I need help to optimize the rails code to update Memcache data.
The problem is like,
I have JSON data for a particular match in the following manner and writing into the cache.
match_data = {'teams' : 'Team one', 'Team two', 'score' { 'team1':0, 'team2': 1 }, time: 60 }
Rails.cache.write('match_123', match_data) #123 is match id
The above one is a very small example of a match it can have huge data.
So the match data is receiving in the application from the service frequently and updating the same in the cache and used the same to display in front-end as well.
So the actual problem is that I received the match updates in response like score, time, individually and frequently.
So I use the following code to update the cache data.
data = Rails.cache.read('match_123')
data[:time] = 120
OR
data[:score][:team1] = 1
Rails.cache.write('match_123', data)
I am using background jobs to perform the above process.
This process Is being too quick and we have multiple matches running together,
So at a point what is happening here as we updating complete match hash each time in the cache for a particular key-value change.
So what happening when we have two queues for example:
UpdateMatchCacheDataJob.perform_later(score_update)
UpdateMatchCacheDataJob.perform_later(time_update)
Suppose this queue runs together at a time it will either update the time in the cache or score.
This is the complexity I am facing. I have also tried to perform the job now yet got the issue sometime.
UpdateMatchCacheDataJob.perform_now(score_update)
UpdateMatchCacheDataJob.perform_now(time_update)
My problem may resolve if I play with particular data that needs to be updated instead not to update complete hash each time. Or is there a way to update the particular data in a hash
Note: I am using the AWS Memcache instance to store cache data.
I hope I could explain my issue, please let me know if anything needs from my side to explain the issue.
Related
We are already using cookie based sessions, and switching off them to file store sessions in not an option. However, I need a way to store larger amounts of session data (up to 10MG or so) -- beyond the limit of cookie session and, even it weren't, round-tripping that much data on multiple requests would be slow.
I am currently attempting to solve this by using (abusing?) Rails.cache. The basic setup is like this:
I post to a route, which has the following code:
# calculate some results...
Rails.cache.write('search_results' + session.id), search_results)
redirect_to '/results'
Inside GET /results, I read the cached data and send it to the client:
#results = Rails.cache.read('search_results' + session.id)
This works fine. However, if I subsequently make a request to another route like GET /results2 that also calls Rails.cache.read('search_results' + session.id), it will return nil. Even if all calls happen within a 5-10s span.
So my questions are:
Why does this happen? What determines when Rails.cache clean itself?
Is there a way to make this work?
Is there a better approach altogether that doesn't involve using a DB or redis?
Answer to your questions:
The problem with file cache store is that it stores file locally. Thus, if you have multiple servers, cache can be written to one server while cache is read on another server which will return ‘nil’. The solution is to use cache store that can be shared among multiple servers.
Using redis-store may be a solution: https://github.com/redis-store/redis-rails
I have websocket price data streaming in to my rails api app which I want to keep updated so any api requests get an updated response. It would be too expensive to save each update to the database. How can I do this? In Ember I can modify the model and it persists. It doesn't seem to happen in rails.
Channel controller:
def receive(message)
#ActionCable.server.broadcast('channel', message)
platform = Platform.find(params[:id]);
market = platform.markets.find_by market_name: message["market_name"]
market.attributes = {
market.price = message.values["price"],
etc......
}
#market.save [this is too expensive every time]
end
Am I going about this in the right way? It also seems inefficient to use find every time I want to update which could be multiple times per second. In Ember I created a record Id lookup array so I could quickly match the market_name, I don't see how to do this in rails.
Persistence to some store is the only way you can have other threads respond with latest value.
Instead of 3 queries( 2 selects and 1 update) you can do it with just 1 update
Market.where(platform_id: params[:id], market_name: message["market_name"]).
update_all(price: message.values["price"])
With proper index, you might have a sub-ms performance for each update.
Depending on your business need:
If you are getting tons of updates for a market every second(making all prior stale and useless), you can choose to ignore few and not fire update at all.
We are working on a data visualization problem right now. Our customer wants us to show the last 6 months data for a honeybee hive on a graph.
Clearly it's gonna be a huge dataset. Adding indexes we overcame the database slowness problem in loading data though we still have problem in visualizing data on a graph.
Here is the related code:
def self.prepare_single_hive_messages_for_datatable_dygraph(messages, us_metric_enabled)
data = []
messages.each do |message|
record = []
record << message.occurance_time.to_s(:dygraph_format)
record << weight_according_to_metric(message.weight, us_metric_enabled)
record << temperature_according_to_metric(message.temperature, us_metric_enabled)
record << (message.humidity.nil? ? nil : message.humidity.to_f)
data << record
end
return data
end
The problem is that messages.each is very slow and takes more than 30 seconds. Is there any solution to overcome this?
Project Specification:
Rails Version: 4.1.9
Graph Library: Dygraph
Database: Postgres
There are two ways to attack a performance problem like this.
Find and correct the performance bottle neck
Break it into smaller pieces
Finding Performance issues
First, get a dataset large enough to reproduce the problem setup on your dev system. Then look at the logs so you can see how long the transaction is taking. You should be looking for a line like this:
Completed 200 OK in 432.1ms (Views: 367.7ms | ActiveRecord: 61.4ms)
Rerun the task a couple times since caching can cause variations. Write down your different times. Then remove everything in the loop and run it with just the loop. Do the numbers go back to looking reasonable? If that is the case then you know the problem is the work you are doing inside the loop. Next, add each line in the loop back on its own (or one at a time if they depend on each other). Figure out which line causes those numbers to jump the most.
This is the point where you should try to performance tune your code. Check for queries that could be smarter. Make sure you aren't querying the same data over and over. If you have a function in a model that computes something and you call it multiple times to get the same answer then use this to only compute once:
def something
return #savedvalue if #savedvalue
#savedvalue = really complex calculation
end
The goal is to find the worse offender so you can make changes that have the biggest impact. However, if you are working with a LOT of data this may only get you so far. It may be impossible to performance tune enough for all the data. In that case there is option 2.
Break it into smaller pieces
Write a second rails action who's only job is to render a single record on a graph. It will do the inner part of your loop but only on the message who's id was passed to it.
Call your original function to setup the view and pass the list of messages to the view. In the view loop through the list of messages to setup jquery ajax code to call the above action once for each message. Have this run in on document ready.
Then, the page will load with an empty graph... but as soon as it is up the individual processed records will be fed to it and appear one at a time on the page. It will still take just ask long (or even a little longer because of overhead) to complete the graph... but it will no longer time out. Each ajax call will be its own quick hit to the server instead of one big long hit.
I just used this very technique to load a rather long report on a site I work on. Ideally we'd like to fix any underlying performance issues... but what we really wanted was to have a report working right away and then fix the performance issues as we had time.
Ok you said every person sees the same set of data, which is great, means we can cache without worrying about who's logged in, first here's your method, with tiny improvements
def self.prepare_single_hive_messages_for_datatable_dygraph(messages, us_metric_enabled)
messages.inject([]) do |records, message|
records << [].tap do |record|
record << message.occurance_time.to_s(:dygraph_format)
record << weight_according_to_metric(message.weight, us_metric_enabled)
record << temperature_according_to_metric(message.temperature, us_metric_enabled)
record << (message.humidity.nil? ? nil : message.humidity.to_f)
end
end
end
Then create a caching function, that runs this method and caches it
# some class constants
CACHE_KEY = 'some_cache_key'
EXPIRY_TIME = 15.minutes
# the methods
def self.write_single_hive_messages_to_cache(messages, us_metric_enabled)
Rails.cache.write CACHE_KEY,
self.class.prepare_single_hive_messages_for_datatable_dygraph(messages, us_metric_enabled),
expires_in: EXPIRY_TIME
end
And a simple cache reading method
self.read_single_hive_messages_from_cache
Rails.cache.read CACHE_KEY
end
Then create a rake task that just fetches these messages and call the caching method, and rails will write the cache.
Create a cron job that calls this rake task, set the cron job to 5 minutes or so, the expiry time is longer just in case for some reason the cron job didn't run, the data will still be available for the next run.
This way your processing is run in the background, every 5 ( or whatever time you choose ) minutes, the page load should happen normally with no delay at all, since the array data will be loaded from the pre-calculated cache.
In case the cron stops working, the data will expire in the 15 minutes I've set, and then the read cache method will return nil, you could avoid this and set the data to never expire, but then the data will become stale and the old data will keep getting returned.
Another way to handle this is to tell the cache reading method how to generate the cache it self, so if it finds the cache empty it generates one and caches it itself before returning the data, the method would look like this
def self.read_single_hive_messages_from_cache(messages, us_metric_enabled)
Rails.cache.fetch CACHE_KEY, expires_in: EXPIRY_TIME do
self.class.write_single_hive_messages_to_cache(messages, us_metric_enabled)
end
end
But then make sure that messages is an ActiveRecord::Relation and not a processed array, because you don't want to query for 1+ million records and then find the cache already ready, if it's an ActiveRecord::Relation it will not touch the database until the array is started ( inside the caching block ), if the cache exists it will be returned before you enter the block and thus the data won't get fetched, saving you that huge query.
I know the answer got long, if you need more help tell me.
I have a class method (placed in /app/lib/) which performs some heavy calculations and sub-http requests until a result is received.
The result isn't too dynamic, and requested by multiple users accessing a specific view in the app.
So, I want to schedule a periodic run of the method (using cron and Whenever gem), store the results somewhere in the server using JSON format and, by demand, read the results alone to the view.
How can this be achieved? what would be the correct way of doing that?
What I currently have:
def heavyMethod
response = {}
# some calculations, eventually building the response
File.open(File.expand_path('../../../tmp/cache/tests_queue.json', __FILE__), "w") do |f|
f.write(response.to_json)
end
end
and also a corresponding method to read this file.
I searched but couldn't find an example of achieving this using Rails cache convention (and not some private code that I wrote), on data which isn't related with ActiveRecord.
Thanks!
Your solution should work fine, but using Rails.cache should be cleaner and a bit faster. Rails guides provides enough information about Rails.cache and how to get it to work with memcached, let me summarize how I would use it in your case
Heavy method
def heavyMethod
response = {}
# some calculations, eventually building the response
Rails.cache.write("heavy_method_response", response)
end
Request
response = Rails.cache.fetch("heavy_method_response")
The only problem here is that when ur server starts for the first time, the cache will be empty. Also if/when memcache restarts.
One advantage is that somewhere on the flow, the data u pass in is marshalled into storage, and then unmartialled on the way out. Meaning u can pass in complex datastructures, and dont need to serialize to json manually.
Edit: memcached will clear your item if it runs out of memory. Will be very rare since its using a LRU (i think) algoritm to expire things, and I presume you will use this often.
To prevent this,
set expires_in larger than your cron period,
change your fetch code to call the heavy_method if ur fetch fails (like Rails.cache.fetch("heavy_method_response") {heavy_method}, and change heavy_method to just return the object.
Use something like redis which will not delete items.
I am looking to find information on how the caching mechanism in Rails 4 prevents against multiple users trying to regenerate cache keys at once, aka a cache stampede: http://en.wikipedia.org/wiki/Cache_stampede
I've not been able to find out much information via Googling. If I look at other systems (such as Drupal) cache stampede prevention is implemented via a semaphores table in the database.
Rails does not have a built-in mechanism to prevent cache stampedes.
According to the README for atomic_mem_cache_store (a replacement for ActiveSupport::Cache::MemCacheStore that mitigates cache stampedes):
Rails (and any framework relying on active support cache store) does
not offer any built-in solution to this problem
Unfortunately, I'm guessing that this gem won't solve your problem either. It supports fragment caching, but it only works with time-based expiration.
Read more about it here:
https://github.com/nel/atomic_mem_cache_store
Update and possible solution:
I thought about this a bit more and came up with what seems to me to be a plausible solution. I haven't verified that this works, and there are probably better ways to do it, but I was trying to think of the smallest change that would mitigate the majority of the problem.
I assume you're doing something like cache model do in your templates as described by DHH (http://37signals.com/svn/posts/3113-how-key-based-cache-expiration-works). The problem is that when the model's updated_at column changes, the cache_key likewise changes, and all your servers try to re-create the template at the same time. In order to prevent the servers from stampeding, you would need to retain the old cache_key for a brief time.
You might be able to do this by (dum da dum) caching the cache_key of the object with a short expiration (say, 1 second) and a race_condition_ttl.
You could create a module like this and include it in your models:
module StampedeAvoider
def cache_key
orig_cache_key = super
Rails.cache.fetch("/cache-keys/#{self.class.table_name}/#{self.id}", expires_in: 1, race_condition_ttl: 2) { orig_cache_key }
end
end
Let's review what would happen. There are a bunch of servers calling cache model. If your model includes StampedeAvoider, then its cache_key will now be fetching /cache-keys/models/1, and returning something like /models/1-111 (where 111 is the timestamp), which cache will use to fetch the compiled template fragment.
When you update the model, model.cache_key will begin returning /models/1-222 (assuming 222 is the new timestamp), but for the first second after that, cache will keep seeing /models/1-111, since that is what is returned by cache_key. Once 1 second passes, all of the servers will get a cache-miss on /cache-keys/models/1 and will try to regenerate it. If they all recreated it immediately, it would defeat the point of overriding cache_key. But because we set race_condition_ttl to 2, all of the servers except for the first will be delayed for 2 seconds, during which time they will continue to fetch the old cached template based on the old cache key. Once the 2 seconds have passed, fetch will begin returning the new cache key (which will have been updated by the first thread which tried to read/update /cache-keys/models/1) and they will get a cache hit, returning the template compiled by that first thread.
Ta-da! Stampede averted.
Note that if you did this, you would be doing twice as many cache reads, but depending on how common stampedes are, it could be worth it.
I haven't tested this. If you try it, please let me know how it goes :)
The :race_condition_ttl setting in ActiveSupport::Cache::Store#fetch should help avoid this problem. As the documentation says:
Setting :race_condition_ttl is very useful in situations where a cache entry is used very frequently and is under heavy load. If a cache expires and due to heavy load seven different processes will try to read data natively and then they all will try to write to cache. To avoid that case the first process to find an expired cache entry will bump the cache expiration time by the value set in :race_condition_ttl. Yes, this process is extending the time for a stale value by another few seconds. Because of extended life of the previous cache, other processes will continue to use slightly stale data for a just a bit longer. In the meantime that first process will go ahead and will write into cache the new value. After that all the processes will start getting new value. The key is to keep :race_condition_ttl small.
Great question. A partial answer that applies to single multi-threaded Rails servers but not multiprocess(or) environments (thanks to Nick Urban for drawing this distinction) is that the ActionView template compilation code blocks on a mutex that is per template. See line 230 in template.rb here. Notice there is a check for completed compilation both before grabbing the lock and after.
The effect is to serialize attempts to compile the same template, where only the first will actually do the compilation and the rest will get the already completed result.
Very interesting question. I searched on google (you get more results if you search for "dog pile" instead of "stampede") but like you, did I not get any answers, except this one blog post: protecting from dogpile using memcache.
Basically does it store you fragment in two keys: key:timestamp (where timestamp would be updated_at for active record objects) and key:last.
def custom_write_dogpile(key, timestamp, fragment, options)
Rails.cache.write(key + ':' + timestamp.to_s, fragment)
Rails.cache.write(key + ':last', fragment)
Rails.cache.delete(key + ':refresh-thread')
fragment
end
Now when reading from the cache, and trying to fetch a non existing cache, will it instead try to fecth the key:last fragment instead:
def custom_read_dogpile(key, timestamp, options)
result = Rails.cache.read(timestamp_key(name, timestamp))
if result.blank?
Rails.cache.write(name + ':refresh-thread', 0, raw: true, unless_exist: true, expires_in: 5.seconds)
if Rails.cache.increment(name + ':refresh-thread') == 1
# The cache didn't exists
result = nil
else
# Fetch the last cache, as the new one has not been created yet
result = Rails.cache.read(name + ':last')
end
end
result
end
This is a simplified summary of the by Moshe Bergman that i linked to before, or you can find here.
There is no protection against memcache stampedes. This is a real problem when multiple machines are involved and multiple processes on those multiple machines. -Ouch-.
The problem is compounded when one of the key processes has "died" leaving any "locking" ... locked.
In order to prevent stampedes you have to re-compute the data before it expires. So, if your data is valid for 10 minutes, you need to regenerate again at the 5th minute and re-set the data with a new expiration for 10 more minutes. Thus you don't wait until the data expires to set it again.
Should also not allow your data to expire at the 10 minute mark, but re-compute it every 5 minutes, and it should never expire. :)
You can use wget & cron to periodically call the code.
I recommend using redis, which will allow you to save the data and reload it in the advent of a crash.
-daniel
A reasonable strategy would be to:
use a :race_condition_ttl with at least the expected time it takes to refresh the resource. Setting it to less time than expected to perform a refresh is not advisable as the angry mob will end up trying to refresh it, resulting in a stampede.
use an :expires_in time calculated as the maximum acceptable expiry time minus the :race_condition_ttl to allow for refreshing the resource by a single worker and avoiding a stampede.
Using the above strategy will ensure that you don't exceed your expiry/staleness deadline and also avoid a stampede. It works because only one worker gets through to refresh, whilst the angry mob are held off using the cache value with the race_condition_ttl extension time right up to the originally intended expiry time.