Following problem. I have decimal numbers in my Google Sheets that I get from a website.
The numbers have 3 digits after the decimal point or they have no comma in there. I need the numbers without a comma and adding Zero after 1,2 => 1200 or 1,22 => 1220 and 2 should be 2.
Say if a number looks like this on the website:
1,200
1,220
1,222
12,220
2
I get the data via Google spreadsheet with the formula =IMPORTDATA("API_LINK")
There is the problem that the zeros that I don't want to lose are automatically deleted by =IMPORTDATA
Means I get that copied into the table like this :
1,2
1,22
1,222
12,22
2
My question is, how do I get the numbers to be automatically converted with another formula or even with a script that looks like this:
1,2 => 1200
1,22 => 1220
1,222 => 1222
12,22 => 12220
2 => 2
So normal numbers should be normal and decimals should be converted.
The formula what I tried but is only working for 1,222 => 1222. The other looke like this 1,2 => 43862 and 1,22 => 1,22 also 12,22 => 12,22.
=IFERROR(VALUE(SUBSTITUTE(A2;",";"."));VALUE(SUBSTITUTE(A2;".";",")))
I tried even to change the settings in the sheet but isn't working at all.
It would be very nice if someone could help me with that.
If your import is removing final zeros, this indicates that what winds up in your sheet is most likely text and not a number at all.
It is always easier to help if you share a sample sheet with full editing permissions. However, given what I know from your post, try this:
=IF(A2="","",VALUE(A2&IFERROR(REPT("0",3-(LEN(A2)-FIND(",",A2))))))
This would also work as an array formula with slight modification (i.e., it could "solve" a whole column with one formula rather than dragging a formula down). For instance, if your raw data were in A2:A, you could put the following array formula in B2 (assuming column B is completely blank below B2):
=ArrayFormula(IF(A2:A="","",VALUE(A2:A&IFERROR(REPT("0",3-(LEN(A2:A)-FIND(",",A2:A)))))))
try:
=ARRAYFORMULA(SUBSTITUTE(TO_TEXT(IMPORTDATA("API_LINK")), ",", ))
You also can use format patterns.
You can define how many digits wants in the decimal side with TEXT function. In this case, always three digits even zeros:
##.000
Then, once you have the number you want, you can remove the decimal separator with the SUBSTITUTE funtion.
Finally you got:
SUBSTITUTE(TEXT(YOURNUMBER;"##.000");",";"")
More info in this google site.
Related
I have two different sheets, with two of the same ranges (age). I want to combine these two separate ranges into one on a different sheet. Current formula / function I am using:
={(importrange("https...", "Sheet1!A2:A100"));(importrange(""https...", "Sheet2!A2:A100"))}"))
What am I doing wrong?
I was able to bring in one range at a time with this formula / function:
=IMPORTRANGE("https...", "Sheet1!A2:A100")
=IMPORTRANGE("https...", "Sheet2!A2:A100")
but I need them to be in one column together (the order does not matter, I just need the values to be pulled across).
Try two IMPORTRANGE functions within one formula separated by a semi-colon and wrapped in braces (e.g. { and } that you type yourself)
={IMPORTRANGE("https://docs.google.com/spreadsheets/d/1mYWnO8vzyb5o4jzp-Ti-369nSyQoCfg-WzqaaTb94tE", "Sheet1!A2:A10");IMPORTRANGE("https://docs.google.com/spreadsheets/d/1mYWnO8vzyb5o4jzp-Ti-369nSyQoCfg-WzqaaTb94tE", "Sheet2!A2:A")}
If you do not have a set number of rows in the source sheet1 (e.g. A2:A100), then the retrieved data from sheet2 will start on the 101st row with blanks above it. To get around this, concatenate a dynamic 'last populated' row number onto the range string.
={IMPORTRANGE("https://docs.google.com/spreadsheets/d/1mYWnO8vzyb5o4jzp-Ti-369nSyQoCfg-WzqaaTb94tE", "Sheet1!A2:A"&match(1E+99, IMPORTRANGE("https://docs.google.com/spreadsheets/d/1mYWnO8vzyb5o4jzp-Ti-369nSyQoCfg-WzqaaTb94tE", "Sheet1!A:A")));IMPORTRANGE("https://docs.google.com/spreadsheets/d/1mYWnO8vzyb5o4jzp-Ti-369nSyQoCfg-WzqaaTb94tE", "Sheet2!A2:A")}
source link
destination link
What am I doing wrong?
You have a couple of double inverted commas too many and unmatched parentheses (also some unnecessary spaces and parentheses). Following should work, with granting authorisation if required.:
={importrange(" k e y 1 ","Sheet1!A2:A100");importrange(" k e y 2 ","Sheet2!A2:A100")}
It might help to compare 'yours' and 'mine' in a word processor and fixed width font.
I'm using Google Sheets and looking for an arrayformula that able to take a list in two columns and arrange it alternately in one column. The sheet contains about 5,000 rows, each row has more than 35 characters.
I tried this:
=transpose(split(join(" ", query(transpose(B5:C),,50000)), " "))
But then I got this message:
Please take a look at the sheet here:
https://docs.google.com/spreadsheets/d/11T1Roj1trviOSiiTZS292-4l3oODid7KLi9oGz3Z66o/edit#gid=0
Assuming your 2 columns are A and B, this formula will "interlace" them:
=query(
sort(
{arrayformula({row(A1:A3)*2, A1:A3});
arrayformula({row(B1:B3)*2+1, B1:B3})}
),
"select Col2")
Explanation, unwrapping the formula from the inside:
Each value gets a unique number, based on its row number times 2 (+1 for the 2nd column)
Everything is sorted based on this number
Only the 2nd column is extracted for the result.
There is a function for this called FLATTEN().
This works perfectly as a general solution since it takes an array of any size and outputs the items in the order they appear left-right-top-down (See here).
It can be combined with TRANSPOSE() to accomplish the same thing but in the horizontal case, and if needed blank cells can be omitted with FILTER().
EDIT:
My sincere apologies, I did not read the question carefully enough. My response is incorrect.
This should work:
={B5:B12;C5:C12}
just be careful to NOT change it to
={B5:B;C5:C}
This will start an infinite loop where the spreadsheet will increase the amount of rows in the spreadsheet to allow this output column to expand, but in doing so increases the length of the 2 input columns, meaning the length of the output column increases even more, so the spreadsheet tries adding more rows, etc, etc. It'll make your sheet crash your browser or something each time you try to open it.
In Row5:
=ArrayFormula(offset(B$5,INT((row()-5)/2),iseven(row())))
Would need to be copied down however.
I'm trying to sort a list of documents, but I'm having an issue with the documents that have a letter as a suffix.
Whenever we amend a document we add a letter to the end of the number, but when I sort by number in excel it sorts like this:
1
2
3
10
11
1606
1603D
1605B
1606A
1606C
1610A
1623A
20A
220B
390A
399A
402A
415A
450A
488A
557B
How can I make it sort in order of document number and amendment?
Like so:
1
2
3
10
11
1603D
1605B
1606
1606A
1606C
1610A
1623A
20A
220B
390A
399A
402A
415A
450A
488A
557B
As long as you have a mix of text and number, you won't be able to use Excel's built-in sort to achieve the result you describe.
If you append a letter to a number you effectively change the data type from number to text. Text will always be sorted after any number, hence the number 1606 comes before the text 1606A.
You could try to make all values real text, maybe indicate levels by appending digits with dots, like this:
1.
1.0.
1.1.
1.6.0.3.D
1.6.0.5.B
1.6.0.6.
1.6.0.6.A
1.6.0.6.C
1.6.1.0.A
1.6.2.3.A
2.
2.0.A.
2.2.0.B.
3.
3.9.0.A.
3.9.9.A.
4.0.2.A.
4.1.5.A.
4.5.0.A.
4.8.8.A.
5.5.7.B.
But even that does not give you the sort order you describe as the desired result.
Your desired sort order will be hard to achieve even if all values are text, or if you replace the A, B, C with a decimal .1, .2, .3. -- It's really hard to understand why 20 would come after 1623.
The solution I found was to add a column, and copy this formula into each cell:
=IF(ISNUMBER(--RIGHT(A2)),A2,LEFT(A2,LEN(A2)-1))
The formula removes the letters from the numbers, you can then sort your sheet using the new column of clean numbers.
I've been at this problem for a while now. I am trying to sum numbers under a specific column when the rows equal a certain text and then display that sum on a different sheet. So far I came up with this formula: =IF(EXACT(A2,Table!A2:A)=TRUE,SUM(Table!C2:C)); however the only problem is that is sums everything in column C (which makes sense).
I wish there was a way to do something like the following: SUM(Table!C2:C where EXACT(A2,TABLE!A2:A)=TRUE). I've also tried the SUMIF(), DSUM(), and QUERY() functions to no avail. I must be getting logically tripped up somewhere.
Figured it out: =SUM(FILTER(Table!E4:E, EXACT(Table!A4:A,A4)=TRUE)).
=sum ( FILTER (b1:b10, a1:a10 = "Text" ) )
// the above formula will help you to take the sum of the values in column B when another column A contain a specific text.
The formula is applicable only in Google Spreadsheets
I have 5 columns of numbers that I want to sort per row into another set of columns. I figured I need to use small() (e.g. small(a2:e2,1) for f2; small(a2:e2,2) for g2 and so on). Is there away to iterate this for the next rows; if possible using only native google spreadsheet formulas?
Thanks in advance
I was able to make a temporary work around, but I had to use 3 cheat columns. It looks ok for now but I imagine it will be troublesome for really huge numbers.
Here's a sample sheet for reference: https://docs.google.com/spreadsheets/d/1MQTP2XkRsPRAnPQ5wLhkR8JoNVY6YOExVlOkkX8UeRs/edit#gid=0
The original data are in A3:E
The first cheat column (G3:G) simply creates a column of numbers from 1 to the largest number found in the source data. 1-9 is changed to 01-09 for easier searching. "#" is then added at the end-this will come handy later:
Cheat Column 1 =filter(if(row(A:A)=max(A:E)+1,ʺ#ʺ,text(row(A:A),ʺ00ʺ)),row(A:A)<=max(A:E)+1)
The second cheat column (H3:H) combines each row into a string separated by "-" with a "#" marker:
Cheat Column 2=filter(text(A3:A,ʺ00ʺ)&ʺ-ʺ&text(B3:B,ʺ00ʺ)&ʺ-ʺ&text(C3:C,ʺ00ʺ)&ʺ-ʺ&text(D3:D,ʺ00ʺ)&ʺ-ʺ&text(E3:E,ʺ00ʺ)&ʺ#ʺ,A3:A<>ʺʺ)
The last cheat column (I3:I) sorts each line (from cheat column 2) by finding each number from cheat column from 01 up to the max number, then the "#" char (this ensures that each line will still have the # end marker). "Find" will return the "position" of each number or an error if it's not found. By using "if", we can make "find" return the actual number or "" instead.
=filter(arrayformula(if(iferror(find(transpose(filter(G3:G,G3:G<>ʺʺ)),H3:H),ʺʺ), transpose(filter(G3:G,G3:G<>ʺʺ)),ʺʺ)),A3:A<>ʺʺ)
The formula above creates as many columns as there are numbers from cheat column 1. To prevent this, a "-" is added to each number then "Concatenate" is used to combine everything into one massive string with each set separated by "#". The string is then split using the "#" marker.
Cheat Column 3 =transpose(split(concatenate(filter(arrayformula(if(iferror(find(transpose(filter(G3:G,G3:G<>ʺʺ)),H3:H),ʺʺ),ʺ-ʺ&transpose(filter(G3:G,G3:G<>ʺʺ)),ʺʺ)),A3:A<>ʺʺ)),ʺ#ʺ))
Each number is then separated into each corresponding column by using mid().
Small 1 =filter(mid(I3:I,2,2)*1,A3:A<>ʺʺ)
Small 2 =filter(mid(I3:I,5,2)*1,A3:A<>ʺʺ)
Small 3 =filter(mid(I3:I,8,2)*1,A3:A<>ʺʺ)
Small 4 =filter(mid(I3:I,11,2)*1,A3:A<>ʺʺ)
Small 5 =filter(mid(I3:I,14,2)*1,A3:A<>ʺʺ)
Note that the formula above is only for numbers 1-99. For larger numbers, the Text() formulas should have more zeroes to correspond to the number of digits of the biggest number. The Mid() formulas should also be adjusted accordingly.
I would like to stress that I am very far from being a spreadsheet expert and that this solution is very "unoptimized". It requires several cheat columns; with the first one even having more rows than the original data. If anyone can help me get rid of the cheat columns (or at least the first one) I will be very grateful.
How about using SMALL like you mentioned in your question?
=small($A3:$E3,column()-columns($A3:$G3))
You will need to change the ranges accordingly. The last $G$3 is the cell just before the cell where the formula is placed.
Sample