I am trying to show the number on iPhone dialer pad with spaces using tel:// url.
Wanted to show the number as xxx xxx xxx but when I directly give spaces in number string it wont show the number to dial.
Even I tried following code to
var url = "tel://155".addingPercentEncoding(withAllowedCharacters: charSet)
url = url! + "666"
url = url?.addingPercentEncoding(withAllowedCharacters: charSet)
url = url! + "908"
let telUrl = URL(string: url!)
but nothing works.
Can someone suggest me the way to to this?
Thank you
instead of space try adding hyphen (-).
Related
I am implementing Firebase dynamic links in my iOS project. It is working fine and it is opening my iOS Home screen properly. But now I would like to extract values from url and open appropriate screen based on url.
for example:
https://www.dd.com/forums/hot-deals-online/topics/smart-tv-carniva
in this url I would like to get 'hot-deals-online' and 'smart-tv-carniva' permalink which I will pass to view controller to open that screen on the app
can someone suggest me best approach for this.
Shortest is to access path of URLComponents object:
let url = "https://www.dd.com/forums/hot-deals-online/topics/smart-tv-carniva"
if let comps = URLComponents(string: url) {
var elements = comps.path.split(separator: "/").map(String.init)
// ["forums", "hot-deals-online", "topics", "smart-tv-carniva"]
// To build an url back, example:
var url = URL(string: comps.host!)!
url.appendPathComponent(elements[0])
url.appendPathComponent(elements[1])
// Result: www.dd.com/forums/hot-deals-online
}
P.S. calling .map(String.init) makes in-place conversion from array of substrings to normal String array.
I have x 2 questions about urls and webViews.
Question 1:
I have a string which I am getting from an API that is supposed to be a url. The string is https://godochurch.blob.core.windows.net/sermons/1031/30-1-2017-Vision Sunday-Devotion.mp3
When trying to convert to a url I'm getting nil.
Here is the code:
if let sermonUrl = sermonUrl {
if let url = URL(string: sermonUrl) {
let requestObj = URLRequest(url: url)
webView.loadRequest(requestObj)
}
}
I have worked out that the space between 'Vision' and 'Sunday' is the problem.
Should I be encoding the string in some way before trying to convert it to a URL? What's confusing is that if I paste the string into my browser it works just fine, but I notice the browser is percent encoding the space.
If I am supposed to be encoding the string, how do I do that?
Question 2:
I see that URL(string: "urlStringHere") is only available from iOS 10. My app needs to work for iOS 9. How can I convert the above code so it works on iOS 9 and 10.
Thanks in advance for your time.
1: escape that space with %20 or +:
if let url = URL(string: "https://godochurch.blob.core.windows.net/sermons/1031/30-1-2017-Vision%20Sunday-Devotion.mp3") {
// ...
}
2: URL was introduced with Swift 3, which is compatible with iOS 8 and later. See this question on how to make it work with older versions of iOS.
Edit: the easiest way to percent-escape a URL is to use URLComponents:
var components = URLComponents(string: "https://godochurch.blob.core.windows.net")!
components.path = "/sermons/1031/30-1-2017-Vision Sunday-Devotion.mp3"
if let url = components.url {
// ...
}
If you happen to get you URL strings from a webservice and it contains a space, that service is bad. Space is not allowed in an URL. Web browsers relax that rule because they know there are bad URLs out there. Swift won't take it.
So I have a url like this:
let remoetURL = "http://xxx-test.img-cn-hangzhou.aliyuncs.com/materials/talk_-XXXXX-XXXXXXX/STEM RULE.pdf"
As you can see, at then end of the url, there is a white space, so I need to get rid of it to have a valid encoded url.
After doing some research, I realized I might use
let escapedString = remoteURL.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLPathAllowedCharacterSet())
But this does not returned the expected working url, because it encodes the ":" after "http" too
http%3A//xiaobandeng-staging.img-cn-hangzhou.aliyuncs.com/talk_materials/talk_-K4yjX4-238Ku74WVIJk/STEM%20RULE.pdf
I have also tried URLHostAllowedCharacterSet, but no luck. So I wonder if it is because I don't have www here, so it does not recognise which part is the host correctly. If so, what might be the elegant solution? I know I could replace white spaces with %20 by calling stringByReplacingOccurrencesOfString, but that seems just a bit fragile.
Thank you in advance.
Try this used by SwiftyJSON
let urlString = remoteURL.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())
Swift 3:
let urlString = remoteURL.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)
Have you try this
let urlPath = NSString(format: remoetURL).stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!
For iOS 9
let encodedHost = NSString(format: remoetURL).stringByAddingPercentEncodingWithAllowedCharacters(.URLQueryAllowedCharacterSet())
Hope this will help you
I'm working on an horoscope application now I have a problem after user selected is zodiac how can I know what php url to show him for example:
there is 12 zodiac's so how can I give him his horoscope for this url for example
NSURL: "blablabla_horscope.com/libra/today_horoscope"
I mean I don't want to write in Xcode twelve options of url, and start making if statements for example "if this user and then use here is NSUserDefaults with his choosed zodiac"
since then I will have to start making a list of a lot of if statement and it will make my app work slow and it's a bad idea so I have thinking about making some kinda of php file, that will handle all that after the user registered in the background but where to start for that?
I'm currently working on Swift, core-data, php.
let urlString = "http://www.blablabla/?sign=libra&time=today"
let url = NSURL (string: urlString)
let dataURL = try? NSData(contentsOfURL: url!, options: [])
let result: String = String(data: dataURL!, encoding: NSUTF8StringEncoding)!
print("the result is %#", result)
Set your constant for the sign type prior to setting your urlString.
let sign = "libra"
or
let sign = "cancer"
etc...
and then you can:
let urlString = "http://www.blablabla/?sign=\(sign)&time=today"
Late
I have an NSURL being returned to me as something like
tel:555-555-5555
I can recognize it as a telephone by identifying the NSURL's scheme as "tel" using
let url = NSURL(string: "tel:555-555-5555")
if url.scheme == "tel" {
// it's a telephone number
}
But I can't find a command to get the actual phone number component. The phone numbers can come back much more messy than the example I gave, so I thought it would be much safer to ask if there was a way to get the phone number component directly instead of saving as string and clipping out the scheme.
Use resourceSpecifier:
let url = NSURL(string: "tel:555-555-5555")!
if url.scheme == "tel" {
let number = url.resourceSpecifier
}