I'm trying to create a Google Sheet that lets you enter the number of pages in each chapter of a book like so:
Chapter | # of pages
5 | 75
6 | 88
... | ...
53 | 63
And split it into x number of chunks of chapters, so that each chunk has about the same number of pages. So say I want to read 300 pages in the next 5 days, and in the next 300 pages are a total of 13 chapters, each of varying length. How can I break those 13 chapters up so I have about the same amount of reading each day?
Edit:
 and distribute the chapters between the days so that there's an approximately even amount of pages per day, while keeping the chapters in order.
try:
=TEXT(((C1*C3)/TEXT(C2, "[m]"))/24, "[h] \da\y(\s) m \min")
Related
Hello all Sheet users out there.
I have a sheet with a list of resources with their production and usage being calculated on the left side and the overall prod/use being monitored on the right side.
A B C D | E F G H
1 Input In Output Out | Resource totIn totOut effective
2 Iron 20 FeIngot 30 | Iron 30 =SUMIF(...) =totIn-totOut
3 Copper 20 CuIngot 20 | Copper 25 =SUMIF(...) =totIn-totOut
4 Stone 10 Gravel 50 | CuIngot =SUMIF(...) =SUMIF(...) =totIn-totOut
5 FeIngot 10 FePlate 5 | FeIngot =SUMIF(...) =SUMIF(...) =totIn-totOut
6 CuIngot 25 Wire 75 | Stone 45 =SUMIF(...) =totIn-totOut
7 CuIngot 10 Cable 20 | Gravel =SUMIF(...) =SUMIF(...) =totIn-totOut
The actual sheet would look more like this:
A B C D | E F G H
1 Input In Output Out | Resource totIn totOut effective
2 Iron 20 FeIngot 30 | Iron 30 20 10
3 Copper 20 CuIngot 20 | Copper 25 20 5
4 Stone 10 Gravel 50 | CuIngot 20 35 -15
5 FeIngot 10 FePlate 5 | FeIngot 30 10 20
6 CuIngot 25 Wire 75 | Stone 45 10 35
7 CuIngot 10 Cable 20 | Gravel 50 0 50
On the left side, I want to mark all cells in column "In" red that have a negative effective production calculated on the right side. I thought about using the conditional formatting, looping through every text cell in the "Resource" column to find the one that equals the "Input" of the same row the cell I want to check is in and then check if the "effective" value of the "Resource" I found is less than 0. The problem is that I don't know how to loop through the values and store the matching row to check if the H value is negative.
Example 1: B6 is checked. A6 needs to be compared to every cell in E2:E and when there is a match, in this case E4, check if H4 is negative. It is, so there is formatting applied.
Example 2: B3 is checked. A3 needs to be compared to every cell in E2:E and when there is a match, in this case E3, check if H3 is negative. It is not, so there is no formatting applied.
Is there any way that I can apply this formatting in the conditional formatting tool?
Keep in mind that my sheet is much more complex than these examples and it has about 120 resources that can't all be moved in order with the left side because multiple rows can use the same resource as input or output.
Thank you in advance for every ounce of your help.
try this formula =VLOOKUP($A1,$E:$H,4,false)<0 in conditional formatting
As im so new to this field and im trying to explore the data for a time series, and find the missing values and count them and study a distribution of their length and fill in these gaps, the thing is i have, let's say 10 file.txt and for each file i have 2 columns as follows:
C1 C2
944 0
920 1
920 2
928 3
912 7
920 8
920 9
880 10
888 11
920 12
944 13
and so on... lets say till 100 and not necessarily the 10 files have the same number of observations.
so here for example the missing values and not necessarily appears in all files that i have, missing value are: 4,5 and 6 in C2 and the corresponding 1st column C1(measured in milliseconds, so the value of 928ms is not a time neighbor of 912ms). So i want to find those gaps(the total missing values in all 10 files) and show a histogram of their lengths.
i wrote a piece of code in R, but the problem is that i don't get the exact total number that i should have for the missing values.
path = "files path"
out.file<-data.frame(TS = 0, Index = 0, File = '')
file.names <- dir(path, pattern =".txt")
for(i in 1:length(file.names)){
file <- cbind(read.table(file.names[i],
header=F,
sep ="\t",
stringsAsFactors=FALSE),
file.names[i])
colnames(file) <- c('TS', 'Index', 'File')
out.file <- rbind(out.file, file)
}
d = dim(out.file)[1]
misDa = 0
for(i in 2:(d-1)){
if(abs(out.file$Index[i]-out.file$Index[i+1]) > 1)
misDa = misDa+1
}
Hard to give specific hints without having a more extensive example of your data that contains some of the actual NAs.
If you are using R (like it seems) the naniar and the imputeTS packages offer nice functions for missing data visualizations.
Some examples from the naniar package, which is especially good for multivariate data (more plot examples):
Some examples from the imputeTS package, which is especially good for time series data (additional plot examples):
In my application, the set of tests for an Estimate and Invoice are very similar. I can use the Scenario Outline and Examples to repeat a test with these types. But how do I repeat all the tests within a feature with examples and not repeat the examples at every scenario outline?
For example, is there a way I can rewrite the tests below without having the state the examples twice?
Scenario Outline: Adding a sales line item
Given I have a <Transaction>
And Add Hours of quantity 2 and rate 3
When I save
Then the total is 6
Examples:
| Transaction |
| Invoice |
| Estimate |
Scenario Outline: Adding two sales line item
Given I have a <Transaction>
And Add Hours of quantity 2 and rate 3
And Add Hours of quantity 5 and rate 2
When I save
Then the total is 16
Examples:
| Transaction |
| Invoice |
| Estimate |
In other words, is there such a thing called, for a lack of a better, Feature Outline?
Unfortunatelly Gherkin language does not support anything like this
I just started learning Memory Management and have an idea of page,frames,virtual memory and so on but I'm not understanding the procedure from changing logical addresses to their corresponding page numbers,
Here is the scenario-
Page Size = 100 words /8000 bits?
Process generates this logical address:
10 11 104 170 73 309 185 245 246 434 458 364
Process takes up two page frames,and that none of its are resident (in page frames) when the process begins execution.
Determine the page number corresponding to each logical address and fill them into a table with one row and 12 columns.
I know the answer is :
0 0 1 1 0 3 1 2 2 4 4 3
But can someone explain how this is done? Is there a equation or something? I remember seeing something with a table and changing things to binary and putting them in the page table like 00100 in Page 1 but I am not really sure. Graphical representations of how this works would be more than appreciated. Thanks
I want to subtract a number form a duration but not sure how can I do it.
A1 : 137:47:00 (formatted as duration)
A2 : 126 (formatted as number)
When I subtract it is showing unexpected value
=(A1-A2) = -120.26
I was expecting something similar to 11.
Subtracting a number (without dimension) from a duration does not really make a lot of sense but if 137:47:00 represented 137 hours and 47 minutes then subtracting 126 hours from that would (and give a result between 11 and 12 hours). To be able to compare like with like, the duration can be represented as a number by accessing the fact that Google spreadsheets treats 24 hours as number 1. So multiply 137:47:00 (if representing hour, minutes, seconds) by 24 to get a number from which another number can be subtracted to give a meaningful result (ie 11.7833333 - representing 11 hours 47 minutes if to subtract 126 hours from 137 hours and 47 minutes). Therefore:
=24*A1-A2
might suit.
Calculating time worked per day on Web Applications addresses a vaguely similar issue.