Anyway to rotate marquee label? - ios

Question

Hey I implemented marquee label into my project with cocoa pods but have been unsuccessful in getting it to rotate.
let newsFeed: MarqueeLabel = MarqueeLabel(
frame: CGRect(x:15, y:66, width:28, height:159))
newsFeed.textAlignment = .right newsFeed.text = "TEXT"
self.view.addSubview(newsFeed)
newsFeed.transform = CGAffineTransform(
rotationAngle: CGFloat(-(Double.pi / 2.0)))
newsFeed.frame = CGRect(x:15, y:66, width:28, height:159)

Answer 1

You should:
Set the height and width of your field to the unrotated height and
width when you create it:
Not try to manipulate the frame once you've changed the view's
transform. Instead you should set the view's center: To quote Apple's
docs on UIView.transform:
Warning When the value of this property is anything other than the
identity transform, the value in the frame property is undefined and
should be ignored.
I don't know what a MarqueeLabel is, but this code using a vanilla UILabel works:
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
let startingFrameRect = CGRect(x:15, y:66, width:159, height:28)
let newsFeed = UILabel(
//Create the label wide and short as if it is not rotated.
frame: startingFrameRect)
newsFeed.text = "Some Text"
self.view.addSubview(newsFeed)
newsFeed.transform = CGAffineTransform(
rotationAngle: CGFloat(-(Double.pi / 2.0)))
//Add a border so you can see the label's rotated frame
newsFeed.layer.borderWidth = 1.0
//Adjust the view's center based on it's origin, but exchanging height and width
newsFeed.center = CGPoint (x: startingFrameRect.origin.x + startingFrameRect.size.height / 2,
y: startingFrameRect.origin.y + startingFrameRect.size.width / 2)
//Also add a view to show where the unrotated view would land.
let boxView = UIView(frame: startingFrameRect)
boxView.layer.borderWidth = 1.0
boxView.layer.borderColor = UIColor.blue.cgColor
self.view.addSubview(boxView)
}
}