(I started learning about arrays today.) Edit: I realized the = is apperently causing the error because it's seen as a "compare if equal" vs "assign this".
i don't see which part in the referenced line is causing the error:
'Option 1
Var citylistDE(5) as string
citylistDE(0) ="Genf"
citylistDE(1)="Lausanne"
citylistDE(2)="Bern"
citylistDE(3)="Basel"
citylistDE(4)="Zürich"
citylistDE(5)="St.Gallen"
dim countDe as Integer = citylistDE.LastRowIndex
for i as integer = 0 to countDe
de.Value = de.Value = citylistDE(i) + EndOfLine '<=== THIS LINE ?
next
'Option2
var citylistFR() as string = array("Genève", "Lausanne", "Berne", "Bale", "Zurich", "Sant-Gall")
dim countFR as integer = citylistFR.LastRowIndex
for i as integer = 0 to countFR
fr.Value = fr.Value + citylistFR(i) + EndOFLine
next
i found the error. It was the = between de.Value and citylistDE.
I changed it from = to +.
de.Value = de.Value = citylistDE(i) + EndOfLine
next
to
de.Value = de.Value + citylistDE(i) + EndOfLine
next
Related
Quick explanation, I have recently started using codewars to further improve my programming skills and my first challenge was to make a roman numeral decoder, I went through many versions because I wasnt satisfied with what I had, So I am asking if there is an easier way of handling all the patterns that roman numerals have, for example I is 1 but if I is next to another number it takes it away for example V = 5 but IV = 4.
here is my CODE:
function Roman_Numerals_Decoder (roman)
local Dict = {I = 1, V = 5, X = 10, L = 50, C = 100, D = 500, M = 1000}
local number = 0
local i = 1
while i < #roman + 1 do
local letter = roman:sub(i,i) -- Gets the current character in the string roman
if roman:sub(i,i) == "I" and roman:sub(i + 1,i + 1) ~= "I" and roman:sub(i + 1,i + 1) ~= "" then -- Checks for the I pattern when I exists and next isnt I
number = number + (Dict[roman:sub(i +1,i + 1)] - Dict[roman:sub(i,i)]) -- Taking one away from the next number
i = i + 2 -- Increase the counter
else
number = number + Dict[letter] -- Adds the numbers together if no pattern is found, currently checking only I
i = i + 1
end
end
return number
end
print(Roman_Numerals_Decoder("MXLIX")) -- 1049 = MXLIX , 2008 = MMVIII
at the moment I am trying to get 1049 (MXLIX) to work but I am getting 1069, obviously I am not following a rule and I feel like its more wrong then it should be because usually if its not correct its 1 or 2 numbers wrong.
The algorithm is slightly different: you need to consider subtraction when the previous character has less weight than the next one.
function Roman_Numerals_Decoder (roman)
local Dict = {I = 1, V = 5, X = 10, L = 50, C = 100, D = 500, M = 1000}
local num = 0
local i = 1
for i=1, #roman-1 do
local letter = roman:sub(i,i) -- Gets the current character in the string roman
local letter_p = roman:sub(i+1,i+1)
if (Dict[letter] < Dict[letter_p]) then
num = num - Dict[letter] -- Taking one away from the next number
print("-",Dict[letter],num)
else
num = num + Dict[letter] -- Adds the numbers together if no pattern is found, currently checking only I
print("+",Dict[letter],num)
end
end
num = num + Dict[roman:sub(-1)];
print("+",Dict[roman:sub(-1)], num)
return num
end
print(Roman_Numerals_Decoder("MXLIX")) -- 1049 = MXLIX , 2008 = MMVIII
I am writing a wireshark dissector of a custom protocol using LUA.For this custom protocol,there are no underlying TCP port or UDP port hence i have written a postdissector.
I am able to capture the payload from the below layers and convert it into a string.
local io_b = tostring(customprotocol)
After this, io_b has the following data
io_b = 10:10:10:10:01:0f:00:0d:00:00:00:00:01:00:00:00:00:20:0a:00:00
At first I split this string with : as the seperator and copy the elements into an array/table.
datafields = {}
index = 1
for value in string.gmatch(io_b, "[^:]+") do
datafields[index] = value
index = index + 1
end
Then I read each element of the datafield array as a uint8 value and check if a bit is set in that datafield element.How to make sure that each element of the table is uint8?
function lshift(x, by)
return x * 2 ^ by
end
--checks if a bit is set at a position
function IsBitSet( b, pos)
if b ~= nil then
return tostring(bit32.band(tonumber(b),lshift(1,pos)) ~= 0)
else
return "nil"
end
end
Then I want to display the value of each bit in the wireshark.I dont care about the first four bytes. The script displays each bit of the 5th byte(which is the 1st considered byte) correctly but displays all the bits value of the 6th byte and other remaining bytes as "nil".
local data_in_2 = subtree:add(customprotocol,"secondbyte")
data_in_2:add(firstbit,(IsBitSet((datafields[6]),7)))
data_in_2:add(secondbit,(IsBitSet((datafields[6]),6)))
data_in_2:add(thirdbit,(IsBitSet((datafields[6]),5)))
data_in_2:add(fourbit,(IsBitSet((datafields[6]),4)))
data_in_2:add(fivebit,(IsBitSet((datafields[6]),3)))
data_in_2:add(sixbit,(IsBitSet((datafields[6]),2)))
data_in_2:add(sevenbit,(IsBitSet((datafields[6]),1)))
data_in_2:add(eightbit,(IsBitSet((datafields[6]),0)))
What am i doing wrong?
Maybe i am wrong but it seems you can do it simpler with...
io_b = '10:10:10:10:01:0f:00:0d:00:00:00:00:01:00:00:00:00:20:0a:00:00'
-- Now replace all : on the fly with nothing and convert it with #Egor' comment tip
-- Simply by using string method gsub() from within io_b
b_num = tonumber(io_b:gsub('%:', ''), 16)
print(b_num)
-- Output: 537526272
#shakingwindow - I cant comment so i ask here...
Do you mean...
io_b = '10:10:10:10:01:0f:00:0d:00:00:00:00:01:00:00:00:00:20:0a:00:00'
-- Converting HEX to string - Replacing : with ,
io_hex = io_b:gsub('[%x]+', '"%1"'):gsub(':', ',')
-- Converting string to table
io_hex_tab = load('return {' .. io_hex .. '}')()
-- Put out key/value pairs by converting HEX value string to a number on the fly
for key, value in pairs(io_hex_tab) do
print(key, '=', tonumber(value, 16))
end
...that puts out...
1 = 16
2 = 16
3 = 16
4 = 16
5 = 1
6 = 15
7 = 0
8 = 13
9 = 0
10 = 0
11 = 0
12 = 0
13 = 1
14 = 0
15 = 0
16 = 0
17 = 0
18 = 32
19 = 10
20 = 0
21 = 0
...?
im trying to make a calculation script with python but im running into this problem:
ValueError: invalid literal for int() with base 10: '1.8'
Im trying to ask a user for an input that is in numbers like 2000 but when the input contains a ',' or '.' it will output that error.
This is the code:
Buiten = int(input("Buiten: "))
Binnen = int(input("Binnen: "))
DikteF = int(input("Dikte: "))
Sortle = int(input("Soortelijk gewicht: "))
inputs = Buiten,Binnen,DikteF,Sortle
Pi = 3.14
R1 = Buiten / 2
R2 = Binnen / 2
UD1 = Pi*R1/1000*R1/1000
UD2 = Pi*R2/1000*R2/1000
Tpv = UD1 - UD2
Ltr = Tpv * DikteF
Srt = Ltr * Sortle
print("")
print("Uitwendige Diameter = ",(round(UD1, 3)),"m²")
print("Inwendige Diameter = ",(round(UD2, 3)),"m²")
print("Product Oppervlak = ",(round(Tpv, 3)), "m²")
print("")
print("Inhoud in L = ",(round(Ltr, 3)),"Liters")
print("Totaal gewicht = ",(round(Srt, 3), "Kilos" ))
print("")
os.system("pause")
while True:
try:
Bereken()
except:
print("Fout: Gebruik alleen cijfers.")
time.sleep(4)
Bereken()
Python returns an error since it is expecting an integer value as string to convert to integer. However, when passing decimals, the attempt to convert to integer fails since they are not integers.
if you are going to insert either integers or decimals, use float
Buiten = float(input("Buiten: "))
Binnen = float(input("Binnen: "))
DikteF = float(input("Dikte: "))
Sortle = float(input("Soortelijk gewicht: "))
I have very simple code,
var i = 1
var f = 10.34
println("i = \(i)") //fine
println("f = \(f)") //fine
println("i + f = \(i + f)")//error --> could not find member init
Now why I am getting error in last line? Am I not allowed to write expression with different data type in println?
In this line println("i + f = \(i + f)") you are adding Int and Double which is not possible in swift.
You can convert i to double and your code will be:
println("i + f = \(Double(i) + f)") // i + f = 11.34
I have a project where the user pulls up a specific URL where the values for Dept, Queue, and Day change by what hyperlink they choose. For example, they would click on a hyperlink and the URL would be something like:
http://www.myworkplace.com/UserPlatform/User/Process.aspx?Dept=DeptOne&Queue=18&Day=0
The next hyperlink could be:
http://www.myworkplace.com/UserPlatform/User/Process.aspx?Dept=DeptFive&Queue=13&Day=9.
I would like to use InStr to find Dept, Queue, and Day within the URL, then set their values to variables, such as UDept, UQueue, and UDay. Depending upon these values, the user can then copy a specific ID number that can only be found on the URL with these values. The end result would be a search for the URL:
http://www.myworkplace.com/UserPlatform/User/Process.aspx?Dept=UDept&Queue=UQueue&Day=UDay
Here's my code so far:
Option Explicit
Dim objIE, objShell, objShellWindows
Dim strIDNum, strURL, strWindow, strURLFound, WShell, i
strURL = "http://www.myworkplace.com/UserPlatform/User/Process.aspx?Dept=DeptOne&Queue=18&Day=0"
strWindow = "Workflow Process"
Set objIE = CreateObject("InternetExplorer.Application")
Set objShell = CreateObject("Shell.Application")
Set objShellWindows = objShell.Windows
Set WShell = CreateObject("WScript.Shell")
strURLFound = False
'To fix item not found error
For Each objIE in objShellWindows
Next
For i = 0 to objShellWindows.Count - 1
Set objIE = objShellWindows.Item(i)
On Error Resume Next
If InStr(Ucase(objShellWindows.Item(i).LocationURL), Ucase(strURL)) Then
If InStr(Ucase(objShellWindows.Item(i).FullName), "IEXPLORE.EXE") Then
If Err.Number = 0 Then
If InStr(objShellWindows.Item(i).document.title, (strWindow)) Then
strURLFound = True
Exit For
End If
End If
End If
End If
Next
WShell.AppActivate strWindow
WScript.Sleep 300
strIDNum = objIE.document.getElementByID("ID_PlaceHolder").value
Thank you in advance to anyone who can help me with this.
Have you considered using a regular expression?
dim re, s
dim matches
s = "http://www.myworkplace.com/UserPlatform/User/Process.aspx?Dept=DeptFive&Queue=13&Day=9"
Set re = new RegExp
re.Pattern = ".*?Dept=(\w+)&Queue=(\d+)&Day=(\d+)$"
Set matches = re.Execute(s)
Dim uDept, uQueue, uDay
uDept = matches(0).submatches(0)
uQueue = matches(0).submatches(1)
uDay = matches(0).submatches(2)
Msgbox join(array("uDept = " & uDept, "uQueue = " & uQueue , "uDay = " & uDay), vbNewLine)
' Output:
' uDept = DeptFive
' uQueue = 13
' uDay = 9
To replace you can also use a Regular Expression:
Set re = new RegExp
s = "http://www.myworkplace.com/UserPlatform/User/Process.aspx?Dept=DeptFive&Queue=13&Day=9"
newDept = "DeptFourtyTwo"
newQueue = 404
newDay = 12
re.Pattern = "(Dept=)\w+"
newUrl = re.Replace(s, "$1" & newDept)
re.Pattern = "(Queue=)\d+"
newUrl = re.Replace(newUrl, "$1" & newQueue)
re.Pattern = "(Day=)\d+"
newUrl = re.Replace(newUrl, "$1" & newDay)
msgbox newUrl
' output:
' http://www.myworkplace.com/UserPlatform/User/Process.aspx?Dept=DeptFourtyTwo&Queue=404&Day=12
' Alternatively you can replace everything at once if the order and presence of
' parameters is guaranteed:
re.Pattern = "(Dept=)\w+(&Queue=)\d+(&Day=)\d+"
MsgBox re.Replace(s, "$1DeptFourtyTwo$2404$312")
This only using Instr and Mid Function's
s="http://www.myworkplace.com/UserPlatform/User/Process.aspx?Dept=DeptFive&Queue=13&Day=9"
a = InStr(s, "?") 'We get the value until ?
d1 = Mid(s, a)
c1 = InStr(d1, "=")
c2 = InStr(d1, "&")
d2 = Mid(d1, c2 + 1)
d3 = Mid(d1, c1 + 1, (c2 - c1) - 1) 'value of Dept is d3
c3 = InStr(d2, "=")
c4 = InStr(d2, "&")
d5 = Mid(d2, c4 + 1)
d4 = Mid(d2, c3 + 1, (c4 - c3) - 1) 'value of Queue is d4
c6 = InStr(d5, "=")
d6 = Mid(d5, c6 + 1) ' Value of Day is d6
Hope this helps