REGEX for capturing only words? - dart

Question

here is a text I want to split its words in a list, but the problem is there are commas, periods and a big spacing between the two paragraphs, so can one any suggest a REGEX for extracting only whole words using split(RegExp()) method?
input:
String text = '''
You find so many people are fimble
But you, you are mostly humble
I love the way you wear your hair,
Spreading your style everywhere.
You're like a style fountain.
Enough for a whole mountain.
''';
desired output:
[You, find, so, many, people, are, fimble, But, you, you, are, mostly, humble, I, love, the, way, you, wear, your, hair, Spreading, your, style, everywhere, You're, like, a, style, fountain, Enough, for, a, whole, mountain]

Answer 1

I can see the same question was asked on Reddit where I gave my answer. This is a copy of my solution for the problem.
Also, I would not use split in this case but just use the RegExp class to get matches which is much simpler since it is easier to define what we define a word to be instead of trying to define what we want to delete. So something like this would do the trick:
void main() {
const text = '''
You find so many people are fimble
But you, you are mostly humble
I love the way you wear your hair,
Spreading your style everywhere.
You're like a style fountain.
Enough for a whole mountain.
''';
final words = [...RegExp(r"[\w']+").allMatches(text).map((e) => e.group(0))];
print(words);
// [You, find, so, many, people, are, fimble, But, you, you, are, mostly,
// humble, I, love, the, way, you, wear, your, hair, Spreading, your, style,
// everywhere, You're, like, a, style, fountain, Enough, for, a, whole,
// mountain]
}

Answer 2

Try var newVar = text.split(' ')
Find it here :
https://www.tutorialkart.com/dart/dart-split-string/

Answer 3

I'm pretty sure that you can do with the regex the same thing, I don't like to use regex if I can use the logic to make a logic split inside the string.
I'm proposing a draft code to make your solution customizable without worry about the regex logic. Maybe you need to return on the split login to two years from now!
void main() {
String value = '''
You find so many people are fimble
But you, you are mostly humble
I love the way you wear your hair,
Spreading your style everywhere.
You're like a style fountain.
Enough for a whole mountain.
''';
//Inside the text can be a , ., in this case I use the solution to introcuce a not usual token inside
//inside the list and after split for this token.
var tokenBySpace = value.split(' ').join("#").split("\n").join("#").split("#");
tokenBySpace = tokenBySpace.map((word) => word = cleanString(word.trim())).toList();
tokenBySpace.removeWhere((item) => item.isEmpty); //Easy solution to remove the " . " string
print(tokenBySpace);
}
String cleanString(word){
var grammarRules = [".", ",", "(", ")"];
grammarRules.forEach((rule) => {
if(word.contains(rule)){
word = word.replaceAll(rule, '')
}
});
return word;
}
The result is
[You, find, so, many, people, are, fimble, But, you, you, are, mostly, humble, , I, love, the, way, you, wear, your, hair, Spreading, your, style, everywhere, You're, like, a, style, fountain, Enough, for, a, whole, mountain]
A solution inside one line can be
void main() {
String value = '''
You find so many people are fimble
But you, you are mostly humble
I love the way you wear your hair,
Spreading your style everywhere.
You're like a style fountain.
Enough for a whole mountain.
''';
//Inside the text can be a , ., in this case I use the solution to introcuce a not usual token inside
//inside the list and after split for this token.
var tokenBySpace = value.split(' ').join("#")
.split("\n").join("#")
.split(".").join("#")
.split(",").join("#")
.split(":").join("#")
.split(";").join("#")
.split("#");
tokenBySpace.removeWhere((item) => item.isEmpty); //Easy solution to remove the " . " string
print(tokenBySpace);
}
But I preferer the first!
Can you find a complete example here
the code inside the example is reported below
void main() {
var value = '''I preferer the previos solution because is more customizzable,
and help you to preserve some exception inside the text, such as URL
In addition, the this solution, subdivide the logic inside a function.
This solution is made by https://github.com/vincenzopalazzo
''';
//Inside the text can be a , ., in this case I use the solution to introcuce a not usual token inside
//inside the list and after split for this token.
var tokenBySpace = value.split(' ').join("#").split("\n").join("#").split("#");
tokenBySpace = tokenBySpace.map((word) => word = cleanString(word.trim())).toList();
tokenBySpace.removeWhere((item) => item.isEmpty); //Easy solution to remove the " . " string
print("------------- FIRST SOLUTION -------------------");
print(tokenBySpace);
value = '''
You find so many people are fimble
But you, you are mostly humble
I love the way you wear your hair,
Spreading your style everywhere.
You're like a style fountain.
Enough for a whole mountain.
''';
tokenBySpace = value.split(' ').join("#")
.split("\n").join("#")
.split(".").join("#")
.split(",").join("#")
.split(":").join("#")
.split(";").join("#")
.split("#");
tokenBySpace.removeWhere((item) => item.isEmpty); //Easy solution to remove the " . " string
print("------------- FIRST SOLUTION -------------------");
print(tokenBySpace);
}
String cleanString(word){
var grammarRules = [".", ",", "(", ")"];
grammarRules.forEach((rule) => {
if(word.contains(rule)){
word = word.replaceAll(rule, '')
}
});
return word;
}