Add last element to an array from for loop - ios

Question

I have a code like so...
for element in self.arr_Offline {
self.arr_OfflineTemp.add(element)
break
}
self.arr_Offline.removeObject(at: 0)
Here I'm looping through an array called self.arr_Offline, adding the first element from that array into another array called self.arr_OfflineTemp and immediately doing break so that the second array will have just one element and then once I'm outside the for-loop, I remove the added object from the main array by doing self.arr_Offline.removeObject(at: 0)
But I want to add the last element to self.arr_OfflineTemp instead of the first and then remove that last element from self.arr_Offline. It should look something like so...
for element in self.arr_Offline { // looping through array
self.arr_OfflineTemp.add(lastElementOf'self.arr_Offline') //add last element
break
}
self.arr_Offline.removeObject(at: 'last') //remove that last element that was added to `arr_OfflineTemp`
How can I achieve this..?

Answer 1

First of all never use NS(Mutable)Array and NS(Mutable)Dictionary in Swift.
Native Swift Array has a convenient way to do that without a loop
First element:
if !arr_Offline.isEmpty { // the check is necessary to avoid a crash
let removedElement = self.arr_Offline.removeFirst()
self.arr_OfflineTemp.append(removedElement)
}
Last element:
if !arr_Offline.isEmpty {
let removedElement = self.arr_Offline.removeLast()
self.arr_OfflineTemp.append(removedElement)
}
And please drop the unswifty snake_case names in favor of camelCase

Answer 2

Did you try the same approach with reversed() Swift:
for i in arr.reversed():
// your code logic
After adding element, you can remove the last element from the list using this:
lst.popLast() or lst.removeLast()
Try this for the above code:
for element in self.arr_Offline.reversed() {
self.arr_OfflineTemp.add(element)
break
}
self.arr_Offline.popLast()
Is this something you are looking for?