In Lua Random number generation issue - lua

Question

We are performing task as Accept a number as the seed value for math.randomseed(), and generate a random integer (interval [1,6]) using math.random() during each iteration of a loop, and continue the loop till the number is 6.
For which we had written code as
i = io.read()
local count = 0
math.randomseed(i)
for x = 1, 4 do
value = math.random(1, 6)
print(value)
count = count + 1
end
print(count)
We failed to pass test because
Input (stdin)
Run as Custom Input
0
Your Output (stdout)
3
5
5
6
2
Expected Output
3
5
5
6
4
Please help us

Answer 1

OP code seems to be having loop problems. I encourage the OP to read the Lua documentation about Control Structures, where Lua's while, repeat until, and goto are described, as well as the following manual section about Lua's For Statement. It is difficult to write any program in any language without understanding the fundamental control structures of the language.
OP problem can be solved in a variety of ways.
Using for
-- for version
i = io.read()
math.randomseed(i)
local count
for i = 1, math.huge do
local value = math.random(1, 6)
print(value)
count = i
if value == 6 then break end
end
print(count)
Here math.huge is the largest representable number in Lua, typically the special value inf, making this effectively an infinite loop. The variable i keeps track of how many random numbers have been generated, but since i will not be visible outside of the loop, the count variable is needed to copy the value of i so that it can be printed at the end.
Using while
-- while version
i = io.read()
math.randomseed(i)
local value = math.random(1, 6)
local count = 1
while value < 6 do
print(value)
count = count + 1
value = math.random(1, 6)
end
print(value)
print(count)
Here the looping construct begins with a test, so a test value must be created before the loop begins. This means that the count must be initialized to 1 before the loop begins, and it also means that the call to math.random will be duplicated. Not pretty.
Using repeat until
-- repeat until version
i = io.read()
math.randomseed(i)
local count = 0
repeat
local value = math.random(1, 6)
print(value)
count = count + 1
until value == 6
print(count)
Here the test comes at the end of the loop construct. This allows the code to call math.random only once.
Using goto
-- goto version
i = io.read()
math.randomseed(i)
local count = 0
::loop::
local value = math.random(1, 6)
print(value)
count = count + 1
if value < 6 then goto loop end
print(count)
You probably should not use goto to solve this problem, but you can. You have to be careful with goto in Lua; you can't jump into a block, out of a function, or into the scope of a local variable.
As you can see, there are some subtleties to these looping constructs, and using them requires some familiarity with the details.
All four versions produce identical outputs for the same inputs:
$ lua loops.lua
42
2
5
3
2
2
4
6
7