How to copy a gray-scale bitmap via ScanLine - delphi

I want to copy pixels from BMP1 to BMP2 but the copied image is gabbled. Why?
Note: The input image is pf8bit;
TYPE
TPixArray = array[0..4095] of Byte;
PPixArray = ^TPixArray;
procedure Tfrm1.CopyImage;
VAR
BMP1, BMP2: TBitmap;
y, x: Integer;
LineI, LineO: PPixArray;
begin
BMP1:= TBitmap.Create;
BMP2:= TBitmap.Create;
TRY
BMP1.LoadFromFile('test.bmp');
BMP2.SetSize(BMP1.Width, BMP1.Height);
BMP2.PixelFormat:= BMP1.PixelFormat;
for y:= 0 to BMP1.Height -1 DO
begin
LineI := BMP1.ScanLine[y];
LineO := BMP2.ScanLine[y];
for x := 0 to BMP1.Width -1 DO
LineO[x]:= LineI[x];
end;
//BMP2.SaveToFile('out.bmp');
imgOut.Picture.Assign(BMP2); //TImage
FINALLY
FreeAndNil(BMP2);
FreeAndNil(BMP1);
END;
end;
For the saved image, a graphic editor says "Pixel depth/colors: indexed, 256 color palette".

It might be worth pointing out that an 8-bit bitmap isn't necessarily greyscale.
Instead, it is a bitmap with a "colour table" consisting of up to 256 entries, and each pixel refers to an entry in this table. So if a pixel's value is 185, this means that it should use the colour at location 185 in the bitmap's "colour table". Hence, an 8-bit bitmap works entirely different compared to a 16-, 24- or 32-bit bitmap, which does not have a colour table, but instead has actual RGB(A) values at each pixel.
The problem in your case is likely that the target pixmap doesn't have the same colour table as the source bitmap.
I have actually never worked with 8-bit bitmaps and palettes before, but I think it is this simple:
var
s, t: TBitmap;
y: Integer;
sp, tp: PByte;
x: Integer;
begin
s := TBitmap.Create;
try
s.LoadFromFile('C:\Users\Andreas Rejbrand\Desktop\bitmap.bmp');
Assert(s.PixelFormat = pf8bit);
t := TBitmap.Create;
try
t.PixelFormat := pf8bit;
t.SetSize(s.Width, s.Height);
t.Palette := s.Palette; // <-- Let the new image have the same colour table
for y := 0 to s.Height - 1 do
begin
sp := s.ScanLine[y];
tp := t.ScanLine[y];
for x := 0 to s.Width - 1 do
tp[x] := sp[x];
end;
t.SaveToFile('C:\Users\Andreas Rejbrand\Desktop\bitmap2.bmp');
finally
t.Free;
end;
finally
s.Free;
end;

Related

In Delphi, how does TBitmap.Monochrome and .PixelFormat influcence the format of .ScanLine?

I want to assign a given buffer with a bitmap in Mono8 format (Monochrome 8 Bits) to a bitmap. I then assign the resulting bitmap to a TImage component to display it. The pictures are screenshots of the resulting display.
The following code works but seems a bit wasteful:
procedure CopyToBitmapMono824(_Buffer: PByte; _Bmp: TBitmap);
var
y: Integer;
x: Integer;
ScanLine: PdzRgbTripleArray;
begin
for y := 0 to _Bmp.Height - 1 do begin
ScanLine := _Bmp.ScanLine[y];
for x := 0 to _Bmp.Width - 1 do begin
// monochrome: all 3 colors set to the same value
ScanLine[x].Red := _Buffer^;
ScanLine[x].Green := _Buffer^;
ScanLine[x].Blue := _Buffer^;
Inc(_Buffer);
end;
end;
end;
// [...]
fBmp.PixelFormat := pf24Bit;
FBmp.Monochrome := False;
CopyToBitmap(Buffer, fBmp);
I would rather use a bitmap in pf8Bit format which I tried:
procedure CopyToBitmapMono8(_Buffer: PByte; _Bmp: TBitmap);
var
y: Integer;
x: Integer;
ScanLine: PByteArray;
begin
for y := 0 to _Bmp.Height - 1 do begin
ScanLine := _Bmp.ScanLine[y];
for x := 0 to _Bmp.Width - 1 do begin
ScanLine[x] := _Buffer^;
Inc(_Buffer);
end;
end;
end;
// [...]
FBmp.PixelFormat := pf8bit;
FBmp.Monochrome := False; // I also tried Monochrome := true
CopyToBitmapMono8(Buffer, FBmp)
If MonoChrome is true, the picture only has about 1/4 of the expected width, the rest is white.
If MonoChrome is false, the picture has the expected width, but the left 1/4 of it is monochrome, the rest contains false colors.
I'm obviously missing something, but what?
EDIT: The effect that the bitmap is only 1/4 of the expected size apparently was a side effect of converting it to a JPEG for saving prior to displaying it (code that I did not show above, mea culpa). So the problem was simply that I did not set a monochrome palette for the bitmap.
Monochrome has sense for pf1bit bitmaps.
Otherwise Monochrome := True changes bitmap format to DDB (pfDevice). Your screen is 32-bit, so call to Scanline caused DibNeeded call and transformation to 32bit, and using of function CopyToBitmapMono8 (intended for 8-bit) filled only 1/4 of screen.
For proper usage of 8-bit bitmaps you have to change standard weird palette (used in the right part of last image) to gray one.
procedure CopyToBitmapMono8(_Buffer: PByte; _Bmp: TBitmap);
var
y: Integer;
x: Integer;
ScanLine: PByteArray;
begin
for y := 0 to _Bmp.Height - 1 do begin
ScanLine := _Bmp.ScanLine[y];
for x := 0 to _Bmp.Width - 1 do begin
ScanLine[x] := _Buffer^;
Inc(_Buffer);
end;
end;
end;
var
FBmp: TBitmap;
Buffer: PbyteArray;
i: integer;
begin
GetMem(Buffer, 512 * 100);
for i := 0 to 512 * 100 - 1 do
Buffer[i] := (i and 511) div 2; // gray gradient
FBmp := Tbitmap.Create;
FBmp.Width := 512;
FBmp.Height := 100;
FBmp.PixelFormat := pf8bit;
CopyToBitmapMono8(PByte(Buffer), FBmp);
Canvas.Draw(0, 0, FBmp);
//now right approach
FBmp.Palette := MakeGrayPalette; // try to comment
CopyToBitmapMono8(PByte(Buffer), FBmp);
Canvas.Draw(0, 110, FBmp);
end;
function TForm1.MakeGrayPalette: HPalette;
var
i: integer;
lp: TMaxLogPalette;
begin
lp.palVersion := $300;
lp.palNumEntries := 256;
for i := 0 TO 255 do begin
lp.palPalEntry[i].peRed := i;
lp.palPalEntry[i].peGreen := i;
lp.palPalEntry[i].peBlue := i;
lp.palPalEntry[i].peFlags := PC_RESERVED;
end;
Result := CreatePalette(pLogPalette(#lp)^);
end;
And example at efg2 page

Graphics32 - saving transparent drawing layer to png

I draw a dotted line on a layer of an ImgView32. Later, I want to save each layer as transparent PNGs.
For any other layer that I have, the saving works just fine. But for the drawing layer, it does not.
In order to make the question simpler to understand, take the example code from the gr32 library, more specifically the Layers example. One of the options in its main menu is to add a custom drawing layer (New Custom Layer -> Simple Drawing Layer).
Then try to save that layer as a transparent PNG image and you will end up with a corrupted PNG file (you can't open it with any other picture viewer like for example Paint.net or Microsoft Photo Viewer). Same thing happens if you try to save the layer's bitmap32 as a bitmap as you can see in the bellow code...
I tried two approaches for saving Bitmap32 as a transparent PNG, so the first one is as follows:
procedure TMainForm.SavePNGTransparentX(bm32:TBitmap32; dest:string);
var
Y: Integer;
X: Integer;
Png: TPortableNetworkGraphic32;
function IsBlack(Color32: TColor32): Boolean;
begin
Result:= (TColor32Entry(Color32).B = 0) and
(TColor32Entry(Color32).G = 0) and
(TColor32Entry(Color32).R = 0);
end;
function IsWhite(Color32: TColor32): Boolean;
begin
Result:= (TColor32Entry(Color32).B = 255) and
(TColor32Entry(Color32).G = 255) and
(TColor32Entry(Color32).R = 255);
end;
begin
bm32.ResetAlpha;
for Y := 0 to bm32.Height-1 do
for X := 0 to bm32.Width-1 do
begin
// if IsWhite(bm32.Pixel[X, Y]) then
// bm32.Pixel[X,Y]:=Color32(255,255,255, 0);
if IsBlack(bm32.Pixel[X, Y]) then
bm32.Pixel[X,Y]:=Color32( 0, 0, 0, 0);
end;
Png:= TPortableNetworkGraphic32.Create;
try
Png.Assign(bm32);
Png.SaveToFile(dest);
finally
Png.Free;
end;
end;
So the above method works if I have a PNG loaded into the layer like this:
mypng := TPortableNetworkGraphic32.Create;
mypng.LoadFromStream(myStream);
B := TBitmapLayer.Create(ImgView.Layers);
with B do
try
mypng.AssignTo(B.Bitmap);
...
But as soon as I try to save the layer created with the code from the Layers example, the result is corrupted.
Even if I try to save the layer as bitmap like this (though this is not my intention since I need them to be PNG):
mylay := TBitmapLayer(ImgView.Layers.Items[i]);
mylay.Bitmap.SaveToFile('C:\tmp\Layer'+IntToStr(i)+'.bmp');
the same corruption occurs.
So, it's not like I receive an exception or anything... it just gets saved corrupted somehow;
I also tried other ways to save the Bitmap32 as transparent PNG, like for instance the GR32_PNG approach:
function SaveBitmap32ToPNG (sourceBitmap: TBitmap32;transparent: Boolean;bgColor32: TColor32;filename: String;compressionLevel: TCompressionLevel = 9;interlaceMethod: TInterlaceMethod = imNone): boolean;
var png: TPNGImage;
begin
result := false;
try
png := Bitmap32ToPNG (sourceBitmap,false,transparent,WinColor(bgColor32),compressionLevel,interlaceMethod);
try
png.SaveToFile (filename);
result := true;
finally
png.Free;
end;
except
result := false;
end;
end;
where
function Bitmap32ToPNG (sourceBitmap: TBitmap32;paletted, transparent: Boolean;bgColor: TColor;compressionLevel: TCompressionLevel = 9;interlaceMethod: TInterlaceMethod = imNone): TPNGImage; // TPNGObject
var
bm: TBitmap;
png: TPNGImage;//TPngObject;
TRNS: TCHUNKtRNS;
p: pngImage.PByteArray;
x, y: Integer;
begin
Result := nil;
png := TPngImage.Create; // TPNGObject
try
bm := TBitmap.Create;
try
bm.Assign (sourceBitmap); // convert data into bitmap
// force paletted on TBitmap, transparent for the web must be 8bit
if paletted then
bm.PixelFormat := pf8bit;
png.interlaceMethod := interlaceMethod;
png.compressionLevel := compressionLevel;
png.Assign(bm); // convert bitmap into PNG
// this is where the access violation occurs
finally
FreeAndNil(bm);
end;
if transparent then begin
if png.Header.ColorType in [COLOR_PALETTE] then begin
if (png.Chunks.ItemFromClass(TChunktRNS) = nil) then png.CreateAlpha;
TRNS := png.Chunks.ItemFromClass(TChunktRNS) as TChunktRNS;
if Assigned(TRNS) then TRNS.TransparentColor := bgColor;
end;
if png.Header.ColorType in [COLOR_RGB, COLOR_GRAYSCALE] then png.CreateAlpha;
if png.Header.ColorType in [COLOR_RGBALPHA, COLOR_GRAYSCALEALPHA] then
begin
for y := 0 to png.Header.Height - 1 do begin
p := png.AlphaScanline[y];
for x := 0 to png.Header.Width - 1
do p[x] := AlphaComponent(sourceBitmap.Pixel[x,y]); // TARGB(bm.Pixel[x,y]).a;
end;
end;
end;
Result := png;
except
png.Free;
end;
end;
but using this approach, I get an EAccessViolation when trying to save this particular layer. For any other layers (not drawing ones), it does not crash my project except for this custom drawing one.
The access violation occurs at this line:
png.Assign(bm);
inside the Bitmap32ToPNG function
Do you have any idea why that happens and how can I prevent this?
EDIT
I tried using TBitmapLayer instead, because the TPositionedLayer might lack the Bitmap32 for some reason.
So my code is like this:
// adding a BitmapLayer and setting it's onPaint event to my handler
procedure TMainForm.Mynewlayer1Click(Sender: TObject);
var
B: TBitmapLayer;
P: TPoint;
W, H: Single;
begin
B := TBitmapLayer.Create(ImgView.Layers);
with B do
try
Bitmap.SetSize(100,200);
Bitmap.DrawMode := dmBlend;
with ImgView.GetViewportRect do
P := ImgView.ControlToBitmap(GR32.Point((Right + Left) div 2, (Top + Bottom) div 2));
W := Bitmap.Width * 0.5;
H := Bitmap.Height * 0.5;
with ImgView.Bitmap do
Location := GR32.FloatRect(P.X - W, P.Y - H, P.X + W, P.Y + H);
Scaled := True;
OnMouseDown := LayerMouseDown;
OnPaint := PaintMy3Handler;
except
Free;
raise;
end;
Selection := B;
end;
// and the PaintHandler is as follows:
procedure TMainForm.PaintMy3Handler(Sender: TObject;Buffer: TBitmap32);
var
Cx, Cy: Single;
W2, H2: Single;
const
CScale = 1 / 200;
begin
if Sender is TBitmapLayer then
with TBitmapLayer(Sender).GetAdjustedLocation do
begin
// Five black pixels, five white pixels since width of the line is 5px
Buffer.SetStipple([clBlack32, clBlack32, clBlack32, clBlack32, clBlack32,
clWhite32, clWhite32, clWhite32, clWhite32, clWhite32]);
W2 := (Right - Left) * 0.5;
H2 := (Bottom - Top) * 0.5;
Cx := Left + W2;
Cy := Top + H2;
W2 := W2 * CScale;
H2 := H2 * CScale;
Buffer.PenColor := clRed32;
Buffer.StippleCounter := 0;
Buffer.MoveToF(Cx-2,Top);
Buffer.LineToFSP(Cx-2 , Bottom);
Buffer.StippleCounter := 0;
Buffer.MoveToF(Cx-1,Top);
Buffer.LineToFSP(Cx-1 , Bottom);
Buffer.StippleCounter := 0;
Buffer.MoveToF(Cx,Top);
Buffer.LineToFSP(Cx , Bottom);
Buffer.StippleCounter := 0;
Buffer.MoveToF(Cx+1,Top);
Buffer.LineToFSP(Cx+1 , Bottom);
Buffer.StippleCounter := 0;
Buffer.MoveToF(Cx+2,Top);
Buffer.LineToFSP(Cx+2 , Bottom);
end;
end;
Keep in mind that I use the default layers demo application. So this is just added code. I did not remove nor change anything in the demo code.
So I create a new layer (TBitmapLayer) and onPaint I do my drawing. In the end I want to save the contents of that layer as PNG. But it seems like the onPaint might draw somewhere else instead of the actual layer. Otherwise I do not understand why the saved image is empty.
So this time the resulted PNG is not corrupted, but it is empty...
The error is in the fact that the examples create TPositionedLayer layers which do not hold a bitmap. You can not type cast this layer type into a TBitmapLayer and expect it to create a bitmap image of the layer, as you do in this code:
mylay := TBitmapLayer(ImgView.Layers.Items[i]);
mylay.Bitmap.SaveToFile('C:\tmp\Layer'+IntToStr(i)+'.bmp');
I assume you do something similar to save to .png file, although you did not show that code.
The examples (with TPositionedLayer layers) use ImgView.Buffer for drawing on the screen. You can save that to a .png file like this:
SavePNGTransparentX(ImgView.Buffer, 'c:\tmp\imgs\buffer.png');
but I don't expect that to work satisfactorily for your separate layer images.
What is the reason you don't use TBitmapLayers as you have done before?
Edit after comments by user1137313
Inspired by the solution you found yourself (ref. your comment) I suggest the following which paints the layer to the extra bitmap only when needed for saving.
Starting from a menu item
procedure TMainForm.mnFileSaveClick(Sender: TObject);
begin
SaveLayerToPng(ImgView.Layers[ImgView.Layers.Count-1], 'c:\tmp\imgs\buffer.png');
end;
You possibly want to call SaveLayerToPng() in a loop if you save several layers at the same time, and also change the file name(s) as needed.
Then the SaveLayerToPng() procedure
procedure TMainForm.SaveLayerToPng(L: TCustomLayer; FileName: string);
var
bm32: TBitmap32;
begin
bm32:= TBitmap32.Create;
try
bm32.SetSizeFrom(ImgView.Buffer);
PaintSimpleDrawingHandler(L, bm32);
SavePNGTransparentX(bm32, FileName);
finally
bm32.Free;
end;
end;
It calls the existing PaintSimpleDrawingHandler(Sender: TObject; buffer: TBitmap32) procedure to paint to bm32 which it then passes on to `SavePNGTransparentX() for actual saving.
I used the paint handler of the Graphics32 example, but your PaintMy3Handler() can be used just as well.
The end result is same as your solution, just that the extra TBitmap32 is only painted when the file is to be saved.

Convert Bitmap with any pixel format to specific pixel format

I'm trying to convert a bunch of images with could have pixel formats of anything (4bit, 8bit, 16bit, 24bit etc) to an image that is 1bit.
I have the following code which will convert 24bit to 1bit, but this doesn't handle any other pixel formats.
procedure TFormMain.ButtonConvertClick(Sender: TObject);
var
Bitmap: TBitmap;
NewBitmap: TBitmap;
x,y: Integer;
ScanLine: pRGBTriple;
Colour: Integer;
FilePath: String;
FileName: String;
begin
Bitmap := TBitmap.Create;
try
Bitmap.LoadFromFile(EditFileName.Text);
NewBitmap := TBitmap.Create;
try
NewBitmap.PixelFormat := pf1bit;
NewBitmap.Height := Bitmap.Height;
NewBitmap.Width := Bitmap.Width;
for y := 0 to Bitmap.Height -1 do
begin
ScanLine := Bitmap.ScanLine[y];
for x := 0 to Bitmap.Width -1 do
begin
Colour := (ScanLine.rgbtBlue + ScanLine.rgbtGreen + ScanLine.rgbtRed) div 3;
if (Colour >= 128)
then Colour := clWhite
else Colour := clBlack;
NewBitmap.Canvas.Pixels[x, y] := Colour;
Inc(ScanLine);
end;
end;
FilePath := ExtractFilePath(EditFileName.Text);
FileName := TPath.GetFileNameWithoutExtension(EditFileName.Text);
NewBitmap.SaveToFile(TPath.Combine(FilePath, FileName + '-copy.bmp'));
finally
FreeAndNil(NewBitmap);
end;
finally
FreeAndNil(Bitmap);
end;
end;
I could handle each case individually, but there seems like there should be a function that does this. I have looked into the TGPBitmap.Clone function class, but I could only get it to produce blank(white) images and was unable to find any examples of its use.
The simplest way - draw any bitmap on 24bit one and use existing code.
The slowest way - get color of every pixel through Pixels[] property
Otherwise you have to treat every kind of bitmap individually. Note that 1,4 and 8-bit bitmaps contain indexes of palette, so you need to get proper color from bitmap palette, and 15 and 16-bit bitmaps pixels have structure xRRRRRGGGGGBBBBB and RRRRRGGGGGGBBBBB, so you need to extract 5 and 6-bit color parts and calculate overall pixel luminance.

png to bmp conversion (maintaining transparency)

I am using delphi XE-5 and I am loading button information from a JSON file, in order to create buttons on a TMS ADVToolBar control. Each button is 50X35 and in png format with transparency.
I am getting each url, using the idHTTP component to retrieve it to a stream and then load it into a png. I then draw it onto a transparent BMP. However, I dont think this is the correct way. Anyway, the bmp is then added to a TImageList where it is assigned to a button using the index. The Image shows up on the button, but with no transparency.
see my code below:
imgUrl:= //code to get img url from JSON file;
MS := TMemoryStream.Create;
png := TPngImage.Create;
png.Transparent:= True;
try
idHTTP1.get(imgUrl,MS);
Ms.Seek(0,soFromBeginning);
png.LoadFromStream(MS);
bmp:= TBitmap.Create;
bmp.Transparent:= True;
bmp.Width:= 50;
bmp.Height:= 50;
png.Draw(bmp.Canvas, Rect(7, 7, png.Width, png.Height));
ImageList1.Add(bmp, nil);
AdvGlowBtn.Images:= ImageList1;
AdvGlowBtn.Layout:= blGlyphTop;
AdvGlowBtn.WordWrap:= False;
AdvGlowBtn.AutoSize:= True;
AdvGlowBtn.ImageIndex:= ImageList1.Count-1;
bmp.Free;
finally
FreeAndNil(png);
FreeAndNil(MS);
end;
At first you have to enable the runtime themes (Project Manager) otherwise you will have no transparency of your images.
And this is the code to load the PNG image into your ImageList1
bmp := TBitmap.Create;
try
// everything done before to bmp has no effect
bmp.Assign( png );
// if for some reason the loaded image is smaller
// set the size to avoid the invalid image size error
bmp.Width := ImageList1.Width;
bmp.Height := ImageList1.Height;
AdvGlowBtn.Images:= ImageList1;
...
// now add the Bitmap to the ImageList
AdvGlowBtn.ImageIndex := ImageList1.Add( bmp, nil );
finally
bmp.Free;
end;
I have an old project in Delphi 5 and I still using it sometimes.
This is my solution using the png object.
procedure ImageList2Alpha(const ImageList: TImageList);
const
Mask: array[Boolean] of Longint = (0, ILC_MASK);
var
TempList: TImageList;
begin
if Assigned(ImageList) then
begin
TempList := TImageList.Create(nil);
try
TempList.Assign(ImageList);
with ImageList do
begin
Handle := ImageList_Create(Width, Height, ILC_COLOR32 or Mask[Masked], 0, AllocBy);
if not HandleAllocated then
raise EInvalidOperation.Create(SInvalidImageList);
end;
Imagelist.AddImages(TempList);
finally
FreeAndNil(TempList);
end;
end;
end;
procedure LoadPngToBmp(var Dest: TBitmap; AFilename: TFilename);
type
TRGB32 = packed record
B, G, R, A : Byte;
end;
PRGBArray32 = ^TRGBArray32;
TRGBArray32 = array[0..0] of TRGB32;
type
TRG24 = packed record
rgbtBlue, rgbtGreen, rgbtRed : Byte;
end;
PRGBArray24 = ^TPRGBArray24;
TPRGBArray24 = array[0..0] of TRG24;
type
TByteArray = Array[Word] of Byte;
PByteArray = ^TByteArray;
TPByteArray = array[0..0] of TByteArray;
var
BMP : TBitmap;
PNG: TPNGObject;
x, y: Integer;
BmpRow: PRGBArray32;
PngRow : PRGBArray24;
AlphaRow: PByteArray;
begin
Bmp := TBitmap.Create;
PNG := TPNGObject.Create;
try
if AFilename <> '' then
begin
PNG.LoadFromFile(AFilename);
BMP.PixelFormat := pf32bit;
BMP.Height := PNG.Height;
BMP.Width := PNG.Width;
if ( PNG.TransparencyMode = ptmPartial ) then
begin
for Y := 0 to BMP.Height-1 do
begin
BmpRow := PRGBArray32(BMP.ScanLine[Y]);
PngRow := PRGBArray24(PNG.ScanLine[Y]);
AlphaRow := PByteArray(PNG.AlphaScanline[Y]);
for X := 0 to BMP.Width - 1 do
begin
with BmpRow[X] do
begin
with PngRow[X] do
begin
R := rgbtRed; G := rgbtGreen; B := rgbtBlue;
end;
A := Byte(AlphaRow[X]);
end;
end;
end;
end else
begin
for Y := 0 to BMP.Height-1 do
begin
BmpRow := PRGBArray32(BMP.ScanLine[Y]);
PngRow := PRGBArray24(PNG.ScanLine[Y]);
for X := 0 to BMP.Width - 1 do
begin
with BmpRow[X] do
begin
with PngRow[X] do
begin
R := rgbtRed; G := rgbtGreen; B := rgbtBlue;
end;
A := 255;
end;
end;
end;
end;
Dest.Assign(BMP);
end;
finally
Bmp.Free;
PNG.Free;
end;
end;
Call ImageList2Alpha(YourImageList) on the OnCreate of the Form (FormCreate), and the ImageList will be ready to store your Bitmaps32 keeping the transparency.
Call the LoadPngToBmp procedure to convert a PNG to Bitmap32 and then, store it on your ImageList.
The TBitmap class uses Windows own libraries to manipulate Bitmaps. Depending on you Windows version, the underlying Operating System libraries does not support 32 bits BMPs, despite the libraries header files declares a BITMAPQUAD struct.
For newer versions of Windows (Vista and above afaik), the field BITMAPQUAD.reserved is used to store the alpha channel. For older versions, this field must remain zero (0x00).
If you are using a "recent" version of Windows, the only possible explanation I see is that the TBitmap class were not updated to support the alpha channel.
Using the class TPNGImage should not be an issue instead of converting it to BMP before using, unless you have some more specific needs.
Use it like that:
ABitmap.SetSize(png.Width, png.Height);
png.AssignTo(ABitmap);

Create an image and colored ir?

how can I create an image and how can I colored it pixel by pixel using hexadecimal code of colors?
For ex. I wanna create a 100x100 pixel image and I wanto to 1x1 area's color is '$002125',2x2 area's color is '$125487'.... How can I do it?
Thank you for your answers..
Made a simple sample for you. Using Canvas.Pixels not Scanline. Scanline is faster though but for start I think it suits just fine. The colors are randomly generated, so you just need to replace this part of the code.
procedure TForm1.GenerateImageWithRandomColors;
var
Bitmap: TBitmap;
I, J: Integer;
ColorHEX: string;
begin
Bitmap := TBitmap.Create;
Randomize;
try
Bitmap.PixelFormat := pf24bit;
Bitmap.Width := 100;
Bitmap.Height := 100;
for I := 0 to Pred(Bitmap.Width) do
begin
for J := 0 to Pred(Bitmap.Height) do
begin
Bitmap.Canvas.Pixels[I, J] := RGB(Random(256),
Random(256),
Random(256));
// get the HEX value of color and do something with it
ColorHEX := ColorToHex(Bitmap.Canvas.Pixels[I, J]);
end;
end;
Bitmap.SaveToFile('test.bmp');
finally
Bitmap.Free;
end;
end;
function TForm1.ColorToHex(Color : TColor): string;
begin
Result :=
IntToHex(GetRValue(Color), 2) +
IntToHex(GetGValue(Color), 2) +
IntToHex(GetBValue(Color), 2);
end;

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