Keyboard leave a blank space after saving - ios

Since the new Swift version, it looks like the keyboard leaves a blank space when I save the data.
MyView
import SwiftUI
struct AddUpdateUrl: View {
#Environment(\.presentationMode) private var presentationMode: Binding<PresentationMode>
#EnvironmentObject var controller: PlacesViewController
#Binding var place: Place
#State var url = ""
var updateMode = false
var body: some View {
VStack {
Text("Website")
.font(.callout)
TextField("", text: $url)
.keyboardType(.URL)
.border(/*#START_MENU_TOKEN#*/Color.black/*#END_MENU_TOKEN#*/, width: 1)
}
.navigationBarItems(
trailing: Button(action: {save()}) {Text("Save")}.disabled(url.isEmpty)
)
.resignKeyboardOnDragGesture()
}
private func save() {
if !url.isEmpty {
place.url = url
if updateMode {
controller.update(place: place)
}
}
presentationMode.wrappedValue.dismiss()
}
}
And the result.
The view before trying to update the website
The view to add the website
After clicking the save button
I have the same behavior on the simulator and on my iPhone 11 (ios 14.3)
The .resignKeyboardOnDragGesture() is an extension that removes the keyboard.
struct ResignKeyboardOnDragGesture: ViewModifier {
var gesture = DragGesture().onChanged {_ in
UIApplication.shared.endEditing(true)
}
func body(content: Content) -> some View {
content.gesture(gesture)
}
}
extension View {
func resignKeyboardOnDragGesture() -> some View {
return modifier(ResignKeyboardOnDragGesture())
}
}

I know this is very late but if you still have this issues.
Add the following to your view:
.ignoresSafeArea(.keyboard)
This should no longer happen.

Related

SwiftUI - How to focus a TextField within a sheet as it is appearing?

I have a search TextField within a View that is triggered to appear within a sheet on top of the ContentView.
I'm able to automatically focus this TextField when the sheet appears using #FocusState and onAppear, however, I'm finding that the sheet needs to fully appear before the TextField is focused and the on screen keyboard appears.
This feels quite slow and I've noticed in many other apps that they are able to trigger the on screen keyboard and the sheet appearing simultaneously.
Here is my code:
struct ContentView: View {
#State var showSearch = false
var body: some View {
Button {
showSearch = true
} label: {
Text("Search")
}
.sheet(isPresented: $showSearch) {
SearchView()
}
}
}
struct SearchView: View {
#State var searchTerm = ""
#FocusState private var searchFocus: Bool
var body: some View {
TextField("Search", text: $searchTerm)
.focused($searchFocus)
.onAppear() {
searchFocus = true
}
}
}
Is there a different way to do this that will make the keyboard appear as the sheet is appearing, making the overall experience feel more seamless?
Here is an approach with a custom sheet that brings in the keyboard somewhat earlier. Not sure if its worth the effort though:
struct ContentView: View {
#State var showSearch = false
var body: some View {
ZStack {
Button {
withAnimation {
showSearch = true
}
} label: {
Text("Search")
}
.frame(maxWidth: .infinity, maxHeight: .infinity)
if showSearch {
SearchView(isPresented: $showSearch)
.transition(.move(edge: .bottom))
}
}
// .sheet(isPresented: $showSearch) {
// SearchView()
// }
}
}
struct SearchView: View {
#Binding var isPresented: Bool
#State var searchTerm = ""
#FocusState private var searchFocus: Bool
var body: some View {
Form {
TextField("Search", text: $searchTerm)
.focused($searchFocus)
Button("Close") {
searchFocus = false
withAnimation {
isPresented = false
}
}
}
.onAppear() {
searchFocus = true
}
}
}

#Environment(\.presentationMode) reloads body many times in SwiftUI

Set property wrapper to pop view "#Environment(.presentationMode) var presentationMode" but it is reloading view again and again. Why it is happening? any solution?
What i have observed except #Environment(.presentationMode) we should use bool value binding with controller, Please check code:
struct newView: View {
#State private var isActiveView: Bool = false
var body: some View {
VStack(alignment: .center) {
NavigationLink(destination: PushedView(isActiveView: $isActiveView), isActive: $isActiveView) {
Text("Create Account")
}
}
}
}
And on pushed screen check the code:
`struct PushedView: View {
#Binding var isActiveView: Bool
var body: some View {
NavigationView {
VStack {
Text(“Back”).onTapGesture {
isActiveView = false // to pop into previous view
}
}
}
}
}
`

In Swiftui How to automatically close modal with rotation to landscape

I currently use an landscape environmentobject based on this code - https://stackoverflow.com/a/58503841/412154
Within my view I have modals that appear and disappear appropriately using #State/#Binding depending on a "Done" Button press. My app does show a different view when rotated to landscape and I would like for the modal to dismiss automatically on the rotation, but couldn't figure out how to change the #binding var based on another #ennvironmentobject
Here is a simplified sample of my Modal View
struct StepsView: View {
#Binding var isPresented:Bool
#EnvironmentObject var orientation:Orientation
var body: some View {
VStack(alignment: .center) {
Text("Step")
}
.navigationBarItems(trailing: Button(action: {
//print("Dismissing steps view...")
self.isPresented = false
}) {
Text("Done").bold()
})
}
thanks for any help!
Appreciate #davidev's answer but I wanted each Modal to act a little differently so I did it this way
struct StepsView: View {
#Binding var isPresented:Bool
#EnvironmentObject var orientation:Orientation
private var PortraitView:some View {
VStack(alignment: .center) {
Text("Modal")
}
.navigationBarItems(trailing: Button(action: {
self.isPresented = false
}) {
Text("Done").bold()
})
}
var body: some View {
buildView(isLandscape: orientation.isLandScape, isShowing: &isPresented)
}
func buildView(isLandscape:Bool, isShowing:inout Bool) -> AnyView {
if !isLandscape {
return AnyView(PortraitView)
} else {
isShowing = false
return AnyView(EmptyView())
}
}
Here is a possible approach with extending the Device class with a variable which keeps track of the opened modal View.
import Combine
final class Orientation: ObservableObject {
#Published var isLandscape: Bool = false {
willSet {
objectWillChange.send()
if (newValue)
{
self.showModal = false
}
}
}
#Published var showModal : Bool = false
}
Whenever landscape changes, and the orientation is landscape, showModal will be set to false.
Here the ContentView..
struct ContentView6: View {
#EnvironmentObject var orientation:Orientation
// 1.
#State private var showModal = false
var body: some View {
Button("Show Modal") {
// 2.
self.orientation.isLandscape.toggle()
// 3.
}.sheet(isPresented: self.$orientation.isLandscape) {
ModalView(isPresented: self.$orientation.isLandscape).environmentObject(self.orientation)
}
}
}

SwiftUI - Close Keyboard on Scroll

I have a simple search list:
struct ContentView: View {
#State var text:String = ""
var items = 1...100
var body: some View {
VStack {
List {
TextField("Search", text: $text)
Section{
ForEach(items.filter({"\($0)".contains(text)}),id: \.self){(i) in
Text("option \(i)")
}
}
}
}
}
}
How can I make the keyboard close when scrolling for more than 2 cells/few points?
If you are using a ScrollView (probably also with a List but I haven't confirmed it), you could use the UIScrollView appearance, this will affect all ScrollViews though.
UIScrollView.appearance().keyboardDismissMode = .onDrag
A thorough discussion on how to resign the keyboard with various answers can be found for this question.
One solution to resign the keyboard on a drag gesture in the list is using a method on UIApplication window as shown below. For easier handling I created an extension on UIApplication and view modifier for this extension and finally an extension to View:
extension UIApplication {
func endEditing(_ force: Bool) {
self.windows
.filter{$0.isKeyWindow}
.first?
.endEditing(force)
}
}
struct ResignKeyboardOnDragGesture: ViewModifier {
var gesture = DragGesture().onChanged{_ in
UIApplication.shared.endEditing(true)
}
func body(content: Content) -> some View {
content.gesture(gesture)
}
}
extension View {
func resignKeyboardOnDragGesture() -> some View {
return modifier(ResignKeyboardOnDragGesture())
}
}
So the final modifier for resigning the keyboard is just one modifier that has to be placed on the list like this:
List {
ForEach(...) {
//...
}
}
.resignKeyboardOnDragGesture()
I have also implemented a pure swiftUI version of a search bar that might be interesting for you. You can find it in this answer.
As for now, since iOS 16 beta we have a new modifier scrollDismissesKeyboard() that allows to do exactly what you need.
In your example it should look like
struct ContentView: View {
#State var text: String = ""
var items = 1...100
var body: some View {
List {
TextField("Search", text: $text)
Section {
ForEach(items.filter({"\($0)".contains(text)}), id: \.self) { (i) in
Text("option \(i)")
}
}
}
.scrollDismissesKeyboard(.interactively) // <<-- Put this line
}
}
The scrollDismissesKeyboard() modifier has a parameter that determine the dismiss rules. Here are the possible values:
.automatic: Dismissing based on the context of the scroll.
.immediately: The keyboard will be dismissed as soon as any scroll happens.
.interactively: The keyboard will move/disappear inline with the user’s gesture.
.never: The keyboard will never dismissed when user is scrolling.
Form {
...
}.gesture(DragGesture().onChanged { _ in
UIApplication.shared.windows.forEach { $0.endEditing(false) }
})
#FocusState wrapper along with .focused() TextField modifier can be useful.
struct ContentView: View {
#FocusState private var focusedSearchField: Bool
#State var text:String = ""
var items = 1...100
var body: some View {
VStack {
List {
TextField("Search", text: $text)
.focused($focusedSearchField)
Section{
ForEach(items.filter({"\($0)".contains(text)}),id: \.self){(i) in
Text("option \(i)")
}
}
} // to also allow swipes on items (theoretically)
.simultaneousGesture(DragGesture().onChanged({ _ in
focusedSearchField = false
}))
.onTapGesture { // dissmis on tap as well
focusedSearchField = false
}
}
}
}
struct EndEditingKeyboardOnDragGesture: ViewModifier {
func body(content: Content) -> some View {
content.highPriorityGesture (
DragGesture().onChanged { _ in
UIApplication.shared.endEditing()
}
)
}
}
extension View {
func endEditingKeyboardOnDragGesture() -> some View {
return modifier(EndEditingKeyboardOnDragGesture())
}
}

iOS SwiftUI: pop or dismiss view programmatically

I couldn't find any reference about any ways to make a pop or a dismiss programmatically of my presented view with SwiftUI.
Seems to me that the only way is to use the already integrated slide dow action for the modal(and what/how if I want to disable this feature?), and the back button for the navigation stack.
Does anyone know a solution?
Do you know if this is a bug or it will stays like this?
This example uses the new environment var documented in the Beta 5 Release Notes, which was using a value property. It was changed in a later beta to use a wrappedValue property. This example is now current for the GM version. This exact same concept works to dismiss Modal views presented with the .sheet modifier.
import SwiftUI
struct DetailView: View {
#Environment(\.presentationMode) var presentationMode: Binding<PresentationMode>
var body: some View {
Button(
"Here is Detail View. Tap to go back.",
action: { self.presentationMode.wrappedValue.dismiss() }
)
}
}
struct RootView: View {
var body: some View {
VStack {
NavigationLink(destination: DetailView())
{ Text("I am Root. Tap for Detail View.") }
}
}
}
struct ContentView: View {
var body: some View {
NavigationView {
RootView()
}
}
}
SwiftUI Xcode Beta 5
First, declare the #Environment which has a dismiss method which you can use anywhere to dismiss the view.
import SwiftUI
struct GameView: View {
#Environment(\.presentationMode) var presentation
var body: some View {
Button("Done") {
self.presentation.wrappedValue.dismiss()
}
}
}
iOS 15+
Starting from iOS 15 we can use a new #Environment(\.dismiss):
struct SheetView: View {
#Environment(\.dismiss) var dismiss
var body: some View {
NavigationView {
Text("Sheet")
.toolbar {
Button("Done") {
dismiss()
}
}
}
}
}
(There's no more need to use presentationMode.wrappedValue.dismiss().)
Useful links:
DismissAction
There is now a way to programmatically pop in a NavigationView, if you would like. This is in beta 5. Notice that you don't need the back button. You could programmatically trigger the showSelf property in the DetailView any way you like. And you don't have to display the "Push" text in the master. That could be an EmptyView(), thereby creating an invisible segue.
import SwiftUI
struct ContentView: View {
var body: some View {
NavigationView {
MasterView()
}
}
}
struct MasterView: View {
#State private var showDetail = false
var body: some View {
VStack {
NavigationLink(destination: DetailView(showSelf: $showDetail), isActive: $showDetail) {
Text("Push")
}
}
}
}
struct DetailView: View {
#Binding var showSelf: Bool
var body: some View {
Button(action: {
self.showSelf = false
}) {
Text("Pop")
}
}
}
#if DEBUG
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}
#endif
I recently created an open source project called swiftui-navigation-stack (https://github.com/biobeats/swiftui-navigation-stack) that contains the NavigationStackView, an alternative navigation stack for SwiftUI. It offers several features described in the readme of the repo. For example, you can easily push and pop views programmatically. I'll show you how to do that with a simple example:
First of all embed your hierarchy in a NavigationStackVew:
struct RootView: View {
var body: some View {
NavigationStackView {
View1()
}
}
}
NavigationStackView gives your hierarchy access to a useful environment object called NavigationStack. You can use it to, for instance, pop views programmatically as asked in the question above:
struct View1: View {
var body: some View {
ZStack {
Color.yellow.edgesIgnoringSafeArea(.all)
VStack {
Text("VIEW 1")
Spacer()
PushView(destination: View2()) {
Text("PUSH TO VIEW 2")
}
}
}
}
}
struct View2: View {
#EnvironmentObject var navStack: NavigationStack
var body: some View {
ZStack {
Color.green.edgesIgnoringSafeArea(.all)
VStack {
Text("VIEW 2")
Spacer()
Button(action: {
self.navStack.pop()
}, label: {
Text("PROGRAMMATICALLY POP TO VIEW 1")
})
}
}
}
}
In this example I use the PushView to trigger the push navigation with a tap. Then, in the View2 I use the environment object to programmatically come back.
Here is the complete example:
import SwiftUI
import NavigationStack
struct RootView: View {
var body: some View {
NavigationStackView {
View1()
}
}
}
struct View1: View {
var body: some View {
ZStack {
Color.yellow.edgesIgnoringSafeArea(.all)
VStack {
Text("VIEW 1")
Spacer()
PushView(destination: View2()) {
Text("PUSH TO VIEW 2")
}
}
}
}
}
struct View2: View {
#EnvironmentObject var navStack: NavigationStack
var body: some View {
ZStack {
Color.green.edgesIgnoringSafeArea(.all)
VStack {
Text("VIEW 2")
Spacer()
Button(action: {
self.navStack.pop()
}, label: {
Text("PROGRAMMATICALLY POP TO VIEW 1")
})
}
}
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
RootView()
}
}
the result is:
Alternatively, if you don't want to do it programatically from a button, you can emit from the view model whenever you need to pop.
Subscribe to a #Published that changes the value whenever the saving is done.
struct ContentView: View {
#ObservedObject var viewModel: ContentViewModel
#Environment(\.presentationMode) var presentationMode
init(viewModel: ContentViewModel) {
self.viewModel = viewModel
}
var body: some View {
Form {
TextField("Name", text: $viewModel.name)
.textContentType(.name)
}
.onAppear {
self.viewModel.cancellable = self.viewModel
.$saved
.sink(receiveValue: { saved in
guard saved else { return }
self.presentationMode.wrappedValue.dismiss()
}
)
}
}
}
class ContentViewModel: ObservableObject {
#Published var saved = false // This can store any value.
#Published var name = ""
var cancellable: AnyCancellable? // You can use a cancellable set if you have multiple observers.
func onSave() {
// Do the save.
// Emit the new value.
saved = true
}
}
Please check Following Code it's so simple.
FirstView
struct StartUpVC: View {
#State var selection: Int? = nil
var body: some View {
NavigationView{
NavigationLink(destination: LoginView().hiddenNavigationBarStyle(), tag: 1, selection: $selection) {
Button(action: {
print("Signup tapped")
self.selection = 1
}) {
HStack {
Spacer()
Text("Sign up")
Spacer()
}
}
}
}
}
SecondView
struct LoginView: View {
#Environment(\.presentationMode) var presentationMode
var body: some View {
NavigationView{
Button(action: {
print("Login tapped")
self.presentationMode.wrappedValue.dismiss()
}) {
HStack {
Image("Back")
.resizable()
.frame(width: 20, height: 20)
.padding(.leading, 20)
}
}
}
}
}
You can try using a custom view and a Transition.
Here's a custom modal.
struct ModalView<Content>: View where Content: View {
#Binding var isShowing: Bool
var content: () -> Content
var body: some View {
GeometryReader { geometry in
ZStack(alignment: .center) {
if (!self.isShowing) {
self.content()
}
if (self.isShowing) {
self.content()
.disabled(true)
.blur(radius: 3)
VStack {
Text("Modal")
}
.frame(width: geometry.size.width / 2,
height: geometry.size.height / 5)
.background(Color.secondary.colorInvert())
.foregroundColor(Color.primary)
.cornerRadius(20)
.transition(.moveAndFade) // associated transition to the modal view
}
}
}
}
}
I reused the Transition.moveAndFade from the Animation Views and Transition tutorial.
It is defined like this:
extension AnyTransition {
static var moveAndFade: AnyTransition {
let insertion = AnyTransition.move(edge: .trailing)
.combined(with: .opacity)
let removal = AnyTransition.scale()
.combined(with: .opacity)
return .asymmetric(insertion: insertion, removal: removal)
}
}
You can test it - in the simulator, not in the preview - like this:
struct ContentView: View {
#State var isShowingModal: Bool = false
func toggleModal() {
DispatchQueue.main.asyncAfter(deadline: .now() + 3) {
withAnimation {
self.isShowingModal = true
}
DispatchQueue.main.asyncAfter(deadline: .now() + 3) {
withAnimation {
self.isShowingModal = false
}
}
}
}
var body: some View {
ModalView(isShowing: $isShowingModal) {
NavigationView {
List(["1", "2", "3", "4", "5"].identified(by: \.self)) { row in
Text(row)
}.navigationBarTitle(Text("A List"), displayMode: .large)
}.onAppear { self.toggleModal() }
}
}
}
Thanks to that transition, you will see the modal sliding in from the trailing edge, and the it will zoom and fade out when it is dismissed.
The core concept of SwiftUI is to watch over the data flow.
You have to use a #State variable and mutate the value of this variable to control popping and dismissal.
struct MyView: View {
#State
var showsUp = false
var body: some View {
Button(action: { self.showsUp.toggle() }) {
Text("Pop")
}
.presentation(
showsUp ? Modal(
Button(action: { self.showsUp.toggle() }) {
Text("Dismiss")
}
) : nil
)
}
}
I experienced a compiler issue trying to call value on the presentationMode binding. Changing the property to wrappedValue fixed the issue for me. I'm assuming value -> wrappedValue is a language update. I think this note would be more appropriate as a comment on Chuck H's answer but don't have enough rep points to comment, I also suggested this change as and edit but my edit was rejected as being more appropriate as a comment or answer.
This will also dismiss the view
let scenes = UIApplication.shared.connectedScenes
let windowScene = scenes.first as? UIWindowScene
let window = windowScene?.windows.first
window?.rootViewController?.dismiss(animated: true, completion: {
print("dismissed")
})

Resources