,count(Col1) where Col1 is not null group by Col1 label count(Col1) ''"),0,2))
The only difference is that using the first formula you maintain the names within the order they appear, while using the query they get sorted alphabetically.
Functions used:
ARRAY_CONSTRAIN
ArrayFormula
IFERROR
CONCAT
UNIQUE
COUNTIFS
COUNTUNIQUE
When I use the format that I left below, returns in error, I know that something is missing adjusting in relation to WHERE AND... But I could not fit to supply the error.
I would like some help knowing what I missed.
"select Col1,Col2,Col3 where Col1 is not null Order by Col1, Col2 AND Col1 > date'"&TEXT(today()-1,"yyyy/mm/dd")&"'"
The date and time for Col1 and Col2 are like this:
With this formula, I hope I can filter the imported data only for those that have the date of the current day or tomorrow and that today's games are higher than the current time.
Link to spreadsheet:
https://docs.google.com/spreadsheets/d/15T4UPVtEHv43DLomKcTmdaPuGWMsBUoO7bLvlOhab4k/edit?usp=sharing
Formula set in Página1 G2
it may look like you can combine parameters as you like but there is a specific order that needs to be followed:
respectively joining operator like and needs to be proceeded by parent parameter where:
Try:
"select Col1, Col2, Col3 where Col1 >='"&TEXT(TODAY()-1,"yyyy-mm-dd")&"' and Col1 is not null Order by Col1, Col2"
This returns 78 records
In cell C1:C of my table I got 6 rows with ticket id's. I like to search different spreadsheets to search for those ticket id's and calculate the total hours spent on that ticket.
I have it working using the following formula:
=QUERY({IMPORTRANGE("SPREADSHEETID";"B3:B")\ARRAYFORMULA(TO_PURE_NUMBER(IMPORTRANGE("SPREADSHEETID";"F3:F")-IMPORTRANGE("SPREADSHEETID";"E3:E")))};"SELECT SUM(Col2) WHERE Col1 = '"&C1&"' GROUP BY Col1 LABEL SUM(Col2) ''")
In this example, C1 is where the ticket ID can be found.
Now I thought I could just wrap QUERY in a ARRAYFORMULA and use C1:C instead of just C1 but that won't work. Now I could just copy and paste the above formula in every cell but there must be a cleaner way.
ANSWER
I used the following formula to make it work, thanks to Max's answer below.
=QUERY(
{
IMPORTRANGE("SPREADSHEETID";"B3:B")\
ARRAYFORMULA(
TO_PURE_NUMBER(
IMPORTRANGE("SPREADSHEETID";"F3:F") - IMPORTRANGE("SPREADSHEETID";"E3:E")
)
)
};
"
SELECT Col1, SUM(Col2)
WHERE Col1 = '" & JOIN("' OR Col1 = '";FILTER(C:C; C:C <> "")) & "'
GROUP BY Col1
LABEL SUM(Col2) ''
")
Sample formula is:
=QUERY({A:B},"select * where Col1 = '"&JOIN("' or Col1 = '",FILTER(D2:D,D2:D<>""))&"'")
No, one cannot create an array of query strings and use arrayformula(query(...)) to run them all at once.
Alternative: instead of
SELECT SUM(Col2) WHERE Col1 = '"&C1&"' GROUP BY Col1 LABEL SUM(Col2) ''
use the query
SELECT Col1, SUM(Col2) GROUP BY Col1
elsewhere on the sheet, and then use vlookup to look up the sum for each value of Col1 that you want. vlookup can be used inside of arrayformula like this:
=arrayformula(vlookup(C1:C10, E:F, 2, 0))
looks up each of values in C1..C10 in the column E (exact match required) and returns the corresponding value in column F (2nd column of the searched range).