REST Assured: compare field to a long value - rest-assured

Consider this line:
response.body("path.to.some.long",is(getExpectedResult())
What I'm getting is:
java.lang.AssertionError: 1 expectation failed.
JSON path path.to.some.long doesn't match.
Expected: is <1500L>
Actual: 1500
Does that mean REST assured compares a String to a Long? This is very limiting.
How can I tell REST assured to compare it as a long value?

You'd have to go the traditional way
long value = response.jsonPath().getLong("path.to.some.long");
assertThat(value, is(1500L));

Related

randint(low=4, high=12) returns a number lower than 4

I am using using Hyperopt's randint in one of my hyperparameter tuning experiments, where my model is getting hyperparamter values from fmin that are lower than than the lower limit specified for randint,
I am passing the following parameters to the hp.randint function (label, low=4, high=12) and the value I got was 0
my env is setup as follows:
hyperopt==0.2.7
numpy==1.19.4
transformers==2.11.0
torch==1.10.2
Any ideas/pointers on how this can be resolved?
Thanks in advance!
Correct signature for this function is hp.randint(label[, low], upper).
Try it without kwargs, only with usual args.

Why does using two variables give me an error message when using an if statement?

I'm attempting to write a script in LUA for the Minecraft mod ComputerCraft. It's supposed to send a turtle down, mine a hole, and place ladders before returning to the surface. I'm trying to make an error display when the turtle doesn't have enough ladders, but I'm receiving an error that prevents it from running. "mineDown :18: attempt to compare string with number expected, got string."
-- This gets the user to tell the turtle how far to dig down
print('How far down should I go?')
distDown = io.read()
distMoved = 0
ladders = turtle.getItemCount(13)
-- Check if the number of ladders is less than the distance needed to move. If so, returns error.
turtle.select(13)
if ladders < distDown then
error('Not enough ladders!')
end
The error means that ladders is number and distDown is a string. You need to convert them to the same type. For example to convert ladders to a string use tostring or distDown to a number use tonumber:
if ladders < tonumber(distDown) then

No '...' candidates produce 'Range<String.Index>'

While converting an old iOS app to Sift 3.0 I hit the following issue:
The code is:
cutRange = numberString.index(numberString.startIndex, offsetBy:2)...numberString.index(numberString.startIndex, offsetBy:5)
The error message I get is:
No '...' candidates produce the expected contextual result type 'Range<String.Index>' (aka 'Range<String.CharacterView.Index>')
I have seen a few post related to the subject, but was not very satisfied.
So what is the simplest way to solve this problem?
In Swift 3, two range operators generate different results:
closed range operator ... -> ClosedRange (by default)
(half open) range operator ..< -> Range (by default)
So, assuming your cutRange is declared as Range<String.Index>, you need to use half open range operator ..<:
cutRange = numberString.index(numberString.startIndex, offsetBy:2)..<numberString.index(numberString.startIndex, offsetBy:6)
(Please do not miss the last offset is changed to 6.)

How to create a dummy variable

I'm working in a project that uses the IBM SPSS but I had some problems to set a dummy variable(binary variable).The process to get the variable is following : Consider an any variable(width for example), to get the dummy variable, we need
to sort this variable in the decreasing way; The next step is make a somatory of the cases until a limit, the cases before the limit receive the value 1 in the dummy variable the other values receive 0.
Your explanation is rather vague. And the critical value you give in the printscreen should be 2.009 in stead of 20.09?
But I think you mean the following.
When using syntax, use:
compute newdummyvariable eq (ABr gt 2.009477106).
To check if it's okay:
fre newdummyvariable.
UPDATE:
In order to compute a dummy based on the cumulative sum, the answer is as follows:
If your critical value is predetermined, the fastest way is to sort in decending order, and to use the command create with csum() to compute an extra variable which I called ABr_cumul. This one, you use to compute the newdummyvariable. As follows:
sort cases by ABr (d).
create ABr_cumul = csum(VAR00001).
compute newdummyvariable = (ABr_cumul le 20.094771061766488).
fre newdummyvariable.
the dummy comes from the sum of all cases, after decreasing order raqueados when cases of a variable representing 50% of the variable t0tal, these cases receive 1 and the other 0 ...

adding a big offset to an os.time{} value

I'm writing a Wireshark dissector in lua and trying to decode a time-based protocol field.
I've two components 1)
local ref_time = os.time{year=2000, month=1, day=1, hour=0, sec=0}
and 2)
local offset_time = tvbuffer(0:5):bytes()
A 5-Byte (larger than uint32 range) ByteArray() containing the number of milliseconds (in network byte order) since ref_time. Now I'm looking for a human readable date. I didn't know this would be so hard, but 1st it seems I cannot simple add an offset to an os.time value and 2nd the offset exceeds Int32 range ...and most function I tested seem to truncate the exceeding input value.
Any ideas on how I get the date from ref_time and offset_time?
Thank you very much!
Since ref_time is in seconds and offset_time is in milliseconds, just try:
os.date("%c",ref_time+offset_time/1000)
I assume that offset_time is a number. If not, just reconstruct it using arithmetic. Keep in mind that Lua uses doubles for numbers and so a 5-byte integer fits just fine.

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