Related
I have a sheet with a column of data where the entry is one of two strings, for simplicity's sake we'll say "A" and "B". I want another column of calculated data which is the differential between the number of "A"s and the number of "B"s up to that point, so just a countif()-countif() with the range increasing by one row. I can do this using =countif(A$2:A2, "A") - countif(A$2:A2, "B"), but it means I have to keep filling that equation down to cover any newly entered data, so I figured an array formula would be the best option to not have to do that. However when I try to use =arrayformula(countif(A$2:A, "A") - countif(A$2:A, "B")), it only populates a single cell with the difference counting the entire column. Is there a way to use an array formula so that it increases the range by one row for every row it populates?
=ARRAYFORMULA("A2:A"&ROW(A2:A))
This will give a dynamic string for the right range, which in theory, you should be able to wrap with INDIRECT, to plug into COUNTIF.
But COUNTIF only works in some circumstances with ARRAY FORMULA
Unfortunately, AFAIK, only if you use COUNTIF like this:
=ARRAYFORMULA(COUNTIF(A1:A100,A1:A100))
will it work as an array formula. Note how both the ranges in the arguments are the same.
MMULT
There may be a way along these lines with MMULT:
=ARRAYFORMULA(
MMULT(
(A2:A100 = TRANSPOSE(A2:A100)) * (ROW(A2:A100) >= TRANSPOSE(ROW(A2:A100))),
SIGN(ROW(A2:A100))
)
)
But I couldn't get that to work because I am not 100% sure on how to use MMULT in this way, but I have seen that type of solution elsewhere.
An Apps Script Workaround
As you have seen, what you want to achieve with sheet functions quickly gets very complicated. If you wanted to use more letters or different rules, it would get tough to maintain. Apps Script can make these things much simpler.
So here is a custom Apps Script function:
function myFunction() {
// Initializing
let file = SpreadsheetApp.getActive();
let sheet = file.getSheetByName("Sheet1");
var lastRow = sheet.getLastRow();
// This is the range of the As and Bs
let range = sheet.getRange(2,1, parseInt(lastRow) - 1,1)
let rows = range.getValues();
// Creating an object to keep track of the count
let tracker = {}
// This will be the output column
let newCol = []
rows.forEach(row => {
tracker[row[0]] += 1
// Adding a row to the output
newCol.push([tracker.A - tracker.B])
})
return newCol
}
Paste that into the script editor and you can use it like this:
Demo:
You can change the name of the function in the script editor according to what you need it for, just remember to call it with that name from the sheet.
References
Main Page
Sheets Guide
Tutorials
Sheets Reference
INDIRECT
MMULT
try:
=ARRAYFORMULA(
COUNTIFS(A2:A, A2:A, A2:A, "A", ROW(A2:A), "<="&ROW(A2:A))-
COUNTIFS(A2:A, A2:A, A2:A, "B", ROW(A2:A), "<="&ROW(A2:A)))
Alternatively, you may this IF statement:
=ARRAYFORMULA(IF(K2:K<>"",K2:K*B294,""))
Results (Above formula is applied on L2 row onwards):
Source: https://blog.sheetgo.com/google-sheets-formulas/arrayformula-google-sheets/
I have a Google Sheet that is populated automatically via Zapier integration. For each new row added, I need to evaluate a given cell (Shipper Name) to find last instance of Shipper Name in prior rows, and if so, return Row# for the last entry.
Example Data Sheet
I am trying to create a formula that simply looks at name in new row and returns the number of the most recent row with that name.
Formula needs to run as an Array formula so that the data auto populates with each new row added to the Sheet.
I have tried to use this formula, but when refactored as Array formula, it doesn't populate new values for new rows, it just repeats the first value for all rows.
From Row J:
=sumproduct(max(row(A$1:A3)*(F4=F$1:F3)))
I need this formula refactored to be an Array formula that auto populates all the cells below it.
I have tried this version, but it doesn't work:
=ArrayFormula(IF(ISBLANK($A2:$A),"",sumproduct(max(row(A$1:A3)*($F4:$F=F$1:F3))))
A script (custom function maybe?) would be better.
Solution 1
Below is a formula you can place into the header (put in in J1, remove everything below).
It works much faster than the second solution and has no N² size restriction. Also it works with empty shippers (& "♥" is for those empty ones): as long as A:A column has some value it will not be ignored.
={
"Row of Last Entry";
ARRAYFORMULA(
IF(
A2:A = "",
"",
VLOOKUP(
ROW(F2:F)
+ VLOOKUP(
F2:F & "♥",
{
UNIQUE(F2:F & "♥"),
SEQUENCE(ROWS(UNIQUE(F2:F)))
* POWER(10, INT(LOG10(ROWS(F:F))) + 1)
},
2,
0
),
SORT(
{
ROW(F2:F) + 1
+ VLOOKUP(
F2:F & "♥",
{
UNIQUE(F2:F & "♥"),
SEQUENCE(ROWS(UNIQUE(F2:F)))
* POWER(10, INT(LOG10(ROWS(F:F))) + 1)
},
2,
0
),
ROW(F2:F);
{
SEQUENCE(ROWS(UNIQUE(F2:F)))
* POWER(10, INT(LOG10(ROWS(F:F))) + 1),
SEQUENCE(ROWS(UNIQUE(F2:F)), 1, 0, 0)
}
},
1,
1
),
2,
1
)
)
)
}
Details on how it works
For every row we use VLOOKUP to search for a special number in a sorted virtual range to get the row number of the previous entry matching current.
A special number for a row is constructed like this: we get a sequential number for the current entry among unique entries and append to it current row number.
The right part (row number) of the resulting special numbers must be aligned between them. If the entry has sequential number 13 and the row number is 1234 and there are 100500 rows, then the number must be 13001234. 001234 is the aligned right part.
Alignment is done by multiplying a sequential number by 10 to the power of (log10(total number of rows) + 1), gives us 13000000 (from the example above). This approach is used to avoid using LEN and TEXT - working with numbers is faster then working with strings.
Virtual range has almost the same special numbers in the first column and original row numbers in the second.
Almost the same special numbers: they just increased by 1, so VLOOKUP will stop at most one step before the number corresponding to the current string.
Also virtual range has some special rows (added at the bottom before sorting) which have all 0's as the right part of their special numbers (1st column) and 0 for the row number (2nd column). That is done so VLOOKUP will find it for the first occurrence of the entry.
Virtual range is sorted, so we could use is_sorted parameter of the outer VLOOKUP set to 1: that will result in the last match that is less or equal to the number being looked for.
& "♥" are appended to the entries, so that empty entries also will be found by VLOOKUP.
Solution 2 - slow and has restrictions
But for some small enough number of rows this formula works (put in in J1, remove everything below):
={
"Row of Last Entry";
ARRAYFORMULA(
REGEXEXTRACT(
TRANSPOSE(QUERY(TRANSPOSE(
IF(
(FILTER(ROW(F2:F), F2:F <> "") > TRANSPOSE(FILTER(ROW(F2:F), F2:F <> "")))
* (FILTER(F2:F, F2:F <> "") = TRANSPOSE(FILTER(F2:F, F2:F <> ""))),
TRANSPOSE(FILTER(ROW(F2:F), F2:F <> "")),
""
)
), "", ROWS(FILTER(F2:F, F2:F <> "")))),
"(\d*)\s*$"
)
)
}
But there is a problem. The virtual range inside of the formula is of size N², where N is the number of rows. For current 1253 rows it works. But there is a limit after which it will throw an error of a range being too large.
That is the reason to use FILTER(...) and not just F2:F.
Here is a significantly simpler way to get at the information you're interested in. (I think.) I'm mostly guessing about what you want because your question wasn't really about what you want, but rather about how to get something that you think would help you get what you want. This is an example of an XY problem. I attempted to guess based on experience at what you're really after.
This editable sheet contains just 3 formulas. 2 on the raw data sheet and one in a new tab called "analysis."
The first formula on the Raw data tab extracts a properly formatted timestamp using a combination of MMULT and SPLIT functions and looks like this:
=ARRAYFORMulA({"Good Timestamp";IF(A2:A="",,MMULT(N(IFERROR(SPLIT(A2:A,"T"))),{1;1}))})
The second formula finds the amount of time since the previous timestamp for that Shipper. and subtracts it from the current timestamp thereby giving you the time between timestamps. However, it only does this if the time is less than 200 minutes. IF it is more than 200 minutes, it assumes that was a different shift for that shipper. It looks like this and uses a combination of LOOKUP() and SUBSTITUTE() to make sure it's pulling the correct timestamps. Obviously, you can find and change the 200 value to something more appropriate if it makes sense.
=ARRAYFORMULA({"Minutes/Order";IF(A2:A="",,IF(IFERROR((G2:G-1*SUBSTITUTE(LOOKUP(F2:F&G2:G-0.00001,SORT(F2:F&G2:G)),F2:F,""))*24*60)>200,,IFERROR((G2:G-1*SUBSTITUTE(LOOKUP(F2:F&G2:G-0.00001,SORT(F2:F&G2:G)),F2:F,""))*(24*60))))})
The third formula, on the tab called analysis uses query to show the average minutes per order and the number of orders per hour that each shipper is processing. It looks like this:
=QUERY({'Sample Data'!F:I},"Select Col1,AVG(Col3),COUNT(Col3)/(SUM(Col3)/60) where Col3 is not null group by Col1 label COUNT(Col3)/(SUM(Col3)/60)'Orders/ hour',AVG(Col3)'Minutes/ Order'")
Hopefully I've guessed correctly at your real goals. Always do your best to explain what they are rather than asking for only a small portion that you think will help you get to the answer. You can end up overcomplicating your process without realizing it.
I have this formula in spreadsheet that works as supposed. The formula is placed in "O:O" (this one is from O10).
(I've translated the formula from danish - hope I did it right)
=IFERROR(IF(I10<>"";sum(INDIRECT("L"&MATCH(LEFT(B10;LEN(B10)-6);B:B;0)):INDIRECT("L"&ROW()-1));"");"Fejl/Mangler reference")
Here's the result
The data is imported from another sheet and the lines can change over time and there can be added/removed rows that should be taken into consideration in each Sub Total.
This is why I want to convert the formula to an arrayformula - or another solution?
What I thought would work was:
=Arrayformula(IF(ROW(R:R)=5;"Balance";IF(ROW(R:R)<7;"";IF(ROW(R:R)=7;"Sub Total";IF($I:$I<>"";sum(INDIRECT("L"&MATCH(LEFT(B:B;LEN(B:B)-6);B:B;0))&":"&INDIRECT("L"&ROW()-1));"")))))
I guess is the Indirect so I've tried also to do it with a vlookup but that I couldn't figure out either.
Any good ideas?
Here's a link for the document: Spreadsheet
cell P8:
=ARRAYFORMULA(IF(J8:J="";; SUMIF(ROW(O8:O); "<="&ROW(O8:O); O8:O)))
cell O8:
=ARRAYFORMULA(IF(I8:I="";;
SUMIF(ROW(B8:B); "<="&ROW(B8:B); L8:L)-SUMIF(ROW(B8:B); "<"&VLOOKUP(
VLOOKUP(ROW(B8:B); IF(B8:B<>""; {ROW(B8:B)\ SUBSTITUTE(B8:B; " i alt"; )}); 2; 1); {
VLOOKUP(ROW(B8:B); IF(B8:B<>""; {ROW(B8:B)\ SUBSTITUTE(B8:B; " i alt"; )}); 2; 1)\
ROW(B8:B)}; 2; 0); L8:L)))
How do you arrayformula() a sum() such as:
=sum(A1:H1)
I need to go down 1000 rows.
Another option:
=ArrayFormula(SUMIF(IF(COLUMN(A1:H1),ROW(A1:A1000)),ROW(A1:A1000),A1:H1000))
Of the two answers that work, Jacob Jan Tuinstra and AdamL, Jacob gives a better answer. Jacob's runs faster and is easier to remember.
However, why use crazy formulas when it is much easier to use Google Sheets to the fullest?
=ARRAYFORMULA(A2:A+B2:B+C2:C+D2:D+E2:E+F2:F+G2:G+H2:H)
In the foregoing formula, you can use named ranges instead of the ranges by reference.
=ARRAYFORMULA(range1+range2+range3+range4+range5+range6+range7+range8)
As well, you can sum across rows that span sheets rather than being stuck working with columns within the same sheet.
To fix the formula to block returning zeros for blank rows, use this:
=arrayFormula(if(isNumber(A2:A),A2:A+B2:B+C2:C+D2:D+E2:E+F2:F,G2:G,H2:H))
See: See Ahab's answer on Google Forums
For a cool sum accumulation formula, see Otávio Alves Ribeiro's answer on Google Forums
This is what you are looking for:
=MMULT(A1:H1000,TRANSPOSE(ARRAYFORMULA(COLUMN(A1:H1000)^0)))
See this answer on Web Application I gave: https://webapps.stackexchange.com/a/53419/29140
Note: tried it on the new Google Spreadsheet, without succes.
with new functions in google sheets (since 20 Sep, 2022) all you need is:
=BYROW(A:H; LAMBDA(x; SUM(x)))
Summing A-H horizontal and running down for 523 lines:
=ARRAYFORMULA(iferror(mmult(A1:H523;TRANSPOSE(column(A1:H1))^0)))
if I look at this formula I really think the following might be simpler. Add this to Tools > Script Editor:
function row_sum(range_to_sum_per_row) {
var result_column = [];
for (var r = 0; r < range_to_sum_per_row.length; r++) {
var row_sum = parseFloat(0);
for (var c = 0; c < range_to_sum_per_row[r].length; c++) {
row_sum += range_to_sum_per_row[r][c] || 0;
}
result_column.push([row_sum]);
}
return result_column;
}
use this like so for performance reasons, where C:H is the range you want to sum up and A:A is a column that does not contain an empty string:
=row_sum(filter(C2:H, len(A2:A)>0))
If you want to be able to add rows and sum to the last row for all values in A1:H, you can use:
=ArrayFormula(SUMIF(IF(COLUMN(A1:H1),ROW(A1:A)),ROW(A1:A),A1:H))
Alternatively, if you want be be able to add rows and columns to the spreadsheet and sum to the last of both this can also be done. Paste the following code into any cell and it will create a column of summed values for all cells in each row below and to the right of pasted cell:
=arrayformula(SUMIF(IF(COLUMN(indirect(concatenate(REGEXREPLACE(address(row(),column()+1),"[^[:alpha:]]", ""),VALUE(REGEXREPLACE(address(row(),column()),"[^[:digit:]]", "")),":",VALUE(REGEXREPLACE(address(row(),column()),"[^[:digit:]]", ""))))),ROW(indirect(concatenate(REGEXREPLACE(address(row(),column()+1),"[^[:alpha:]]", ""),VALUE(REGEXREPLACE(address(row(),column()),"[^[:digit:]]", "")),":",REGEXREPLACE(address(row(),column()+1),"[^[:alpha:]]", ""))))),ROW(indirect(concatenate(REGEXREPLACE(address(row(),column()+1),"[^[:alpha:]]", ""),VALUE(REGEXREPLACE(address(row(),column()),"[^[:digit:]]", "")),":",REGEXREPLACE(address(row(),column()+1),"[^[:alpha:]]", "")))),indirect(concatenate(concatenate(REGEXREPLACE(address(row(),column()+1),"[^[:alpha:]]", ""),VALUE(REGEXREPLACE(address(row(),column()),"[^[:digit:]]", "")),":"),address(rows($A:$A),columns($1:$1))))))
Using Query
=INDEX(TRANSPOSE(
QUERY(TRANSPOSE(FILTER(A2:H,A2:A<>"")),
"select sum(Col"&JOIN("), sum(Col",SEQUENCE(COUNTA(A2:A)))&")",0)
),,2)
notes:
generating query string on the fly
Using DSUM:
=ARRAYFORMULA(DSUM(
TRANSPOSE(FILTER({A2:A,A2:H},A2:A<>"")),
SEQUENCE(COUNTA(A2:A)),{IFERROR(1/0);IFERROR(1/0)}))
notes:
{IFERROR(1/0);IFERROR(1/0)} is to make zero creteria for DSUM.
{A2:A,A2:H} -- added fake column for DSUM to mimic header column.
may be able to cahnge the formula into DMAX or DAVERAGE
Answer similar to #adamL suggestion, but removing the internal if.
=ArrayFormula(
sumif(ROW(A1:A10)*COLUMN(A1:H1)^0,ROW(A1:A10),A1:A10)
)
In this case I use ROW(A1:A10) * COLUMN(A1:H1)^0 to generate the row number matriz. To understand how it works, you can test just this part in your Google sheets:
= ArrayFormula(ROW(A1:A10) * COLUMN(A1:H1)^0)
So, with your row matrix, sumif can operate for each line, is the line has the matched row number, it will be summed up.
Let us not complicate this.
Simply put parenthesis in each of the array in the range.
=arrayformula( Sum( (A1:A):(H1:H) )
This spans not only upto 1000 rows but upto infiinity.
If you really want to limit then go
=arrayformula( Sum( (A1:A1000):(H1:H1000) )
I use the following function
=DAYS360(A2, A35)
to calculate the difference between two dates in my column. However, the column is ever expanding and I currently have to manually change 'A35' as I update my spreadsheet.
Is there a way (in Google Sheets) to find the last non-empty cell in this column and then dynamically set that parameter in the above function?
There may be a more eloquent way, but this is the way I came up with:
The function to find the last populated cell in a column is:
=INDEX( FILTER( A:A ; NOT( ISBLANK( A:A ) ) ) ; ROWS( FILTER( A:A ; NOT( ISBLANK( A:A ) ) ) ) )
So if you combine it with your current function it would look like this:
=DAYS360(A2,INDEX( FILTER( A:A ; NOT( ISBLANK( A:A ) ) ) ; ROWS( FILTER( A:A ; NOT( ISBLANK( A:A ) ) ) ) ))
To find the last non-empty cell you can use INDEX and MATCH functions like this:
=DAYS360(A2; INDEX(A:A; MATCH(99^99;A:A; 1)))
I think this is a little bit faster and easier.
If A2:A contains dates contiguously then INDEX(A2:A,COUNT(A2:A)) will return the last date. The final formula is
=DAYS360(A2,INDEX(A2:A,COUNT(A2:A)))
Although the question is already answered, there is an eloquent way to do it.
Use just the column name to denote last non-empty row of that column.
For example:
If your data is in A1:A100 and you want to be able to add some more data to column A, say it can be A1:A105 or even A1:A1234 later, you can use this range:
A1:A
So to get last non-empty value in a range, we will use 2 functions:
COUNTA
INDEX
The answer is =INDEX(B3:B,COUNTA(B3:B)).
Here is the explanation:
COUNTA(range): Returns number of values in a range, we can use this to get the count of rows.
INDEX(range, row, col): Returns the content of a cell, specified by row and column offset. If the column is omitted then the whole row is returned.
Examples:
INDEX(A1:C5,1,1) = A1
INDEX(A1:C5,1) = A1,B1,C1 # Whole row since the column is not specified
INDEX(A1:C5,1,2) = B1
INDEX(A1:C5,1,3) = C1
INDEX(A1:C5,2,1) = A2
INDEX(A1:C5,2,2) = B2
INDEX(A1:C5,2,3) = C2
INDEX(A1:C5,3,1) = A3
INDEX(A1:C5,3,2) = B3
INDEX(A1:C5,3,3) = C3
For the picture above, our range will be B3:B. So we will count how many values are there in range B3:B by COUNTA(B3:B) first. In the left side, it will produce 8 since there are 8 values while it will produce 9 in the right side. We also know that the last value is in the 1st column of the range B3:B so the col parameter of INDEX must be 1 and the row parameter should be COUNTA(B3:B).
PS: please upvote #bloodymurderlive's answer since he wrote it first, I'm just explaining it here.
My favorite is:
=INDEX(A2:A,COUNTA(A2:A),1)
So, for the OP's need:
=DAYS360(A2,INDEX(A2:A,COUNTA(A2:A),1))
If the column expanded only by contiguously added dates
as in my case - I used just MAX function to get last date.
The final formula will be:
=DAYS360(A2; MAX(A2:A))
Here's another one:
=indirect("A"&max(arrayformula(if(A:A<>"",row(A:A),""))))
With the final equation being this:
=DAYS360(A2,indirect("A"&max(arrayformula(if(A:A<>"",row(A:A),"")))))
The other equations on here work, but I like this one because it makes getting the row number easy, which I find I need to do more often. Just the row number would be like this:
=max(arrayformula(if(A:A<>"",row(A:A),"")))
I originally tried to find just this to solve a spreadsheet issue, but couldn't find anything useful that just gave the row number of the last entry, so hopefully this is helpful for someone.
Also, this has the added advantage that it works for any type of data in any order, and you can have blank rows in between rows with content, and it doesn't count cells with formulas that evaluate to "". It can also handle repeated values. All in all it's very similar to the equation that uses max((G:G<>"")*row(G:G)) on here, but makes pulling out the row number a little easier if that's what you're after.
Alternatively, if you want to put a script on your sheet you can make it easy on yourself if you plan on doing this a lot. Here's that scirpt:
function lastRow(sheet,column) {
var ss = SpreadsheetApp.getActiveSpreadsheet();
if (column == null) {
if (sheet != null) {
var sheet = ss.getSheetByName(sheet);
} else {
var sheet = ss.getActiveSheet();
}
return sheet.getLastRow();
} else {
var sheet = ss.getSheetByName(sheet);
var lastRow = sheet.getLastRow();
var array = sheet.getRange(column + 1 + ':' + column + lastRow).getValues();
for (i=0;i<array.length;i++) {
if (array[i] != '') {
var final = i + 1;
}
}
if (final != null) {
return final;
} else {
return 0;
}
}
}
Here you can just type in the following if you want the last row on the same of the sheet that you're currently editing:
=LASTROW()
or if you want the last row of a particular column from that sheet, or of a particular column from another sheet you can do the following:
=LASTROW("Sheet1","A")
And for the last row of a particular sheet in general:
=LASTROW("Sheet1")
Then to get the actual data you can either use indirect:
=INDIRECT("A"&LASTROW())
or you can modify the above script at the last two return lines (the last two since you would have to put both the sheet and the column to get the actual value from an actual column), and replace the variable with the following:
return sheet.getRange(column + final).getValue();
and
return sheet.getRange(column + lastRow).getValue();
One benefit of this script is that you can choose if you want to include equations that evaluate to "". If no arguments are added equations evaluating to "" will be counted, but if you specify a sheet and column they will now be counted. Also, there's a lot of flexibility if you're willing to use variations of the script.
Probably overkill, but all possible.
This works for me. Get last value of the column A in Google sheet:
=index(A:A,max(row(A:A)*(A:A<>"")))
(It also skips blank rows in between if any)
This seems like the simplest solution that I've found to retrieve the last value in an ever-expanding column:
=INDEX(A:A,COUNTA(A:A),1)
For strictly finding the last non-empty cell in a column, this should work...
=LOOKUP(2^99, A2:A)
What about this formula for getting the last value:
=index(G:G;max((G:G<>"")*row(G:G)))
And this would be a final formula for your original task:
=DAYS360(G10;index(G:G;max((G:G<>"")*row(G:G))))
Suppose that your initial date is in G10.
I went a different route. Since I know I'll be adding something into a row/column one by one, I find out the last row by first counting the fields that have data. I'll demonstrate this with a column:
=COUNT(A5:A34)
So, let's say that returned 21. A5 is 4 rows down, so I need to get the 21st position from the 4th row down. I can do this using inderect, like so:
=INDIRECT("A"&COUNT(A5:A34)+4)
It's finding the amount of rows with data, and returning me a number I'm using as an index modifier.
for a row:
=ARRAYFORMULA(INDIRECT("A"&MAX(IF(A:A<>"", ROW(A:A), ))))
for a column:
=ARRAYFORMULA(INDIRECT(ADDRESS(1, MAX(IF(1:1<>"", COLUMN(1:1), )), 4)))
This will give the contents of the last cell:
=indirect("A"&max(ARRAYFORMULA(row(a:a)*--(a:a<>""))))
This will give the address of the last cell:
="A"&max(ARRAYFORMULA(row(a:a)*--(a:a<>"")))
This will give the row of the last cell:
=max(ARRAYFORMULA(row(a:a)*--(a:a<>"")))
Maybe you'd prefer a script. This script is way shorter than the huge one posted above by someone else:
Go to script editor and save this script:
function getLastRow(range){
while(range.length>0 && range[range.length-1][0]=='') range.pop();
return range.length;
}
One this is done you just need to enter this in a cell:
=getLastRow(A:A)
Calculate the difference between latest date in column A with the date in cell A2.
=MAX(A2:A)-A2
To find last nonempty row number (allowing blanks between them) I used below to search column A.
=ArrayFormula(IFNA(match(2,1/(A:A<>""))))
The way an amateur does it is "=CONCATENATE("A",COUNTUNIQUE(A1:A9999))", where A1 is the first cell in the column, and A9999 is farther down that column than I ever expect to have any entries. This resultant A# can be used with the INDIRECT function as needed.
Ben Collins is a Google sheets guru, he has many tips on his site for free and also offers courses. He has a free article on dynamic range names and I have used this as the basis for many of my projects.
https://www.benlcollins.com/formula-examples/dynamic-named-ranges/
Disclaimer, I have nothing to gain by referring Ben's site.
Here is a screenshot of one of my projects using dynamic ranges:
Cell D3 has this formula which was shown above except this is as an array formula:
=ArrayFormula(MAX(IF(L2s!A2:A1009<>"",ROW(2:1011))))
Cell D4 has this formula:
="L2s!A2:E"&D3
This may work:
=DAYS360(A2,INDEX(A2:A,COUNTA(A2:A)))
To pick the last in a column of arbitrary, non-empty values ignoring the header cell (A1):
=INDEX(A2:A,COUNT(A2:A))
With the introduction of LAMBDA and REDUCE functions we can now compute the row number in a single pass through the cells (Several of the solutions above filter the range twice.) and without relying on magic text or numeric values.
=lambda(rng,
REDUCE(0, rng, lambda(maxrow, cell, if(isblank(cell),maxrow,row(cell)) ) )
)(A:A)
which can be nicely packaged into a Named Function for usage like
=LAST_ROWNUM(A:A)
It works on columns with interspersed blanks, and multi-column ranges (because REDUCE iterates over the range in row-first), and partial columns (like A20:A), still returning the actual row number (not the offset within the range).
This can then be combined with Index to return the value
=DAYS360(A2, Index(A1, LAST_ROWNUM(A:A)))
(In truth, though, I suspect that the OPs date values are monotonic (even if with blanks in between), and that he could get away with
=DAYS360(A2, MAX(A2:A))
This solution is identified above as relying on the dates being "contiguous" - whether that means "no blanks" or "no missing dates" I'm not certain - but either stipulation is not necessary.)